An example of the fact that from measurability of a random process does not follow measurability of its...
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Let {$ xi _t(omega), tin[0,infty)$} be a random process and $ xi _t(omega)in {mathfrak F_t}$ (some filtration). If $ xi _t(omega) $ is $ mathfrak F_t $ measurable then $int_0^txi _s(omega)L(ds)$ not necessarily $ mathfrak F_t $ measurable. I am looking for a process, that will demonstrate this statement. Thanks in advance for any tips.
measure-theory stochastic-processes lebesgue-integral examples-counterexamples filtrations
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add a comment |
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Let {$ xi _t(omega), tin[0,infty)$} be a random process and $ xi _t(omega)in {mathfrak F_t}$ (some filtration). If $ xi _t(omega) $ is $ mathfrak F_t $ measurable then $int_0^txi _s(omega)L(ds)$ not necessarily $ mathfrak F_t $ measurable. I am looking for a process, that will demonstrate this statement. Thanks in advance for any tips.
measure-theory stochastic-processes lebesgue-integral examples-counterexamples filtrations
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What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
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– saz
Dec 1 '18 at 17:31
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@saz Lebesgue measure
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– Emerald
Dec 1 '18 at 17:32
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I see. What makes you believe that such a process exist?
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– saz
Dec 1 '18 at 17:42
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@saz I think such an example could be Heaviside function. But I'm not sure.
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– Emerald
Dec 1 '18 at 17:45
add a comment |
$begingroup$
Let {$ xi _t(omega), tin[0,infty)$} be a random process and $ xi _t(omega)in {mathfrak F_t}$ (some filtration). If $ xi _t(omega) $ is $ mathfrak F_t $ measurable then $int_0^txi _s(omega)L(ds)$ not necessarily $ mathfrak F_t $ measurable. I am looking for a process, that will demonstrate this statement. Thanks in advance for any tips.
measure-theory stochastic-processes lebesgue-integral examples-counterexamples filtrations
$endgroup$
Let {$ xi _t(omega), tin[0,infty)$} be a random process and $ xi _t(omega)in {mathfrak F_t}$ (some filtration). If $ xi _t(omega) $ is $ mathfrak F_t $ measurable then $int_0^txi _s(omega)L(ds)$ not necessarily $ mathfrak F_t $ measurable. I am looking for a process, that will demonstrate this statement. Thanks in advance for any tips.
measure-theory stochastic-processes lebesgue-integral examples-counterexamples filtrations
measure-theory stochastic-processes lebesgue-integral examples-counterexamples filtrations
edited Dec 1 '18 at 18:03
Emerald
asked Dec 1 '18 at 14:36
EmeraldEmerald
378
378
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What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
$endgroup$
– saz
Dec 1 '18 at 17:31
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@saz Lebesgue measure
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– Emerald
Dec 1 '18 at 17:32
$begingroup$
I see. What makes you believe that such a process exist?
$endgroup$
– saz
Dec 1 '18 at 17:42
$begingroup$
@saz I think such an example could be Heaviside function. But I'm not sure.
$endgroup$
– Emerald
Dec 1 '18 at 17:45
add a comment |
$begingroup$
What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
$endgroup$
– saz
Dec 1 '18 at 17:31
$begingroup$
@saz Lebesgue measure
$endgroup$
– Emerald
Dec 1 '18 at 17:32
$begingroup$
I see. What makes you believe that such a process exist?
$endgroup$
– saz
Dec 1 '18 at 17:42
$begingroup$
@saz I think such an example could be Heaviside function. But I'm not sure.
$endgroup$
– Emerald
Dec 1 '18 at 17:45
$begingroup$
What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
$endgroup$
– saz
Dec 1 '18 at 17:31
$begingroup$
What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
$endgroup$
– saz
Dec 1 '18 at 17:31
$begingroup$
@saz Lebesgue measure
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– Emerald
Dec 1 '18 at 17:32
$begingroup$
@saz Lebesgue measure
$endgroup$
– Emerald
Dec 1 '18 at 17:32
$begingroup$
I see. What makes you believe that such a process exist?
$endgroup$
– saz
Dec 1 '18 at 17:42
$begingroup$
I see. What makes you believe that such a process exist?
$endgroup$
– saz
Dec 1 '18 at 17:42
$begingroup$
@saz I think such an example could be Heaviside function. But I'm not sure.
$endgroup$
– Emerald
Dec 1 '18 at 17:45
$begingroup$
@saz I think such an example could be Heaviside function. But I'm not sure.
$endgroup$
– Emerald
Dec 1 '18 at 17:45
add a comment |
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$begingroup$
What is $L$...? And what exactly do you mean by $xi_t(omega)$ is measurable (measurable with respect to which variable? $omega$ or $t$? or jointly measurable)?
$endgroup$
– saz
Dec 1 '18 at 17:31
$begingroup$
@saz Lebesgue measure
$endgroup$
– Emerald
Dec 1 '18 at 17:32
$begingroup$
I see. What makes you believe that such a process exist?
$endgroup$
– saz
Dec 1 '18 at 17:42
$begingroup$
@saz I think such an example could be Heaviside function. But I'm not sure.
$endgroup$
– Emerald
Dec 1 '18 at 17:45