Regular expression with iterator
I am trying to scrape prices from online commerce store. I am iterating through the products on page and included it in the regular expression. Despite escaping the curly brackets, the regular expression does not work. (findall returns an empty list)
HTML code returned by soup.findall:
[<div class="ps4-price at-min-price-1"> from 29 GBP </div>]
[<div class="ps4-price at-min-price-2"> from 35 GBP </div>]
Python coode:
for product in range(21):
min_prices_text = str(soup.findAll("div", class_="ps4-price at-
min- price-{}".format(product)))
min_price = re.findall('<div class="ps4-price at-min-price-
{{}}"> (.+?)<'.format(product), str(min_prices_text))
regex python-3.x
add a comment |
I am trying to scrape prices from online commerce store. I am iterating through the products on page and included it in the regular expression. Despite escaping the curly brackets, the regular expression does not work. (findall returns an empty list)
HTML code returned by soup.findall:
[<div class="ps4-price at-min-price-1"> from 29 GBP </div>]
[<div class="ps4-price at-min-price-2"> from 35 GBP </div>]
Python coode:
for product in range(21):
min_prices_text = str(soup.findAll("div", class_="ps4-price at-
min- price-{}".format(product)))
min_price = re.findall('<div class="ps4-price at-min-price-
{{}}"> (.+?)<'.format(product), str(min_prices_text))
regex python-3.x
Trymin_prices = soup.find_all("div", class_="ps4-price")
and thenarr =
,for el in min_prices:
,arr.append(re.sub(r'D+', '', el.string))
=>print(list(map(int, arr)))
. If you need to make sure there are both classes listed, trymin_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
Nov 19 '18 at 10:47
1
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
Nov 19 '18 at 10:47
BTW, your formatted string is broken,{{}}
is actually a couple of literal braces. You need to use single ones,{}
, there.
– Wiktor Stribiżew
Nov 19 '18 at 11:05
add a comment |
I am trying to scrape prices from online commerce store. I am iterating through the products on page and included it in the regular expression. Despite escaping the curly brackets, the regular expression does not work. (findall returns an empty list)
HTML code returned by soup.findall:
[<div class="ps4-price at-min-price-1"> from 29 GBP </div>]
[<div class="ps4-price at-min-price-2"> from 35 GBP </div>]
Python coode:
for product in range(21):
min_prices_text = str(soup.findAll("div", class_="ps4-price at-
min- price-{}".format(product)))
min_price = re.findall('<div class="ps4-price at-min-price-
{{}}"> (.+?)<'.format(product), str(min_prices_text))
regex python-3.x
I am trying to scrape prices from online commerce store. I am iterating through the products on page and included it in the regular expression. Despite escaping the curly brackets, the regular expression does not work. (findall returns an empty list)
HTML code returned by soup.findall:
[<div class="ps4-price at-min-price-1"> from 29 GBP </div>]
[<div class="ps4-price at-min-price-2"> from 35 GBP </div>]
Python coode:
for product in range(21):
min_prices_text = str(soup.findAll("div", class_="ps4-price at-
min- price-{}".format(product)))
min_price = re.findall('<div class="ps4-price at-min-price-
{{}}"> (.+?)<'.format(product), str(min_prices_text))
regex python-3.x
regex python-3.x
asked Nov 19 '18 at 10:41
dzakobdzakob
11
11
Trymin_prices = soup.find_all("div", class_="ps4-price")
and thenarr =
,for el in min_prices:
,arr.append(re.sub(r'D+', '', el.string))
=>print(list(map(int, arr)))
. If you need to make sure there are both classes listed, trymin_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
Nov 19 '18 at 10:47
1
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
Nov 19 '18 at 10:47
BTW, your formatted string is broken,{{}}
is actually a couple of literal braces. You need to use single ones,{}
, there.
– Wiktor Stribiżew
Nov 19 '18 at 11:05
add a comment |
Trymin_prices = soup.find_all("div", class_="ps4-price")
and thenarr =
,for el in min_prices:
,arr.append(re.sub(r'D+', '', el.string))
=>print(list(map(int, arr)))
. If you need to make sure there are both classes listed, trymin_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
Nov 19 '18 at 10:47
1
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
Nov 19 '18 at 10:47
BTW, your formatted string is broken,{{}}
is actually a couple of literal braces. You need to use single ones,{}
, there.
– Wiktor Stribiżew
Nov 19 '18 at 11:05
Try
min_prices = soup.find_all("div", class_="ps4-price")
and then arr =
, for el in min_prices:
, arr.append(re.sub(r'D+', '', el.string))
=> print(list(map(int, arr)))
. If you need to make sure there are both classes listed, try min_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
Nov 19 '18 at 10:47
Try
min_prices = soup.find_all("div", class_="ps4-price")
and then arr =
, for el in min_prices:
, arr.append(re.sub(r'D+', '', el.string))
=> print(list(map(int, arr)))
. If you need to make sure there are both classes listed, try min_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
Nov 19 '18 at 10:47
1
1
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
Nov 19 '18 at 10:47
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
Nov 19 '18 at 10:47
BTW, your formatted string is broken,
{{}}
is actually a couple of literal braces. You need to use single ones, {}
, there.– Wiktor Stribiżew
Nov 19 '18 at 11:05
BTW, your formatted string is broken,
{{}}
is actually a couple of literal braces. You need to use single ones, {}
, there.– Wiktor Stribiżew
Nov 19 '18 at 11:05
add a comment |
1 Answer
1
active
oldest
votes
You may access the .string
property of the elements you get with findAll
, and only apply the regex to the plain text. E.g., since you expect only single integer numbers there, you may apply re.sub(r'D+', '', min_prices_text.string)
on those strings.
See example code:
results =
for product in range(21):
min_prices_text = soup.find("div", class_="ps4-price at-min-price-{}".format(product))
if min_prices_text:
results.append(re.sub(r'D+', '', min_prices_text.string))
print(results) # => ['29', '35']
Or use list(map(int, results))
if you want to cast the list of strings to integer.
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You may access the .string
property of the elements you get with findAll
, and only apply the regex to the plain text. E.g., since you expect only single integer numbers there, you may apply re.sub(r'D+', '', min_prices_text.string)
on those strings.
See example code:
results =
for product in range(21):
min_prices_text = soup.find("div", class_="ps4-price at-min-price-{}".format(product))
if min_prices_text:
results.append(re.sub(r'D+', '', min_prices_text.string))
print(results) # => ['29', '35']
Or use list(map(int, results))
if you want to cast the list of strings to integer.
add a comment |
You may access the .string
property of the elements you get with findAll
, and only apply the regex to the plain text. E.g., since you expect only single integer numbers there, you may apply re.sub(r'D+', '', min_prices_text.string)
on those strings.
See example code:
results =
for product in range(21):
min_prices_text = soup.find("div", class_="ps4-price at-min-price-{}".format(product))
if min_prices_text:
results.append(re.sub(r'D+', '', min_prices_text.string))
print(results) # => ['29', '35']
Or use list(map(int, results))
if you want to cast the list of strings to integer.
add a comment |
You may access the .string
property of the elements you get with findAll
, and only apply the regex to the plain text. E.g., since you expect only single integer numbers there, you may apply re.sub(r'D+', '', min_prices_text.string)
on those strings.
See example code:
results =
for product in range(21):
min_prices_text = soup.find("div", class_="ps4-price at-min-price-{}".format(product))
if min_prices_text:
results.append(re.sub(r'D+', '', min_prices_text.string))
print(results) # => ['29', '35']
Or use list(map(int, results))
if you want to cast the list of strings to integer.
You may access the .string
property of the elements you get with findAll
, and only apply the regex to the plain text. E.g., since you expect only single integer numbers there, you may apply re.sub(r'D+', '', min_prices_text.string)
on those strings.
See example code:
results =
for product in range(21):
min_prices_text = soup.find("div", class_="ps4-price at-min-price-{}".format(product))
if min_prices_text:
results.append(re.sub(r'D+', '', min_prices_text.string))
print(results) # => ['29', '35']
Or use list(map(int, results))
if you want to cast the list of strings to integer.
answered Nov 19 '18 at 11:13
Wiktor StribiżewWiktor Stribiżew
311k16131207
311k16131207
add a comment |
add a comment |
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Try
min_prices = soup.find_all("div", class_="ps4-price")
and thenarr =
,for el in min_prices:
,arr.append(re.sub(r'D+', '', el.string))
=>print(list(map(int, arr)))
. If you need to make sure there are both classes listed, trymin_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
Nov 19 '18 at 10:47
1
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
Nov 19 '18 at 10:47
BTW, your formatted string is broken,
{{}}
is actually a couple of literal braces. You need to use single ones,{}
, there.– Wiktor Stribiżew
Nov 19 '18 at 11:05