How to convert this curl request to Http post request for file upload in java?
Following is my curl request:
curl -X POST --data-urlencode 'data1@/Users/Documents/file.csv' http://localhost:8000/predict
Following is my equivalent Java implementation.
String filePath = inputFilePath;
String url = inputUrl;
File file = new File(filePath);
CloseableHttpClient httpClient = HttpClients.createDefault();
HttpPost uploadFile = new HttpPost(inputUrl);
uploadFile.addHeader("content-type", "application/x-www-form-urlencoded;charset=utf-8");
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
FileBody fileBody = new FileBody(new File(inputFilePath));
HttpEntity reqEntity = MultipartEntityBuilder.create()
.addPart("data1", fileBody)
.build();
uploadFile.setEntity(reqEntity);
CloseableHttpResponse response = null;
try {
response = httpClient.execute(uploadFile);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
I am trying to invoke my R Rest API endpoint from my Java HTTP post.
#* @post /predict
mypredict <- function(data1) {
print(data1)
}
(1) Is my equivalent Java HTTP Post request correct?
(2) I am able to invoke the R rest endpoint using my curl command. But for some reason when i sent the POST request through my Java code, i see that data1 is not being passed as part of post request. I see this error in R.
<simpleError in print(data1): argument "data1" is missing, with no default>
I feel my Java equivalent curl implementation is wrong. Can someone help?
java rest curl
edited Nov 19 '18 at 8:11
hrbrmstr
60.3k687148
asked Nov 19 '18 at 6:42
CloudCloud
2915
add a comment |
Following is my curl request:
curl -X POST --data-urlencode 'data1@/Users/Documents/file.csv' http://localhost:8000/predict
Following is my equivalent Java implementation.
String filePath = inputFilePath;
String url = inputUrl;
File file = new File(filePath);
CloseableHttpClient httpClient = HttpClients.createDefault();
HttpPost uploadFile = new HttpPost(inputUrl);
uploadFile.addHeader("content-type", "application/x-www-form-urlencoded;charset=utf-8");
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
FileBody fileBody = new FileBody(new File(inputFilePath));
HttpEntity reqEntity = MultipartEntityBuilder.create()
.addPart("data1", fileBody)
.build();
uploadFile.setEntity(reqEntity);
CloseableHttpResponse response = null;
try {
response = httpClient.execute(uploadFile);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
I am trying to invoke my R Rest API endpoint from my Java HTTP post.
#* @post /predict
mypredict <- function(data1) {
print(data1)
}
(1) Is my equivalent Java HTTP Post request correct?
(2) I am able to invoke the R rest endpoint using my curl command. But for some reason when i sent the POST request through my Java code, i see that data1 is not being passed as part of post request. I see this error in R.
<simpleError in print(data1): argument "data1" is missing, with no default>
I feel my Java equivalent curl implementation is wrong. Can someone help?
java rest curl
edited Nov 19 '18 at 8:11
hrbrmstr
60.3k687148
asked Nov 19 '18 at 6:42
CloudCloud
2915
add a comment |
Following is my curl request:
curl -X POST --data-urlencode 'data1@/Users/Documents/file.csv' http://localhost:8000/predict
Following is my equivalent Java implementation.
String filePath = inputFilePath;
String url = inputUrl;
File file = new File(filePath);
CloseableHttpClient httpClient = HttpClients.createDefault();
HttpPost uploadFile = new HttpPost(inputUrl);
uploadFile.addHeader("content-type", "application/x-www-form-urlencoded;charset=utf-8");
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
FileBody fileBody = new FileBody(new File(inputFilePath));
HttpEntity reqEntity = MultipartEntityBuilder.create()
.addPart("data1", fileBody)
.build();
uploadFile.setEntity(reqEntity);
CloseableHttpResponse response = null;
try {
response = httpClient.execute(uploadFile);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
I am trying to invoke my R Rest API endpoint from my Java HTTP post.
#* @post /predict
mypredict <- function(data1) {
print(data1)
}
(1) Is my equivalent Java HTTP Post request correct?
(2) I am able to invoke the R rest endpoint using my curl command. But for some reason when i sent the POST request through my Java code, i see that data1 is not being passed as part of post request. I see this error in R.
<simpleError in print(data1): argument "data1" is missing, with no default>
I feel my Java equivalent curl implementation is wrong. Can someone help?
java rest curl
edited Nov 19 '18 at 8:11
hrbrmstr
60.3k687148
asked Nov 19 '18 at 6:42
CloudCloud
2915
Following is my curl request:
curl -X POST --data-urlencode 'data1@/Users/Documents/file.csv' http://localhost:8000/predict
Following is my equivalent Java implementation.
String filePath = inputFilePath;
String url = inputUrl;
File file = new File(filePath);
CloseableHttpClient httpClient = HttpClients.createDefault();
HttpPost uploadFile = new HttpPost(inputUrl);
uploadFile.addHeader("content-type", "application/x-www-form-urlencoded;charset=utf-8");
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
FileBody fileBody = new FileBody(new File(inputFilePath));
HttpEntity reqEntity = MultipartEntityBuilder.create()
.addPart("data1", fileBody)
.build();
uploadFile.setEntity(reqEntity);
CloseableHttpResponse response = null;
try {
response = httpClient.execute(uploadFile);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
I am trying to invoke my R Rest API endpoint from my Java HTTP post.
#* @post /predict
mypredict <- function(data1) {
print(data1)
}
(1) Is my equivalent Java HTTP Post request correct?
(2) I am able to invoke the R rest endpoint using my curl command. But for some reason when i sent the POST request through my Java code, i see that data1 is not being passed as part of post request. I see this error in R.
<simpleError in print(data1): argument "data1" is missing, with no default>
I feel my Java equivalent curl implementation is wrong. Can someone help?
java rest curl
java rest curl
edited Nov 19 '18 at 8:11
hrbrmstr
60.3k687148
asked Nov 19 '18 at 6:42
CloudCloud
2915
edited Nov 19 '18 at 8:11
hrbrmstr
60.3k687148
asked Nov 19 '18 at 6:42
CloudCloud
2915
edited Nov 19 '18 at 8:11
hrbrmstr
60.3k687148
edited Nov 19 '18 at 8:11
hrbrmstr
60.3k687148
edited Nov 19 '18 at 8:11
hrbrmstr
60.3k687148
60.3k687148
asked Nov 19 '18 at 6:42
CloudCloud
2915
asked Nov 19 '18 at 6:42
CloudCloud
2915
asked Nov 19 '18 at 6:42
CloudCloud
2915
2915
add a comment |
add a comment |
1 Answer
1
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oldest
votes
You specify content-type application/x-www-form-urlencoded (as curl does for this case) but supply an actual body (entity) that corresponds to multipart/form-data which is radically different. Instead use URLEncodedFormEntity containing (for your case) one NameValuePair something like this:
byte contents = Files.readAllBytes (new File(filepath).toPath());
List<BasicNameValuePair> list = new ArrayList<BasicNameValuePair>();
list.add(new BasicNameValuePair("data1", new String(contents,charset));
uploadFile.setEntity(new UrlEncodedFormEntity (list));
And you don't need addHeader("content-type",...) because setting the entity automatically supplies the content-type header (and content-length).
answered Nov 19 '18 at 12:01
dave_thompson_085dave_thompson_085
13k11631
Thank you. It is working now.
– Cloud
Nov 19 '18 at 17:04
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You specify content-type application/x-www-form-urlencoded (as curl does for this case) but supply an actual body (entity) that corresponds to multipart/form-data which is radically different. Instead use URLEncodedFormEntity containing (for your case) one NameValuePair something like this:
byte contents = Files.readAllBytes (new File(filepath).toPath());
List<BasicNameValuePair> list = new ArrayList<BasicNameValuePair>();
list.add(new BasicNameValuePair("data1", new String(contents,charset));
uploadFile.setEntity(new UrlEncodedFormEntity (list));
And you don't need addHeader("content-type",...) because setting the entity automatically supplies the content-type header (and content-length).
answered Nov 19 '18 at 12:01
dave_thompson_085dave_thompson_085
13k11631
Thank you. It is working now.
– Cloud
Nov 19 '18 at 17:04
add a comment |
You specify content-type application/x-www-form-urlencoded (as curl does for this case) but supply an actual body (entity) that corresponds to multipart/form-data which is radically different. Instead use URLEncodedFormEntity containing (for your case) one NameValuePair something like this:
byte contents = Files.readAllBytes (new File(filepath).toPath());
List<BasicNameValuePair> list = new ArrayList<BasicNameValuePair>();
list.add(new BasicNameValuePair("data1", new String(contents,charset));
uploadFile.setEntity(new UrlEncodedFormEntity (list));
And you don't need addHeader("content-type",...) because setting the entity automatically supplies the content-type header (and content-length).
answered Nov 19 '18 at 12:01
dave_thompson_085dave_thompson_085
13k11631
Thank you. It is working now.
– Cloud
Nov 19 '18 at 17:04
add a comment |
You specify content-type application/x-www-form-urlencoded (as curl does for this case) but supply an actual body (entity) that corresponds to multipart/form-data which is radically different. Instead use URLEncodedFormEntity containing (for your case) one NameValuePair something like this:
byte contents = Files.readAllBytes (new File(filepath).toPath());
List<BasicNameValuePair> list = new ArrayList<BasicNameValuePair>();
list.add(new BasicNameValuePair("data1", new String(contents,charset));
uploadFile.setEntity(new UrlEncodedFormEntity (list));
And you don't need addHeader("content-type",...) because setting the entity automatically supplies the content-type header (and content-length).
answered Nov 19 '18 at 12:01
dave_thompson_085dave_thompson_085
13k11631
You specify content-type application/x-www-form-urlencoded (as curl does for this case) but supply an actual body (entity) that corresponds to multipart/form-data which is radically different. Instead use URLEncodedFormEntity containing (for your case) one NameValuePair something like this:
byte contents = Files.readAllBytes (new File(filepath).toPath());
List<BasicNameValuePair> list = new ArrayList<BasicNameValuePair>();
list.add(new BasicNameValuePair("data1", new String(contents,charset));
uploadFile.setEntity(new UrlEncodedFormEntity (list));
And you don't need addHeader("content-type",...) because setting the entity automatically supplies the content-type header (and content-length).
answered Nov 19 '18 at 12:01
dave_thompson_085dave_thompson_085
13k11631
answered Nov 19 '18 at 12:01
dave_thompson_085dave_thompson_085
13k11631
answered Nov 19 '18 at 12:01
dave_thompson_085dave_thompson_085
13k11631
answered Nov 19 '18 at 12:01
dave_thompson_085dave_thompson_085
13k11631
13k11631
Thank you. It is working now.
– Cloud
Nov 19 '18 at 17:04
add a comment |
Thank you. It is working now.
– Cloud
Nov 19 '18 at 17:04
Thank you. It is working now.
– Cloud
Nov 19 '18 at 17:04
Thank you. It is working now.
– Cloud
Nov 19 '18 at 17:04
add a comment |
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