Gradient Descent: Cost Function











up vote
2
down vote

favorite












I'm trying to implement the gradient descent method for the problem of minimising the following function:



$$f(x) = frac{1}{2}(x-m)^{T}A(x-m)-sumlimits_{i=1}^nlogleft(x_i^{2}right),$$



where $x in R^n$ is a vector; $m in R^n$ is a fixed vector; and $A$ is a fixed positive definite matrix.



The only applications of gradient descent I have come across is for linear regression! So, as a starting point for helping me to solve this, I'd like to know in what situations this cost function would be applied. Does anyone out there recognise it?










share|cite|improve this question
























  • Your objective function is a special case of a quadratic cost function with a regularization term that uses the $log$ of the coefficients. $L_1$ or $L_2$ regularization cost functions are more typical, but you can impose a gentler penalty with a $log$ cost function.
    – Aditya Dua
    Nov 12 at 22:25






  • 1




    Thanks @AdityaDua. This response has been useful to me
    – Barton
    Nov 14 at 21:52












  • @AdityaDua do you know what the role of the matrix A would be in this cost function?
    – Barton
    2 days ago












  • I'd suggest reading up on "generalised least squares". The matrix A allows you to deal with correlated errors and unequal variances (Heteroscedasticity).
    – Aditya Dua
    2 days ago















up vote
2
down vote

favorite












I'm trying to implement the gradient descent method for the problem of minimising the following function:



$$f(x) = frac{1}{2}(x-m)^{T}A(x-m)-sumlimits_{i=1}^nlogleft(x_i^{2}right),$$



where $x in R^n$ is a vector; $m in R^n$ is a fixed vector; and $A$ is a fixed positive definite matrix.



The only applications of gradient descent I have come across is for linear regression! So, as a starting point for helping me to solve this, I'd like to know in what situations this cost function would be applied. Does anyone out there recognise it?










share|cite|improve this question
























  • Your objective function is a special case of a quadratic cost function with a regularization term that uses the $log$ of the coefficients. $L_1$ or $L_2$ regularization cost functions are more typical, but you can impose a gentler penalty with a $log$ cost function.
    – Aditya Dua
    Nov 12 at 22:25






  • 1




    Thanks @AdityaDua. This response has been useful to me
    – Barton
    Nov 14 at 21:52












  • @AdityaDua do you know what the role of the matrix A would be in this cost function?
    – Barton
    2 days ago












  • I'd suggest reading up on "generalised least squares". The matrix A allows you to deal with correlated errors and unequal variances (Heteroscedasticity).
    – Aditya Dua
    2 days ago













up vote
2
down vote

favorite









up vote
2
down vote

favorite











I'm trying to implement the gradient descent method for the problem of minimising the following function:



$$f(x) = frac{1}{2}(x-m)^{T}A(x-m)-sumlimits_{i=1}^nlogleft(x_i^{2}right),$$



where $x in R^n$ is a vector; $m in R^n$ is a fixed vector; and $A$ is a fixed positive definite matrix.



The only applications of gradient descent I have come across is for linear regression! So, as a starting point for helping me to solve this, I'd like to know in what situations this cost function would be applied. Does anyone out there recognise it?










share|cite|improve this question















I'm trying to implement the gradient descent method for the problem of minimising the following function:



$$f(x) = frac{1}{2}(x-m)^{T}A(x-m)-sumlimits_{i=1}^nlogleft(x_i^{2}right),$$



where $x in R^n$ is a vector; $m in R^n$ is a fixed vector; and $A$ is a fixed positive definite matrix.



The only applications of gradient descent I have come across is for linear regression! So, as a starting point for helping me to solve this, I'd like to know in what situations this cost function would be applied. Does anyone out there recognise it?







gradient-descent






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 13 at 13:31









Davide Giraudo

123k16149253




123k16149253










asked Nov 12 at 20:13









Barton

133




133












  • Your objective function is a special case of a quadratic cost function with a regularization term that uses the $log$ of the coefficients. $L_1$ or $L_2$ regularization cost functions are more typical, but you can impose a gentler penalty with a $log$ cost function.
    – Aditya Dua
    Nov 12 at 22:25






  • 1




    Thanks @AdityaDua. This response has been useful to me
    – Barton
    Nov 14 at 21:52












  • @AdityaDua do you know what the role of the matrix A would be in this cost function?
    – Barton
    2 days ago












  • I'd suggest reading up on "generalised least squares". The matrix A allows you to deal with correlated errors and unequal variances (Heteroscedasticity).
    – Aditya Dua
    2 days ago


















  • Your objective function is a special case of a quadratic cost function with a regularization term that uses the $log$ of the coefficients. $L_1$ or $L_2$ regularization cost functions are more typical, but you can impose a gentler penalty with a $log$ cost function.
    – Aditya Dua
    Nov 12 at 22:25






  • 1




    Thanks @AdityaDua. This response has been useful to me
    – Barton
    Nov 14 at 21:52












  • @AdityaDua do you know what the role of the matrix A would be in this cost function?
    – Barton
    2 days ago












  • I'd suggest reading up on "generalised least squares". The matrix A allows you to deal with correlated errors and unequal variances (Heteroscedasticity).
    – Aditya Dua
    2 days ago
















Your objective function is a special case of a quadratic cost function with a regularization term that uses the $log$ of the coefficients. $L_1$ or $L_2$ regularization cost functions are more typical, but you can impose a gentler penalty with a $log$ cost function.
– Aditya Dua
Nov 12 at 22:25




Your objective function is a special case of a quadratic cost function with a regularization term that uses the $log$ of the coefficients. $L_1$ or $L_2$ regularization cost functions are more typical, but you can impose a gentler penalty with a $log$ cost function.
– Aditya Dua
Nov 12 at 22:25




1




1




Thanks @AdityaDua. This response has been useful to me
– Barton
Nov 14 at 21:52






Thanks @AdityaDua. This response has been useful to me
– Barton
Nov 14 at 21:52














@AdityaDua do you know what the role of the matrix A would be in this cost function?
– Barton
2 days ago






@AdityaDua do you know what the role of the matrix A would be in this cost function?
– Barton
2 days ago














I'd suggest reading up on "generalised least squares". The matrix A allows you to deal with correlated errors and unequal variances (Heteroscedasticity).
– Aditya Dua
2 days ago




I'd suggest reading up on "generalised least squares". The matrix A allows you to deal with correlated errors and unequal variances (Heteroscedasticity).
– Aditya Dua
2 days ago










1 Answer
1






active

oldest

votes

















up vote
0
down vote













From the question, we have that f is a convex quadratic function



$$f(x) = frac{1}{2}(x-m)^{mathrm T} mathrm A (x-m)-sumlimits_{i=1}^nlogleft(x_i^{2}right),$$



where $x in R^n$ is a vector; $m in R^n$ is a fixed vector, and $A$ is a fixed positive definite matrix (symmetric and positive semidefinite).



$$nabla f ( x) = frac{mathrm T+1}{2} mathrm A (x-m)^{mathrm T}-sumlimits_{i=1}^nleft(frac{2x}{x_i^{2}ln(10)}right)$$



Using gradient descent with step $mu$,



$$ x_{k+1} = x_k - mu nabla f ( x_k)$$



Choose $mu$ such that $f(x_k) < f(x_{k+1}) $,then do a loop until we find $x^{*}: f(x^{*}_k) - f(x^{*}_{k+1}) sim 0$



This is a general way to take gradient descent for a convex quadratic function in n-dimensional space. Hope it is helpful.






share|cite|improve this answer










New contributor




AnNg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.


















    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "69"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














     

    draft saved


    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2995797%2fgradient-descent-cost-function%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    From the question, we have that f is a convex quadratic function



    $$f(x) = frac{1}{2}(x-m)^{mathrm T} mathrm A (x-m)-sumlimits_{i=1}^nlogleft(x_i^{2}right),$$



    where $x in R^n$ is a vector; $m in R^n$ is a fixed vector, and $A$ is a fixed positive definite matrix (symmetric and positive semidefinite).



    $$nabla f ( x) = frac{mathrm T+1}{2} mathrm A (x-m)^{mathrm T}-sumlimits_{i=1}^nleft(frac{2x}{x_i^{2}ln(10)}right)$$



    Using gradient descent with step $mu$,



    $$ x_{k+1} = x_k - mu nabla f ( x_k)$$



    Choose $mu$ such that $f(x_k) < f(x_{k+1}) $,then do a loop until we find $x^{*}: f(x^{*}_k) - f(x^{*}_{k+1}) sim 0$



    This is a general way to take gradient descent for a convex quadratic function in n-dimensional space. Hope it is helpful.






    share|cite|improve this answer










    New contributor




    AnNg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      0
      down vote













      From the question, we have that f is a convex quadratic function



      $$f(x) = frac{1}{2}(x-m)^{mathrm T} mathrm A (x-m)-sumlimits_{i=1}^nlogleft(x_i^{2}right),$$



      where $x in R^n$ is a vector; $m in R^n$ is a fixed vector, and $A$ is a fixed positive definite matrix (symmetric and positive semidefinite).



      $$nabla f ( x) = frac{mathrm T+1}{2} mathrm A (x-m)^{mathrm T}-sumlimits_{i=1}^nleft(frac{2x}{x_i^{2}ln(10)}right)$$



      Using gradient descent with step $mu$,



      $$ x_{k+1} = x_k - mu nabla f ( x_k)$$



      Choose $mu$ such that $f(x_k) < f(x_{k+1}) $,then do a loop until we find $x^{*}: f(x^{*}_k) - f(x^{*}_{k+1}) sim 0$



      This is a general way to take gradient descent for a convex quadratic function in n-dimensional space. Hope it is helpful.






      share|cite|improve this answer










      New contributor




      AnNg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















        up vote
        0
        down vote










        up vote
        0
        down vote









        From the question, we have that f is a convex quadratic function



        $$f(x) = frac{1}{2}(x-m)^{mathrm T} mathrm A (x-m)-sumlimits_{i=1}^nlogleft(x_i^{2}right),$$



        where $x in R^n$ is a vector; $m in R^n$ is a fixed vector, and $A$ is a fixed positive definite matrix (symmetric and positive semidefinite).



        $$nabla f ( x) = frac{mathrm T+1}{2} mathrm A (x-m)^{mathrm T}-sumlimits_{i=1}^nleft(frac{2x}{x_i^{2}ln(10)}right)$$



        Using gradient descent with step $mu$,



        $$ x_{k+1} = x_k - mu nabla f ( x_k)$$



        Choose $mu$ such that $f(x_k) < f(x_{k+1}) $,then do a loop until we find $x^{*}: f(x^{*}_k) - f(x^{*}_{k+1}) sim 0$



        This is a general way to take gradient descent for a convex quadratic function in n-dimensional space. Hope it is helpful.






        share|cite|improve this answer










        New contributor




        AnNg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        From the question, we have that f is a convex quadratic function



        $$f(x) = frac{1}{2}(x-m)^{mathrm T} mathrm A (x-m)-sumlimits_{i=1}^nlogleft(x_i^{2}right),$$



        where $x in R^n$ is a vector; $m in R^n$ is a fixed vector, and $A$ is a fixed positive definite matrix (symmetric and positive semidefinite).



        $$nabla f ( x) = frac{mathrm T+1}{2} mathrm A (x-m)^{mathrm T}-sumlimits_{i=1}^nleft(frac{2x}{x_i^{2}ln(10)}right)$$



        Using gradient descent with step $mu$,



        $$ x_{k+1} = x_k - mu nabla f ( x_k)$$



        Choose $mu$ such that $f(x_k) < f(x_{k+1}) $,then do a loop until we find $x^{*}: f(x^{*}_k) - f(x^{*}_{k+1}) sim 0$



        This is a general way to take gradient descent for a convex quadratic function in n-dimensional space. Hope it is helpful.







        share|cite|improve this answer










        New contributor




        AnNg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        share|cite|improve this answer



        share|cite|improve this answer








        edited yesterday





















        New contributor




        AnNg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        answered yesterday









        AnNg

        375




        375




        New contributor




        AnNg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        New contributor





        AnNg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        AnNg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






























             

            draft saved


            draft discarded



















































             


            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2995797%2fgradient-descent-cost-function%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            mysqli_query(): Empty query in /home/lucindabrummitt/public_html/blog/wp-includes/wp-db.php on line 1924

            How to change which sound is reproduced for terminal bell?

            Can I use Tabulator js library in my java Spring + Thymeleaf project?