QGIS: use geometry from different layer in symbology expression
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited Mar 2 at 21:25
Matthias Kuhn
19k14890
asked Mar 2 at 21:17
CaptainAhabCaptainAhab
807
add a comment |
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited Mar 2 at 21:25
Matthias Kuhn
19k14890
asked Mar 2 at 21:17
CaptainAhabCaptainAhab
807
add a comment |
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited Mar 2 at 21:25
Matthias Kuhn
19k14890
asked Mar 2 at 21:17
CaptainAhabCaptainAhab
807
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
qgis symbology z-value
edited Mar 2 at 21:25
Matthias Kuhn
19k14890
asked Mar 2 at 21:17
CaptainAhabCaptainAhab
807
edited Mar 2 at 21:25
Matthias Kuhn
19k14890
asked Mar 2 at 21:17
CaptainAhabCaptainAhab
807
edited Mar 2 at 21:25
Matthias Kuhn
19k14890
edited Mar 2 at 21:25
Matthias Kuhn
19k14890
edited Mar 2 at 21:25
Matthias Kuhn
19k14890
19k14890
asked Mar 2 at 21:17
CaptainAhabCaptainAhab
807
asked Mar 2 at 21:17
CaptainAhabCaptainAhab
807
asked Mar 2 at 21:17
CaptainAhabCaptainAhab
807
807
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered Mar 2 at 22:02
VitruviusVitruvius
489210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
Mar 2 at 23:41
Nope it wouldn't.
– Vitruvius
Mar 3 at 5:28
That's surprising... Did you try?
– Matthias Kuhn
Mar 3 at 7:04
Is it possible that this doesn' t work in rule-based symbology? I can get it work in a test environment, but not in my project. I used if( within($geometry,geometry(get_feature('bronpolygonen_4a087198_dafa_4185_a358_d410ed1a980e','TYPECTRL','MONITOR HOOFD VERLICHT'))), 1, 0 )
– CaptainAhab
Mar 4 at 16:54
Or is it possible that my dataset is just to big (626000 features)?
– CaptainAhab
Mar 4 at 17:29
|
show 1 more comment
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered Mar 2 at 22:02
VitruviusVitruvius
489210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
Mar 2 at 23:41
Nope it wouldn't.
– Vitruvius
Mar 3 at 5:28
That's surprising... Did you try?
– Matthias Kuhn
Mar 3 at 7:04
Is it possible that this doesn' t work in rule-based symbology? I can get it work in a test environment, but not in my project. I used if( within($geometry,geometry(get_feature('bronpolygonen_4a087198_dafa_4185_a358_d410ed1a980e','TYPECTRL','MONITOR HOOFD VERLICHT'))), 1, 0 )
– CaptainAhab
Mar 4 at 16:54
Or is it possible that my dataset is just to big (626000 features)?
– CaptainAhab
Mar 4 at 17:29
|
show 1 more comment
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered Mar 2 at 22:02
VitruviusVitruvius
489210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
Mar 2 at 23:41
Nope it wouldn't.
– Vitruvius
Mar 3 at 5:28
That's surprising... Did you try?
– Matthias Kuhn
Mar 3 at 7:04
Is it possible that this doesn' t work in rule-based symbology? I can get it work in a test environment, but not in my project. I used if( within($geometry,geometry(get_feature('bronpolygonen_4a087198_dafa_4185_a358_d410ed1a980e','TYPECTRL','MONITOR HOOFD VERLICHT'))), 1, 0 )
– CaptainAhab
Mar 4 at 16:54
Or is it possible that my dataset is just to big (626000 features)?
– CaptainAhab
Mar 4 at 17:29
|
show 1 more comment
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered Mar 2 at 22:02
VitruviusVitruvius
489210
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered Mar 2 at 22:02
VitruviusVitruvius
489210
edited Mar 2 at 23:19
answered Mar 2 at 22:02
VitruviusVitruvius
489210
answered Mar 2 at 22:02
VitruviusVitruvius
489210
answered Mar 2 at 22:02
VitruviusVitruvius
489210
489210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
Mar 2 at 23:41
Nope it wouldn't.
– Vitruvius
Mar 3 at 5:28
That's surprising... Did you try?
– Matthias Kuhn
Mar 3 at 7:04
Is it possible that this doesn' t work in rule-based symbology? I can get it work in a test environment, but not in my project. I used if( within($geometry,geometry(get_feature('bronpolygonen_4a087198_dafa_4185_a358_d410ed1a980e','TYPECTRL','MONITOR HOOFD VERLICHT'))), 1, 0 )
– CaptainAhab
Mar 4 at 16:54
Or is it possible that my dataset is just to big (626000 features)?
– CaptainAhab
Mar 4 at 17:29
|
show 1 more comment
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
Mar 2 at 23:41
Nope it wouldn't.
– Vitruvius
Mar 3 at 5:28
That's surprising... Did you try?
– Matthias Kuhn
Mar 3 at 7:04
Is it possible that this doesn' t work in rule-based symbology? I can get it work in a test environment, but not in my project. I used if( within($geometry,geometry(get_feature('bronpolygonen_4a087198_dafa_4185_a358_d410ed1a980e','TYPECTRL','MONITOR HOOFD VERLICHT'))), 1, 0 )
– CaptainAhab
Mar 4 at 16:54
Or is it possible that my dataset is just to big (626000 features)?
– CaptainAhab
Mar 4 at 17:29
Good answer! Would it work to drop the if-part completely and just use
within(...)?– Matthias Kuhn
Mar 2 at 23:41
Good answer! Would it work to drop the if-part completely and just use
within(...)?– Matthias Kuhn
Mar 2 at 23:41
Nope it wouldn't.
– Vitruvius
Mar 3 at 5:28
Nope it wouldn't.
– Vitruvius
Mar 3 at 5:28
That's surprising... Did you try?
– Matthias Kuhn
Mar 3 at 7:04
That's surprising... Did you try?
– Matthias Kuhn
Mar 3 at 7:04
Is it possible that this doesn' t work in rule-based symbology? I can get it work in a test environment, but not in my project. I used if( within($geometry,geometry(get_feature('bronpolygonen_4a087198_dafa_4185_a358_d410ed1a980e','TYPECTRL','MONITOR HOOFD VERLICHT'))), 1, 0 )
– CaptainAhab
Mar 4 at 16:54
Is it possible that this doesn' t work in rule-based symbology? I can get it work in a test environment, but not in my project. I used if( within($geometry,geometry(get_feature('bronpolygonen_4a087198_dafa_4185_a358_d410ed1a980e','TYPECTRL','MONITOR HOOFD VERLICHT'))), 1, 0 )
– CaptainAhab
Mar 4 at 16:54
Or is it possible that my dataset is just to big (626000 features)?
– CaptainAhab
Mar 4 at 17:29
Or is it possible that my dataset is just to big (626000 features)?
– CaptainAhab
Mar 4 at 17:29
|
show 1 more comment
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