Parameter estimation for Stochastic differential equation











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I have a process $X(t)$ defined on some finite time horizon $[0,T]$ and I know that my process satisfies the following SDE:



$dX(t)=X_t mu dt + X_t sigma dB_t$.



where $B$ is a standard Brownian motion. In particular I'm assuming that both the drift and volatility are constant over time.



Question:



Given data points $x_{t_1}, ldots x_{t_n}$ that are realizations of the random variable $X(t)$ at times $t_1 ldots t_n$, how do I estimate the drift and volatility parameters $mu, sigma$ ? I'm interested in a method that is relatively easy to implement.



I would also like to know if there already exist libraries in say Python that might help for this task.



What would be a method for estimating $mu$ and $sigma$ if they change over time? (I.e. they are are time dependent)










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    up vote
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    down vote

    favorite
    1












    I have a process $X(t)$ defined on some finite time horizon $[0,T]$ and I know that my process satisfies the following SDE:



    $dX(t)=X_t mu dt + X_t sigma dB_t$.



    where $B$ is a standard Brownian motion. In particular I'm assuming that both the drift and volatility are constant over time.



    Question:



    Given data points $x_{t_1}, ldots x_{t_n}$ that are realizations of the random variable $X(t)$ at times $t_1 ldots t_n$, how do I estimate the drift and volatility parameters $mu, sigma$ ? I'm interested in a method that is relatively easy to implement.



    I would also like to know if there already exist libraries in say Python that might help for this task.



    What would be a method for estimating $mu$ and $sigma$ if they change over time? (I.e. they are are time dependent)










    share|cite|improve this question


























      up vote
      5
      down vote

      favorite
      1









      up vote
      5
      down vote

      favorite
      1






      1





      I have a process $X(t)$ defined on some finite time horizon $[0,T]$ and I know that my process satisfies the following SDE:



      $dX(t)=X_t mu dt + X_t sigma dB_t$.



      where $B$ is a standard Brownian motion. In particular I'm assuming that both the drift and volatility are constant over time.



      Question:



      Given data points $x_{t_1}, ldots x_{t_n}$ that are realizations of the random variable $X(t)$ at times $t_1 ldots t_n$, how do I estimate the drift and volatility parameters $mu, sigma$ ? I'm interested in a method that is relatively easy to implement.



      I would also like to know if there already exist libraries in say Python that might help for this task.



      What would be a method for estimating $mu$ and $sigma$ if they change over time? (I.e. they are are time dependent)










      share|cite|improve this question















      I have a process $X(t)$ defined on some finite time horizon $[0,T]$ and I know that my process satisfies the following SDE:



      $dX(t)=X_t mu dt + X_t sigma dB_t$.



      where $B$ is a standard Brownian motion. In particular I'm assuming that both the drift and volatility are constant over time.



      Question:



      Given data points $x_{t_1}, ldots x_{t_n}$ that are realizations of the random variable $X(t)$ at times $t_1 ldots t_n$, how do I estimate the drift and volatility parameters $mu, sigma$ ? I'm interested in a method that is relatively easy to implement.



      I would also like to know if there already exist libraries in say Python that might help for this task.



      What would be a method for estimating $mu$ and $sigma$ if they change over time? (I.e. they are are time dependent)







      reference-request stochastic-processes parameter-estimation






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      share|cite|improve this question













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      edited Nov 26 at 9:59

























      asked Nov 5 at 14:15









      sigmatau

      1,7401924




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          2 Answers
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          For geometric Brownian motion we have (by solving the SDE)
          $$log X_{t_i}=log X_{t_{i-1}}+tildemu(t_i-t_{i-1})+sigma(B_{t_i}-B_{t_{i-1}}),quad i=1,..,n$$
          where $tildemu=mu-frac{sigma^2}{2}$.
          Hence the conditional distribution of $X_{t_i}$ given $X_{t_{i-1}}$ is log-normal with mean equal to $log X_{t_{i-1}}+tildemu(t_i-t_{i-1})$ and variance $sigma^2 (t_i-t_{i-1})$.
          Suppose that $X_0=x_0$ is fixed (the calculations are very similar if $X_0$ is itself lognormal, just add another term), the log of the joint density of the vector $(X_{t_1},...,X_{t_n})$ at $x_1,...,x_n$ takes the following form:
          $$log p(x_1,...,x_n)=-sum_{i=1}^nlog x_i-frac{n}{2}log 2pisigma^2-frac{1}{2}sum_{i=1}^nlogDelta t_i-frac{1}{2}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{sigma^2Delta t_i},$$
          where we introduced $Delta t_i=t_i-t_{i-1}$.
          Differentiating this wrt. $mu$, we obtain
          $$partial_{tildemu}log p=frac{1}{sigma^2}Big(log x_n-log x_0-tildemu(t_n-t_0)Big)=0quadLongrightarrowquadtildemu=frac{log x_n-log x_0}{t_n-t_0},$$
          and by using this, we can also solve the other equation:
          $$partial_{sigma^2}log p=frac{1}{2sigma^2}Big(frac{1}{sigma^2}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{Delta t_i}-nBig)=0$$
          $$quadLongrightarrowquadsigma^2=frac{1}{n}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{Delta t_i}.$$






          share|cite|improve this answer























          • Indeed, I found this: math.stackexchange.com/questions/2554579/…. Or, maybe better, equation (14) here: file:///C:/Users/Me/Downloads/SSRN-id2944341.pdf . So it would be enough to maximize the likelihood function with respect to $mu$ and $sigma$ right? This can be done in python, there are some optimiztion packages. or
            – sigmatau
            Nov 26 at 9:54








          • 1




            But that is for a different SDE (geometric Brownian motion). What you have is Brownian motion with drift.
            – S.Surace
            Nov 26 at 9:57










          • You are totally right, I did a mistake in writing down the formula. I am considering geometric brownian motion, will fix that now.
            – sigmatau
            Nov 26 at 9:59






          • 1




            Ok, in that case you can do the same with just a couple of logs. I will change my answer. You don't need any optimization packages. You can solve for $mu$ and $sigma$ algebraically!
            – S.Surace
            Nov 26 at 10:00






          • 1




            Yes, thank you. I made the corrections, hope everything is correct now.
            – S.Surace
            Dec 2 at 13:46


















          up vote
          1
          down vote













          I'm not so familiar with this formulation of the problem, but a common practice in engineering is the method based on Allan Variance. You basically assume the high frequency noise to be the volatility while the low frequency is the drift and identify btoh from the slopes on the chart..



          As for the case when they are not constant it would be necessary to make some assumptions on how they vary over time. Either by giving them specific time functions with parameters to be estimated or possibly assuming that they are themselves performing soem kind of random (possibly Brownian) motion, in which case some technique like an Extended Kalman Filter or a Particle Filter could be envisaged.






          share|cite|improve this answer























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            2 Answers
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            active

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            2 Answers
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            active

            oldest

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            active

            oldest

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            active

            oldest

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            up vote
            1
            down vote



            accepted










            For geometric Brownian motion we have (by solving the SDE)
            $$log X_{t_i}=log X_{t_{i-1}}+tildemu(t_i-t_{i-1})+sigma(B_{t_i}-B_{t_{i-1}}),quad i=1,..,n$$
            where $tildemu=mu-frac{sigma^2}{2}$.
            Hence the conditional distribution of $X_{t_i}$ given $X_{t_{i-1}}$ is log-normal with mean equal to $log X_{t_{i-1}}+tildemu(t_i-t_{i-1})$ and variance $sigma^2 (t_i-t_{i-1})$.
            Suppose that $X_0=x_0$ is fixed (the calculations are very similar if $X_0$ is itself lognormal, just add another term), the log of the joint density of the vector $(X_{t_1},...,X_{t_n})$ at $x_1,...,x_n$ takes the following form:
            $$log p(x_1,...,x_n)=-sum_{i=1}^nlog x_i-frac{n}{2}log 2pisigma^2-frac{1}{2}sum_{i=1}^nlogDelta t_i-frac{1}{2}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{sigma^2Delta t_i},$$
            where we introduced $Delta t_i=t_i-t_{i-1}$.
            Differentiating this wrt. $mu$, we obtain
            $$partial_{tildemu}log p=frac{1}{sigma^2}Big(log x_n-log x_0-tildemu(t_n-t_0)Big)=0quadLongrightarrowquadtildemu=frac{log x_n-log x_0}{t_n-t_0},$$
            and by using this, we can also solve the other equation:
            $$partial_{sigma^2}log p=frac{1}{2sigma^2}Big(frac{1}{sigma^2}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{Delta t_i}-nBig)=0$$
            $$quadLongrightarrowquadsigma^2=frac{1}{n}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{Delta t_i}.$$






            share|cite|improve this answer























            • Indeed, I found this: math.stackexchange.com/questions/2554579/…. Or, maybe better, equation (14) here: file:///C:/Users/Me/Downloads/SSRN-id2944341.pdf . So it would be enough to maximize the likelihood function with respect to $mu$ and $sigma$ right? This can be done in python, there are some optimiztion packages. or
              – sigmatau
              Nov 26 at 9:54








            • 1




              But that is for a different SDE (geometric Brownian motion). What you have is Brownian motion with drift.
              – S.Surace
              Nov 26 at 9:57










            • You are totally right, I did a mistake in writing down the formula. I am considering geometric brownian motion, will fix that now.
              – sigmatau
              Nov 26 at 9:59






            • 1




              Ok, in that case you can do the same with just a couple of logs. I will change my answer. You don't need any optimization packages. You can solve for $mu$ and $sigma$ algebraically!
              – S.Surace
              Nov 26 at 10:00






            • 1




              Yes, thank you. I made the corrections, hope everything is correct now.
              – S.Surace
              Dec 2 at 13:46















            up vote
            1
            down vote



            accepted










            For geometric Brownian motion we have (by solving the SDE)
            $$log X_{t_i}=log X_{t_{i-1}}+tildemu(t_i-t_{i-1})+sigma(B_{t_i}-B_{t_{i-1}}),quad i=1,..,n$$
            where $tildemu=mu-frac{sigma^2}{2}$.
            Hence the conditional distribution of $X_{t_i}$ given $X_{t_{i-1}}$ is log-normal with mean equal to $log X_{t_{i-1}}+tildemu(t_i-t_{i-1})$ and variance $sigma^2 (t_i-t_{i-1})$.
            Suppose that $X_0=x_0$ is fixed (the calculations are very similar if $X_0$ is itself lognormal, just add another term), the log of the joint density of the vector $(X_{t_1},...,X_{t_n})$ at $x_1,...,x_n$ takes the following form:
            $$log p(x_1,...,x_n)=-sum_{i=1}^nlog x_i-frac{n}{2}log 2pisigma^2-frac{1}{2}sum_{i=1}^nlogDelta t_i-frac{1}{2}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{sigma^2Delta t_i},$$
            where we introduced $Delta t_i=t_i-t_{i-1}$.
            Differentiating this wrt. $mu$, we obtain
            $$partial_{tildemu}log p=frac{1}{sigma^2}Big(log x_n-log x_0-tildemu(t_n-t_0)Big)=0quadLongrightarrowquadtildemu=frac{log x_n-log x_0}{t_n-t_0},$$
            and by using this, we can also solve the other equation:
            $$partial_{sigma^2}log p=frac{1}{2sigma^2}Big(frac{1}{sigma^2}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{Delta t_i}-nBig)=0$$
            $$quadLongrightarrowquadsigma^2=frac{1}{n}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{Delta t_i}.$$






            share|cite|improve this answer























            • Indeed, I found this: math.stackexchange.com/questions/2554579/…. Or, maybe better, equation (14) here: file:///C:/Users/Me/Downloads/SSRN-id2944341.pdf . So it would be enough to maximize the likelihood function with respect to $mu$ and $sigma$ right? This can be done in python, there are some optimiztion packages. or
              – sigmatau
              Nov 26 at 9:54








            • 1




              But that is for a different SDE (geometric Brownian motion). What you have is Brownian motion with drift.
              – S.Surace
              Nov 26 at 9:57










            • You are totally right, I did a mistake in writing down the formula. I am considering geometric brownian motion, will fix that now.
              – sigmatau
              Nov 26 at 9:59






            • 1




              Ok, in that case you can do the same with just a couple of logs. I will change my answer. You don't need any optimization packages. You can solve for $mu$ and $sigma$ algebraically!
              – S.Surace
              Nov 26 at 10:00






            • 1




              Yes, thank you. I made the corrections, hope everything is correct now.
              – S.Surace
              Dec 2 at 13:46













            up vote
            1
            down vote



            accepted







            up vote
            1
            down vote



            accepted






            For geometric Brownian motion we have (by solving the SDE)
            $$log X_{t_i}=log X_{t_{i-1}}+tildemu(t_i-t_{i-1})+sigma(B_{t_i}-B_{t_{i-1}}),quad i=1,..,n$$
            where $tildemu=mu-frac{sigma^2}{2}$.
            Hence the conditional distribution of $X_{t_i}$ given $X_{t_{i-1}}$ is log-normal with mean equal to $log X_{t_{i-1}}+tildemu(t_i-t_{i-1})$ and variance $sigma^2 (t_i-t_{i-1})$.
            Suppose that $X_0=x_0$ is fixed (the calculations are very similar if $X_0$ is itself lognormal, just add another term), the log of the joint density of the vector $(X_{t_1},...,X_{t_n})$ at $x_1,...,x_n$ takes the following form:
            $$log p(x_1,...,x_n)=-sum_{i=1}^nlog x_i-frac{n}{2}log 2pisigma^2-frac{1}{2}sum_{i=1}^nlogDelta t_i-frac{1}{2}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{sigma^2Delta t_i},$$
            where we introduced $Delta t_i=t_i-t_{i-1}$.
            Differentiating this wrt. $mu$, we obtain
            $$partial_{tildemu}log p=frac{1}{sigma^2}Big(log x_n-log x_0-tildemu(t_n-t_0)Big)=0quadLongrightarrowquadtildemu=frac{log x_n-log x_0}{t_n-t_0},$$
            and by using this, we can also solve the other equation:
            $$partial_{sigma^2}log p=frac{1}{2sigma^2}Big(frac{1}{sigma^2}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{Delta t_i}-nBig)=0$$
            $$quadLongrightarrowquadsigma^2=frac{1}{n}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{Delta t_i}.$$






            share|cite|improve this answer














            For geometric Brownian motion we have (by solving the SDE)
            $$log X_{t_i}=log X_{t_{i-1}}+tildemu(t_i-t_{i-1})+sigma(B_{t_i}-B_{t_{i-1}}),quad i=1,..,n$$
            where $tildemu=mu-frac{sigma^2}{2}$.
            Hence the conditional distribution of $X_{t_i}$ given $X_{t_{i-1}}$ is log-normal with mean equal to $log X_{t_{i-1}}+tildemu(t_i-t_{i-1})$ and variance $sigma^2 (t_i-t_{i-1})$.
            Suppose that $X_0=x_0$ is fixed (the calculations are very similar if $X_0$ is itself lognormal, just add another term), the log of the joint density of the vector $(X_{t_1},...,X_{t_n})$ at $x_1,...,x_n$ takes the following form:
            $$log p(x_1,...,x_n)=-sum_{i=1}^nlog x_i-frac{n}{2}log 2pisigma^2-frac{1}{2}sum_{i=1}^nlogDelta t_i-frac{1}{2}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{sigma^2Delta t_i},$$
            where we introduced $Delta t_i=t_i-t_{i-1}$.
            Differentiating this wrt. $mu$, we obtain
            $$partial_{tildemu}log p=frac{1}{sigma^2}Big(log x_n-log x_0-tildemu(t_n-t_0)Big)=0quadLongrightarrowquadtildemu=frac{log x_n-log x_0}{t_n-t_0},$$
            and by using this, we can also solve the other equation:
            $$partial_{sigma^2}log p=frac{1}{2sigma^2}Big(frac{1}{sigma^2}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{Delta t_i}-nBig)=0$$
            $$quadLongrightarrowquadsigma^2=frac{1}{n}sum_{i=1}^nfrac{(log x_i-log x_{i-1}-tildemuDelta t_i)^2}{Delta t_i}.$$







            share|cite|improve this answer














            share|cite|improve this answer



            share|cite|improve this answer








            edited Dec 2 at 13:45

























            answered Nov 26 at 9:51









            S.Surace

            731412




            731412












            • Indeed, I found this: math.stackexchange.com/questions/2554579/…. Or, maybe better, equation (14) here: file:///C:/Users/Me/Downloads/SSRN-id2944341.pdf . So it would be enough to maximize the likelihood function with respect to $mu$ and $sigma$ right? This can be done in python, there are some optimiztion packages. or
              – sigmatau
              Nov 26 at 9:54








            • 1




              But that is for a different SDE (geometric Brownian motion). What you have is Brownian motion with drift.
              – S.Surace
              Nov 26 at 9:57










            • You are totally right, I did a mistake in writing down the formula. I am considering geometric brownian motion, will fix that now.
              – sigmatau
              Nov 26 at 9:59






            • 1




              Ok, in that case you can do the same with just a couple of logs. I will change my answer. You don't need any optimization packages. You can solve for $mu$ and $sigma$ algebraically!
              – S.Surace
              Nov 26 at 10:00






            • 1




              Yes, thank you. I made the corrections, hope everything is correct now.
              – S.Surace
              Dec 2 at 13:46


















            • Indeed, I found this: math.stackexchange.com/questions/2554579/…. Or, maybe better, equation (14) here: file:///C:/Users/Me/Downloads/SSRN-id2944341.pdf . So it would be enough to maximize the likelihood function with respect to $mu$ and $sigma$ right? This can be done in python, there are some optimiztion packages. or
              – sigmatau
              Nov 26 at 9:54








            • 1




              But that is for a different SDE (geometric Brownian motion). What you have is Brownian motion with drift.
              – S.Surace
              Nov 26 at 9:57










            • You are totally right, I did a mistake in writing down the formula. I am considering geometric brownian motion, will fix that now.
              – sigmatau
              Nov 26 at 9:59






            • 1




              Ok, in that case you can do the same with just a couple of logs. I will change my answer. You don't need any optimization packages. You can solve for $mu$ and $sigma$ algebraically!
              – S.Surace
              Nov 26 at 10:00






            • 1




              Yes, thank you. I made the corrections, hope everything is correct now.
              – S.Surace
              Dec 2 at 13:46
















            Indeed, I found this: math.stackexchange.com/questions/2554579/…. Or, maybe better, equation (14) here: file:///C:/Users/Me/Downloads/SSRN-id2944341.pdf . So it would be enough to maximize the likelihood function with respect to $mu$ and $sigma$ right? This can be done in python, there are some optimiztion packages. or
            – sigmatau
            Nov 26 at 9:54






            Indeed, I found this: math.stackexchange.com/questions/2554579/…. Or, maybe better, equation (14) here: file:///C:/Users/Me/Downloads/SSRN-id2944341.pdf . So it would be enough to maximize the likelihood function with respect to $mu$ and $sigma$ right? This can be done in python, there are some optimiztion packages. or
            – sigmatau
            Nov 26 at 9:54






            1




            1




            But that is for a different SDE (geometric Brownian motion). What you have is Brownian motion with drift.
            – S.Surace
            Nov 26 at 9:57




            But that is for a different SDE (geometric Brownian motion). What you have is Brownian motion with drift.
            – S.Surace
            Nov 26 at 9:57












            You are totally right, I did a mistake in writing down the formula. I am considering geometric brownian motion, will fix that now.
            – sigmatau
            Nov 26 at 9:59




            You are totally right, I did a mistake in writing down the formula. I am considering geometric brownian motion, will fix that now.
            – sigmatau
            Nov 26 at 9:59




            1




            1




            Ok, in that case you can do the same with just a couple of logs. I will change my answer. You don't need any optimization packages. You can solve for $mu$ and $sigma$ algebraically!
            – S.Surace
            Nov 26 at 10:00




            Ok, in that case you can do the same with just a couple of logs. I will change my answer. You don't need any optimization packages. You can solve for $mu$ and $sigma$ algebraically!
            – S.Surace
            Nov 26 at 10:00




            1




            1




            Yes, thank you. I made the corrections, hope everything is correct now.
            – S.Surace
            Dec 2 at 13:46




            Yes, thank you. I made the corrections, hope everything is correct now.
            – S.Surace
            Dec 2 at 13:46










            up vote
            1
            down vote













            I'm not so familiar with this formulation of the problem, but a common practice in engineering is the method based on Allan Variance. You basically assume the high frequency noise to be the volatility while the low frequency is the drift and identify btoh from the slopes on the chart..



            As for the case when they are not constant it would be necessary to make some assumptions on how they vary over time. Either by giving them specific time functions with parameters to be estimated or possibly assuming that they are themselves performing soem kind of random (possibly Brownian) motion, in which case some technique like an Extended Kalman Filter or a Particle Filter could be envisaged.






            share|cite|improve this answer



























              up vote
              1
              down vote













              I'm not so familiar with this formulation of the problem, but a common practice in engineering is the method based on Allan Variance. You basically assume the high frequency noise to be the volatility while the low frequency is the drift and identify btoh from the slopes on the chart..



              As for the case when they are not constant it would be necessary to make some assumptions on how they vary over time. Either by giving them specific time functions with parameters to be estimated or possibly assuming that they are themselves performing soem kind of random (possibly Brownian) motion, in which case some technique like an Extended Kalman Filter or a Particle Filter could be envisaged.






              share|cite|improve this answer

























                up vote
                1
                down vote










                up vote
                1
                down vote









                I'm not so familiar with this formulation of the problem, but a common practice in engineering is the method based on Allan Variance. You basically assume the high frequency noise to be the volatility while the low frequency is the drift and identify btoh from the slopes on the chart..



                As for the case when they are not constant it would be necessary to make some assumptions on how they vary over time. Either by giving them specific time functions with parameters to be estimated or possibly assuming that they are themselves performing soem kind of random (possibly Brownian) motion, in which case some technique like an Extended Kalman Filter or a Particle Filter could be envisaged.






                share|cite|improve this answer














                I'm not so familiar with this formulation of the problem, but a common practice in engineering is the method based on Allan Variance. You basically assume the high frequency noise to be the volatility while the low frequency is the drift and identify btoh from the slopes on the chart..



                As for the case when they are not constant it would be necessary to make some assumptions on how they vary over time. Either by giving them specific time functions with parameters to be estimated or possibly assuming that they are themselves performing soem kind of random (possibly Brownian) motion, in which case some technique like an Extended Kalman Filter or a Particle Filter could be envisaged.







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                edited Nov 19 at 12:34

























                answered Nov 19 at 12:24









                Mefitico

                920117




                920117






























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