Predicate logic, substitution when using resolutionmethod
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Formulae F = p(x) ∧ (q(y) ∨ r(z))
substitution = {x := a, y := f(z), z := g(b)}
This example is from a course am having right now. I dont know what I am missing
but can someone explain why y and z are substituted by a function (f(z), g(b)) while x is substituted with a constant (a)?
I cant find the reason in the book, on the recorded lecture or on the classforums, so I guess its really obvious.
Really greatfull for input
/Jonatan
substitution
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up vote
0
down vote
favorite
Formulae F = p(x) ∧ (q(y) ∨ r(z))
substitution = {x := a, y := f(z), z := g(b)}
This example is from a course am having right now. I dont know what I am missing
but can someone explain why y and z are substituted by a function (f(z), g(b)) while x is substituted with a constant (a)?
I cant find the reason in the book, on the recorded lecture or on the classforums, so I guess its really obvious.
Really greatfull for input
/Jonatan
substitution
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Formulae F = p(x) ∧ (q(y) ∨ r(z))
substitution = {x := a, y := f(z), z := g(b)}
This example is from a course am having right now. I dont know what I am missing
but can someone explain why y and z are substituted by a function (f(z), g(b)) while x is substituted with a constant (a)?
I cant find the reason in the book, on the recorded lecture or on the classforums, so I guess its really obvious.
Really greatfull for input
/Jonatan
substitution
Formulae F = p(x) ∧ (q(y) ∨ r(z))
substitution = {x := a, y := f(z), z := g(b)}
This example is from a course am having right now. I dont know what I am missing
but can someone explain why y and z are substituted by a function (f(z), g(b)) while x is substituted with a constant (a)?
I cant find the reason in the book, on the recorded lecture or on the classforums, so I guess its really obvious.
Really greatfull for input
/Jonatan
substitution
substitution
asked Nov 19 at 13:13
Jonatan Helenason
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