Solving dynamical ODE System with Python












0














I am trying to solve a dynamical system with three state variables V1,V2,I3 and then plot these in a 3d Plot. My code so far looks as follows:



from scipy.integrate import ode
import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
import math
def ID(V,a,b):
return a*(math.exp(b*V)-math.exp(-b*V))


def dynamical_system(t,z,C1,C2,L,R1,R2,R3,RN,a,b):

V1,V2,I3 = z
f = [(1/C1)*(V1*(1/RN-1/R1)-ID(V1-V2,a,b)-(V1-V2)/R2),(1/C2)*(ID(V1-V2,a,b)+(V1-V2)/R2-I3),(1/L)*(-I3*R3+V2)]
return f

# Create an `ode` instance to solve the system of differential
# equations defined by `dynamical_system`, and set the solver method to 'dopri5'.
solver = ode(dynamical_system)
solver.set_integrator('dopri5')

# Set the initial value z(0) = z0.
C1=10
C2=100
L=0.32
R1=22
R2=14.5
R3=100
RN=6.9
a=2.295*10**(-5)
b=3.0038
solver.set_f_params(C1,C2,L,R1,R2,R3,RN,a,b)
t0 = 0.0
z0 = [-3, 0.5, 0.25] #here you can set the inital values V1,V2,I3
solver.set_initial_value(z0, t0)


# Create the array `t` of time values at which to compute
# the solution, and create an array to hold the solution.
# Put the initial value in the solution array.
t1 = 25
N = 200 #number of iterations
t = np.linspace(t0, t1, N)
sol = np.empty((N, 3))
sol[0] = z0

# Repeatedly call the `integrate` method to advance the
# solution to time t[k], and save the solution in sol[k].
k = 1
while solver.successful() and solver.t < t1:
solver.integrate(t[k])
sol[k] = solver.y
k += 1


xlim = (-4,1)
ylim= (-1,1)
zlim=(-1,1)
fig=plt.figure()
ax=fig.gca(projection='3d')
#ax.view_init(35,-28)
ax.set_xlim(xlim)
ax.set_ylim(ylim)
ax.set_zlim(zlim)

print sol[:,0]
print sol[:,1]
print sol[:,2]
ax.plot3D(sol[:,0], sol[:,1], sol[:,2], 'gray')

plt.show()


Printing the arrays that should hold the solutions sol[:,0] etc. shows that apparently it constantly fills it with the initial value. Can anyone help? Thanks!










share|improve this question



























    0














    I am trying to solve a dynamical system with three state variables V1,V2,I3 and then plot these in a 3d Plot. My code so far looks as follows:



    from scipy.integrate import ode
    import numpy as np
    import matplotlib.pyplot as plt
    from mpl_toolkits.mplot3d import Axes3D
    import math
    def ID(V,a,b):
    return a*(math.exp(b*V)-math.exp(-b*V))


    def dynamical_system(t,z,C1,C2,L,R1,R2,R3,RN,a,b):

    V1,V2,I3 = z
    f = [(1/C1)*(V1*(1/RN-1/R1)-ID(V1-V2,a,b)-(V1-V2)/R2),(1/C2)*(ID(V1-V2,a,b)+(V1-V2)/R2-I3),(1/L)*(-I3*R3+V2)]
    return f

    # Create an `ode` instance to solve the system of differential
    # equations defined by `dynamical_system`, and set the solver method to 'dopri5'.
    solver = ode(dynamical_system)
    solver.set_integrator('dopri5')

    # Set the initial value z(0) = z0.
    C1=10
    C2=100
    L=0.32
    R1=22
    R2=14.5
    R3=100
    RN=6.9
    a=2.295*10**(-5)
    b=3.0038
    solver.set_f_params(C1,C2,L,R1,R2,R3,RN,a,b)
    t0 = 0.0
    z0 = [-3, 0.5, 0.25] #here you can set the inital values V1,V2,I3
    solver.set_initial_value(z0, t0)


    # Create the array `t` of time values at which to compute
    # the solution, and create an array to hold the solution.
    # Put the initial value in the solution array.
    t1 = 25
    N = 200 #number of iterations
    t = np.linspace(t0, t1, N)
    sol = np.empty((N, 3))
    sol[0] = z0

    # Repeatedly call the `integrate` method to advance the
    # solution to time t[k], and save the solution in sol[k].
    k = 1
    while solver.successful() and solver.t < t1:
    solver.integrate(t[k])
    sol[k] = solver.y
    k += 1


    xlim = (-4,1)
    ylim= (-1,1)
    zlim=(-1,1)
    fig=plt.figure()
    ax=fig.gca(projection='3d')
    #ax.view_init(35,-28)
    ax.set_xlim(xlim)
    ax.set_ylim(ylim)
    ax.set_zlim(zlim)

    print sol[:,0]
    print sol[:,1]
    print sol[:,2]
    ax.plot3D(sol[:,0], sol[:,1], sol[:,2], 'gray')

    plt.show()


    Printing the arrays that should hold the solutions sol[:,0] etc. shows that apparently it constantly fills it with the initial value. Can anyone help? Thanks!










    share|improve this question

























      0












      0








      0







      I am trying to solve a dynamical system with three state variables V1,V2,I3 and then plot these in a 3d Plot. My code so far looks as follows:



      from scipy.integrate import ode
      import numpy as np
      import matplotlib.pyplot as plt
      from mpl_toolkits.mplot3d import Axes3D
      import math
      def ID(V,a,b):
      return a*(math.exp(b*V)-math.exp(-b*V))


      def dynamical_system(t,z,C1,C2,L,R1,R2,R3,RN,a,b):

      V1,V2,I3 = z
      f = [(1/C1)*(V1*(1/RN-1/R1)-ID(V1-V2,a,b)-(V1-V2)/R2),(1/C2)*(ID(V1-V2,a,b)+(V1-V2)/R2-I3),(1/L)*(-I3*R3+V2)]
      return f

      # Create an `ode` instance to solve the system of differential
      # equations defined by `dynamical_system`, and set the solver method to 'dopri5'.
      solver = ode(dynamical_system)
      solver.set_integrator('dopri5')

      # Set the initial value z(0) = z0.
      C1=10
      C2=100
      L=0.32
      R1=22
      R2=14.5
      R3=100
      RN=6.9
      a=2.295*10**(-5)
      b=3.0038
      solver.set_f_params(C1,C2,L,R1,R2,R3,RN,a,b)
      t0 = 0.0
      z0 = [-3, 0.5, 0.25] #here you can set the inital values V1,V2,I3
      solver.set_initial_value(z0, t0)


      # Create the array `t` of time values at which to compute
      # the solution, and create an array to hold the solution.
      # Put the initial value in the solution array.
      t1 = 25
      N = 200 #number of iterations
      t = np.linspace(t0, t1, N)
      sol = np.empty((N, 3))
      sol[0] = z0

      # Repeatedly call the `integrate` method to advance the
      # solution to time t[k], and save the solution in sol[k].
      k = 1
      while solver.successful() and solver.t < t1:
      solver.integrate(t[k])
      sol[k] = solver.y
      k += 1


      xlim = (-4,1)
      ylim= (-1,1)
      zlim=(-1,1)
      fig=plt.figure()
      ax=fig.gca(projection='3d')
      #ax.view_init(35,-28)
      ax.set_xlim(xlim)
      ax.set_ylim(ylim)
      ax.set_zlim(zlim)

      print sol[:,0]
      print sol[:,1]
      print sol[:,2]
      ax.plot3D(sol[:,0], sol[:,1], sol[:,2], 'gray')

      plt.show()


      Printing the arrays that should hold the solutions sol[:,0] etc. shows that apparently it constantly fills it with the initial value. Can anyone help? Thanks!










      share|improve this question













      I am trying to solve a dynamical system with three state variables V1,V2,I3 and then plot these in a 3d Plot. My code so far looks as follows:



      from scipy.integrate import ode
      import numpy as np
      import matplotlib.pyplot as plt
      from mpl_toolkits.mplot3d import Axes3D
      import math
      def ID(V,a,b):
      return a*(math.exp(b*V)-math.exp(-b*V))


      def dynamical_system(t,z,C1,C2,L,R1,R2,R3,RN,a,b):

      V1,V2,I3 = z
      f = [(1/C1)*(V1*(1/RN-1/R1)-ID(V1-V2,a,b)-(V1-V2)/R2),(1/C2)*(ID(V1-V2,a,b)+(V1-V2)/R2-I3),(1/L)*(-I3*R3+V2)]
      return f

      # Create an `ode` instance to solve the system of differential
      # equations defined by `dynamical_system`, and set the solver method to 'dopri5'.
      solver = ode(dynamical_system)
      solver.set_integrator('dopri5')

      # Set the initial value z(0) = z0.
      C1=10
      C2=100
      L=0.32
      R1=22
      R2=14.5
      R3=100
      RN=6.9
      a=2.295*10**(-5)
      b=3.0038
      solver.set_f_params(C1,C2,L,R1,R2,R3,RN,a,b)
      t0 = 0.0
      z0 = [-3, 0.5, 0.25] #here you can set the inital values V1,V2,I3
      solver.set_initial_value(z0, t0)


      # Create the array `t` of time values at which to compute
      # the solution, and create an array to hold the solution.
      # Put the initial value in the solution array.
      t1 = 25
      N = 200 #number of iterations
      t = np.linspace(t0, t1, N)
      sol = np.empty((N, 3))
      sol[0] = z0

      # Repeatedly call the `integrate` method to advance the
      # solution to time t[k], and save the solution in sol[k].
      k = 1
      while solver.successful() and solver.t < t1:
      solver.integrate(t[k])
      sol[k] = solver.y
      k += 1


      xlim = (-4,1)
      ylim= (-1,1)
      zlim=(-1,1)
      fig=plt.figure()
      ax=fig.gca(projection='3d')
      #ax.view_init(35,-28)
      ax.set_xlim(xlim)
      ax.set_ylim(ylim)
      ax.set_zlim(zlim)

      print sol[:,0]
      print sol[:,1]
      print sol[:,2]
      ax.plot3D(sol[:,0], sol[:,1], sol[:,2], 'gray')

      plt.show()


      Printing the arrays that should hold the solutions sol[:,0] etc. shows that apparently it constantly fills it with the initial value. Can anyone help? Thanks!







      python ode solver






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      asked Nov 18 '18 at 14:19









      MarkMark

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          Use from __future__ import division.





          I can't reproduce your problem: I see a gradual change from -3 to -2.46838127, from 0.5 to 0.38022886 and from 0.25 to 0.00380239 (with a sharp change from 0.25 to 0.00498674 in the first step). This is with Python 3.7.0, NumPy version 1.15.3 and SciPy version 1.1.0.



          Given that you are using Python 2.7, integer division may be the culprit here. Quite a number of your constants are integer, and you have a bunch of 1/<constant> integer divisions in your equation.



          Indeed, if I replace / with // in my version (for Python 3), I can reproduce your problem.



          Simply add from __future__ import division at the top of your script to solve your problem.





          Also add from __future__ import print_function at the top, replace print <something> with print(<something>) and your script is fully Python 3 and 2 compatible).






          share|improve this answer





















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            1 Answer
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            active

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            0














            Use from __future__ import division.





            I can't reproduce your problem: I see a gradual change from -3 to -2.46838127, from 0.5 to 0.38022886 and from 0.25 to 0.00380239 (with a sharp change from 0.25 to 0.00498674 in the first step). This is with Python 3.7.0, NumPy version 1.15.3 and SciPy version 1.1.0.



            Given that you are using Python 2.7, integer division may be the culprit here. Quite a number of your constants are integer, and you have a bunch of 1/<constant> integer divisions in your equation.



            Indeed, if I replace / with // in my version (for Python 3), I can reproduce your problem.



            Simply add from __future__ import division at the top of your script to solve your problem.





            Also add from __future__ import print_function at the top, replace print <something> with print(<something>) and your script is fully Python 3 and 2 compatible).






            share|improve this answer


























              0














              Use from __future__ import division.





              I can't reproduce your problem: I see a gradual change from -3 to -2.46838127, from 0.5 to 0.38022886 and from 0.25 to 0.00380239 (with a sharp change from 0.25 to 0.00498674 in the first step). This is with Python 3.7.0, NumPy version 1.15.3 and SciPy version 1.1.0.



              Given that you are using Python 2.7, integer division may be the culprit here. Quite a number of your constants are integer, and you have a bunch of 1/<constant> integer divisions in your equation.



              Indeed, if I replace / with // in my version (for Python 3), I can reproduce your problem.



              Simply add from __future__ import division at the top of your script to solve your problem.





              Also add from __future__ import print_function at the top, replace print <something> with print(<something>) and your script is fully Python 3 and 2 compatible).






              share|improve this answer
























                0












                0








                0






                Use from __future__ import division.





                I can't reproduce your problem: I see a gradual change from -3 to -2.46838127, from 0.5 to 0.38022886 and from 0.25 to 0.00380239 (with a sharp change from 0.25 to 0.00498674 in the first step). This is with Python 3.7.0, NumPy version 1.15.3 and SciPy version 1.1.0.



                Given that you are using Python 2.7, integer division may be the culprit here. Quite a number of your constants are integer, and you have a bunch of 1/<constant> integer divisions in your equation.



                Indeed, if I replace / with // in my version (for Python 3), I can reproduce your problem.



                Simply add from __future__ import division at the top of your script to solve your problem.





                Also add from __future__ import print_function at the top, replace print <something> with print(<something>) and your script is fully Python 3 and 2 compatible).






                share|improve this answer












                Use from __future__ import division.





                I can't reproduce your problem: I see a gradual change from -3 to -2.46838127, from 0.5 to 0.38022886 and from 0.25 to 0.00380239 (with a sharp change from 0.25 to 0.00498674 in the first step). This is with Python 3.7.0, NumPy version 1.15.3 and SciPy version 1.1.0.



                Given that you are using Python 2.7, integer division may be the culprit here. Quite a number of your constants are integer, and you have a bunch of 1/<constant> integer divisions in your equation.



                Indeed, if I replace / with // in my version (for Python 3), I can reproduce your problem.



                Simply add from __future__ import division at the top of your script to solve your problem.





                Also add from __future__ import print_function at the top, replace print <something> with print(<something>) and your script is fully Python 3 and 2 compatible).







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 18 '18 at 14:46









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