modifying calculated nodes in foreach loop
2
Using the following code from the answer to this question
how can the nodes 0sigma be replaced by mu
and how can the nodes 1sigma 2sigma 3sigma be replaced by +1sigma +2sigma +3sigma
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{i$sigma$}coordinate(i);
end{scope}
end{tikzpicture}
end{frame}
end{document}
tikz-pgf foreach
asked Dec 9 at 14:14
Hany
1,090415
add a comment |
2
Using the following code from the answer to this question
how can the nodes 0sigma be replaced by mu
and how can the nodes 1sigma 2sigma 3sigma be replaced by +1sigma +2sigma +3sigma
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{i$sigma$}coordinate(i);
end{scope}
end{tikzpicture}
end{frame}
end{document}
tikz-pgf foreach
asked Dec 9 at 14:14
Hany
1,090415
add a comment |
2
2
2
Using the following code from the answer to this question
how can the nodes 0sigma be replaced by mu
and how can the nodes 1sigma 2sigma 3sigma be replaced by +1sigma +2sigma +3sigma
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{i$sigma$}coordinate(i);
end{scope}
end{tikzpicture}
end{frame}
end{document}
tikz-pgf foreach
asked Dec 9 at 14:14
Hany
1,090415
Using the following code from the answer to this question
how can the nodes 0sigma be replaced by mu
and how can the nodes 1sigma 2sigma 3sigma be replaced by +1sigma +2sigma +3sigma
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{i$sigma$}coordinate(i);
end{scope}
end{tikzpicture}
end{frame}
end{document}
tikz-pgf foreach
tikz-pgf foreach
asked Dec 9 at 14:14
Hany
1,090415
asked Dec 9 at 14:14
Hany
1,090415
asked Dec 9 at 14:14
Hany
1,090415
asked Dec 9 at 14:14
Hany
1,090415
asked Dec 9 at 14:14
Hany
1,090415
1,090415
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
If you do not want to delve into the depths of pgfmathprintnumber, you could just use some ifnum statements.
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
foreach[count=j] i in {-3,...,3}
{ifnumi=0
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{$mu$}coordinate(i);
else
ifnumi>0
defmysign{+}
else
defmysign{}
fi
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{$mysignisigma$}coordinate(i);
fi
}
end{scope}
end{tikzpicture}
end{frame}
end{document}
answered Dec 9 at 14:22
marmot
86.6k499185
Thank you very much for your valuable answer.
– Hany
Dec 9 at 14:52
@Hany As always, you're very welcome!
– marmot
Dec 9 at 14:52
add a comment |
1
Just use the pgf key pgfkeys{/pgf/number format/showpos}
and display the number with pgfmathprintnumber{i} (see page 952 of the 3.0.1a manual).
Update:
To have a symbol mu instead of the 0sigma, we can simply rewrite over the one that was written in the loop.
draw (4*1.227,-.2)node[yshift=-.35cm,fill=white,minimum width=7mm]{$mu$};
Foreach code:
begin{scope}[xshift=-1.cm, yshift=-2.cm]
pgfkeys{/pgf/number format/showpos}
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{pgfmathprintnumber{i}$sigma$}coordinate(i);
draw (4*1.227,-.2)node[yshift=-.35cm,fill=white,minimum width=7mm]{$mu$};
end{scope}
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
pgfkeys{/pgf/number format/showpos}
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{pgfmathprintnumber{i}$sigma$}coordinate(i);
end{scope}
end{tikzpicture}
end{frame}
end{document}
answered Dec 9 at 14:23
AndréC
7,57011440
1
Note that the OP wants amuinstead of0sigma. This is why I used anifnumstatement in my answer....
– marmot
Dec 9 at 14:41
@AndréC Thank you for your answer.
– Hany
Dec 9 at 14:55
1
Thanks, I just updated my answer.
– AndréC
Dec 9 at 14:55
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
If you do not want to delve into the depths of pgfmathprintnumber, you could just use some ifnum statements.
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
foreach[count=j] i in {-3,...,3}
{ifnumi=0
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{$mu$}coordinate(i);
else
ifnumi>0
defmysign{+}
else
defmysign{}
fi
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{$mysignisigma$}coordinate(i);
fi
}
end{scope}
end{tikzpicture}
end{frame}
end{document}
answered Dec 9 at 14:22
marmot
86.6k499185
Thank you very much for your valuable answer.
– Hany
Dec 9 at 14:52
@Hany As always, you're very welcome!
– marmot
Dec 9 at 14:52
add a comment |
1
If you do not want to delve into the depths of pgfmathprintnumber, you could just use some ifnum statements.
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
foreach[count=j] i in {-3,...,3}
{ifnumi=0
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{$mu$}coordinate(i);
else
ifnumi>0
defmysign{+}
else
defmysign{}
fi
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{$mysignisigma$}coordinate(i);
fi
}
end{scope}
end{tikzpicture}
end{frame}
end{document}
answered Dec 9 at 14:22
marmot
86.6k499185
Thank you very much for your valuable answer.
– Hany
Dec 9 at 14:52
@Hany As always, you're very welcome!
– marmot
Dec 9 at 14:52
add a comment |
1
1
1
If you do not want to delve into the depths of pgfmathprintnumber, you could just use some ifnum statements.
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
foreach[count=j] i in {-3,...,3}
{ifnumi=0
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{$mu$}coordinate(i);
else
ifnumi>0
defmysign{+}
else
defmysign{}
fi
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{$mysignisigma$}coordinate(i);
fi
}
end{scope}
end{tikzpicture}
end{frame}
end{document}
answered Dec 9 at 14:22
marmot
86.6k499185
If you do not want to delve into the depths of pgfmathprintnumber, you could just use some ifnum statements.
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
foreach[count=j] i in {-3,...,3}
{ifnumi=0
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{$mu$}coordinate(i);
else
ifnumi>0
defmysign{+}
else
defmysign{}
fi
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{$mysignisigma$}coordinate(i);
fi
}
end{scope}
end{tikzpicture}
end{frame}
end{document}
answered Dec 9 at 14:22
marmot
86.6k499185
answered Dec 9 at 14:22
marmot
86.6k499185
answered Dec 9 at 14:22
marmot
86.6k499185
answered Dec 9 at 14:22
marmot
86.6k499185
86.6k499185
Thank you very much for your valuable answer.
– Hany
Dec 9 at 14:52
@Hany As always, you're very welcome!
– marmot
Dec 9 at 14:52
add a comment |
Thank you very much for your valuable answer.
– Hany
Dec 9 at 14:52
@Hany As always, you're very welcome!
– marmot
Dec 9 at 14:52
Thank you very much for your valuable answer.
– Hany
Dec 9 at 14:52
Thank you very much for your valuable answer.
– Hany
Dec 9 at 14:52
@Hany As always, you're very welcome!
– marmot
Dec 9 at 14:52
@Hany As always, you're very welcome!
– marmot
Dec 9 at 14:52
add a comment |
1
Just use the pgf key pgfkeys{/pgf/number format/showpos}
and display the number with pgfmathprintnumber{i} (see page 952 of the 3.0.1a manual).
Update:
To have a symbol mu instead of the 0sigma, we can simply rewrite over the one that was written in the loop.
draw (4*1.227,-.2)node[yshift=-.35cm,fill=white,minimum width=7mm]{$mu$};
Foreach code:
begin{scope}[xshift=-1.cm, yshift=-2.cm]
pgfkeys{/pgf/number format/showpos}
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{pgfmathprintnumber{i}$sigma$}coordinate(i);
draw (4*1.227,-.2)node[yshift=-.35cm,fill=white,minimum width=7mm]{$mu$};
end{scope}
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
pgfkeys{/pgf/number format/showpos}
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{pgfmathprintnumber{i}$sigma$}coordinate(i);
end{scope}
end{tikzpicture}
end{frame}
end{document}
answered Dec 9 at 14:23
AndréC
7,57011440
1
Note that the OP wants amuinstead of0sigma. This is why I used anifnumstatement in my answer....
– marmot
Dec 9 at 14:41
@AndréC Thank you for your answer.
– Hany
Dec 9 at 14:55
1
Thanks, I just updated my answer.
– AndréC
Dec 9 at 14:55
add a comment |
1
Just use the pgf key pgfkeys{/pgf/number format/showpos}
and display the number with pgfmathprintnumber{i} (see page 952 of the 3.0.1a manual).
Update:
To have a symbol mu instead of the 0sigma, we can simply rewrite over the one that was written in the loop.
draw (4*1.227,-.2)node[yshift=-.35cm,fill=white,minimum width=7mm]{$mu$};
Foreach code:
begin{scope}[xshift=-1.cm, yshift=-2.cm]
pgfkeys{/pgf/number format/showpos}
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{pgfmathprintnumber{i}$sigma$}coordinate(i);
draw (4*1.227,-.2)node[yshift=-.35cm,fill=white,minimum width=7mm]{$mu$};
end{scope}
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
pgfkeys{/pgf/number format/showpos}
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{pgfmathprintnumber{i}$sigma$}coordinate(i);
end{scope}
end{tikzpicture}
end{frame}
end{document}
answered Dec 9 at 14:23
AndréC
7,57011440
1
Note that the OP wants amuinstead of0sigma. This is why I used anifnumstatement in my answer....
– marmot
Dec 9 at 14:41
@AndréC Thank you for your answer.
– Hany
Dec 9 at 14:55
1
Thanks, I just updated my answer.
– AndréC
Dec 9 at 14:55
add a comment |
1
1
1
Just use the pgf key pgfkeys{/pgf/number format/showpos}
and display the number with pgfmathprintnumber{i} (see page 952 of the 3.0.1a manual).
Update:
To have a symbol mu instead of the 0sigma, we can simply rewrite over the one that was written in the loop.
draw (4*1.227,-.2)node[yshift=-.35cm,fill=white,minimum width=7mm]{$mu$};
Foreach code:
begin{scope}[xshift=-1.cm, yshift=-2.cm]
pgfkeys{/pgf/number format/showpos}
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{pgfmathprintnumber{i}$sigma$}coordinate(i);
draw (4*1.227,-.2)node[yshift=-.35cm,fill=white,minimum width=7mm]{$mu$};
end{scope}
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
pgfkeys{/pgf/number format/showpos}
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{pgfmathprintnumber{i}$sigma$}coordinate(i);
end{scope}
end{tikzpicture}
end{frame}
end{document}
answered Dec 9 at 14:23
AndréC
7,57011440
Just use the pgf key pgfkeys{/pgf/number format/showpos}
and display the number with pgfmathprintnumber{i} (see page 952 of the 3.0.1a manual).
Update:
To have a symbol mu instead of the 0sigma, we can simply rewrite over the one that was written in the loop.
draw (4*1.227,-.2)node[yshift=-.35cm,fill=white,minimum width=7mm]{$mu$};
Foreach code:
begin{scope}[xshift=-1.cm, yshift=-2.cm]
pgfkeys{/pgf/number format/showpos}
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{pgfmathprintnumber{i}$sigma$}coordinate(i);
draw (4*1.227,-.2)node[yshift=-.35cm,fill=white,minimum width=7mm]{$mu$};
end{scope}
documentclass{beamer}
beamertemplatenavigationsymbolsempty
usepackage{verbatim}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
tikzset{pics/.cd,
curvea/.style n args={2}{code={
node [red] at (#1,#2) (begin){}
([shift={(0.:.2cm)}]begin.center) node (beginr){}
([shift={(30:4.cm)}]beginr.center) node (midtop){}
([shift={(-30:4.cm)}]midtop.center) node (end){}
([shift={(0.:.2cm)}]end.center) node (endr){}
;
}}}
begin{frame}[t]
frametitle{mu +sigma}
vspace {.6cm}
begin{tikzpicture}[scale=.86, transform shape]
draw [thick,-latex](0,0) -- (8.4,0) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.) -- (8.4,-2.) node [black, xshift=.3cm, yshift=0cm] {Z};
draw [thick,-latex](0,-2.5) -- (0,4);
pic at (0,0) {curvea={.246}{.2}};
draw[blue, very thick] ([shift={(-150.:.14cm)}]begin.center) to [out=10, in=10, looseness=.68] (beginr.center) to [out=10, in=180, looseness=.6] ([shift={(90:1.2cm)}]midtop.center) node (midtopnew){} to [out=0, in=170, looseness=.6] (end.center) to [out=170, in=170, looseness=.68] ([shift={(-30.:.14cm)}]endr.center) ([shift={(180:1.2cm)}]midtopnew.center) node (ml){} ([shift={(0:1.22cm)}]midtopnew.center) node (mr){};
draw [very thick, black] (midtopnew.center) -- (midtopnew.center|-0,0);
begin{scope}[xshift=-1.cm, yshift=-2.cm]
pgfkeys{/pgf/number format/showpos}
foreach[count=j] i in {-3,...,3}
draw[very thick] (j*1.227,.2) -- ++(0,-.4) node[yshift=-.35cm]{pgfmathprintnumber{i}$sigma$}coordinate(i);
end{scope}
end{tikzpicture}
end{frame}
end{document}
answered Dec 9 at 14:23
AndréC
7,57011440
edited Dec 9 at 14:54
answered Dec 9 at 14:23
AndréC
7,57011440
answered Dec 9 at 14:23
AndréC
7,57011440
answered Dec 9 at 14:23
AndréC
7,57011440
7,57011440
1
Note that the OP wants amuinstead of0sigma. This is why I used anifnumstatement in my answer....
– marmot
Dec 9 at 14:41
@AndréC Thank you for your answer.
– Hany
Dec 9 at 14:55
1
Thanks, I just updated my answer.
– AndréC
Dec 9 at 14:55
add a comment |
1
Note that the OP wants amuinstead of0sigma. This is why I used anifnumstatement in my answer....
– marmot
Dec 9 at 14:41
@AndréC Thank you for your answer.
– Hany
Dec 9 at 14:55
1
Thanks, I just updated my answer.
– AndréC
Dec 9 at 14:55
1
1
Note that the OP wants a
mu instead of 0sigma. This is why I used an ifnum statement in my answer....– marmot
Dec 9 at 14:41
Note that the OP wants a
mu instead of 0sigma. This is why I used an ifnum statement in my answer....– marmot
Dec 9 at 14:41
@AndréC Thank you for your answer.
– Hany
Dec 9 at 14:55
@AndréC Thank you for your answer.
– Hany
Dec 9 at 14:55
1
1
Thanks, I just updated my answer.
– AndréC
Dec 9 at 14:55
Thanks, I just updated my answer.
– AndréC
Dec 9 at 14:55
add a comment |
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