How to make Composite Primary Key Using Two Foreign key?
I have Three table in which one table is using the foreign key of other two table to make the composite primary key. Now i am using the @Embeddable but as both the key are the foreign key, How i will create the composite primary key now in the Entity.
CREATE TABLE table1
(table1id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY (table1id));
table2
CREATE TABLE table2
(table2id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY (table2id));
table3
CREATE TABLE table3 (
table1id INT NOT NULL,
table2id INT NOT NULL,
PRIMARY KEY (table1id, table2id),
FOREIGN KEY (table1id) REFERENCES table1 (table1id),
FOREIGN KEY (table2id) REFERENCES table2 (table2id)
);
How to convert this table into an Hibenate Entity.
@Entity
@Table(name="table3")
class Table1 {
@Id
long table1id;
//getter and setter
}
@Entity
@Table(name="table3")
class Table2 {
@Id
long table2id;
//getter and Setter
}
@Entity
@Table(name="table3")
class Table3 {
@EmbeddedId
private table3PK table3PKId;
//getter and Setter
}
@Embeddable
Class table3PK{
@ManyToOne
@JoinColumn(name="table1Id" ,referencedColumnName="table1id")
Table1 table1;
@ManyToOne
@JoinColumn(name="table2Id" ,referencedColumnName="table2id")
Table2 table2;
public table3PK(){
}
public table3PK(Table1 table1 ,Table2 table2){
this.table1;
this.table2;
}
}
}
hibernate jpa spring-data-jpa
asked Nov 19 '18 at 13:09
Prabhat YadavPrabhat Yadav
1962417
add a comment |
I have Three table in which one table is using the foreign key of other two table to make the composite primary key. Now i am using the @Embeddable but as both the key are the foreign key, How i will create the composite primary key now in the Entity.
CREATE TABLE table1
(table1id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY (table1id));
table2
CREATE TABLE table2
(table2id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY (table2id));
table3
CREATE TABLE table3 (
table1id INT NOT NULL,
table2id INT NOT NULL,
PRIMARY KEY (table1id, table2id),
FOREIGN KEY (table1id) REFERENCES table1 (table1id),
FOREIGN KEY (table2id) REFERENCES table2 (table2id)
);
How to convert this table into an Hibenate Entity.
@Entity
@Table(name="table3")
class Table1 {
@Id
long table1id;
//getter and setter
}
@Entity
@Table(name="table3")
class Table2 {
@Id
long table2id;
//getter and Setter
}
@Entity
@Table(name="table3")
class Table3 {
@EmbeddedId
private table3PK table3PKId;
//getter and Setter
}
@Embeddable
Class table3PK{
@ManyToOne
@JoinColumn(name="table1Id" ,referencedColumnName="table1id")
Table1 table1;
@ManyToOne
@JoinColumn(name="table2Id" ,referencedColumnName="table2id")
Table2 table2;
public table3PK(){
}
public table3PK(Table1 table1 ,Table2 table2){
this.table1;
this.table2;
}
}
}
hibernate jpa spring-data-jpa
asked Nov 19 '18 at 13:09
Prabhat YadavPrabhat Yadav
1962417
add a comment |
I have Three table in which one table is using the foreign key of other two table to make the composite primary key. Now i am using the @Embeddable but as both the key are the foreign key, How i will create the composite primary key now in the Entity.
CREATE TABLE table1
(table1id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY (table1id));
table2
CREATE TABLE table2
(table2id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY (table2id));
table3
CREATE TABLE table3 (
table1id INT NOT NULL,
table2id INT NOT NULL,
PRIMARY KEY (table1id, table2id),
FOREIGN KEY (table1id) REFERENCES table1 (table1id),
FOREIGN KEY (table2id) REFERENCES table2 (table2id)
);
How to convert this table into an Hibenate Entity.
@Entity
@Table(name="table3")
class Table1 {
@Id
long table1id;
//getter and setter
}
@Entity
@Table(name="table3")
class Table2 {
@Id
long table2id;
//getter and Setter
}
@Entity
@Table(name="table3")
class Table3 {
@EmbeddedId
private table3PK table3PKId;
//getter and Setter
}
@Embeddable
Class table3PK{
@ManyToOne
@JoinColumn(name="table1Id" ,referencedColumnName="table1id")
Table1 table1;
@ManyToOne
@JoinColumn(name="table2Id" ,referencedColumnName="table2id")
Table2 table2;
public table3PK(){
}
public table3PK(Table1 table1 ,Table2 table2){
this.table1;
this.table2;
}
}
}
hibernate jpa spring-data-jpa
asked Nov 19 '18 at 13:09
Prabhat YadavPrabhat Yadav
1962417
I have Three table in which one table is using the foreign key of other two table to make the composite primary key. Now i am using the @Embeddable but as both the key are the foreign key, How i will create the composite primary key now in the Entity.
CREATE TABLE table1
(table1id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY (table1id));
table2
CREATE TABLE table2
(table2id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY (table2id));
table3
CREATE TABLE table3 (
table1id INT NOT NULL,
table2id INT NOT NULL,
PRIMARY KEY (table1id, table2id),
FOREIGN KEY (table1id) REFERENCES table1 (table1id),
FOREIGN KEY (table2id) REFERENCES table2 (table2id)
);
How to convert this table into an Hibenate Entity.
@Entity
@Table(name="table3")
class Table1 {
@Id
long table1id;
//getter and setter
}
@Entity
@Table(name="table3")
class Table2 {
@Id
long table2id;
//getter and Setter
}
@Entity
@Table(name="table3")
class Table3 {
@EmbeddedId
private table3PK table3PKId;
//getter and Setter
}
@Embeddable
Class table3PK{
@ManyToOne
@JoinColumn(name="table1Id" ,referencedColumnName="table1id")
Table1 table1;
@ManyToOne
@JoinColumn(name="table2Id" ,referencedColumnName="table2id")
Table2 table2;
public table3PK(){
}
public table3PK(Table1 table1 ,Table2 table2){
this.table1;
this.table2;
}
}
}
hibernate jpa spring-data-jpa
hibernate jpa spring-data-jpa
asked Nov 19 '18 at 13:09
Prabhat YadavPrabhat Yadav
1962417
asked Nov 19 '18 at 13:09
Prabhat YadavPrabhat Yadav
1962417
asked Nov 19 '18 at 13:09
Prabhat YadavPrabhat Yadav
1962417
asked Nov 19 '18 at 13:09
Prabhat YadavPrabhat Yadav
1962417
asked Nov 19 '18 at 13:09
Prabhat YadavPrabhat Yadav
1962417
1962417
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
It's not clear what problem you are encountering; but you might try using "derived identities" and mapping your entities like this:
@Entity
public class Table1 {
@Id
long table1id;
// ...
}
@Entity
public class Table2 {
@Id
long table2id;
// ...
}
@Embeddable
public class Table3PK {
long table1PK; // corresponds to PK type of Table1
long table2PK; // corresponds to PK type of Table2
}
@Entity
public class Table3 {
@EmbeddedId
private Table3PK id;
@MapsId("table1PK") // maps table1PK attribute of embedded id
@ManyToOne
Table1 table1;
@MapsId("table2PK") // maps table2PK attribute of embedded id
@ManyToOne
Table2 table2;
// ...
}
Derived identities are discussed (with examples) in the JPA 2.2 spec in section 2.4.1.
answered Nov 21 '18 at 3:31
Brian VosburghBrian Vosburgh
2,0131912
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
It's not clear what problem you are encountering; but you might try using "derived identities" and mapping your entities like this:
@Entity
public class Table1 {
@Id
long table1id;
// ...
}
@Entity
public class Table2 {
@Id
long table2id;
// ...
}
@Embeddable
public class Table3PK {
long table1PK; // corresponds to PK type of Table1
long table2PK; // corresponds to PK type of Table2
}
@Entity
public class Table3 {
@EmbeddedId
private Table3PK id;
@MapsId("table1PK") // maps table1PK attribute of embedded id
@ManyToOne
Table1 table1;
@MapsId("table2PK") // maps table2PK attribute of embedded id
@ManyToOne
Table2 table2;
// ...
}
Derived identities are discussed (with examples) in the JPA 2.2 spec in section 2.4.1.
answered Nov 21 '18 at 3:31
Brian VosburghBrian Vosburgh
2,0131912
add a comment |
It's not clear what problem you are encountering; but you might try using "derived identities" and mapping your entities like this:
@Entity
public class Table1 {
@Id
long table1id;
// ...
}
@Entity
public class Table2 {
@Id
long table2id;
// ...
}
@Embeddable
public class Table3PK {
long table1PK; // corresponds to PK type of Table1
long table2PK; // corresponds to PK type of Table2
}
@Entity
public class Table3 {
@EmbeddedId
private Table3PK id;
@MapsId("table1PK") // maps table1PK attribute of embedded id
@ManyToOne
Table1 table1;
@MapsId("table2PK") // maps table2PK attribute of embedded id
@ManyToOne
Table2 table2;
// ...
}
Derived identities are discussed (with examples) in the JPA 2.2 spec in section 2.4.1.
answered Nov 21 '18 at 3:31
Brian VosburghBrian Vosburgh
2,0131912
add a comment |
It's not clear what problem you are encountering; but you might try using "derived identities" and mapping your entities like this:
@Entity
public class Table1 {
@Id
long table1id;
// ...
}
@Entity
public class Table2 {
@Id
long table2id;
// ...
}
@Embeddable
public class Table3PK {
long table1PK; // corresponds to PK type of Table1
long table2PK; // corresponds to PK type of Table2
}
@Entity
public class Table3 {
@EmbeddedId
private Table3PK id;
@MapsId("table1PK") // maps table1PK attribute of embedded id
@ManyToOne
Table1 table1;
@MapsId("table2PK") // maps table2PK attribute of embedded id
@ManyToOne
Table2 table2;
// ...
}
Derived identities are discussed (with examples) in the JPA 2.2 spec in section 2.4.1.
answered Nov 21 '18 at 3:31
Brian VosburghBrian Vosburgh
2,0131912
It's not clear what problem you are encountering; but you might try using "derived identities" and mapping your entities like this:
@Entity
public class Table1 {
@Id
long table1id;
// ...
}
@Entity
public class Table2 {
@Id
long table2id;
// ...
}
@Embeddable
public class Table3PK {
long table1PK; // corresponds to PK type of Table1
long table2PK; // corresponds to PK type of Table2
}
@Entity
public class Table3 {
@EmbeddedId
private Table3PK id;
@MapsId("table1PK") // maps table1PK attribute of embedded id
@ManyToOne
Table1 table1;
@MapsId("table2PK") // maps table2PK attribute of embedded id
@ManyToOne
Table2 table2;
// ...
}
Derived identities are discussed (with examples) in the JPA 2.2 spec in section 2.4.1.
answered Nov 21 '18 at 3:31
Brian VosburghBrian Vosburgh
2,0131912
answered Nov 21 '18 at 3:31
Brian VosburghBrian Vosburgh
2,0131912
answered Nov 21 '18 at 3:31
Brian VosburghBrian Vosburgh
2,0131912
answered Nov 21 '18 at 3:31
Brian VosburghBrian Vosburgh
2,0131912
2,0131912
add a comment |
add a comment |
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