Binary Tree deletion setting to NULL after freeing
I'm performing binary tree deletion in c.I was trying out few methods interestingly this weird situation came.
void Delete(){
struct BinaryTree* ptr = root;
int element;
printf("Enter element to delete : ");
scanf("%d",&element);
while(ptr){
if(element>ptr->data)
ptr = ptr->right;
else if(element<ptr->data)
ptr = ptr->left;
else
break;
}
if(ptr->left && ptr->right){
struct BinaryTree **smallest = &(ptr);
smallest = &((*smallest)->right);
while((*smallest)->left){
smallest = &((*smallest)->left);
}
ptr->data = (*smallest)->data;
free(*smallest);
*smallest = NULL;
} else if(ptr->left){
/*rest cases*/
}
}
The above code works and it sets the the NODE to NULL.
But when i do this procedure in this way it doesn't set to NULL.
if(ptr->left && ptr->right){
struct BinaryTree *smallest = ptr;
smallest = smallest->right;
while(smallest->left){
smallest = smallest->left;
}
ptr->data = smallest->data;
struct BinaryTree **refsmall = &smallest;
free(*refsmall);
*refsmall = NULL;
}
Aren't these two methods are same? If not can someone explain me how they are different?Why the first method work and second didn't?
c binary-search-tree pointer-to-pointer
add a comment |
I'm performing binary tree deletion in c.I was trying out few methods interestingly this weird situation came.
void Delete(){
struct BinaryTree* ptr = root;
int element;
printf("Enter element to delete : ");
scanf("%d",&element);
while(ptr){
if(element>ptr->data)
ptr = ptr->right;
else if(element<ptr->data)
ptr = ptr->left;
else
break;
}
if(ptr->left && ptr->right){
struct BinaryTree **smallest = &(ptr);
smallest = &((*smallest)->right);
while((*smallest)->left){
smallest = &((*smallest)->left);
}
ptr->data = (*smallest)->data;
free(*smallest);
*smallest = NULL;
} else if(ptr->left){
/*rest cases*/
}
}
The above code works and it sets the the NODE to NULL.
But when i do this procedure in this way it doesn't set to NULL.
if(ptr->left && ptr->right){
struct BinaryTree *smallest = ptr;
smallest = smallest->right;
while(smallest->left){
smallest = smallest->left;
}
ptr->data = smallest->data;
struct BinaryTree **refsmall = &smallest;
free(*refsmall);
*refsmall = NULL;
}
Aren't these two methods are same? If not can someone explain me how they are different?Why the first method work and second didn't?
c binary-search-tree pointer-to-pointer
2
They're not the same*refsmall = NULL
in the second procedure just sets the value of the local variablesmallest
toNULL
. The pointer in the tree that got you there remains unchanged.
– WhozCraig
Nov 20 '18 at 16:52
So in the first one doesn't local variable ptr is set to NULL not the original tree right?But it wasn't like that
– Sreyas
Nov 20 '18 at 16:55
3
Actually, the first is broken too if you're intent is ever to delete the root element unless the "rest cases" not shown accounts for that.
– WhozCraig
Nov 20 '18 at 16:58
add a comment |
I'm performing binary tree deletion in c.I was trying out few methods interestingly this weird situation came.
void Delete(){
struct BinaryTree* ptr = root;
int element;
printf("Enter element to delete : ");
scanf("%d",&element);
while(ptr){
if(element>ptr->data)
ptr = ptr->right;
else if(element<ptr->data)
ptr = ptr->left;
else
break;
}
if(ptr->left && ptr->right){
struct BinaryTree **smallest = &(ptr);
smallest = &((*smallest)->right);
while((*smallest)->left){
smallest = &((*smallest)->left);
}
ptr->data = (*smallest)->data;
free(*smallest);
*smallest = NULL;
} else if(ptr->left){
/*rest cases*/
}
}
The above code works and it sets the the NODE to NULL.
But when i do this procedure in this way it doesn't set to NULL.
if(ptr->left && ptr->right){
struct BinaryTree *smallest = ptr;
smallest = smallest->right;
while(smallest->left){
smallest = smallest->left;
}
ptr->data = smallest->data;
struct BinaryTree **refsmall = &smallest;
free(*refsmall);
*refsmall = NULL;
}
Aren't these two methods are same? If not can someone explain me how they are different?Why the first method work and second didn't?
c binary-search-tree pointer-to-pointer
I'm performing binary tree deletion in c.I was trying out few methods interestingly this weird situation came.
void Delete(){
struct BinaryTree* ptr = root;
int element;
printf("Enter element to delete : ");
scanf("%d",&element);
while(ptr){
if(element>ptr->data)
ptr = ptr->right;
else if(element<ptr->data)
ptr = ptr->left;
else
break;
}
if(ptr->left && ptr->right){
struct BinaryTree **smallest = &(ptr);
smallest = &((*smallest)->right);
while((*smallest)->left){
smallest = &((*smallest)->left);
}
ptr->data = (*smallest)->data;
free(*smallest);
*smallest = NULL;
} else if(ptr->left){
/*rest cases*/
}
}
The above code works and it sets the the NODE to NULL.
But when i do this procedure in this way it doesn't set to NULL.
if(ptr->left && ptr->right){
struct BinaryTree *smallest = ptr;
smallest = smallest->right;
while(smallest->left){
smallest = smallest->left;
}
ptr->data = smallest->data;
struct BinaryTree **refsmall = &smallest;
free(*refsmall);
*refsmall = NULL;
}
Aren't these two methods are same? If not can someone explain me how they are different?Why the first method work and second didn't?
c binary-search-tree pointer-to-pointer
c binary-search-tree pointer-to-pointer
asked Nov 20 '18 at 16:50
SreyasSreyas
11310
11310
2
They're not the same*refsmall = NULL
in the second procedure just sets the value of the local variablesmallest
toNULL
. The pointer in the tree that got you there remains unchanged.
– WhozCraig
Nov 20 '18 at 16:52
So in the first one doesn't local variable ptr is set to NULL not the original tree right?But it wasn't like that
– Sreyas
Nov 20 '18 at 16:55
3
Actually, the first is broken too if you're intent is ever to delete the root element unless the "rest cases" not shown accounts for that.
– WhozCraig
Nov 20 '18 at 16:58
add a comment |
2
They're not the same*refsmall = NULL
in the second procedure just sets the value of the local variablesmallest
toNULL
. The pointer in the tree that got you there remains unchanged.
– WhozCraig
Nov 20 '18 at 16:52
So in the first one doesn't local variable ptr is set to NULL not the original tree right?But it wasn't like that
– Sreyas
Nov 20 '18 at 16:55
3
Actually, the first is broken too if you're intent is ever to delete the root element unless the "rest cases" not shown accounts for that.
– WhozCraig
Nov 20 '18 at 16:58
2
2
They're not the same
*refsmall = NULL
in the second procedure just sets the value of the local variable smallest
to NULL
. The pointer in the tree that got you there remains unchanged.– WhozCraig
Nov 20 '18 at 16:52
They're not the same
*refsmall = NULL
in the second procedure just sets the value of the local variable smallest
to NULL
. The pointer in the tree that got you there remains unchanged.– WhozCraig
Nov 20 '18 at 16:52
So in the first one doesn't local variable ptr is set to NULL not the original tree right?But it wasn't like that
– Sreyas
Nov 20 '18 at 16:55
So in the first one doesn't local variable ptr is set to NULL not the original tree right?But it wasn't like that
– Sreyas
Nov 20 '18 at 16:55
3
3
Actually, the first is broken too if you're intent is ever to delete the root element unless the "rest cases" not shown accounts for that.
– WhozCraig
Nov 20 '18 at 16:58
Actually, the first is broken too if you're intent is ever to delete the root element unless the "rest cases" not shown accounts for that.
– WhozCraig
Nov 20 '18 at 16:58
add a comment |
2 Answers
2
active
oldest
votes
You should avoid using global variables in your code. If you really want to use globals the first version of delete should look like this:
void Delete(){
/* at some point you will need to change the 'real' root, not the copy of it */
struct BinaryTree **ptr = &root;
int element;
printf("Enter element to delete : ");
scanf("%d",&element);
while(*ptr){
if(element > (*ptr)->data)
ptr = &(*ptr)->right;
else if(element < (*ptr)->data)
ptr = &(*ptr)->left;
else
break;
}
if((*ptr)->left && (*ptr)->right){
struct BinaryTree **smallest = ptr;
smallest = &(*smallest)->right;
while((*smallest)->left){
smallest = &(*smallest)->left;
}
(*ptr)->data = (*smallest)->data;
free(*smallest);
*smallest = NULL;
} else if((*ptr)->left){
/*rest cases*/
}
}
In the first version you would not be able to delete the root.
1
thanks for such a really nice explanation :)
– Sreyas
Nov 30 '18 at 5:27
add a comment |
struct node {
struct node *l,*r;
int data;
};
void delnode(struct node **pp, int data)
{
struct node *del, *l,*r;
// Walk the tree
while(*pp) {
if ((*pp)->data < data) {pp = &(*pp)->l; continue;}
if ((*pp)->data > data) {pp = &(*pp)->r; continue;}
break; // found it!
}
if (!*pp) return; // not found
del = *pp;
l = del->l;
r = del->r;
// If only one child it wil take del's place.
if (!r) *pp = l;
else if (!l) *pp = r;
// del has two children.
// pick one (R) child, and append the (L) other onto its (Leftmost) shoulder
else {
*pp = r;
for (pp= &del->r; *pp; pp=&(*pp)->l) {;} // find Leftmost NULL pointer in the R tree
*pp = l;
}
free(del);
}
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You should avoid using global variables in your code. If you really want to use globals the first version of delete should look like this:
void Delete(){
/* at some point you will need to change the 'real' root, not the copy of it */
struct BinaryTree **ptr = &root;
int element;
printf("Enter element to delete : ");
scanf("%d",&element);
while(*ptr){
if(element > (*ptr)->data)
ptr = &(*ptr)->right;
else if(element < (*ptr)->data)
ptr = &(*ptr)->left;
else
break;
}
if((*ptr)->left && (*ptr)->right){
struct BinaryTree **smallest = ptr;
smallest = &(*smallest)->right;
while((*smallest)->left){
smallest = &(*smallest)->left;
}
(*ptr)->data = (*smallest)->data;
free(*smallest);
*smallest = NULL;
} else if((*ptr)->left){
/*rest cases*/
}
}
In the first version you would not be able to delete the root.
1
thanks for such a really nice explanation :)
– Sreyas
Nov 30 '18 at 5:27
add a comment |
You should avoid using global variables in your code. If you really want to use globals the first version of delete should look like this:
void Delete(){
/* at some point you will need to change the 'real' root, not the copy of it */
struct BinaryTree **ptr = &root;
int element;
printf("Enter element to delete : ");
scanf("%d",&element);
while(*ptr){
if(element > (*ptr)->data)
ptr = &(*ptr)->right;
else if(element < (*ptr)->data)
ptr = &(*ptr)->left;
else
break;
}
if((*ptr)->left && (*ptr)->right){
struct BinaryTree **smallest = ptr;
smallest = &(*smallest)->right;
while((*smallest)->left){
smallest = &(*smallest)->left;
}
(*ptr)->data = (*smallest)->data;
free(*smallest);
*smallest = NULL;
} else if((*ptr)->left){
/*rest cases*/
}
}
In the first version you would not be able to delete the root.
1
thanks for such a really nice explanation :)
– Sreyas
Nov 30 '18 at 5:27
add a comment |
You should avoid using global variables in your code. If you really want to use globals the first version of delete should look like this:
void Delete(){
/* at some point you will need to change the 'real' root, not the copy of it */
struct BinaryTree **ptr = &root;
int element;
printf("Enter element to delete : ");
scanf("%d",&element);
while(*ptr){
if(element > (*ptr)->data)
ptr = &(*ptr)->right;
else if(element < (*ptr)->data)
ptr = &(*ptr)->left;
else
break;
}
if((*ptr)->left && (*ptr)->right){
struct BinaryTree **smallest = ptr;
smallest = &(*smallest)->right;
while((*smallest)->left){
smallest = &(*smallest)->left;
}
(*ptr)->data = (*smallest)->data;
free(*smallest);
*smallest = NULL;
} else if((*ptr)->left){
/*rest cases*/
}
}
In the first version you would not be able to delete the root.
You should avoid using global variables in your code. If you really want to use globals the first version of delete should look like this:
void Delete(){
/* at some point you will need to change the 'real' root, not the copy of it */
struct BinaryTree **ptr = &root;
int element;
printf("Enter element to delete : ");
scanf("%d",&element);
while(*ptr){
if(element > (*ptr)->data)
ptr = &(*ptr)->right;
else if(element < (*ptr)->data)
ptr = &(*ptr)->left;
else
break;
}
if((*ptr)->left && (*ptr)->right){
struct BinaryTree **smallest = ptr;
smallest = &(*smallest)->right;
while((*smallest)->left){
smallest = &(*smallest)->left;
}
(*ptr)->data = (*smallest)->data;
free(*smallest);
*smallest = NULL;
} else if((*ptr)->left){
/*rest cases*/
}
}
In the first version you would not be able to delete the root.
edited Nov 20 '18 at 18:11
answered Nov 20 '18 at 18:06
sstefansstefan
336311
336311
1
thanks for such a really nice explanation :)
– Sreyas
Nov 30 '18 at 5:27
add a comment |
1
thanks for such a really nice explanation :)
– Sreyas
Nov 30 '18 at 5:27
1
1
thanks for such a really nice explanation :)
– Sreyas
Nov 30 '18 at 5:27
thanks for such a really nice explanation :)
– Sreyas
Nov 30 '18 at 5:27
add a comment |
struct node {
struct node *l,*r;
int data;
};
void delnode(struct node **pp, int data)
{
struct node *del, *l,*r;
// Walk the tree
while(*pp) {
if ((*pp)->data < data) {pp = &(*pp)->l; continue;}
if ((*pp)->data > data) {pp = &(*pp)->r; continue;}
break; // found it!
}
if (!*pp) return; // not found
del = *pp;
l = del->l;
r = del->r;
// If only one child it wil take del's place.
if (!r) *pp = l;
else if (!l) *pp = r;
// del has two children.
// pick one (R) child, and append the (L) other onto its (Leftmost) shoulder
else {
*pp = r;
for (pp= &del->r; *pp; pp=&(*pp)->l) {;} // find Leftmost NULL pointer in the R tree
*pp = l;
}
free(del);
}
add a comment |
struct node {
struct node *l,*r;
int data;
};
void delnode(struct node **pp, int data)
{
struct node *del, *l,*r;
// Walk the tree
while(*pp) {
if ((*pp)->data < data) {pp = &(*pp)->l; continue;}
if ((*pp)->data > data) {pp = &(*pp)->r; continue;}
break; // found it!
}
if (!*pp) return; // not found
del = *pp;
l = del->l;
r = del->r;
// If only one child it wil take del's place.
if (!r) *pp = l;
else if (!l) *pp = r;
// del has two children.
// pick one (R) child, and append the (L) other onto its (Leftmost) shoulder
else {
*pp = r;
for (pp= &del->r; *pp; pp=&(*pp)->l) {;} // find Leftmost NULL pointer in the R tree
*pp = l;
}
free(del);
}
add a comment |
struct node {
struct node *l,*r;
int data;
};
void delnode(struct node **pp, int data)
{
struct node *del, *l,*r;
// Walk the tree
while(*pp) {
if ((*pp)->data < data) {pp = &(*pp)->l; continue;}
if ((*pp)->data > data) {pp = &(*pp)->r; continue;}
break; // found it!
}
if (!*pp) return; // not found
del = *pp;
l = del->l;
r = del->r;
// If only one child it wil take del's place.
if (!r) *pp = l;
else if (!l) *pp = r;
// del has two children.
// pick one (R) child, and append the (L) other onto its (Leftmost) shoulder
else {
*pp = r;
for (pp= &del->r; *pp; pp=&(*pp)->l) {;} // find Leftmost NULL pointer in the R tree
*pp = l;
}
free(del);
}
struct node {
struct node *l,*r;
int data;
};
void delnode(struct node **pp, int data)
{
struct node *del, *l,*r;
// Walk the tree
while(*pp) {
if ((*pp)->data < data) {pp = &(*pp)->l; continue;}
if ((*pp)->data > data) {pp = &(*pp)->r; continue;}
break; // found it!
}
if (!*pp) return; // not found
del = *pp;
l = del->l;
r = del->r;
// If only one child it wil take del's place.
if (!r) *pp = l;
else if (!l) *pp = r;
// del has two children.
// pick one (R) child, and append the (L) other onto its (Leftmost) shoulder
else {
*pp = r;
for (pp= &del->r; *pp; pp=&(*pp)->l) {;} // find Leftmost NULL pointer in the R tree
*pp = l;
}
free(del);
}
answered Nov 20 '18 at 18:05
joopjoop
3,2781818
3,2781818
add a comment |
add a comment |
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2
They're not the same
*refsmall = NULL
in the second procedure just sets the value of the local variablesmallest
toNULL
. The pointer in the tree that got you there remains unchanged.– WhozCraig
Nov 20 '18 at 16:52
So in the first one doesn't local variable ptr is set to NULL not the original tree right?But it wasn't like that
– Sreyas
Nov 20 '18 at 16:55
3
Actually, the first is broken too if you're intent is ever to delete the root element unless the "rest cases" not shown accounts for that.
– WhozCraig
Nov 20 '18 at 16:58