How to use two let variables in an if statement in swift
0
I am trying to code an if statement to display text on my label but I want to use two text field variables. It shows no error but when I press the button on the simulator or device the label still shows up blank.
I am just starting coding so I'm guessing it has an easy answer.
Here is my coding:
@IBOutlet var LblResult: UILabel!
@IBAction func Calculate(_ sender: UIButton)
{
let Variable1 = (Variable1.text! as NSString).floatValue
*//var 1 and 2 are text fields*
let Variable2 = (Variable2.text! as NSString).floatValue
if Variable1 > 15 && Variable2 < 30{
LblResult.text = "TEXT"
}
}
swift if-statement
edited Nov 16 at 4:51
rmaddy
238k27309375
asked Nov 16 at 3:02
Bpython
31
add a comment |
0
I am trying to code an if statement to display text on my label but I want to use two text field variables. It shows no error but when I press the button on the simulator or device the label still shows up blank.
I am just starting coding so I'm guessing it has an easy answer.
Here is my coding:
@IBOutlet var LblResult: UILabel!
@IBAction func Calculate(_ sender: UIButton)
{
let Variable1 = (Variable1.text! as NSString).floatValue
*//var 1 and 2 are text fields*
let Variable2 = (Variable2.text! as NSString).floatValue
if Variable1 > 15 && Variable2 < 30{
LblResult.text = "TEXT"
}
}
swift if-statement
edited Nov 16 at 4:51
rmaddy
238k27309375
asked Nov 16 at 3:02
Bpython
31
add a comment |
0
0
0
I am trying to code an if statement to display text on my label but I want to use two text field variables. It shows no error but when I press the button on the simulator or device the label still shows up blank.
I am just starting coding so I'm guessing it has an easy answer.
Here is my coding:
@IBOutlet var LblResult: UILabel!
@IBAction func Calculate(_ sender: UIButton)
{
let Variable1 = (Variable1.text! as NSString).floatValue
*//var 1 and 2 are text fields*
let Variable2 = (Variable2.text! as NSString).floatValue
if Variable1 > 15 && Variable2 < 30{
LblResult.text = "TEXT"
}
}
swift if-statement
edited Nov 16 at 4:51
rmaddy
238k27309375
asked Nov 16 at 3:02
Bpython
31
I am trying to code an if statement to display text on my label but I want to use two text field variables. It shows no error but when I press the button on the simulator or device the label still shows up blank.
I am just starting coding so I'm guessing it has an easy answer.
Here is my coding:
@IBOutlet var LblResult: UILabel!
@IBAction func Calculate(_ sender: UIButton)
{
let Variable1 = (Variable1.text! as NSString).floatValue
*//var 1 and 2 are text fields*
let Variable2 = (Variable2.text! as NSString).floatValue
if Variable1 > 15 && Variable2 < 30{
LblResult.text = "TEXT"
}
}
swift if-statement
swift if-statement
edited Nov 16 at 4:51
rmaddy
238k27309375
asked Nov 16 at 3:02
Bpython
31
edited Nov 16 at 4:51
rmaddy
238k27309375
asked Nov 16 at 3:02
Bpython
31
edited Nov 16 at 4:51
rmaddy
238k27309375
edited Nov 16 at 4:51
rmaddy
238k27309375
edited Nov 16 at 4:51
rmaddy
238k27309375
238k27309375
asked Nov 16 at 3:02
Bpython
31
asked Nov 16 at 3:02
Bpython
31
asked Nov 16 at 3:02
Bpython
31
31
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
You should be doing it like this in Swift.
if let text1 = CGFloat(variable1.text!), let text2 = CGFloat(variable2.text!), text1 > 15, text2 < 30 {
lblResult.text = "TEXT"
}
A few things to note
- variables should be in lowerCamelCase.
textfromUITextFieldcan be force-unwrapped. They always return at least "".- Use
Stringinstead ofNSStringin Swift.
answered Nov 16 at 3:33
Rakesha Shastri
6,83421232
Thank you so much! Works great!
– Bpython
Nov 16 at 19:29
add a comment |
1
You can try this:
// Using a guard statement is a safe way to unwrap optionals
guard let text1 = Variable1.text else { return }
guard let text2 = Variable2.text else { return }
if (Float(text1) > 15) && (Float(text2) < 30) {
LblResult.text = "TEXT"
}
answered Nov 16 at 19:29
droberson
271
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You should be doing it like this in Swift.
if let text1 = CGFloat(variable1.text!), let text2 = CGFloat(variable2.text!), text1 > 15, text2 < 30 {
lblResult.text = "TEXT"
}
A few things to note
- variables should be in lowerCamelCase.
textfromUITextFieldcan be force-unwrapped. They always return at least "".- Use
Stringinstead ofNSStringin Swift.
answered Nov 16 at 3:33
Rakesha Shastri
6,83421232
Thank you so much! Works great!
– Bpython
Nov 16 at 19:29
add a comment |
1
You should be doing it like this in Swift.
if let text1 = CGFloat(variable1.text!), let text2 = CGFloat(variable2.text!), text1 > 15, text2 < 30 {
lblResult.text = "TEXT"
}
A few things to note
- variables should be in lowerCamelCase.
textfromUITextFieldcan be force-unwrapped. They always return at least "".- Use
Stringinstead ofNSStringin Swift.
answered Nov 16 at 3:33
Rakesha Shastri
6,83421232
Thank you so much! Works great!
– Bpython
Nov 16 at 19:29
add a comment |
1
1
1
You should be doing it like this in Swift.
if let text1 = CGFloat(variable1.text!), let text2 = CGFloat(variable2.text!), text1 > 15, text2 < 30 {
lblResult.text = "TEXT"
}
A few things to note
- variables should be in lowerCamelCase.
textfromUITextFieldcan be force-unwrapped. They always return at least "".- Use
Stringinstead ofNSStringin Swift.
answered Nov 16 at 3:33
Rakesha Shastri
6,83421232
You should be doing it like this in Swift.
if let text1 = CGFloat(variable1.text!), let text2 = CGFloat(variable2.text!), text1 > 15, text2 < 30 {
lblResult.text = "TEXT"
}
A few things to note
- variables should be in lowerCamelCase.
textfromUITextFieldcan be force-unwrapped. They always return at least "".- Use
Stringinstead ofNSStringin Swift.
answered Nov 16 at 3:33
Rakesha Shastri
6,83421232
edited Nov 16 at 5:01
answered Nov 16 at 3:33
Rakesha Shastri
6,83421232
answered Nov 16 at 3:33
Rakesha Shastri
6,83421232
answered Nov 16 at 3:33
Rakesha Shastri
6,83421232
6,83421232
Thank you so much! Works great!
– Bpython
Nov 16 at 19:29
add a comment |
Thank you so much! Works great!
– Bpython
Nov 16 at 19:29
Thank you so much! Works great!
– Bpython
Nov 16 at 19:29
Thank you so much! Works great!
– Bpython
Nov 16 at 19:29
add a comment |
1
You can try this:
// Using a guard statement is a safe way to unwrap optionals
guard let text1 = Variable1.text else { return }
guard let text2 = Variable2.text else { return }
if (Float(text1) > 15) && (Float(text2) < 30) {
LblResult.text = "TEXT"
}
answered Nov 16 at 19:29
droberson
271
add a comment |
1
You can try this:
// Using a guard statement is a safe way to unwrap optionals
guard let text1 = Variable1.text else { return }
guard let text2 = Variable2.text else { return }
if (Float(text1) > 15) && (Float(text2) < 30) {
LblResult.text = "TEXT"
}
answered Nov 16 at 19:29
droberson
271
add a comment |
1
1
1
You can try this:
// Using a guard statement is a safe way to unwrap optionals
guard let text1 = Variable1.text else { return }
guard let text2 = Variable2.text else { return }
if (Float(text1) > 15) && (Float(text2) < 30) {
LblResult.text = "TEXT"
}
answered Nov 16 at 19:29
droberson
271
You can try this:
// Using a guard statement is a safe way to unwrap optionals
guard let text1 = Variable1.text else { return }
guard let text2 = Variable2.text else { return }
if (Float(text1) > 15) && (Float(text2) < 30) {
LblResult.text = "TEXT"
}
answered Nov 16 at 19:29
droberson
271
answered Nov 16 at 19:29
droberson
271
answered Nov 16 at 19:29
droberson
271
answered Nov 16 at 19:29
droberson
271
271
add a comment |
add a comment |
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