draw graph showing the distribution of energy
2
Could you help me to draw the last option using in/out draw? Other way is ok.
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](0,0) to[out=10, in=199] (1.25,2);
draw[red, thick](1.25,2) to[out=-5, in=170] (3.75,0.5);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](1.5,0) to[out=50, in=119] (2,2.5);
draw[red, thick](2,2.5) to[out=-70, in=111] (2.5,0);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.2,2.2) to[out=-70, in=179] (3.6,.55);
end{tikzpicture}
begin{tikzpicture}[scale=.71 ]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.3,.0) to[out=70, in=179] (1.2,1.7);
end{tikzpicture}
end{document}
tikz-pgf
edited Jan 4 at 4:01
marmot
90.7k4104195
asked Jan 4 at 3:55
ThumboltThumbolt
1,396819
add a comment |
2
Could you help me to draw the last option using in/out draw? Other way is ok.
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](0,0) to[out=10, in=199] (1.25,2);
draw[red, thick](1.25,2) to[out=-5, in=170] (3.75,0.5);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](1.5,0) to[out=50, in=119] (2,2.5);
draw[red, thick](2,2.5) to[out=-70, in=111] (2.5,0);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.2,2.2) to[out=-70, in=179] (3.6,.55);
end{tikzpicture}
begin{tikzpicture}[scale=.71 ]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.3,.0) to[out=70, in=179] (1.2,1.7);
end{tikzpicture}
end{document}
tikz-pgf
edited Jan 4 at 4:01
marmot
90.7k4104195
asked Jan 4 at 3:55
ThumboltThumbolt
1,396819
add a comment |
2
2
2
Could you help me to draw the last option using in/out draw? Other way is ok.
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](0,0) to[out=10, in=199] (1.25,2);
draw[red, thick](1.25,2) to[out=-5, in=170] (3.75,0.5);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](1.5,0) to[out=50, in=119] (2,2.5);
draw[red, thick](2,2.5) to[out=-70, in=111] (2.5,0);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.2,2.2) to[out=-70, in=179] (3.6,.55);
end{tikzpicture}
begin{tikzpicture}[scale=.71 ]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.3,.0) to[out=70, in=179] (1.2,1.7);
end{tikzpicture}
end{document}
tikz-pgf
edited Jan 4 at 4:01
marmot
90.7k4104195
asked Jan 4 at 3:55
ThumboltThumbolt
1,396819
Could you help me to draw the last option using in/out draw? Other way is ok.
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](0,0) to[out=10, in=199] (1.25,2);
draw[red, thick](1.25,2) to[out=-5, in=170] (3.75,0.5);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](1.5,0) to[out=50, in=119] (2,2.5);
draw[red, thick](2,2.5) to[out=-70, in=111] (2.5,0);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.2,2.2) to[out=-70, in=179] (3.6,.55);
end{tikzpicture}
begin{tikzpicture}[scale=.71 ]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.3,.0) to[out=70, in=179] (1.2,1.7);
end{tikzpicture}
end{document}
tikz-pgf
tikz-pgf
edited Jan 4 at 4:01
marmot
90.7k4104195
asked Jan 4 at 3:55
ThumboltThumbolt
1,396819
edited Jan 4 at 4:01
marmot
90.7k4104195
asked Jan 4 at 3:55
ThumboltThumbolt
1,396819
edited Jan 4 at 4:01
marmot
90.7k4104195
edited Jan 4 at 4:01
marmot
90.7k4104195
edited Jan 4 at 4:01
marmot
90.7k4104195
90.7k4104195
asked Jan 4 at 3:55
ThumboltThumbolt
1,396819
asked Jan 4 at 3:55
ThumboltThumbolt
1,396819
asked Jan 4 at 3:55
ThumboltThumbolt
1,396819
1,396819
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
2
I would like to argue that the simplest way is to define some standard functions and plot a linear combination of them.
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](0,0) to[out=10, in=199] (1.25,2);
draw[red, thick](1.25,2) to[out=-5, in=170] (3.75,0.5);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](1.5,0) to[out=50, in=119] (2,2.5);
draw[red, thick](2,2.5) to[out=-70, in=111] (2.5,0);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.2,2.2) to[out=-70, in=179] (3.6,.55);
end{tikzpicture}
begin{tikzpicture}[scale=.71,declare function={
fcont(x)=x*x*exp(-2*x);
fpeak(x,y,z)=exp(-(x-y)*(x-y)/(z*z));}]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:3.5,samples=81]
({x+0.5},{10*fcont(x)+1.3*fpeak(x,1.3,0.05)+0.9*fpeak(x,1,0.05)});
end{tikzpicture}
end{document}
I could not resist to draw the other curves using the same strategy, and also arranging the plots in a 2x2 scheme.
documentclass{article}
usepackage{subcaption}
usepackage{tikz}
tikzset{declare function={
fcont(x,b)=x*x*exp(-2*b*x);
fpeak(x,y,z)=exp(-(x-y)*(x-y)/(z*z));}}
begin{document}
begin{figure}
centering
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:4,samples=81]
({x},{8*fcont(x,0.8)});
end{tikzpicture}
caption{I look like a Planck distribution.}label{fig:Planck}
end{subfigure}
quad
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=1.6:2.4,samples=81]
({x},{2.5*(fpeak(x,2,0.2)-fpeak(1.6,2,0.2))});
end{tikzpicture}
caption{I look like a Gaussian peak.}label{fig:Gauss}
end{subfigure}\
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:4,samples=81]
({x},{2*exp(-x)});
end{tikzpicture}
caption{I look like a an exponentially decaying function.}label{fig:Exp}
end{subfigure}
quad
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:3.5,samples=81]
({x+0.5},{10*fcont(x,1)+1.3*fpeak(x,1.3,0.05)+0.9*fpeak(x,1,0.05)});
end{tikzpicture}
caption{I look like a Planck distribution plus two Gaussian
peaks.}label{fig:Spectrum}
end{subfigure}
caption{Cartoons of a few distributions that often occur in science.}
end{figure}
end{document}
I had to adjust the prefactors by trial and error. This is not necessary if you switch to pgfplots, where you can use group plots to arrange the plots in a 2x2 scheme, too.
answered Jan 4 at 4:10
marmotmarmot
90.7k4104195
1
The graphs look much better. Thank you for the improvement.
– Thumbolt
Jan 4 at 5:42
add a comment |
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1 Answer
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active
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votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
I would like to argue that the simplest way is to define some standard functions and plot a linear combination of them.
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](0,0) to[out=10, in=199] (1.25,2);
draw[red, thick](1.25,2) to[out=-5, in=170] (3.75,0.5);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](1.5,0) to[out=50, in=119] (2,2.5);
draw[red, thick](2,2.5) to[out=-70, in=111] (2.5,0);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.2,2.2) to[out=-70, in=179] (3.6,.55);
end{tikzpicture}
begin{tikzpicture}[scale=.71,declare function={
fcont(x)=x*x*exp(-2*x);
fpeak(x,y,z)=exp(-(x-y)*(x-y)/(z*z));}]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:3.5,samples=81]
({x+0.5},{10*fcont(x)+1.3*fpeak(x,1.3,0.05)+0.9*fpeak(x,1,0.05)});
end{tikzpicture}
end{document}
I could not resist to draw the other curves using the same strategy, and also arranging the plots in a 2x2 scheme.
documentclass{article}
usepackage{subcaption}
usepackage{tikz}
tikzset{declare function={
fcont(x,b)=x*x*exp(-2*b*x);
fpeak(x,y,z)=exp(-(x-y)*(x-y)/(z*z));}}
begin{document}
begin{figure}
centering
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:4,samples=81]
({x},{8*fcont(x,0.8)});
end{tikzpicture}
caption{I look like a Planck distribution.}label{fig:Planck}
end{subfigure}
quad
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=1.6:2.4,samples=81]
({x},{2.5*(fpeak(x,2,0.2)-fpeak(1.6,2,0.2))});
end{tikzpicture}
caption{I look like a Gaussian peak.}label{fig:Gauss}
end{subfigure}\
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:4,samples=81]
({x},{2*exp(-x)});
end{tikzpicture}
caption{I look like a an exponentially decaying function.}label{fig:Exp}
end{subfigure}
quad
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:3.5,samples=81]
({x+0.5},{10*fcont(x,1)+1.3*fpeak(x,1.3,0.05)+0.9*fpeak(x,1,0.05)});
end{tikzpicture}
caption{I look like a Planck distribution plus two Gaussian
peaks.}label{fig:Spectrum}
end{subfigure}
caption{Cartoons of a few distributions that often occur in science.}
end{figure}
end{document}
I had to adjust the prefactors by trial and error. This is not necessary if you switch to pgfplots, where you can use group plots to arrange the plots in a 2x2 scheme, too.
answered Jan 4 at 4:10
marmotmarmot
90.7k4104195
1
The graphs look much better. Thank you for the improvement.
– Thumbolt
Jan 4 at 5:42
add a comment |
2
I would like to argue that the simplest way is to define some standard functions and plot a linear combination of them.
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](0,0) to[out=10, in=199] (1.25,2);
draw[red, thick](1.25,2) to[out=-5, in=170] (3.75,0.5);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](1.5,0) to[out=50, in=119] (2,2.5);
draw[red, thick](2,2.5) to[out=-70, in=111] (2.5,0);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.2,2.2) to[out=-70, in=179] (3.6,.55);
end{tikzpicture}
begin{tikzpicture}[scale=.71,declare function={
fcont(x)=x*x*exp(-2*x);
fpeak(x,y,z)=exp(-(x-y)*(x-y)/(z*z));}]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:3.5,samples=81]
({x+0.5},{10*fcont(x)+1.3*fpeak(x,1.3,0.05)+0.9*fpeak(x,1,0.05)});
end{tikzpicture}
end{document}
I could not resist to draw the other curves using the same strategy, and also arranging the plots in a 2x2 scheme.
documentclass{article}
usepackage{subcaption}
usepackage{tikz}
tikzset{declare function={
fcont(x,b)=x*x*exp(-2*b*x);
fpeak(x,y,z)=exp(-(x-y)*(x-y)/(z*z));}}
begin{document}
begin{figure}
centering
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:4,samples=81]
({x},{8*fcont(x,0.8)});
end{tikzpicture}
caption{I look like a Planck distribution.}label{fig:Planck}
end{subfigure}
quad
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=1.6:2.4,samples=81]
({x},{2.5*(fpeak(x,2,0.2)-fpeak(1.6,2,0.2))});
end{tikzpicture}
caption{I look like a Gaussian peak.}label{fig:Gauss}
end{subfigure}\
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:4,samples=81]
({x},{2*exp(-x)});
end{tikzpicture}
caption{I look like a an exponentially decaying function.}label{fig:Exp}
end{subfigure}
quad
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:3.5,samples=81]
({x+0.5},{10*fcont(x,1)+1.3*fpeak(x,1.3,0.05)+0.9*fpeak(x,1,0.05)});
end{tikzpicture}
caption{I look like a Planck distribution plus two Gaussian
peaks.}label{fig:Spectrum}
end{subfigure}
caption{Cartoons of a few distributions that often occur in science.}
end{figure}
end{document}
I had to adjust the prefactors by trial and error. This is not necessary if you switch to pgfplots, where you can use group plots to arrange the plots in a 2x2 scheme, too.
answered Jan 4 at 4:10
marmotmarmot
90.7k4104195
1
The graphs look much better. Thank you for the improvement.
– Thumbolt
Jan 4 at 5:42
add a comment |
2
2
2
I would like to argue that the simplest way is to define some standard functions and plot a linear combination of them.
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](0,0) to[out=10, in=199] (1.25,2);
draw[red, thick](1.25,2) to[out=-5, in=170] (3.75,0.5);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](1.5,0) to[out=50, in=119] (2,2.5);
draw[red, thick](2,2.5) to[out=-70, in=111] (2.5,0);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.2,2.2) to[out=-70, in=179] (3.6,.55);
end{tikzpicture}
begin{tikzpicture}[scale=.71,declare function={
fcont(x)=x*x*exp(-2*x);
fpeak(x,y,z)=exp(-(x-y)*(x-y)/(z*z));}]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:3.5,samples=81]
({x+0.5},{10*fcont(x)+1.3*fpeak(x,1.3,0.05)+0.9*fpeak(x,1,0.05)});
end{tikzpicture}
end{document}
I could not resist to draw the other curves using the same strategy, and also arranging the plots in a 2x2 scheme.
documentclass{article}
usepackage{subcaption}
usepackage{tikz}
tikzset{declare function={
fcont(x,b)=x*x*exp(-2*b*x);
fpeak(x,y,z)=exp(-(x-y)*(x-y)/(z*z));}}
begin{document}
begin{figure}
centering
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:4,samples=81]
({x},{8*fcont(x,0.8)});
end{tikzpicture}
caption{I look like a Planck distribution.}label{fig:Planck}
end{subfigure}
quad
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=1.6:2.4,samples=81]
({x},{2.5*(fpeak(x,2,0.2)-fpeak(1.6,2,0.2))});
end{tikzpicture}
caption{I look like a Gaussian peak.}label{fig:Gauss}
end{subfigure}\
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:4,samples=81]
({x},{2*exp(-x)});
end{tikzpicture}
caption{I look like a an exponentially decaying function.}label{fig:Exp}
end{subfigure}
quad
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:3.5,samples=81]
({x+0.5},{10*fcont(x,1)+1.3*fpeak(x,1.3,0.05)+0.9*fpeak(x,1,0.05)});
end{tikzpicture}
caption{I look like a Planck distribution plus two Gaussian
peaks.}label{fig:Spectrum}
end{subfigure}
caption{Cartoons of a few distributions that often occur in science.}
end{figure}
end{document}
I had to adjust the prefactors by trial and error. This is not necessary if you switch to pgfplots, where you can use group plots to arrange the plots in a 2x2 scheme, too.
answered Jan 4 at 4:10
marmotmarmot
90.7k4104195
I would like to argue that the simplest way is to define some standard functions and plot a linear combination of them.
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](0,0) to[out=10, in=199] (1.25,2);
draw[red, thick](1.25,2) to[out=-5, in=170] (3.75,0.5);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick](1.5,0) to[out=50, in=119] (2,2.5);
draw[red, thick](2,2.5) to[out=-70, in=111] (2.5,0);
end{tikzpicture}
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick](0.2,2.2) to[out=-70, in=179] (3.6,.55);
end{tikzpicture}
begin{tikzpicture}[scale=.71,declare function={
fcont(x)=x*x*exp(-2*x);
fpeak(x,y,z)=exp(-(x-y)*(x-y)/(z*z));}]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.414);
draw(4.15,0) node[right] {$E$};
draw(0,2.41) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:3.5,samples=81]
({x+0.5},{10*fcont(x)+1.3*fpeak(x,1.3,0.05)+0.9*fpeak(x,1,0.05)});
end{tikzpicture}
end{document}
I could not resist to draw the other curves using the same strategy, and also arranging the plots in a 2x2 scheme.
documentclass{article}
usepackage{subcaption}
usepackage{tikz}
tikzset{declare function={
fcont(x,b)=x*x*exp(-2*b*x);
fpeak(x,y,z)=exp(-(x-y)*(x-y)/(z*z));}}
begin{document}
begin{figure}
centering
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:4,samples=81]
({x},{8*fcont(x,0.8)});
end{tikzpicture}
caption{I look like a Planck distribution.}label{fig:Planck}
end{subfigure}
quad
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=1.6:2.4,samples=81]
({x},{2.5*(fpeak(x,2,0.2)-fpeak(1.6,2,0.2))});
end{tikzpicture}
caption{I look like a Gaussian peak.}label{fig:Gauss}
end{subfigure}\
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:4,samples=81]
({x},{2*exp(-x)});
end{tikzpicture}
caption{I look like a an exponentially decaying function.}label{fig:Exp}
end{subfigure}
quad
begin{subfigure}{0.4textwidth}
centering
begin{tikzpicture}[scale=.71]
draw[->](0,0)--(4.05,0);
draw[->](0,-.3)--(0,2.14);
draw(4.15,0) node[right] {$E$};
draw(0,2.1) node[above] {$p(E)$};
draw[red, thick] plot[smooth,variable=x,domain=0:3.5,samples=81]
({x+0.5},{10*fcont(x,1)+1.3*fpeak(x,1.3,0.05)+0.9*fpeak(x,1,0.05)});
end{tikzpicture}
caption{I look like a Planck distribution plus two Gaussian
peaks.}label{fig:Spectrum}
end{subfigure}
caption{Cartoons of a few distributions that often occur in science.}
end{figure}
end{document}
I had to adjust the prefactors by trial and error. This is not necessary if you switch to pgfplots, where you can use group plots to arrange the plots in a 2x2 scheme, too.
answered Jan 4 at 4:10
marmotmarmot
90.7k4104195
edited Jan 4 at 4:30
answered Jan 4 at 4:10
marmotmarmot
90.7k4104195
answered Jan 4 at 4:10
marmotmarmot
90.7k4104195
answered Jan 4 at 4:10
marmotmarmot
90.7k4104195
90.7k4104195
1
The graphs look much better. Thank you for the improvement.
– Thumbolt
Jan 4 at 5:42
add a comment |
1
The graphs look much better. Thank you for the improvement.
– Thumbolt
Jan 4 at 5:42
1
1
The graphs look much better. Thank you for the improvement.
– Thumbolt
Jan 4 at 5:42
The graphs look much better. Thank you for the improvement.
– Thumbolt
Jan 4 at 5:42
add a comment |
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