An example of the fact that from measurability of a random process does not follow measurability of its...












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Let {$ xi _t(omega), tin[0,infty)$} be a random process and $ xi _t(omega)in {mathfrak F_t}$ (some filtration). If $ xi _t(omega) $ is $ mathfrak F_t $ measurable then $int_0^txi _s(omega)L(ds)$ not necessarily $ mathfrak F_t $ measurable. I am looking for a process, that will demonstrate this statement. Thanks in advance for any tips.










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  • $begingroup$
    What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
    $endgroup$
    – saz
    Dec 1 '18 at 17:31












  • $begingroup$
    @saz Lebesgue measure
    $endgroup$
    – Emerald
    Dec 1 '18 at 17:32










  • $begingroup$
    I see. What makes you believe that such a process exist?
    $endgroup$
    – saz
    Dec 1 '18 at 17:42










  • $begingroup$
    @saz I think such an example could be Heaviside function. But I'm not sure.
    $endgroup$
    – Emerald
    Dec 1 '18 at 17:45
















1












$begingroup$


Let {$ xi _t(omega), tin[0,infty)$} be a random process and $ xi _t(omega)in {mathfrak F_t}$ (some filtration). If $ xi _t(omega) $ is $ mathfrak F_t $ measurable then $int_0^txi _s(omega)L(ds)$ not necessarily $ mathfrak F_t $ measurable. I am looking for a process, that will demonstrate this statement. Thanks in advance for any tips.










share|cite|improve this question











$endgroup$












  • $begingroup$
    What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
    $endgroup$
    – saz
    Dec 1 '18 at 17:31












  • $begingroup$
    @saz Lebesgue measure
    $endgroup$
    – Emerald
    Dec 1 '18 at 17:32










  • $begingroup$
    I see. What makes you believe that such a process exist?
    $endgroup$
    – saz
    Dec 1 '18 at 17:42










  • $begingroup$
    @saz I think such an example could be Heaviside function. But I'm not sure.
    $endgroup$
    – Emerald
    Dec 1 '18 at 17:45














1












1








1


2



$begingroup$


Let {$ xi _t(omega), tin[0,infty)$} be a random process and $ xi _t(omega)in {mathfrak F_t}$ (some filtration). If $ xi _t(omega) $ is $ mathfrak F_t $ measurable then $int_0^txi _s(omega)L(ds)$ not necessarily $ mathfrak F_t $ measurable. I am looking for a process, that will demonstrate this statement. Thanks in advance for any tips.










share|cite|improve this question











$endgroup$




Let {$ xi _t(omega), tin[0,infty)$} be a random process and $ xi _t(omega)in {mathfrak F_t}$ (some filtration). If $ xi _t(omega) $ is $ mathfrak F_t $ measurable then $int_0^txi _s(omega)L(ds)$ not necessarily $ mathfrak F_t $ measurable. I am looking for a process, that will demonstrate this statement. Thanks in advance for any tips.







measure-theory stochastic-processes lebesgue-integral examples-counterexamples filtrations






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share|cite|improve this question













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edited Dec 1 '18 at 18:03







Emerald

















asked Dec 1 '18 at 14:36









EmeraldEmerald

378




378












  • $begingroup$
    What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
    $endgroup$
    – saz
    Dec 1 '18 at 17:31












  • $begingroup$
    @saz Lebesgue measure
    $endgroup$
    – Emerald
    Dec 1 '18 at 17:32










  • $begingroup$
    I see. What makes you believe that such a process exist?
    $endgroup$
    – saz
    Dec 1 '18 at 17:42










  • $begingroup$
    @saz I think such an example could be Heaviside function. But I'm not sure.
    $endgroup$
    – Emerald
    Dec 1 '18 at 17:45


















  • $begingroup$
    What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
    $endgroup$
    – saz
    Dec 1 '18 at 17:31












  • $begingroup$
    @saz Lebesgue measure
    $endgroup$
    – Emerald
    Dec 1 '18 at 17:32










  • $begingroup$
    I see. What makes you believe that such a process exist?
    $endgroup$
    – saz
    Dec 1 '18 at 17:42










  • $begingroup$
    @saz I think such an example could be Heaviside function. But I'm not sure.
    $endgroup$
    – Emerald
    Dec 1 '18 at 17:45
















$begingroup$
What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
$endgroup$
– saz
Dec 1 '18 at 17:31






$begingroup$
What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
$endgroup$
– saz
Dec 1 '18 at 17:31














$begingroup$
@saz Lebesgue measure
$endgroup$
– Emerald
Dec 1 '18 at 17:32




$begingroup$
@saz Lebesgue measure
$endgroup$
– Emerald
Dec 1 '18 at 17:32












$begingroup$
I see. What makes you believe that such a process exist?
$endgroup$
– saz
Dec 1 '18 at 17:42




$begingroup$
I see. What makes you believe that such a process exist?
$endgroup$
– saz
Dec 1 '18 at 17:42












$begingroup$
@saz I think such an example could be Heaviside function. But I'm not sure.
$endgroup$
– Emerald
Dec 1 '18 at 17:45




$begingroup$
@saz I think such an example could be Heaviside function. But I'm not sure.
$endgroup$
– Emerald
Dec 1 '18 at 17:45










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