Rearrangement of lists of strings
5
$begingroup$
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
edited Nov 25 '18 at 9:27
kglr
179k9198410
asked Nov 25 '18 at 2:43
Suite401Suite401
981312
$endgroup$
add a comment |
5
$begingroup$
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
edited Nov 25 '18 at 9:27
kglr
179k9198410
asked Nov 25 '18 at 2:43
Suite401Suite401
981312
$endgroup$
add a comment |
5
5
5
$begingroup$
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
edited Nov 25 '18 at 9:27
kglr
179k9198410
asked Nov 25 '18 at 2:43
Suite401Suite401
981312
$endgroup$
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
string-manipulation
edited Nov 25 '18 at 9:27
kglr
179k9198410
asked Nov 25 '18 at 2:43
Suite401Suite401
981312
edited Nov 25 '18 at 9:27
kglr
179k9198410
asked Nov 25 '18 at 2:43
Suite401Suite401
981312
edited Nov 25 '18 at 9:27
kglr
179k9198410
edited Nov 25 '18 at 9:27
kglr
179k9198410
edited Nov 25 '18 at 9:27
kglr
179k9198410
179k9198410
asked Nov 25 '18 at 2:43
Suite401Suite401
981312
asked Nov 25 '18 at 2:43
Suite401Suite401
981312
asked Nov 25 '18 at 2:43
Suite401Suite401
981312
981312
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
14
$begingroup$
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 '18 at 2:56
kglrkglr
179k9198410
$endgroup$
add a comment |
6
$begingroup$
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 '18 at 2:52
Bob HanlonBob Hanlon
59.2k33595
$endgroup$
add a comment |
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2 Answers
2
active
oldest
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2 Answers
2
active
oldest
votes
active
oldest
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active
oldest
votes
14
$begingroup$
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 '18 at 2:56
kglrkglr
179k9198410
$endgroup$
add a comment |
14
$begingroup$
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 '18 at 2:56
kglrkglr
179k9198410
$endgroup$
add a comment |
14
14
14
$begingroup$
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 '18 at 2:56
kglrkglr
179k9198410
$endgroup$
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 '18 at 2:56
kglrkglr
179k9198410
answered Nov 25 '18 at 2:56
kglrkglr
179k9198410
answered Nov 25 '18 at 2:56
kglrkglr
179k9198410
answered Nov 25 '18 at 2:56
kglrkglr
179k9198410
179k9198410
add a comment |
add a comment |
6
$begingroup$
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 '18 at 2:52
Bob HanlonBob Hanlon
59.2k33595
$endgroup$
add a comment |
6
$begingroup$
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 '18 at 2:52
Bob HanlonBob Hanlon
59.2k33595
$endgroup$
add a comment |
6
6
6
$begingroup$
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 '18 at 2:52
Bob HanlonBob Hanlon
59.2k33595
$endgroup$
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 '18 at 2:52
Bob HanlonBob Hanlon
59.2k33595
answered Nov 25 '18 at 2:52
Bob HanlonBob Hanlon
59.2k33595
answered Nov 25 '18 at 2:52
Bob HanlonBob Hanlon
59.2k33595
answered Nov 25 '18 at 2:52
Bob HanlonBob Hanlon
59.2k33595
59.2k33595
add a comment |
add a comment |
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