Plotting a parameterized curve on a certain coordinate system












1















Trying to plot the 3D curve



(t,t^2,2*t^3), tin [0,1],


with the code:



begin{tikzpicture}
begin{axis}
%view={105}{5},
[samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]

addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);

end{axis}

end{tikzpicture}


I got the following output:



enter image description here



But I want to plot that curve in the regular coordinate system:



   begin{tikzpicture}

draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};

end{tikzpicture}


that is:



enter image description here



Which would be the code ?



Later Edit: By using view{95}{5}, the axes seem to be like in the second output, but not perfect:



begin{tikzpicture}
begin{axis}
[view={95}{5}, samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]

addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}


The output being:
enter image description here










share|improve this question




















  • 1





    Adjusting view= won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.

    – Jānis Lazovskis
    Dec 4 '17 at 20:27
















1















Trying to plot the 3D curve



(t,t^2,2*t^3), tin [0,1],


with the code:



begin{tikzpicture}
begin{axis}
%view={105}{5},
[samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]

addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);

end{axis}

end{tikzpicture}


I got the following output:



enter image description here



But I want to plot that curve in the regular coordinate system:



   begin{tikzpicture}

draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};

end{tikzpicture}


that is:



enter image description here



Which would be the code ?



Later Edit: By using view{95}{5}, the axes seem to be like in the second output, but not perfect:



begin{tikzpicture}
begin{axis}
[view={95}{5}, samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]

addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}


The output being:
enter image description here










share|improve this question




















  • 1





    Adjusting view= won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.

    – Jānis Lazovskis
    Dec 4 '17 at 20:27














1












1








1








Trying to plot the 3D curve



(t,t^2,2*t^3), tin [0,1],


with the code:



begin{tikzpicture}
begin{axis}
%view={105}{5},
[samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]

addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);

end{axis}

end{tikzpicture}


I got the following output:



enter image description here



But I want to plot that curve in the regular coordinate system:



   begin{tikzpicture}

draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};

end{tikzpicture}


that is:



enter image description here



Which would be the code ?



Later Edit: By using view{95}{5}, the axes seem to be like in the second output, but not perfect:



begin{tikzpicture}
begin{axis}
[view={95}{5}, samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]

addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}


The output being:
enter image description here










share|improve this question
















Trying to plot the 3D curve



(t,t^2,2*t^3), tin [0,1],


with the code:



begin{tikzpicture}
begin{axis}
%view={105}{5},
[samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]

addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);

end{axis}

end{tikzpicture}


I got the following output:



enter image description here



But I want to plot that curve in the regular coordinate system:



   begin{tikzpicture}

draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};

end{tikzpicture}


that is:



enter image description here



Which would be the code ?



Later Edit: By using view{95}{5}, the axes seem to be like in the second output, but not perfect:



begin{tikzpicture}
begin{axis}
[view={95}{5}, samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]

addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}


The output being:
enter image description here







tikz-pgf pgfplots






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 15 at 19:28









Stefan Pinnow

19.7k83275




19.7k83275










asked Dec 4 '17 at 19:06









CrisCris

473211




473211








  • 1





    Adjusting view= won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.

    – Jānis Lazovskis
    Dec 4 '17 at 20:27














  • 1





    Adjusting view= won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.

    – Jānis Lazovskis
    Dec 4 '17 at 20:27








1




1





Adjusting view= won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.

– Jānis Lazovskis
Dec 4 '17 at 20:27





Adjusting view= won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.

– Jānis Lazovskis
Dec 4 '17 at 20:27










1 Answer
1






active

oldest

votes


















1














This is not an answer but an attempt to understand the question better. In your desired coordinate system, you perform a cyclic permutation of the x-, y- and z-directions, right? If that's the case, why does a change of the view and relabeling of the axes by hand not work? A brute force solution, which is certainly not a final solution, is



documentclass[border2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}

draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
defn{80}
foreach i in {1,...,n} {
pgfmathsetmacro{u}{(i-1)/n}
pgfmathsetmacro{v}{((i-1)/n)^2}
pgfmathsetmacro{w}{2*((i-1)/n)^3}
pgfmathsetmacro{x}{(i/n)}
pgfmathsetmacro{y}{(i/n)^2}
pgfmathsetmacro{z}{2*(i/n)^3}
draw[-,blue,thick,smooth] (v,w,u) -- (y,z,x);
}
end{tikzpicture}
end{document}


enter image description here



I just posted this in order to find out whether this is the plot you want to get, and I understand that this is a hilariously complicated way of producing the plot.






share|improve this answer
























  • thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.

    – Cris
    Dec 5 '17 at 6:36











  • @Cris That's what I thought. I was just confused by the comment that view would not work. A

    – marmot
    Dec 5 '17 at 16:53











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














This is not an answer but an attempt to understand the question better. In your desired coordinate system, you perform a cyclic permutation of the x-, y- and z-directions, right? If that's the case, why does a change of the view and relabeling of the axes by hand not work? A brute force solution, which is certainly not a final solution, is



documentclass[border2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}

draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
defn{80}
foreach i in {1,...,n} {
pgfmathsetmacro{u}{(i-1)/n}
pgfmathsetmacro{v}{((i-1)/n)^2}
pgfmathsetmacro{w}{2*((i-1)/n)^3}
pgfmathsetmacro{x}{(i/n)}
pgfmathsetmacro{y}{(i/n)^2}
pgfmathsetmacro{z}{2*(i/n)^3}
draw[-,blue,thick,smooth] (v,w,u) -- (y,z,x);
}
end{tikzpicture}
end{document}


enter image description here



I just posted this in order to find out whether this is the plot you want to get, and I understand that this is a hilariously complicated way of producing the plot.






share|improve this answer
























  • thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.

    – Cris
    Dec 5 '17 at 6:36











  • @Cris That's what I thought. I was just confused by the comment that view would not work. A

    – marmot
    Dec 5 '17 at 16:53
















1














This is not an answer but an attempt to understand the question better. In your desired coordinate system, you perform a cyclic permutation of the x-, y- and z-directions, right? If that's the case, why does a change of the view and relabeling of the axes by hand not work? A brute force solution, which is certainly not a final solution, is



documentclass[border2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}

draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
defn{80}
foreach i in {1,...,n} {
pgfmathsetmacro{u}{(i-1)/n}
pgfmathsetmacro{v}{((i-1)/n)^2}
pgfmathsetmacro{w}{2*((i-1)/n)^3}
pgfmathsetmacro{x}{(i/n)}
pgfmathsetmacro{y}{(i/n)^2}
pgfmathsetmacro{z}{2*(i/n)^3}
draw[-,blue,thick,smooth] (v,w,u) -- (y,z,x);
}
end{tikzpicture}
end{document}


enter image description here



I just posted this in order to find out whether this is the plot you want to get, and I understand that this is a hilariously complicated way of producing the plot.






share|improve this answer
























  • thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.

    – Cris
    Dec 5 '17 at 6:36











  • @Cris That's what I thought. I was just confused by the comment that view would not work. A

    – marmot
    Dec 5 '17 at 16:53














1












1








1







This is not an answer but an attempt to understand the question better. In your desired coordinate system, you perform a cyclic permutation of the x-, y- and z-directions, right? If that's the case, why does a change of the view and relabeling of the axes by hand not work? A brute force solution, which is certainly not a final solution, is



documentclass[border2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}

draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
defn{80}
foreach i in {1,...,n} {
pgfmathsetmacro{u}{(i-1)/n}
pgfmathsetmacro{v}{((i-1)/n)^2}
pgfmathsetmacro{w}{2*((i-1)/n)^3}
pgfmathsetmacro{x}{(i/n)}
pgfmathsetmacro{y}{(i/n)^2}
pgfmathsetmacro{z}{2*(i/n)^3}
draw[-,blue,thick,smooth] (v,w,u) -- (y,z,x);
}
end{tikzpicture}
end{document}


enter image description here



I just posted this in order to find out whether this is the plot you want to get, and I understand that this is a hilariously complicated way of producing the plot.






share|improve this answer













This is not an answer but an attempt to understand the question better. In your desired coordinate system, you perform a cyclic permutation of the x-, y- and z-directions, right? If that's the case, why does a change of the view and relabeling of the axes by hand not work? A brute force solution, which is certainly not a final solution, is



documentclass[border2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}

draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
defn{80}
foreach i in {1,...,n} {
pgfmathsetmacro{u}{(i-1)/n}
pgfmathsetmacro{v}{((i-1)/n)^2}
pgfmathsetmacro{w}{2*((i-1)/n)^3}
pgfmathsetmacro{x}{(i/n)}
pgfmathsetmacro{y}{(i/n)^2}
pgfmathsetmacro{z}{2*(i/n)^3}
draw[-,blue,thick,smooth] (v,w,u) -- (y,z,x);
}
end{tikzpicture}
end{document}


enter image description here



I just posted this in order to find out whether this is the plot you want to get, and I understand that this is a hilariously complicated way of producing the plot.







share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 5 '17 at 1:32









marmotmarmot

93.8k4109208




93.8k4109208













  • thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.

    – Cris
    Dec 5 '17 at 6:36











  • @Cris That's what I thought. I was just confused by the comment that view would not work. A

    – marmot
    Dec 5 '17 at 16:53



















  • thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.

    – Cris
    Dec 5 '17 at 6:36











  • @Cris That's what I thought. I was just confused by the comment that view would not work. A

    – marmot
    Dec 5 '17 at 16:53

















thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.

– Cris
Dec 5 '17 at 6:36





thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.

– Cris
Dec 5 '17 at 6:36













@Cris That's what I thought. I was just confused by the comment that view would not work. A

– marmot
Dec 5 '17 at 16:53





@Cris That's what I thought. I was just confused by the comment that view would not work. A

– marmot
Dec 5 '17 at 16:53


















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