Python NameError: name 'isAnagram' is not defined

-4

I want to print whether a number is an anagram or not from the user input. I get an error saying nameError. Error message

And this is my code for checking an input for an anagram.

n = input("Enter a long number")

factor = 2

factor_anagram = False

while factor < 10:

    if isAnagram(n, factor):

    print(n, "is an anagram with factor", factor)

    factor_anagram = True 

    factor += 1

if not factor_anagram:

     print("No")

Do I need to create a class? I tried creating an isAnagram class as well. But my implementation did not solve the issue.

edited Nov 18 '18 at 14:34

asked Nov 18 '18 at 14:22

Chaite

1

Where do you define isAnagram?
– Carcigenicate
Nov 18 '18 at 14:24

There is no built-in isAnagram function. You have to define one your own.
– Austin
Nov 18 '18 at 14:25

You don't need to create a class. You need to create a function :D
– Canh
Nov 18 '18 at 14:27

add a comment |

-4

I want to print whether a number is an anagram or not from the user input. I get an error saying nameError. Error message

And this is my code for checking an input for an anagram.

n = input("Enter a long number")

factor = 2

factor_anagram = False

while factor < 10:

    if isAnagram(n, factor):

    print(n, "is an anagram with factor", factor)

    factor_anagram = True 

    factor += 1

if not factor_anagram:

     print("No")

Do I need to create a class? I tried creating an isAnagram class as well. But my implementation did not solve the issue.

edited Nov 18 '18 at 14:34

asked Nov 18 '18 at 14:22

Chaite

1

Where do you define isAnagram?
– Carcigenicate
Nov 18 '18 at 14:24

There is no built-in isAnagram function. You have to define one your own.
– Austin
Nov 18 '18 at 14:25

You don't need to create a class. You need to create a function :D
– Canh
Nov 18 '18 at 14:27

add a comment |

-4

I want to print whether a number is an anagram or not from the user input. I get an error saying nameError. Error message

And this is my code for checking an input for an anagram.

n = input("Enter a long number")

factor = 2

factor_anagram = False

while factor < 10:

    if isAnagram(n, factor):

    print(n, "is an anagram with factor", factor)

    factor_anagram = True 

    factor += 1

if not factor_anagram:

     print("No")

Do I need to create a class? I tried creating an isAnagram class as well. But my implementation did not solve the issue.

edited Nov 18 '18 at 14:34

asked Nov 18 '18 at 14:22

Chaite

I want to print whether a number is an anagram or not from the user input. I get an error saying nameError. Error message

And this is my code for checking an input for an anagram.

n = input("Enter a long number")

factor = 2

factor_anagram = False

while factor < 10:

    if isAnagram(n, factor):

    print(n, "is an anagram with factor", factor)

    factor_anagram = True 

    factor += 1

if not factor_anagram:

     print("No")

Do I need to create a class? I tried creating an isAnagram class as well. But my implementation did not solve the issue.

python python-3.7

edited Nov 18 '18 at 14:34

asked Nov 18 '18 at 14:22

Chaite

edited Nov 18 '18 at 14:34

asked Nov 18 '18 at 14:22

Chaite

edited Nov 18 '18 at 14:34

asked Nov 18 '18 at 14:22

Chaite

asked Nov 18 '18 at 14:22

Chaite

asked Nov 18 '18 at 14:22

Chaite

1

Where do you define isAnagram?
– Carcigenicate
Nov 18 '18 at 14:24

There is no built-in isAnagram function. You have to define one your own.
– Austin
Nov 18 '18 at 14:25

You don't need to create a class. You need to create a function :D
– Canh
Nov 18 '18 at 14:27

add a comment |

1

Where do you define isAnagram?
– Carcigenicate
Nov 18 '18 at 14:24

There is no built-in isAnagram function. You have to define one your own.
– Austin
Nov 18 '18 at 14:25

You don't need to create a class. You need to create a function :D
– Canh
Nov 18 '18 at 14:27

Where do you define isAnagram?
– Carcigenicate
Nov 18 '18 at 14:24

There is no built-in isAnagram function. You have to define one your own.
– Austin
Nov 18 '18 at 14:25

You don't need to create a class. You need to create a function :D
– Canh
Nov 18 '18 at 14:27

add a comment |

2 Answers
2

active

oldest

votes

You are trying to use isAnagram(n, factor) as a built in function like print("xyz"). isAnagram() is not a built in function, so you will have to define it at the top of your code. It can look like this:

def isAnagram(n, factor):

    if (whatever comparison needs to be made here):

        return True

    else:

        return False

Now when you call the isAnagram function, either True or False will be returned.

answered Nov 18 '18 at 14:31

Harry Weinman

313

add a comment |

isAnagram does not exist in the default Python library - you have to define it yourself. From the way you're attempting to use it, you want to create a function

def is_anagram(n, factor):

    # Your code here

    # return True or False

You can then do something like if is_anagram(n, factor):.

edited Nov 18 '18 at 14:31

answered Nov 18 '18 at 14:29

Moralous

71111

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

def isAnagram(n, factor):

    if (whatever comparison needs to be made here):

        return True

    else:

        return False

Now when you call the isAnagram function, either True or False will be returned.

answered Nov 18 '18 at 14:31

Harry Weinman

313

add a comment |

def isAnagram(n, factor):

    if (whatever comparison needs to be made here):

        return True

    else:

        return False

Now when you call the isAnagram function, either True or False will be returned.

answered Nov 18 '18 at 14:31

Harry Weinman

313

add a comment |

def isAnagram(n, factor):

    if (whatever comparison needs to be made here):

        return True

    else:

        return False

Now when you call the isAnagram function, either True or False will be returned.

answered Nov 18 '18 at 14:31

Harry Weinman

313

def isAnagram(n, factor):

    if (whatever comparison needs to be made here):

        return True

    else:

        return False

Now when you call the isAnagram function, either True or False will be returned.

answered Nov 18 '18 at 14:31

Harry Weinman

313

answered Nov 18 '18 at 14:31

Harry Weinman

313

answered Nov 18 '18 at 14:31

Harry Weinman

313

answered Nov 18 '18 at 14:31

Harry Weinman

313

add a comment |

isAnagram does not exist in the default Python library - you have to define it yourself. From the way you're attempting to use it, you want to create a function

def is_anagram(n, factor):

    # Your code here

    # return True or False

You can then do something like if is_anagram(n, factor):.

edited Nov 18 '18 at 14:31

answered Nov 18 '18 at 14:29

Moralous

71111

add a comment |

isAnagram does not exist in the default Python library - you have to define it yourself. From the way you're attempting to use it, you want to create a function

def is_anagram(n, factor):

    # Your code here

    # return True or False

You can then do something like if is_anagram(n, factor):.

edited Nov 18 '18 at 14:31

answered Nov 18 '18 at 14:29

Moralous

71111

add a comment |

isAnagram does not exist in the default Python library - you have to define it yourself. From the way you're attempting to use it, you want to create a function

def is_anagram(n, factor):

    # Your code here

    # return True or False

You can then do something like if is_anagram(n, factor):.

edited Nov 18 '18 at 14:31

answered Nov 18 '18 at 14:29

Moralous

71111

isAnagram does not exist in the default Python library - you have to define it yourself. From the way you're attempting to use it, you want to create a function

def is_anagram(n, factor):

    # Your code here

    # return True or False

You can then do something like if is_anagram(n, factor):.

edited Nov 18 '18 at 14:31

answered Nov 18 '18 at 14:29

Moralous

71111

edited Nov 18 '18 at 14:31

answered Nov 18 '18 at 14:29

Moralous

71111

answered Nov 18 '18 at 14:29

Moralous

71111

answered Nov 18 '18 at 14:29

Moralous

71111

add a comment |

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