What's the connection between moment generating function and methods of moment?












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The moment generating function is given by $m(t)=E(e^{tY})$ where $Y$ is a random variable.



However, the methods of moment is given by $m'_k=frac{1}{n}sum_{i=1}^nY_i^k$ where $frac{d^k m(t)}{dt^k}|_{t=0}=mu'_k$.



What's the connection between $m_k'$ and $m(t)$? Why $m'_k=frac{1}{n}sum_{i=1}^nY_i^k$?










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    0












    $begingroup$


    The moment generating function is given by $m(t)=E(e^{tY})$ where $Y$ is a random variable.



    However, the methods of moment is given by $m'_k=frac{1}{n}sum_{i=1}^nY_i^k$ where $frac{d^k m(t)}{dt^k}|_{t=0}=mu'_k$.



    What's the connection between $m_k'$ and $m(t)$? Why $m'_k=frac{1}{n}sum_{i=1}^nY_i^k$?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      The moment generating function is given by $m(t)=E(e^{tY})$ where $Y$ is a random variable.



      However, the methods of moment is given by $m'_k=frac{1}{n}sum_{i=1}^nY_i^k$ where $frac{d^k m(t)}{dt^k}|_{t=0}=mu'_k$.



      What's the connection between $m_k'$ and $m(t)$? Why $m'_k=frac{1}{n}sum_{i=1}^nY_i^k$?










      share|cite|improve this question









      $endgroup$




      The moment generating function is given by $m(t)=E(e^{tY})$ where $Y$ is a random variable.



      However, the methods of moment is given by $m'_k=frac{1}{n}sum_{i=1}^nY_i^k$ where $frac{d^k m(t)}{dt^k}|_{t=0}=mu'_k$.



      What's the connection between $m_k'$ and $m(t)$? Why $m'_k=frac{1}{n}sum_{i=1}^nY_i^k$?







      statistics moment-generating-functions






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      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Nov 26 '18 at 3:38









      user9976437user9976437

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