Finding multiple patterns in a string in Ruby
I am trying to find strings in an array that match multiple regular expression patterns. I figured out how to do this for one pattern as below:
spamWords = Regexp.new("Delighted")
spamCount1 = 0
spamArray.each do |word|
if word =~ spamWords
spamCount1 +=1
end
end
p spamCount1
I iterated over an array of spamWord
strings, but I was wondering if there is a simpler way of doing this.
arrays ruby regex
add a comment |
I am trying to find strings in an array that match multiple regular expression patterns. I figured out how to do this for one pattern as below:
spamWords = Regexp.new("Delighted")
spamCount1 = 0
spamArray.each do |word|
if word =~ spamWords
spamCount1 +=1
end
end
p spamCount1
I iterated over an array of spamWord
strings, but I was wondering if there is a simpler way of doing this.
arrays ruby regex
If you just want to count rather than get the matches, then you should do:smapArray.count(&spamWords.method(:=~))
.
– sawa
Nov 21 '18 at 3:28
add a comment |
I am trying to find strings in an array that match multiple regular expression patterns. I figured out how to do this for one pattern as below:
spamWords = Regexp.new("Delighted")
spamCount1 = 0
spamArray.each do |word|
if word =~ spamWords
spamCount1 +=1
end
end
p spamCount1
I iterated over an array of spamWord
strings, but I was wondering if there is a simpler way of doing this.
arrays ruby regex
I am trying to find strings in an array that match multiple regular expression patterns. I figured out how to do this for one pattern as below:
spamWords = Regexp.new("Delighted")
spamCount1 = 0
spamArray.each do |word|
if word =~ spamWords
spamCount1 +=1
end
end
p spamCount1
I iterated over an array of spamWord
strings, but I was wondering if there is a simpler way of doing this.
arrays ruby regex
arrays ruby regex
edited Nov 21 '18 at 3:23
sawa
131k29205303
131k29205303
asked Nov 20 '18 at 12:58
rhanlyrhanly
2616
2616
If you just want to count rather than get the matches, then you should do:smapArray.count(&spamWords.method(:=~))
.
– sawa
Nov 21 '18 at 3:28
add a comment |
If you just want to count rather than get the matches, then you should do:smapArray.count(&spamWords.method(:=~))
.
– sawa
Nov 21 '18 at 3:28
If you just want to count rather than get the matches, then you should do:
smapArray.count(&spamWords.method(:=~))
.– sawa
Nov 21 '18 at 3:28
If you just want to count rather than get the matches, then you should do:
smapArray.count(&spamWords.method(:=~))
.– sawa
Nov 21 '18 at 3:28
add a comment |
1 Answer
1
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oldest
votes
You can union multiple patterns into one regular expression, then perform the search exactly like you did below:
spamWords = Regexp.new("Delighted|Saddened")
You can also use Regexp.union
to auto-generate this regexp for you:
spamWords = Regexp.union("Delighted", "Saddened")
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can union multiple patterns into one regular expression, then perform the search exactly like you did below:
spamWords = Regexp.new("Delighted|Saddened")
You can also use Regexp.union
to auto-generate this regexp for you:
spamWords = Regexp.union("Delighted", "Saddened")
add a comment |
You can union multiple patterns into one regular expression, then perform the search exactly like you did below:
spamWords = Regexp.new("Delighted|Saddened")
You can also use Regexp.union
to auto-generate this regexp for you:
spamWords = Regexp.union("Delighted", "Saddened")
add a comment |
You can union multiple patterns into one regular expression, then perform the search exactly like you did below:
spamWords = Regexp.new("Delighted|Saddened")
You can also use Regexp.union
to auto-generate this regexp for you:
spamWords = Regexp.union("Delighted", "Saddened")
You can union multiple patterns into one regular expression, then perform the search exactly like you did below:
spamWords = Regexp.new("Delighted|Saddened")
You can also use Regexp.union
to auto-generate this regexp for you:
spamWords = Regexp.union("Delighted", "Saddened")
answered Nov 20 '18 at 13:09
Tom LordTom Lord
15.3k22951
15.3k22951
add a comment |
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If you just want to count rather than get the matches, then you should do:
smapArray.count(&spamWords.method(:=~))
.– sawa
Nov 21 '18 at 3:28