Executing a python script using Flask [duplicate]












-4
















This question already has an answer here:




  • Flask view raises TypeError: 'bool' object is not callable

    1 answer




I trying to executing a Python script through Flask.



I wrote below python code to execute another python script.



from flask import Flask
import subprocess

app = Flask(__name__)

@app.route("/")
def home():
subprocess.call("/home/tech/Downloads/labelme-master/labelme/main.py 1", shell=True)
#return "Hello, World!"

if __name__ == "__main__":
app.run(debug=True)


But unfortunately when I run above python code and check the 127.0.0.1:5000 It's giving this error in browser :



TypeError: The view function did not return a valid response. The function either returned None or ended without a return statement.


Any solution?



My ultimate goal is to open a python script via HTML page's Button.










share|improve this question













marked as duplicate by davidism flask
Users with the  flask badge can single-handedly close flask questions as duplicates and reopen them as needed.

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Nov 21 '18 at 13:29


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.























    -4
















    This question already has an answer here:




    • Flask view raises TypeError: 'bool' object is not callable

      1 answer




    I trying to executing a Python script through Flask.



    I wrote below python code to execute another python script.



    from flask import Flask
    import subprocess

    app = Flask(__name__)

    @app.route("/")
    def home():
    subprocess.call("/home/tech/Downloads/labelme-master/labelme/main.py 1", shell=True)
    #return "Hello, World!"

    if __name__ == "__main__":
    app.run(debug=True)


    But unfortunately when I run above python code and check the 127.0.0.1:5000 It's giving this error in browser :



    TypeError: The view function did not return a valid response. The function either returned None or ended without a return statement.


    Any solution?



    My ultimate goal is to open a python script via HTML page's Button.










    share|improve this question













    marked as duplicate by davidism flask
    Users with the  flask badge can single-handedly close flask questions as duplicates and reopen them as needed.

    StackExchange.ready(function() {
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    $hover.hover(
    function() {
    $hover.showInfoMessage('', {
    messageElement: $msg.clone().show(),
    transient: false,
    position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
    dismissable: false,
    relativeToBody: true
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    Nov 21 '18 at 13:29


    This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.





















      -4












      -4








      -4









      This question already has an answer here:




      • Flask view raises TypeError: 'bool' object is not callable

        1 answer




      I trying to executing a Python script through Flask.



      I wrote below python code to execute another python script.



      from flask import Flask
      import subprocess

      app = Flask(__name__)

      @app.route("/")
      def home():
      subprocess.call("/home/tech/Downloads/labelme-master/labelme/main.py 1", shell=True)
      #return "Hello, World!"

      if __name__ == "__main__":
      app.run(debug=True)


      But unfortunately when I run above python code and check the 127.0.0.1:5000 It's giving this error in browser :



      TypeError: The view function did not return a valid response. The function either returned None or ended without a return statement.


      Any solution?



      My ultimate goal is to open a python script via HTML page's Button.










      share|improve this question















      This question already has an answer here:




      • Flask view raises TypeError: 'bool' object is not callable

        1 answer




      I trying to executing a Python script through Flask.



      I wrote below python code to execute another python script.



      from flask import Flask
      import subprocess

      app = Flask(__name__)

      @app.route("/")
      def home():
      subprocess.call("/home/tech/Downloads/labelme-master/labelme/main.py 1", shell=True)
      #return "Hello, World!"

      if __name__ == "__main__":
      app.run(debug=True)


      But unfortunately when I run above python code and check the 127.0.0.1:5000 It's giving this error in browser :



      TypeError: The view function did not return a valid response. The function either returned None or ended without a return statement.


      Any solution?



      My ultimate goal is to open a python script via HTML page's Button.





      This question already has an answer here:




      • Flask view raises TypeError: 'bool' object is not callable

        1 answer








      python flask






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 21 '18 at 6:45









      dishcodedishcode

      86




      86




      marked as duplicate by davidism flask
      Users with the  flask badge can single-handedly close flask questions as duplicates and reopen them as needed.

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      $hover.hover(
      function() {
      $hover.showInfoMessage('', {
      messageElement: $msg.clone().show(),
      transient: false,
      position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
      dismissable: false,
      relativeToBody: true
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      Nov 21 '18 at 13:29


      This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.









      marked as duplicate by davidism flask
      Users with the  flask badge can single-handedly close flask questions as duplicates and reopen them as needed.

      StackExchange.ready(function() {
      if (StackExchange.options.isMobile) return;

      $('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
      var $hover = $(this).addClass('hover-bound'),
      $msg = $hover.siblings('.dupe-hammer-message');

      $hover.hover(
      function() {
      $hover.showInfoMessage('', {
      messageElement: $msg.clone().show(),
      transient: false,
      position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
      dismissable: false,
      relativeToBody: true
      });
      },
      function() {
      StackExchange.helpers.removeMessages();
      }
      );
      });
      });
      Nov 21 '18 at 13:29


      This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.


























          1 Answer
          1






          active

          oldest

          votes


















          0














          As a response, you have to return from the function. so you can do like this



          from flask import Flask
          import subprocess

          app = Flask(__name__)

          @app.route("/")
          def home():
          subprocess.call("python /home/tech/Downloads/labelme-master/labelme/main.py 1", shell=True)
          return "ok"
          if __name__ == "__main__":
          app.run(debug=True)





          share|improve this answer


























          • any idea how to run above python script using html Button?

            – dishcode
            Nov 21 '18 at 7:00











          • You can make ajax call from javascript

            – Ram
            Nov 21 '18 at 7:09


















          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          As a response, you have to return from the function. so you can do like this



          from flask import Flask
          import subprocess

          app = Flask(__name__)

          @app.route("/")
          def home():
          subprocess.call("python /home/tech/Downloads/labelme-master/labelme/main.py 1", shell=True)
          return "ok"
          if __name__ == "__main__":
          app.run(debug=True)





          share|improve this answer


























          • any idea how to run above python script using html Button?

            – dishcode
            Nov 21 '18 at 7:00











          • You can make ajax call from javascript

            – Ram
            Nov 21 '18 at 7:09
















          0














          As a response, you have to return from the function. so you can do like this



          from flask import Flask
          import subprocess

          app = Flask(__name__)

          @app.route("/")
          def home():
          subprocess.call("python /home/tech/Downloads/labelme-master/labelme/main.py 1", shell=True)
          return "ok"
          if __name__ == "__main__":
          app.run(debug=True)





          share|improve this answer


























          • any idea how to run above python script using html Button?

            – dishcode
            Nov 21 '18 at 7:00











          • You can make ajax call from javascript

            – Ram
            Nov 21 '18 at 7:09














          0












          0








          0







          As a response, you have to return from the function. so you can do like this



          from flask import Flask
          import subprocess

          app = Flask(__name__)

          @app.route("/")
          def home():
          subprocess.call("python /home/tech/Downloads/labelme-master/labelme/main.py 1", shell=True)
          return "ok"
          if __name__ == "__main__":
          app.run(debug=True)





          share|improve this answer















          As a response, you have to return from the function. so you can do like this



          from flask import Flask
          import subprocess

          app = Flask(__name__)

          @app.route("/")
          def home():
          subprocess.call("python /home/tech/Downloads/labelme-master/labelme/main.py 1", shell=True)
          return "ok"
          if __name__ == "__main__":
          app.run(debug=True)






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 21 '18 at 7:05

























          answered Nov 21 '18 at 6:51









          RamRam

          385112




          385112













          • any idea how to run above python script using html Button?

            – dishcode
            Nov 21 '18 at 7:00











          • You can make ajax call from javascript

            – Ram
            Nov 21 '18 at 7:09



















          • any idea how to run above python script using html Button?

            – dishcode
            Nov 21 '18 at 7:00











          • You can make ajax call from javascript

            – Ram
            Nov 21 '18 at 7:09

















          any idea how to run above python script using html Button?

          – dishcode
          Nov 21 '18 at 7:00





          any idea how to run above python script using html Button?

          – dishcode
          Nov 21 '18 at 7:00













          You can make ajax call from javascript

          – Ram
          Nov 21 '18 at 7:09





          You can make ajax call from javascript

          – Ram
          Nov 21 '18 at 7:09





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