How to Implement Hierarchical Query in bigquery
I have some table "tab1", which contains the sample data as like follws
I am expecting the output like as follows
How to implement in "BIGQUERY", Please help me to achieve this.
Thanks
Kalyan
sql google-bigquery
add a comment |
I have some table "tab1", which contains the sample data as like follws
I am expecting the output like as follows
How to implement in "BIGQUERY", Please help me to achieve this.
Thanks
Kalyan
sql google-bigquery
could you please describe your logic of this output
– Zaynul Abadin Tuhin
Nov 20 '18 at 10:30
If you see the existed data table, term1 has definition 'xyz' and it was given on 01-jan-2018, but for the same term a new definition has given on 01-apr-2018. so the term1 first definition was valid from 01-jan-2018 to 01-apr-2018. this will continued as long as new definitions were added. its kind of slowly changing dimension
– kalyan4uonly
Nov 20 '18 at 11:08
add a comment |
I have some table "tab1", which contains the sample data as like follws
I am expecting the output like as follows
How to implement in "BIGQUERY", Please help me to achieve this.
Thanks
Kalyan
sql google-bigquery
I have some table "tab1", which contains the sample data as like follws
I am expecting the output like as follows
How to implement in "BIGQUERY", Please help me to achieve this.
Thanks
Kalyan
sql google-bigquery
sql google-bigquery
edited Nov 20 '18 at 15:08
Mikhail Berlyant
59.2k43671
59.2k43671
asked Nov 20 '18 at 10:17
kalyan4uonlykalyan4uonly
244
244
could you please describe your logic of this output
– Zaynul Abadin Tuhin
Nov 20 '18 at 10:30
If you see the existed data table, term1 has definition 'xyz' and it was given on 01-jan-2018, but for the same term a new definition has given on 01-apr-2018. so the term1 first definition was valid from 01-jan-2018 to 01-apr-2018. this will continued as long as new definitions were added. its kind of slowly changing dimension
– kalyan4uonly
Nov 20 '18 at 11:08
add a comment |
could you please describe your logic of this output
– Zaynul Abadin Tuhin
Nov 20 '18 at 10:30
If you see the existed data table, term1 has definition 'xyz' and it was given on 01-jan-2018, but for the same term a new definition has given on 01-apr-2018. so the term1 first definition was valid from 01-jan-2018 to 01-apr-2018. this will continued as long as new definitions were added. its kind of slowly changing dimension
– kalyan4uonly
Nov 20 '18 at 11:08
could you please describe your logic of this output
– Zaynul Abadin Tuhin
Nov 20 '18 at 10:30
could you please describe your logic of this output
– Zaynul Abadin Tuhin
Nov 20 '18 at 10:30
If you see the existed data table, term1 has definition 'xyz' and it was given on 01-jan-2018, but for the same term a new definition has given on 01-apr-2018. so the term1 first definition was valid from 01-jan-2018 to 01-apr-2018. this will continued as long as new definitions were added. its kind of slowly changing dimension
– kalyan4uonly
Nov 20 '18 at 11:08
If you see the existed data table, term1 has definition 'xyz' and it was given on 01-jan-2018, but for the same term a new definition has given on 01-apr-2018. so the term1 first definition was valid from 01-jan-2018 to 01-apr-2018. this will continued as long as new definitions were added. its kind of slowly changing dimension
– kalyan4uonly
Nov 20 '18 at 11:08
add a comment |
1 Answer
1
active
oldest
votes
I think you just need lead()
:
select t.*,
lead(effective_from, 1, date('9999-12-31')) over
(partition by sno
order by effective_from
) as effective_to
from t
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think you just need lead()
:
select t.*,
lead(effective_from, 1, date('9999-12-31')) over
(partition by sno
order by effective_from
) as effective_to
from t
add a comment |
I think you just need lead()
:
select t.*,
lead(effective_from, 1, date('9999-12-31')) over
(partition by sno
order by effective_from
) as effective_to
from t
add a comment |
I think you just need lead()
:
select t.*,
lead(effective_from, 1, date('9999-12-31')) over
(partition by sno
order by effective_from
) as effective_to
from t
I think you just need lead()
:
select t.*,
lead(effective_from, 1, date('9999-12-31')) over
(partition by sno
order by effective_from
) as effective_to
from t
answered Nov 20 '18 at 11:45
Gordon LinoffGordon Linoff
774k35306408
774k35306408
add a comment |
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could you please describe your logic of this output
– Zaynul Abadin Tuhin
Nov 20 '18 at 10:30
If you see the existed data table, term1 has definition 'xyz' and it was given on 01-jan-2018, but for the same term a new definition has given on 01-apr-2018. so the term1 first definition was valid from 01-jan-2018 to 01-apr-2018. this will continued as long as new definitions were added. its kind of slowly changing dimension
– kalyan4uonly
Nov 20 '18 at 11:08