jQuery: How to refresh data being read from a cookie after the cookie is updated in an Ajax call
0
I have a billing form that reads data from a cookie and prefills the fields based on the cookie value. If a user changes the field, they can click 'save' which triggers an AJAX call and upon that success, I update the cookie with the new field values. How can I have the page refresh without actually reloading it.
let address = `<input class="street-address inner-inputs" value='${Cookies.getJSON('braintreeData') && Cookies.getJSON('braintreeData').streetAddress || ""}'></input>
jquery ajax
asked Nov 20 '18 at 5:31
Raymon OpieRaymon Opie
827
add a comment |
0
I have a billing form that reads data from a cookie and prefills the fields based on the cookie value. If a user changes the field, they can click 'save' which triggers an AJAX call and upon that success, I update the cookie with the new field values. How can I have the page refresh without actually reloading it.
let address = `<input class="street-address inner-inputs" value='${Cookies.getJSON('braintreeData') && Cookies.getJSON('braintreeData').streetAddress || ""}'></input>
jquery ajax
asked Nov 20 '18 at 5:31
Raymon OpieRaymon Opie
827
What you have tried so far ?
– Sulthan Allaudeen
Nov 20 '18 at 5:44
1
@SulthanAllaudeen remove() and then append() the html again but it's simply not feasible for me to do that.
– Raymon Opie
Nov 20 '18 at 7:02
1
@RaymonOpie it is the only way if he got radios/checkboxes. Best you can do is create a JS method to generate the form using cookie values, and then you can remove it and create it any time.
– darklightcode
Nov 20 '18 at 8:24
the only thing I can suggest is do what RaymonOpie and darklightcode said, its the best solution
– Yash Soni
Nov 20 '18 at 12:23
add a comment |
0
0
0
I have a billing form that reads data from a cookie and prefills the fields based on the cookie value. If a user changes the field, they can click 'save' which triggers an AJAX call and upon that success, I update the cookie with the new field values. How can I have the page refresh without actually reloading it.
let address = `<input class="street-address inner-inputs" value='${Cookies.getJSON('braintreeData') && Cookies.getJSON('braintreeData').streetAddress || ""}'></input>
jquery ajax
asked Nov 20 '18 at 5:31
Raymon OpieRaymon Opie
827
I have a billing form that reads data from a cookie and prefills the fields based on the cookie value. If a user changes the field, they can click 'save' which triggers an AJAX call and upon that success, I update the cookie with the new field values. How can I have the page refresh without actually reloading it.
let address = `<input class="street-address inner-inputs" value='${Cookies.getJSON('braintreeData') && Cookies.getJSON('braintreeData').streetAddress || ""}'></input>
jquery ajax
jquery ajax
asked Nov 20 '18 at 5:31
Raymon OpieRaymon Opie
827
asked Nov 20 '18 at 5:31
Raymon OpieRaymon Opie
827
asked Nov 20 '18 at 5:31
Raymon OpieRaymon Opie
827
asked Nov 20 '18 at 5:31
Raymon OpieRaymon Opie
827
asked Nov 20 '18 at 5:31
Raymon OpieRaymon Opie
827
827
What you have tried so far ?
– Sulthan Allaudeen
Nov 20 '18 at 5:44
1
@SulthanAllaudeen remove() and then append() the html again but it's simply not feasible for me to do that.
– Raymon Opie
Nov 20 '18 at 7:02
1
@RaymonOpie it is the only way if he got radios/checkboxes. Best you can do is create a JS method to generate the form using cookie values, and then you can remove it and create it any time.
– darklightcode
Nov 20 '18 at 8:24
the only thing I can suggest is do what RaymonOpie and darklightcode said, its the best solution
– Yash Soni
Nov 20 '18 at 12:23
add a comment |
What you have tried so far ?
– Sulthan Allaudeen
Nov 20 '18 at 5:44
1
@SulthanAllaudeen remove() and then append() the html again but it's simply not feasible for me to do that.
– Raymon Opie
Nov 20 '18 at 7:02
1
@RaymonOpie it is the only way if he got radios/checkboxes. Best you can do is create a JS method to generate the form using cookie values, and then you can remove it and create it any time.
– darklightcode
Nov 20 '18 at 8:24
the only thing I can suggest is do what RaymonOpie and darklightcode said, its the best solution
– Yash Soni
Nov 20 '18 at 12:23
What you have tried so far ?
– Sulthan Allaudeen
Nov 20 '18 at 5:44
What you have tried so far ?
– Sulthan Allaudeen
Nov 20 '18 at 5:44
1
1
@SulthanAllaudeen remove() and then append() the html again but it's simply not feasible for me to do that.
– Raymon Opie
Nov 20 '18 at 7:02
@SulthanAllaudeen remove() and then append() the html again but it's simply not feasible for me to do that.
– Raymon Opie
Nov 20 '18 at 7:02
1
1
@RaymonOpie it is the only way if he got radios/checkboxes. Best you can do is create a JS method to generate the form using cookie values, and then you can remove it and create it any time.
– darklightcode
Nov 20 '18 at 8:24
@RaymonOpie it is the only way if he got radios/checkboxes. Best you can do is create a JS method to generate the form using cookie values, and then you can remove it and create it any time.
– darklightcode
Nov 20 '18 at 8:24
the only thing I can suggest is do what RaymonOpie and darklightcode said, its the best solution
– Yash Soni
Nov 20 '18 at 12:23
the only thing I can suggest is do what RaymonOpie and darklightcode said, its the best solution
– Yash Soni
Nov 20 '18 at 12:23
add a comment |
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What you have tried so far ?
– Sulthan Allaudeen
Nov 20 '18 at 5:44
1
@SulthanAllaudeen remove() and then append() the html again but it's simply not feasible for me to do that.
– Raymon Opie
Nov 20 '18 at 7:02
1
@RaymonOpie it is the only way if he got radios/checkboxes. Best you can do is create a JS method to generate the form using cookie values, and then you can remove it and create it any time.
– darklightcode
Nov 20 '18 at 8:24
the only thing I can suggest is do what RaymonOpie and darklightcode said, its the best solution
– Yash Soni
Nov 20 '18 at 12:23