Coordinates unit in pt although default is cm in TikZ












3















As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm by default.



When I extract the coordinates, I was expecting the unit as cm. But TikZ shows the unit in the coordinate as pt.



How does TikZ determine the unit of measure in a coordinate if no unit is specified.



MWE:



documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}

newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}

begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);

draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);

node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {(XCoord,YCoord)};
end{tikzpicture}

end{document}


enter image description here










share|improve this question























  • Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579

    – barbara beeton
    Feb 28 at 3:33











  • Barbara I would like to know the default unit of measure when unit of measure is not mentioned

    – subham soni
    Feb 28 at 3:35






  • 1





    Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .

    – marmot
    Feb 28 at 3:38













  • How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?

    – zyy
    Feb 28 at 3:39











  • @zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)

    – marmot
    Feb 28 at 3:41
















3















As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm by default.



When I extract the coordinates, I was expecting the unit as cm. But TikZ shows the unit in the coordinate as pt.



How does TikZ determine the unit of measure in a coordinate if no unit is specified.



MWE:



documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}

newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}

begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);

draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);

node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {(XCoord,YCoord)};
end{tikzpicture}

end{document}


enter image description here










share|improve this question























  • Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579

    – barbara beeton
    Feb 28 at 3:33











  • Barbara I would like to know the default unit of measure when unit of measure is not mentioned

    – subham soni
    Feb 28 at 3:35






  • 1





    Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .

    – marmot
    Feb 28 at 3:38













  • How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?

    – zyy
    Feb 28 at 3:39











  • @zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)

    – marmot
    Feb 28 at 3:41














3












3








3








As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm by default.



When I extract the coordinates, I was expecting the unit as cm. But TikZ shows the unit in the coordinate as pt.



How does TikZ determine the unit of measure in a coordinate if no unit is specified.



MWE:



documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}

newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}

begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);

draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);

node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {(XCoord,YCoord)};
end{tikzpicture}

end{document}


enter image description here










share|improve this question














As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm by default.



When I extract the coordinates, I was expecting the unit as cm. But TikZ shows the unit in the coordinate as pt.



How does TikZ determine the unit of measure in a coordinate if no unit is specified.



MWE:



documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}

newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}

begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);

draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);

node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {(XCoord,YCoord)};
end{tikzpicture}

end{document}


enter image description here







tikz-pgf unit-of-measure






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Feb 28 at 3:10









subham sonisubham soni

4,10382981




4,10382981













  • Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579

    – barbara beeton
    Feb 28 at 3:33











  • Barbara I would like to know the default unit of measure when unit of measure is not mentioned

    – subham soni
    Feb 28 at 3:35






  • 1





    Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .

    – marmot
    Feb 28 at 3:38













  • How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?

    – zyy
    Feb 28 at 3:39











  • @zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)

    – marmot
    Feb 28 at 3:41



















  • Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579

    – barbara beeton
    Feb 28 at 3:33











  • Barbara I would like to know the default unit of measure when unit of measure is not mentioned

    – subham soni
    Feb 28 at 3:35






  • 1





    Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .

    – marmot
    Feb 28 at 3:38













  • How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?

    – zyy
    Feb 28 at 3:39











  • @zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)

    – marmot
    Feb 28 at 3:41

















Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579

– barbara beeton
Feb 28 at 3:33





Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579

– barbara beeton
Feb 28 at 3:33













Barbara I would like to know the default unit of measure when unit of measure is not mentioned

– subham soni
Feb 28 at 3:35





Barbara I would like to know the default unit of measure when unit of measure is not mentioned

– subham soni
Feb 28 at 3:35




1




1





Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .

– marmot
Feb 28 at 3:38







Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .

– marmot
Feb 28 at 3:38















How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?

– zyy
Feb 28 at 3:39





How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?

– zyy
Feb 28 at 3:39













@zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)

– marmot
Feb 28 at 3:41





@zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)

– marmot
Feb 28 at 3:41










1 Answer
1






active

oldest

votes


















4














You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm or its inverse. (If that's not what you're after, I will be happy to remove the post.)



documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}

newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}

begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);

draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);

node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {%
(pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%
pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};
end{tikzpicture}
end{document}


enter image description here






share|improve this answer























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    1 Answer
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    active

    oldest

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    active

    oldest

    votes









    4














    You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm or its inverse. (If that's not what you're after, I will be happy to remove the post.)



    documentclass{article}
    usepackage{tikz}
    usetikzlibrary{decorations.pathmorphing}
    usetikzlibrary{decorations.markings}
    usetikzlibrary{calc}
    usetikzlibrary{positioning}
    tikzset{zigzag/.style={decorate,decoration=zigzag}}
    begin{document}

    newdimenXCoord
    newdimenYCoord
    newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}

    begin{tikzpicture}
    coordinate (c) at (0,-2);
    coordinate (d) at (4,-2);
    coordinate (e) at (2,-4);
    draw[thick,red,zigzag,postaction={
    decoration={
    markings,
    mark=at position 0.7 with { coordinate (x); },
    mark=at position 0.5 with { coordinate (singularity); },
    },
    decorate
    }] (-2,0) coordinate(a) -- (2,0) coordinate(b);

    draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
    draw[thick,postaction={
    decoration={
    markings,
    mark = at position 0.7 with coordinate (y);
    },
    decorate
    }] (a) -- (c);
    draw[thick,red,dashed] (x) -- (y);

    node[above = 10ex of singularity,red] (sn) {singularity};
    draw[red,->] (sn) -- ($(singularity)+(0,1)$);
    ExtractCoordinate{x};
    node[above] at (XCoord,YCoord) {%
    (pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%
    pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer




























      4














      You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm or its inverse. (If that's not what you're after, I will be happy to remove the post.)



      documentclass{article}
      usepackage{tikz}
      usetikzlibrary{decorations.pathmorphing}
      usetikzlibrary{decorations.markings}
      usetikzlibrary{calc}
      usetikzlibrary{positioning}
      tikzset{zigzag/.style={decorate,decoration=zigzag}}
      begin{document}

      newdimenXCoord
      newdimenYCoord
      newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}

      begin{tikzpicture}
      coordinate (c) at (0,-2);
      coordinate (d) at (4,-2);
      coordinate (e) at (2,-4);
      draw[thick,red,zigzag,postaction={
      decoration={
      markings,
      mark=at position 0.7 with { coordinate (x); },
      mark=at position 0.5 with { coordinate (singularity); },
      },
      decorate
      }] (-2,0) coordinate(a) -- (2,0) coordinate(b);

      draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
      draw[thick,postaction={
      decoration={
      markings,
      mark = at position 0.7 with coordinate (y);
      },
      decorate
      }] (a) -- (c);
      draw[thick,red,dashed] (x) -- (y);

      node[above = 10ex of singularity,red] (sn) {singularity};
      draw[red,->] (sn) -- ($(singularity)+(0,1)$);
      ExtractCoordinate{x};
      node[above] at (XCoord,YCoord) {%
      (pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%
      pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};
      end{tikzpicture}
      end{document}


      enter image description here






      share|improve this answer


























        4












        4








        4







        You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm or its inverse. (If that's not what you're after, I will be happy to remove the post.)



        documentclass{article}
        usepackage{tikz}
        usetikzlibrary{decorations.pathmorphing}
        usetikzlibrary{decorations.markings}
        usetikzlibrary{calc}
        usetikzlibrary{positioning}
        tikzset{zigzag/.style={decorate,decoration=zigzag}}
        begin{document}

        newdimenXCoord
        newdimenYCoord
        newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}

        begin{tikzpicture}
        coordinate (c) at (0,-2);
        coordinate (d) at (4,-2);
        coordinate (e) at (2,-4);
        draw[thick,red,zigzag,postaction={
        decoration={
        markings,
        mark=at position 0.7 with { coordinate (x); },
        mark=at position 0.5 with { coordinate (singularity); },
        },
        decorate
        }] (-2,0) coordinate(a) -- (2,0) coordinate(b);

        draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
        draw[thick,postaction={
        decoration={
        markings,
        mark = at position 0.7 with coordinate (y);
        },
        decorate
        }] (a) -- (c);
        draw[thick,red,dashed] (x) -- (y);

        node[above = 10ex of singularity,red] (sn) {singularity};
        draw[red,->] (sn) -- ($(singularity)+(0,1)$);
        ExtractCoordinate{x};
        node[above] at (XCoord,YCoord) {%
        (pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%
        pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};
        end{tikzpicture}
        end{document}


        enter image description here






        share|improve this answer













        You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm or its inverse. (If that's not what you're after, I will be happy to remove the post.)



        documentclass{article}
        usepackage{tikz}
        usetikzlibrary{decorations.pathmorphing}
        usetikzlibrary{decorations.markings}
        usetikzlibrary{calc}
        usetikzlibrary{positioning}
        tikzset{zigzag/.style={decorate,decoration=zigzag}}
        begin{document}

        newdimenXCoord
        newdimenYCoord
        newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}

        begin{tikzpicture}
        coordinate (c) at (0,-2);
        coordinate (d) at (4,-2);
        coordinate (e) at (2,-4);
        draw[thick,red,zigzag,postaction={
        decoration={
        markings,
        mark=at position 0.7 with { coordinate (x); },
        mark=at position 0.5 with { coordinate (singularity); },
        },
        decorate
        }] (-2,0) coordinate(a) -- (2,0) coordinate(b);

        draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
        draw[thick,postaction={
        decoration={
        markings,
        mark = at position 0.7 with coordinate (y);
        },
        decorate
        }] (a) -- (c);
        draw[thick,red,dashed] (x) -- (y);

        node[above = 10ex of singularity,red] (sn) {singularity};
        draw[red,->] (sn) -- ($(singularity)+(0,1)$);
        ExtractCoordinate{x};
        node[above] at (XCoord,YCoord) {%
        (pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%
        pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};
        end{tikzpicture}
        end{document}


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Feb 28 at 4:22









        marmotmarmot

        106k5129243




        106k5129243






























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