Plotting a parameterized curve on a certain coordinate system
Trying to plot the 3D curve
(t,t^2,2*t^3), tin [0,1],
with the code:
begin{tikzpicture}
begin{axis}
%view={105}{5},
[samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]
addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}
I got the following output:
But I want to plot that curve in the regular coordinate system:
begin{tikzpicture}
draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
end{tikzpicture}
that is:
Which would be the code ?
Later Edit: By using view{95}{5}, the axes seem to be like in the second output, but not perfect:
begin{tikzpicture}
begin{axis}
[view={95}{5}, samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]
addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}
The output being:
tikz-pgf pgfplots
add a comment |
Trying to plot the 3D curve
(t,t^2,2*t^3), tin [0,1],
with the code:
begin{tikzpicture}
begin{axis}
%view={105}{5},
[samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]
addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}
I got the following output:
But I want to plot that curve in the regular coordinate system:
begin{tikzpicture}
draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
end{tikzpicture}
that is:
Which would be the code ?
Later Edit: By using view{95}{5}, the axes seem to be like in the second output, but not perfect:
begin{tikzpicture}
begin{axis}
[view={95}{5}, samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]
addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}
The output being:
tikz-pgf pgfplots
1
Adjustingview=
won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.
– Jānis Lazovskis
Dec 4 '17 at 20:27
add a comment |
Trying to plot the 3D curve
(t,t^2,2*t^3), tin [0,1],
with the code:
begin{tikzpicture}
begin{axis}
%view={105}{5},
[samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]
addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}
I got the following output:
But I want to plot that curve in the regular coordinate system:
begin{tikzpicture}
draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
end{tikzpicture}
that is:
Which would be the code ?
Later Edit: By using view{95}{5}, the axes seem to be like in the second output, but not perfect:
begin{tikzpicture}
begin{axis}
[view={95}{5}, samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]
addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}
The output being:
tikz-pgf pgfplots
Trying to plot the 3D curve
(t,t^2,2*t^3), tin [0,1],
with the code:
begin{tikzpicture}
begin{axis}
%view={105}{5},
[samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]
addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}
I got the following output:
But I want to plot that curve in the regular coordinate system:
begin{tikzpicture}
draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
end{tikzpicture}
that is:
Which would be the code ?
Later Edit: By using view{95}{5}, the axes seem to be like in the second output, but not perfect:
begin{tikzpicture}
begin{axis}
[view={95}{5}, samples y=0, axis lines=center,axis on top,xlabel=$x$, ylabel=$y$, zlabel=$z$]
addplot3+[no markers,variable=t,domain=0:1,blue,samples=80,samples y=0] (t,t^2,2*t^3);
end{axis}
end{tikzpicture}
The output being:
tikz-pgf pgfplots
tikz-pgf pgfplots
edited Jan 15 at 19:28
Stefan Pinnow
19.7k83275
19.7k83275
asked Dec 4 '17 at 19:06
CrisCris
473211
473211
1
Adjustingview=
won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.
– Jānis Lazovskis
Dec 4 '17 at 20:27
add a comment |
1
Adjustingview=
won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.
– Jānis Lazovskis
Dec 4 '17 at 20:27
1
1
Adjusting
view=
won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.– Jānis Lazovskis
Dec 4 '17 at 20:27
Adjusting
view=
won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.– Jānis Lazovskis
Dec 4 '17 at 20:27
add a comment |
1 Answer
1
active
oldest
votes
This is not an answer but an attempt to understand the question better. In your desired coordinate system, you perform a cyclic permutation of the x-, y- and z-directions, right? If that's the case, why does a change of the view
and relabeling of the axes by hand not work? A brute force solution, which is certainly not a final solution, is
documentclass[border2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
defn{80}
foreach i in {1,...,n} {
pgfmathsetmacro{u}{(i-1)/n}
pgfmathsetmacro{v}{((i-1)/n)^2}
pgfmathsetmacro{w}{2*((i-1)/n)^3}
pgfmathsetmacro{x}{(i/n)}
pgfmathsetmacro{y}{(i/n)^2}
pgfmathsetmacro{z}{2*(i/n)^3}
draw[-,blue,thick,smooth] (v,w,u) -- (y,z,x);
}
end{tikzpicture}
end{document}
I just posted this in order to find out whether this is the plot you want to get, and I understand that this is a hilariously complicated way of producing the plot.
thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.
– Cris
Dec 5 '17 at 6:36
@Cris That's what I thought. I was just confused by the comment that view would not work. A
– marmot
Dec 5 '17 at 16:53
add a comment |
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1 Answer
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This is not an answer but an attempt to understand the question better. In your desired coordinate system, you perform a cyclic permutation of the x-, y- and z-directions, right? If that's the case, why does a change of the view
and relabeling of the axes by hand not work? A brute force solution, which is certainly not a final solution, is
documentclass[border2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
defn{80}
foreach i in {1,...,n} {
pgfmathsetmacro{u}{(i-1)/n}
pgfmathsetmacro{v}{((i-1)/n)^2}
pgfmathsetmacro{w}{2*((i-1)/n)^3}
pgfmathsetmacro{x}{(i/n)}
pgfmathsetmacro{y}{(i/n)^2}
pgfmathsetmacro{z}{2*(i/n)^3}
draw[-,blue,thick,smooth] (v,w,u) -- (y,z,x);
}
end{tikzpicture}
end{document}
I just posted this in order to find out whether this is the plot you want to get, and I understand that this is a hilariously complicated way of producing the plot.
thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.
– Cris
Dec 5 '17 at 6:36
@Cris That's what I thought. I was just confused by the comment that view would not work. A
– marmot
Dec 5 '17 at 16:53
add a comment |
This is not an answer but an attempt to understand the question better. In your desired coordinate system, you perform a cyclic permutation of the x-, y- and z-directions, right? If that's the case, why does a change of the view
and relabeling of the axes by hand not work? A brute force solution, which is certainly not a final solution, is
documentclass[border2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
defn{80}
foreach i in {1,...,n} {
pgfmathsetmacro{u}{(i-1)/n}
pgfmathsetmacro{v}{((i-1)/n)^2}
pgfmathsetmacro{w}{2*((i-1)/n)^3}
pgfmathsetmacro{x}{(i/n)}
pgfmathsetmacro{y}{(i/n)^2}
pgfmathsetmacro{z}{2*(i/n)^3}
draw[-,blue,thick,smooth] (v,w,u) -- (y,z,x);
}
end{tikzpicture}
end{document}
I just posted this in order to find out whether this is the plot you want to get, and I understand that this is a hilariously complicated way of producing the plot.
thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.
– Cris
Dec 5 '17 at 6:36
@Cris That's what I thought. I was just confused by the comment that view would not work. A
– marmot
Dec 5 '17 at 16:53
add a comment |
This is not an answer but an attempt to understand the question better. In your desired coordinate system, you perform a cyclic permutation of the x-, y- and z-directions, right? If that's the case, why does a change of the view
and relabeling of the axes by hand not work? A brute force solution, which is certainly not a final solution, is
documentclass[border2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
defn{80}
foreach i in {1,...,n} {
pgfmathsetmacro{u}{(i-1)/n}
pgfmathsetmacro{v}{((i-1)/n)^2}
pgfmathsetmacro{w}{2*((i-1)/n)^3}
pgfmathsetmacro{x}{(i/n)}
pgfmathsetmacro{y}{(i/n)^2}
pgfmathsetmacro{z}{2*(i/n)^3}
draw[-,blue,thick,smooth] (v,w,u) -- (y,z,x);
}
end{tikzpicture}
end{document}
I just posted this in order to find out whether this is the plot you want to get, and I understand that this is a hilariously complicated way of producing the plot.
This is not an answer but an attempt to understand the question better. In your desired coordinate system, you perform a cyclic permutation of the x-, y- and z-directions, right? If that's the case, why does a change of the view
and relabeling of the axes by hand not work? A brute force solution, which is certainly not a final solution, is
documentclass[border2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
draw[thick,->] (0,0,0)coordinate (O) -- (3,0,0) coordinate (X)
node[anchor=north east]{$y$};
draw[thick,->] (0,0,0) -- (0,3,0) coordinate (Y) node[anchor=north
west]{$z$};
draw[thick,->] (0,0,0) -- (0,0,3) coordinate (Z) node[anchor=south]{$x$};
defn{80}
foreach i in {1,...,n} {
pgfmathsetmacro{u}{(i-1)/n}
pgfmathsetmacro{v}{((i-1)/n)^2}
pgfmathsetmacro{w}{2*((i-1)/n)^3}
pgfmathsetmacro{x}{(i/n)}
pgfmathsetmacro{y}{(i/n)^2}
pgfmathsetmacro{z}{2*(i/n)^3}
draw[-,blue,thick,smooth] (v,w,u) -- (y,z,x);
}
end{tikzpicture}
end{document}
I just posted this in order to find out whether this is the plot you want to get, and I understand that this is a hilariously complicated way of producing the plot.
answered Dec 5 '17 at 1:32
marmotmarmot
93.8k4109208
93.8k4109208
thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.
– Cris
Dec 5 '17 at 6:36
@Cris That's what I thought. I was just confused by the comment that view would not work. A
– marmot
Dec 5 '17 at 16:53
add a comment |
thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.
– Cris
Dec 5 '17 at 6:36
@Cris That's what I thought. I was just confused by the comment that view would not work. A
– marmot
Dec 5 '17 at 16:53
thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.
– Cris
Dec 5 '17 at 6:36
thank you very much ! Indeed, this way is too complicated. By using view{95}{5}, the axes seem to be like in my second output.
– Cris
Dec 5 '17 at 6:36
@Cris That's what I thought. I was just confused by the comment that view would not work. A
– marmot
Dec 5 '17 at 16:53
@Cris That's what I thought. I was just confused by the comment that view would not work. A
– marmot
Dec 5 '17 at 16:53
add a comment |
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1
Adjusting
view=
won't be enough to solve your problem, you need something more - take a look at this question, which seems to deal with a similar issue.– Jānis Lazovskis
Dec 4 '17 at 20:27