Solving a system of linear ODEs subject to specific conditions
I know this question has been asked and answered before, but my version of the question is a bit easier. Also, I've my exam in a few hours, so please don't close this question. Thanks in advance!
$x_0'=-ax_0+bx_1$
$x_1'=ax_0-(a+b)x_1+2bx_2$
$x_2'=ax_1-2bx_2$
Given that $x_0+x_1+x_2=1$ always. Also, initially, $x_0=1$.
Usually, the previous line is not there given for questions already asked. I guess it will simplify it sufficiently. But, I was unable to solve it. Please help. Thanks
differential-equations
asked Nov 20 at 3:52
Ankit Kumar
1,601119
add a comment |
I know this question has been asked and answered before, but my version of the question is a bit easier. Also, I've my exam in a few hours, so please don't close this question. Thanks in advance!
$x_0'=-ax_0+bx_1$
$x_1'=ax_0-(a+b)x_1+2bx_2$
$x_2'=ax_1-2bx_2$
Given that $x_0+x_1+x_2=1$ always. Also, initially, $x_0=1$.
Usually, the previous line is not there given for questions already asked. I guess it will simplify it sufficiently. But, I was unable to solve it. Please help. Thanks
differential-equations
asked Nov 20 at 3:52
Ankit Kumar
1,601119
add a comment |
I know this question has been asked and answered before, but my version of the question is a bit easier. Also, I've my exam in a few hours, so please don't close this question. Thanks in advance!
$x_0'=-ax_0+bx_1$
$x_1'=ax_0-(a+b)x_1+2bx_2$
$x_2'=ax_1-2bx_2$
Given that $x_0+x_1+x_2=1$ always. Also, initially, $x_0=1$.
Usually, the previous line is not there given for questions already asked. I guess it will simplify it sufficiently. But, I was unable to solve it. Please help. Thanks
differential-equations
asked Nov 20 at 3:52
Ankit Kumar
1,601119
I know this question has been asked and answered before, but my version of the question is a bit easier. Also, I've my exam in a few hours, so please don't close this question. Thanks in advance!
$x_0'=-ax_0+bx_1$
$x_1'=ax_0-(a+b)x_1+2bx_2$
$x_2'=ax_1-2bx_2$
Given that $x_0+x_1+x_2=1$ always. Also, initially, $x_0=1$.
Usually, the previous line is not there given for questions already asked. I guess it will simplify it sufficiently. But, I was unable to solve it. Please help. Thanks
differential-equations
differential-equations
asked Nov 20 at 3:52
Ankit Kumar
1,601119
asked Nov 20 at 3:52
Ankit Kumar
1,601119
asked Nov 20 at 3:52
Ankit Kumar
1,601119
asked Nov 20 at 3:52
Ankit Kumar
1,601119
asked Nov 20 at 3:52
Ankit Kumar
1,601119
1,601119
add a comment |
add a comment |
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