Validation on click in contact form 7
1
I am building custom step-by-step form based on Contact Form 7 and i need to validate field before going to next section. how i can call validate function on click? I can't find it in documentation.
$( "#next-section" ).click(function() {
//call validate function (how to do this)??
if('validate function no errors') {
//call my scripts
}
});
jquery wordpress contact-form-7
asked Mar 30 '16 at 9:32
PonciuszPonciusz
67112
add a comment |
1
I am building custom step-by-step form based on Contact Form 7 and i need to validate field before going to next section. how i can call validate function on click? I can't find it in documentation.
$( "#next-section" ).click(function() {
//call validate function (how to do this)??
if('validate function no errors') {
//call my scripts
}
});
jquery wordpress contact-form-7
asked Mar 30 '16 at 9:32
PonciuszPonciusz
67112
i think you need this . stackoverflow.com/questions/27798264/…
– Noman
Mar 30 '16 at 10:55
add a comment |
1
1
1
1
I am building custom step-by-step form based on Contact Form 7 and i need to validate field before going to next section. how i can call validate function on click? I can't find it in documentation.
$( "#next-section" ).click(function() {
//call validate function (how to do this)??
if('validate function no errors') {
//call my scripts
}
});
jquery wordpress contact-form-7
asked Mar 30 '16 at 9:32
PonciuszPonciusz
67112
I am building custom step-by-step form based on Contact Form 7 and i need to validate field before going to next section. how i can call validate function on click? I can't find it in documentation.
$( "#next-section" ).click(function() {
//call validate function (how to do this)??
if('validate function no errors') {
//call my scripts
}
});
jquery wordpress contact-form-7
jquery wordpress contact-form-7
asked Mar 30 '16 at 9:32
PonciuszPonciusz
67112
asked Mar 30 '16 at 9:32
PonciuszPonciusz
67112
asked Mar 30 '16 at 9:32
PonciuszPonciusz
67112
asked Mar 30 '16 at 9:32
PonciuszPonciusz
67112
asked Mar 30 '16 at 9:32
PonciuszPonciusz
67112
67112
i think you need this . stackoverflow.com/questions/27798264/…
– Noman
Mar 30 '16 at 10:55
add a comment |
i think you need this . stackoverflow.com/questions/27798264/…
– Noman
Mar 30 '16 at 10:55
i think you need this . stackoverflow.com/questions/27798264/…
– Noman
Mar 30 '16 at 10:55
i think you need this . stackoverflow.com/questions/27798264/…
– Noman
Mar 30 '16 at 10:55
add a comment |
3 Answers
3
active
oldest
votes
0
You can do this :
$( "#next-section" ).click(function() {
$('your-form').submit();
});
answered Mar 30 '16 at 9:42
GregGreg
750320
not working. its good idea but how i can init submit on contactform7 in jquery?
– Ponciusz
Mar 30 '16 at 10:05
The problem will occur also when i want to validate and fields after visible content has errors so it will not let use go further more
– Ponciusz
Mar 30 '16 at 10:19
No need init submit. submit() is a function jquery for submit a form. But not verify the fields. Because the .submit() don't use html 5 property in dom.
– Greg
Mar 30 '16 at 11:30
add a comment |
0
You can call .validate plugin for form validation.
$( "#next-section" ).click(function() {
$("#form").validate({
rules: {
name: "required",
},
messages: {
name: "name is required",
},
submitHandler: function(form) {
form.submit();
}
});
});
answered Mar 30 '16 at 10:11
RaviKant SharmaRaviKant Sharma
163
add a comment |
0
I have faced the same problem and got a solution.
I have 2 steps form, and I had an idea to submit the form and then check whether input fields on 1st step were validated (obviously, the form cannot be sent cause there are few fields on a 2nd step, this was made just to use CF7 validation).
$('.go_to_step_2').on('click', function () {
var input = $('input[name="your-name"]'),
form = $(this).parents('.wpcf7-form');
form.submit();
// trigger just one time! so validation works correctly in the 2nd step
form.parent().one('wpcf7:invalid', function() {
if( !input.hasClass('wpcf7-not-valid') ) {
// this will hide valid-tips from step 2
$('.step_2').find('.wpcf7-not-valid-tip').fadeOut(0);
// do stuff to show step 2
}
});
});
answered Nov 20 '18 at 18:08
Rostyk ChaikivskyiRostyk Chaikivskyi
1
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You can do this :
$( "#next-section" ).click(function() {
$('your-form').submit();
});
answered Mar 30 '16 at 9:42
GregGreg
750320
not working. its good idea but how i can init submit on contactform7 in jquery?
– Ponciusz
Mar 30 '16 at 10:05
The problem will occur also when i want to validate and fields after visible content has errors so it will not let use go further more
– Ponciusz
Mar 30 '16 at 10:19
No need init submit. submit() is a function jquery for submit a form. But not verify the fields. Because the .submit() don't use html 5 property in dom.
– Greg
Mar 30 '16 at 11:30
add a comment |
0
You can do this :
$( "#next-section" ).click(function() {
$('your-form').submit();
});
answered Mar 30 '16 at 9:42
GregGreg
750320
not working. its good idea but how i can init submit on contactform7 in jquery?
– Ponciusz
Mar 30 '16 at 10:05
The problem will occur also when i want to validate and fields after visible content has errors so it will not let use go further more
– Ponciusz
Mar 30 '16 at 10:19
No need init submit. submit() is a function jquery for submit a form. But not verify the fields. Because the .submit() don't use html 5 property in dom.
– Greg
Mar 30 '16 at 11:30
add a comment |
0
0
0
You can do this :
$( "#next-section" ).click(function() {
$('your-form').submit();
});
answered Mar 30 '16 at 9:42
GregGreg
750320
You can do this :
$( "#next-section" ).click(function() {
$('your-form').submit();
});
answered Mar 30 '16 at 9:42
GregGreg
750320
answered Mar 30 '16 at 9:42
GregGreg
750320
answered Mar 30 '16 at 9:42
GregGreg
750320
answered Mar 30 '16 at 9:42
GregGreg
750320
750320
not working. its good idea but how i can init submit on contactform7 in jquery?
– Ponciusz
Mar 30 '16 at 10:05
The problem will occur also when i want to validate and fields after visible content has errors so it will not let use go further more
– Ponciusz
Mar 30 '16 at 10:19
No need init submit. submit() is a function jquery for submit a form. But not verify the fields. Because the .submit() don't use html 5 property in dom.
– Greg
Mar 30 '16 at 11:30
add a comment |
not working. its good idea but how i can init submit on contactform7 in jquery?
– Ponciusz
Mar 30 '16 at 10:05
The problem will occur also when i want to validate and fields after visible content has errors so it will not let use go further more
– Ponciusz
Mar 30 '16 at 10:19
No need init submit. submit() is a function jquery for submit a form. But not verify the fields. Because the .submit() don't use html 5 property in dom.
– Greg
Mar 30 '16 at 11:30
not working. its good idea but how i can init submit on contactform7 in jquery?
– Ponciusz
Mar 30 '16 at 10:05
not working. its good idea but how i can init submit on contactform7 in jquery?
– Ponciusz
Mar 30 '16 at 10:05
The problem will occur also when i want to validate and fields after visible content has errors so it will not let use go further more
– Ponciusz
Mar 30 '16 at 10:19
The problem will occur also when i want to validate and fields after visible content has errors so it will not let use go further more
– Ponciusz
Mar 30 '16 at 10:19
No need init submit. submit() is a function jquery for submit a form. But not verify the fields. Because the .submit() don't use html 5 property in dom.
– Greg
Mar 30 '16 at 11:30
No need init submit. submit() is a function jquery for submit a form. But not verify the fields. Because the .submit() don't use html 5 property in dom.
– Greg
Mar 30 '16 at 11:30
add a comment |
0
You can call .validate plugin for form validation.
$( "#next-section" ).click(function() {
$("#form").validate({
rules: {
name: "required",
},
messages: {
name: "name is required",
},
submitHandler: function(form) {
form.submit();
}
});
});
answered Mar 30 '16 at 10:11
RaviKant SharmaRaviKant Sharma
163
add a comment |
0
You can call .validate plugin for form validation.
$( "#next-section" ).click(function() {
$("#form").validate({
rules: {
name: "required",
},
messages: {
name: "name is required",
},
submitHandler: function(form) {
form.submit();
}
});
});
answered Mar 30 '16 at 10:11
RaviKant SharmaRaviKant Sharma
163
add a comment |
0
0
0
You can call .validate plugin for form validation.
$( "#next-section" ).click(function() {
$("#form").validate({
rules: {
name: "required",
},
messages: {
name: "name is required",
},
submitHandler: function(form) {
form.submit();
}
});
});
answered Mar 30 '16 at 10:11
RaviKant SharmaRaviKant Sharma
163
You can call .validate plugin for form validation.
$( "#next-section" ).click(function() {
$("#form").validate({
rules: {
name: "required",
},
messages: {
name: "name is required",
},
submitHandler: function(form) {
form.submit();
}
});
});
answered Mar 30 '16 at 10:11
RaviKant SharmaRaviKant Sharma
163
edited Mar 30 '16 at 10:17
answered Mar 30 '16 at 10:11
RaviKant SharmaRaviKant Sharma
163
answered Mar 30 '16 at 10:11
RaviKant SharmaRaviKant Sharma
163
answered Mar 30 '16 at 10:11
RaviKant SharmaRaviKant Sharma
163
163
add a comment |
add a comment |
0
I have faced the same problem and got a solution.
I have 2 steps form, and I had an idea to submit the form and then check whether input fields on 1st step were validated (obviously, the form cannot be sent cause there are few fields on a 2nd step, this was made just to use CF7 validation).
$('.go_to_step_2').on('click', function () {
var input = $('input[name="your-name"]'),
form = $(this).parents('.wpcf7-form');
form.submit();
// trigger just one time! so validation works correctly in the 2nd step
form.parent().one('wpcf7:invalid', function() {
if( !input.hasClass('wpcf7-not-valid') ) {
// this will hide valid-tips from step 2
$('.step_2').find('.wpcf7-not-valid-tip').fadeOut(0);
// do stuff to show step 2
}
});
});
answered Nov 20 '18 at 18:08
Rostyk ChaikivskyiRostyk Chaikivskyi
1
add a comment |
0
I have faced the same problem and got a solution.
I have 2 steps form, and I had an idea to submit the form and then check whether input fields on 1st step were validated (obviously, the form cannot be sent cause there are few fields on a 2nd step, this was made just to use CF7 validation).
$('.go_to_step_2').on('click', function () {
var input = $('input[name="your-name"]'),
form = $(this).parents('.wpcf7-form');
form.submit();
// trigger just one time! so validation works correctly in the 2nd step
form.parent().one('wpcf7:invalid', function() {
if( !input.hasClass('wpcf7-not-valid') ) {
// this will hide valid-tips from step 2
$('.step_2').find('.wpcf7-not-valid-tip').fadeOut(0);
// do stuff to show step 2
}
});
});
answered Nov 20 '18 at 18:08
Rostyk ChaikivskyiRostyk Chaikivskyi
1
add a comment |
0
0
0
I have faced the same problem and got a solution.
I have 2 steps form, and I had an idea to submit the form and then check whether input fields on 1st step were validated (obviously, the form cannot be sent cause there are few fields on a 2nd step, this was made just to use CF7 validation).
$('.go_to_step_2').on('click', function () {
var input = $('input[name="your-name"]'),
form = $(this).parents('.wpcf7-form');
form.submit();
// trigger just one time! so validation works correctly in the 2nd step
form.parent().one('wpcf7:invalid', function() {
if( !input.hasClass('wpcf7-not-valid') ) {
// this will hide valid-tips from step 2
$('.step_2').find('.wpcf7-not-valid-tip').fadeOut(0);
// do stuff to show step 2
}
});
});
answered Nov 20 '18 at 18:08
Rostyk ChaikivskyiRostyk Chaikivskyi
1
I have faced the same problem and got a solution.
I have 2 steps form, and I had an idea to submit the form and then check whether input fields on 1st step were validated (obviously, the form cannot be sent cause there are few fields on a 2nd step, this was made just to use CF7 validation).
$('.go_to_step_2').on('click', function () {
var input = $('input[name="your-name"]'),
form = $(this).parents('.wpcf7-form');
form.submit();
// trigger just one time! so validation works correctly in the 2nd step
form.parent().one('wpcf7:invalid', function() {
if( !input.hasClass('wpcf7-not-valid') ) {
// this will hide valid-tips from step 2
$('.step_2').find('.wpcf7-not-valid-tip').fadeOut(0);
// do stuff to show step 2
}
});
});
answered Nov 20 '18 at 18:08
Rostyk ChaikivskyiRostyk Chaikivskyi
1
answered Nov 20 '18 at 18:08
Rostyk ChaikivskyiRostyk Chaikivskyi
1
answered Nov 20 '18 at 18:08
Rostyk ChaikivskyiRostyk Chaikivskyi
1
answered Nov 20 '18 at 18:08
Rostyk ChaikivskyiRostyk Chaikivskyi
1
1
add a comment |
add a comment |
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i think you need this . stackoverflow.com/questions/27798264/…
– Noman
Mar 30 '16 at 10:55