Determine all functions $f : mathbb{N} rightarrow mathbb{N}$ such that, for every positive integer $n$, we...












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Determine all functions $f : mathbb{N} rightarrow mathbb{N}$ such that, for every positive integer $n$, we have: $$2n+2001≤f(f(n))+f(n)≤2n+2002,.$$




I don't know where to start as in is there a function that I can get to the solution by slightly modifying it? Any ideas










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Determine all functions $f : mathbb{N} rightarrow mathbb{N}$ such that, for every positive integer $n$, we have: $$2n+2001≤f(f(n))+f(n)≤2n+2002,.$$




I don't know where to start as in is there a function that I can get to the solution by slightly modifying it? Any ideas










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migrated from cs.stackexchange.com Nov 26 '18 at 8:26


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Determine all functions $f : mathbb{N} rightarrow mathbb{N}$ such that, for every positive integer $n$, we have: $$2n+2001≤f(f(n))+f(n)≤2n+2002,.$$




I don't know where to start as in is there a function that I can get to the solution by slightly modifying it? Any ideas










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Determine all functions $f : mathbb{N} rightarrow mathbb{N}$ such that, for every positive integer $n$, we have: $$2n+2001≤f(f(n))+f(n)≤2n+2002,.$$




I don't know where to start as in is there a function that I can get to the solution by slightly modifying it? Any ideas







discrete-mathematics contest-math problem-solving functional-equations functional-inequalities






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edited Dec 11 '18 at 19:27









Batominovski

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1










asked Nov 26 '18 at 2:28









nafhgoodnafhgood

1,801422




1,801422




migrated from cs.stackexchange.com Nov 26 '18 at 8:26


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migrated from cs.stackexchange.com Nov 26 '18 at 8:26


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    Please credit the original source.
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    – Apass.Jack
    Nov 26 '18 at 3:59


















  • $begingroup$
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    – Apass.Jack
    Nov 26 '18 at 3:59
















$begingroup$
Please credit the original source.
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– Apass.Jack
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How to start: You might start for example by checking what f(0) might be. Is f(0) = 0 possible, and if not, why not? If f(0) = 1, what can we then say about f(1)? What can we then say about f(2000) or f(2001)? Get a feeling for the problem. That's how you start.






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    Very old problem from the 2002 Balkan Mathematical Olympiad. You have to keep on
    iterating f(f(f(...(f(n)...))) and see what inequalities you get, see e.g.



    https://artofproblemsolving.com/community/c6h76767






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      2 Answers
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      2 Answers
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      $begingroup$

      How to start: You might start for example by checking what f(0) might be. Is f(0) = 0 possible, and if not, why not? If f(0) = 1, what can we then say about f(1)? What can we then say about f(2000) or f(2001)? Get a feeling for the problem. That's how you start.






      share|cite|improve this answer









      $endgroup$


















        0












        $begingroup$

        How to start: You might start for example by checking what f(0) might be. Is f(0) = 0 possible, and if not, why not? If f(0) = 1, what can we then say about f(1)? What can we then say about f(2000) or f(2001)? Get a feeling for the problem. That's how you start.






        share|cite|improve this answer









        $endgroup$
















          0












          0








          0





          $begingroup$

          How to start: You might start for example by checking what f(0) might be. Is f(0) = 0 possible, and if not, why not? If f(0) = 1, what can we then say about f(1)? What can we then say about f(2000) or f(2001)? Get a feeling for the problem. That's how you start.






          share|cite|improve this answer









          $endgroup$



          How to start: You might start for example by checking what f(0) might be. Is f(0) = 0 possible, and if not, why not? If f(0) = 1, what can we then say about f(1)? What can we then say about f(2000) or f(2001)? Get a feeling for the problem. That's how you start.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 26 '18 at 8:18









          gnasher729gnasher729

          5,9871028




          5,9871028























              0












              $begingroup$

              Very old problem from the 2002 Balkan Mathematical Olympiad. You have to keep on
              iterating f(f(f(...(f(n)...))) and see what inequalities you get, see e.g.



              https://artofproblemsolving.com/community/c6h76767






              share|cite|improve this answer









              $endgroup$


















                0












                $begingroup$

                Very old problem from the 2002 Balkan Mathematical Olympiad. You have to keep on
                iterating f(f(f(...(f(n)...))) and see what inequalities you get, see e.g.



                https://artofproblemsolving.com/community/c6h76767






                share|cite|improve this answer









                $endgroup$
















                  0












                  0








                  0





                  $begingroup$

                  Very old problem from the 2002 Balkan Mathematical Olympiad. You have to keep on
                  iterating f(f(f(...(f(n)...))) and see what inequalities you get, see e.g.



                  https://artofproblemsolving.com/community/c6h76767






                  share|cite|improve this answer









                  $endgroup$



                  Very old problem from the 2002 Balkan Mathematical Olympiad. You have to keep on
                  iterating f(f(f(...(f(n)...))) and see what inequalities you get, see e.g.



                  https://artofproblemsolving.com/community/c6h76767







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Nov 26 '18 at 8:41









                  Sorin TircSorin Tirc

                  1,530213




                  1,530213






























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