Reverse string Python
I would like to get input from a user and then to print the string reversed like this:
input:
hello
output:
o
ol
oll
olle
olleh
This is my code:
s = input()
for i in range(len(s) - 2, -1, -1):
print(s[:i:-1])
And output i receive is:
o
ol
oll
olle
I am constantly missing the last character. I tried many variations of the slicing. What am I missing?
python string python-3.x
asked Nov 19 '18 at 19:05
Strahinja RodicStrahinja Rodic
145314
add a comment |
I would like to get input from a user and then to print the string reversed like this:
input:
hello
output:
o
ol
oll
olle
olleh
This is my code:
s = input()
for i in range(len(s) - 2, -1, -1):
print(s[:i:-1])
And output i receive is:
o
ol
oll
olle
I am constantly missing the last character. I tried many variations of the slicing. What am I missing?
python string python-3.x
asked Nov 19 '18 at 19:05
Strahinja RodicStrahinja Rodic
145314
add a comment |
I would like to get input from a user and then to print the string reversed like this:
input:
hello
output:
o
ol
oll
olle
olleh
This is my code:
s = input()
for i in range(len(s) - 2, -1, -1):
print(s[:i:-1])
And output i receive is:
o
ol
oll
olle
I am constantly missing the last character. I tried many variations of the slicing. What am I missing?
python string python-3.x
asked Nov 19 '18 at 19:05
Strahinja RodicStrahinja Rodic
145314
I would like to get input from a user and then to print the string reversed like this:
input:
hello
output:
o
ol
oll
olle
olleh
This is my code:
s = input()
for i in range(len(s) - 2, -1, -1):
print(s[:i:-1])
And output i receive is:
o
ol
oll
olle
I am constantly missing the last character. I tried many variations of the slicing. What am I missing?
python string python-3.x
python string python-3.x
asked Nov 19 '18 at 19:05
Strahinja RodicStrahinja Rodic
145314
asked Nov 19 '18 at 19:05
Strahinja RodicStrahinja Rodic
145314
asked Nov 19 '18 at 19:05
Strahinja RodicStrahinja Rodic
145314
asked Nov 19 '18 at 19:05
Strahinja RodicStrahinja Rodic
145314
asked Nov 19 '18 at 19:05
Strahinja RodicStrahinja Rodic
145314
145314
add a comment |
add a comment |
7 Answers
7
active
oldest
votes
To get the full string reversed you must use s[::-1] omitting the first value.
Since that doesn't fit into your iteration you'll have to use something like:
s = input()
for i in range(len(s) - 2, -1, -1):
print(s[:i:-1])
print(s[::-1])
answered Nov 19 '18 at 19:19
user10673977user10673977
964
I like this better than mine.
– kabanus
Nov 19 '18 at 19:20
I think this is the easiest solution of all. I really like it, and didn't really think about using s[::-1] in the end of the for loop, I was only trying to reverse it fully through iterations. Thanks! :)
– Strahinja Rodic
Nov 19 '18 at 19:37
add a comment |
You must first obtain the substring and then reverse it:
s = "hello"
for i in range(len(s)-1, -1, -1):
print(s[i:][::-1])
Or:
s = "hello"
for i, _ in enumerate(s):
print(s[i:][::-1])
Or reverse the word and get the substring:
s = "hello"
for i, _ in enumerate(s):
print(s[::-1][:i+1])
answered Nov 19 '18 at 19:10
eyllanesceyllanesc
77.1k103156
1
This is nice, but I don't think the double string slicing is strictly necessary.
– jpp
Nov 19 '18 at 19:16
@jpp Why do you think that double slicing is not right? What problems could it generate? :-)
– eyllanesc
Nov 19 '18 at 19:17
2
Double the operations :). I'm not saying it's wrong, it's just.. not necessary.
– jpp
Nov 19 '18 at 19:19
1
This is cool solution, but I don't think it's necessary to use double slicing
– Strahinja Rodic
Nov 19 '18 at 19:39
add a comment |
Easiest perhaps is to iterate from -1 backwards:
s = 'hello'
for i in range(1, len(s)+1):
print(s[-1: -i-1: -1])
hello
o
ol
oll
olle
olleh
The way this works, you are slicing sequentially:
s[-1: -2: -1],
s[-1: -3: -1],...s[-1: -len(s)-1: -1]
answered Nov 19 '18 at 19:15
jppjpp
98.1k2159109
add a comment |
You were almost there. One thing was already addressed - you iterate to little (the -2). The second thing is you need to use None to include the 0th element in the print:
>>> for i in range(len(s)-1, -1, -1):
... print(s[:i-1 if i else None :-1])
answered Nov 19 '18 at 19:18
kabanuskabanus
11.4k31339
add a comment |
I would do it this way:
a = "Hello"
for i in range(len(a)):
print(a[-i-1])
This way you are not dealing with string slices, only indexing the string and there isn't a bunch of extra numbers to figure out what they are doing.
answered Nov 19 '18 at 19:25
Anthony HerreraAnthony Herrera
1
Unfortunately, this won't work as you aren't defining any slices.
– jpp
Nov 19 '18 at 19:26
I see - I missed the requirement that the whole word is backwards. This method will print out each letter individually in the reverse order.
– Anthony Herrera
Nov 19 '18 at 19:34
add a comment |
You could also simply reverse the complete thing and print it sliced from the start to save you some headache:
b = "hello" # your input
h = b[::-1] # inverse all - so this is now olleh
# list slicing is from:exclusive to - so simply add 1 to fit with the ranges values 0-4
for k in ( h[0:i+1] for i in range(0,len(h)) ):
print(k)
Output:
o
ol
oll
olle
olleh
answered Nov 19 '18 at 19:25
Patrick ArtnerPatrick Artner
23.4k62343
add a comment |
The very basic method to reverse a string s is s[::-1] (and save it
in another variable, say s2).
Then, to print consecutive rows with increasing part of this string (s2),
you need a loop over range(1, len(s2)+1), stating the upper limit of s2
(excluding).
So the script can look like below:
s = 'hello'
s2 = s[::-1]
for i in range(1, len(s2)+1):
print(s2[:i])
answered Nov 19 '18 at 19:28
Valdi_BoValdi_Bo
4,7202815
add a comment |
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7 Answers
7
active
oldest
votes
7 Answers
7
active
oldest
votes
active
oldest
votes
active
oldest
votes
To get the full string reversed you must use s[::-1] omitting the first value.
Since that doesn't fit into your iteration you'll have to use something like:
s = input()
for i in range(len(s) - 2, -1, -1):
print(s[:i:-1])
print(s[::-1])
answered Nov 19 '18 at 19:19
user10673977user10673977
964
I like this better than mine.
– kabanus
Nov 19 '18 at 19:20
I think this is the easiest solution of all. I really like it, and didn't really think about using s[::-1] in the end of the for loop, I was only trying to reverse it fully through iterations. Thanks! :)
– Strahinja Rodic
Nov 19 '18 at 19:37
add a comment |
To get the full string reversed you must use s[::-1] omitting the first value.
Since that doesn't fit into your iteration you'll have to use something like:
s = input()
for i in range(len(s) - 2, -1, -1):
print(s[:i:-1])
print(s[::-1])
answered Nov 19 '18 at 19:19
user10673977user10673977
964
I like this better than mine.
– kabanus
Nov 19 '18 at 19:20
I think this is the easiest solution of all. I really like it, and didn't really think about using s[::-1] in the end of the for loop, I was only trying to reverse it fully through iterations. Thanks! :)
– Strahinja Rodic
Nov 19 '18 at 19:37
add a comment |
To get the full string reversed you must use s[::-1] omitting the first value.
Since that doesn't fit into your iteration you'll have to use something like:
s = input()
for i in range(len(s) - 2, -1, -1):
print(s[:i:-1])
print(s[::-1])
answered Nov 19 '18 at 19:19
user10673977user10673977
964
To get the full string reversed you must use s[::-1] omitting the first value.
Since that doesn't fit into your iteration you'll have to use something like:
s = input()
for i in range(len(s) - 2, -1, -1):
print(s[:i:-1])
print(s[::-1])
answered Nov 19 '18 at 19:19
user10673977user10673977
964
answered Nov 19 '18 at 19:19
user10673977user10673977
964
answered Nov 19 '18 at 19:19
user10673977user10673977
964
answered Nov 19 '18 at 19:19
user10673977user10673977
964
964
I like this better than mine.
– kabanus
Nov 19 '18 at 19:20
I think this is the easiest solution of all. I really like it, and didn't really think about using s[::-1] in the end of the for loop, I was only trying to reverse it fully through iterations. Thanks! :)
– Strahinja Rodic
Nov 19 '18 at 19:37
add a comment |
I like this better than mine.
– kabanus
Nov 19 '18 at 19:20
I think this is the easiest solution of all. I really like it, and didn't really think about using s[::-1] in the end of the for loop, I was only trying to reverse it fully through iterations. Thanks! :)
– Strahinja Rodic
Nov 19 '18 at 19:37
I like this better than mine.
– kabanus
Nov 19 '18 at 19:20
I like this better than mine.
– kabanus
Nov 19 '18 at 19:20
I think this is the easiest solution of all. I really like it, and didn't really think about using s[::-1] in the end of the for loop, I was only trying to reverse it fully through iterations. Thanks! :)
– Strahinja Rodic
Nov 19 '18 at 19:37
I think this is the easiest solution of all. I really like it, and didn't really think about using s[::-1] in the end of the for loop, I was only trying to reverse it fully through iterations. Thanks! :)
– Strahinja Rodic
Nov 19 '18 at 19:37
add a comment |
You must first obtain the substring and then reverse it:
s = "hello"
for i in range(len(s)-1, -1, -1):
print(s[i:][::-1])
Or:
s = "hello"
for i, _ in enumerate(s):
print(s[i:][::-1])
Or reverse the word and get the substring:
s = "hello"
for i, _ in enumerate(s):
print(s[::-1][:i+1])
answered Nov 19 '18 at 19:10
eyllanesceyllanesc
77.1k103156
1
This is nice, but I don't think the double string slicing is strictly necessary.
– jpp
Nov 19 '18 at 19:16
@jpp Why do you think that double slicing is not right? What problems could it generate? :-)
– eyllanesc
Nov 19 '18 at 19:17
2
Double the operations :). I'm not saying it's wrong, it's just.. not necessary.
– jpp
Nov 19 '18 at 19:19
1
This is cool solution, but I don't think it's necessary to use double slicing
– Strahinja Rodic
Nov 19 '18 at 19:39
add a comment |
You must first obtain the substring and then reverse it:
s = "hello"
for i in range(len(s)-1, -1, -1):
print(s[i:][::-1])
Or:
s = "hello"
for i, _ in enumerate(s):
print(s[i:][::-1])
Or reverse the word and get the substring:
s = "hello"
for i, _ in enumerate(s):
print(s[::-1][:i+1])
answered Nov 19 '18 at 19:10
eyllanesceyllanesc
77.1k103156
1
This is nice, but I don't think the double string slicing is strictly necessary.
– jpp
Nov 19 '18 at 19:16
@jpp Why do you think that double slicing is not right? What problems could it generate? :-)
– eyllanesc
Nov 19 '18 at 19:17
2
Double the operations :). I'm not saying it's wrong, it's just.. not necessary.
– jpp
Nov 19 '18 at 19:19
1
This is cool solution, but I don't think it's necessary to use double slicing
– Strahinja Rodic
Nov 19 '18 at 19:39
add a comment |
You must first obtain the substring and then reverse it:
s = "hello"
for i in range(len(s)-1, -1, -1):
print(s[i:][::-1])
Or:
s = "hello"
for i, _ in enumerate(s):
print(s[i:][::-1])
Or reverse the word and get the substring:
s = "hello"
for i, _ in enumerate(s):
print(s[::-1][:i+1])
answered Nov 19 '18 at 19:10
eyllanesceyllanesc
77.1k103156
You must first obtain the substring and then reverse it:
s = "hello"
for i in range(len(s)-1, -1, -1):
print(s[i:][::-1])
Or:
s = "hello"
for i, _ in enumerate(s):
print(s[i:][::-1])
Or reverse the word and get the substring:
s = "hello"
for i, _ in enumerate(s):
print(s[::-1][:i+1])
answered Nov 19 '18 at 19:10
eyllanesceyllanesc
77.1k103156
edited Nov 19 '18 at 19:16
answered Nov 19 '18 at 19:10
eyllanesceyllanesc
77.1k103156
answered Nov 19 '18 at 19:10
eyllanesceyllanesc
77.1k103156
answered Nov 19 '18 at 19:10
eyllanesceyllanesc
77.1k103156
77.1k103156
1
This is nice, but I don't think the double string slicing is strictly necessary.
– jpp
Nov 19 '18 at 19:16
@jpp Why do you think that double slicing is not right? What problems could it generate? :-)
– eyllanesc
Nov 19 '18 at 19:17
2
Double the operations :). I'm not saying it's wrong, it's just.. not necessary.
– jpp
Nov 19 '18 at 19:19
1
This is cool solution, but I don't think it's necessary to use double slicing
– Strahinja Rodic
Nov 19 '18 at 19:39
add a comment |
1
This is nice, but I don't think the double string slicing is strictly necessary.
– jpp
Nov 19 '18 at 19:16
@jpp Why do you think that double slicing is not right? What problems could it generate? :-)
– eyllanesc
Nov 19 '18 at 19:17
2
Double the operations :). I'm not saying it's wrong, it's just.. not necessary.
– jpp
Nov 19 '18 at 19:19
1
This is cool solution, but I don't think it's necessary to use double slicing
– Strahinja Rodic
Nov 19 '18 at 19:39
1
1
This is nice, but I don't think the double string slicing is strictly necessary.
– jpp
Nov 19 '18 at 19:16
This is nice, but I don't think the double string slicing is strictly necessary.
– jpp
Nov 19 '18 at 19:16
@jpp Why do you think that double slicing is not right? What problems could it generate? :-)
– eyllanesc
Nov 19 '18 at 19:17
@jpp Why do you think that double slicing is not right? What problems could it generate? :-)
– eyllanesc
Nov 19 '18 at 19:17
2
2
Double the operations :). I'm not saying it's wrong, it's just.. not necessary.
– jpp
Nov 19 '18 at 19:19
Double the operations :). I'm not saying it's wrong, it's just.. not necessary.
– jpp
Nov 19 '18 at 19:19
1
1
This is cool solution, but I don't think it's necessary to use double slicing
– Strahinja Rodic
Nov 19 '18 at 19:39
This is cool solution, but I don't think it's necessary to use double slicing
– Strahinja Rodic
Nov 19 '18 at 19:39
add a comment |
Easiest perhaps is to iterate from -1 backwards:
s = 'hello'
for i in range(1, len(s)+1):
print(s[-1: -i-1: -1])
hello
o
ol
oll
olle
olleh
The way this works, you are slicing sequentially:
s[-1: -2: -1],
s[-1: -3: -1],...s[-1: -len(s)-1: -1]
answered Nov 19 '18 at 19:15
jppjpp
98.1k2159109
add a comment |
Easiest perhaps is to iterate from -1 backwards:
s = 'hello'
for i in range(1, len(s)+1):
print(s[-1: -i-1: -1])
hello
o
ol
oll
olle
olleh
The way this works, you are slicing sequentially:
s[-1: -2: -1],
s[-1: -3: -1],...s[-1: -len(s)-1: -1]
answered Nov 19 '18 at 19:15
jppjpp
98.1k2159109
add a comment |
Easiest perhaps is to iterate from -1 backwards:
s = 'hello'
for i in range(1, len(s)+1):
print(s[-1: -i-1: -1])
hello
o
ol
oll
olle
olleh
The way this works, you are slicing sequentially:
s[-1: -2: -1],
s[-1: -3: -1],...s[-1: -len(s)-1: -1]
answered Nov 19 '18 at 19:15
jppjpp
98.1k2159109
Easiest perhaps is to iterate from -1 backwards:
s = 'hello'
for i in range(1, len(s)+1):
print(s[-1: -i-1: -1])
hello
o
ol
oll
olle
olleh
The way this works, you are slicing sequentially:
s[-1: -2: -1],
s[-1: -3: -1],...s[-1: -len(s)-1: -1]
answered Nov 19 '18 at 19:15
jppjpp
98.1k2159109
edited Nov 19 '18 at 19:21
answered Nov 19 '18 at 19:15
jppjpp
98.1k2159109
answered Nov 19 '18 at 19:15
jppjpp
98.1k2159109
answered Nov 19 '18 at 19:15
jppjpp
98.1k2159109
98.1k2159109
add a comment |
add a comment |
You were almost there. One thing was already addressed - you iterate to little (the -2). The second thing is you need to use None to include the 0th element in the print:
>>> for i in range(len(s)-1, -1, -1):
... print(s[:i-1 if i else None :-1])
answered Nov 19 '18 at 19:18
kabanuskabanus
11.4k31339
add a comment |
You were almost there. One thing was already addressed - you iterate to little (the -2). The second thing is you need to use None to include the 0th element in the print:
>>> for i in range(len(s)-1, -1, -1):
... print(s[:i-1 if i else None :-1])
answered Nov 19 '18 at 19:18
kabanuskabanus
11.4k31339
add a comment |
You were almost there. One thing was already addressed - you iterate to little (the -2). The second thing is you need to use None to include the 0th element in the print:
>>> for i in range(len(s)-1, -1, -1):
... print(s[:i-1 if i else None :-1])
answered Nov 19 '18 at 19:18
kabanuskabanus
11.4k31339
You were almost there. One thing was already addressed - you iterate to little (the -2). The second thing is you need to use None to include the 0th element in the print:
>>> for i in range(len(s)-1, -1, -1):
... print(s[:i-1 if i else None :-1])
answered Nov 19 '18 at 19:18
kabanuskabanus
11.4k31339
answered Nov 19 '18 at 19:18
kabanuskabanus
11.4k31339
answered Nov 19 '18 at 19:18
kabanuskabanus
11.4k31339
answered Nov 19 '18 at 19:18
kabanuskabanus
11.4k31339
11.4k31339
add a comment |
add a comment |
I would do it this way:
a = "Hello"
for i in range(len(a)):
print(a[-i-1])
This way you are not dealing with string slices, only indexing the string and there isn't a bunch of extra numbers to figure out what they are doing.
answered Nov 19 '18 at 19:25
Anthony HerreraAnthony Herrera
1
Unfortunately, this won't work as you aren't defining any slices.
– jpp
Nov 19 '18 at 19:26
I see - I missed the requirement that the whole word is backwards. This method will print out each letter individually in the reverse order.
– Anthony Herrera
Nov 19 '18 at 19:34
add a comment |
I would do it this way:
a = "Hello"
for i in range(len(a)):
print(a[-i-1])
This way you are not dealing with string slices, only indexing the string and there isn't a bunch of extra numbers to figure out what they are doing.
answered Nov 19 '18 at 19:25
Anthony HerreraAnthony Herrera
1
Unfortunately, this won't work as you aren't defining any slices.
– jpp
Nov 19 '18 at 19:26
I see - I missed the requirement that the whole word is backwards. This method will print out each letter individually in the reverse order.
– Anthony Herrera
Nov 19 '18 at 19:34
add a comment |
I would do it this way:
a = "Hello"
for i in range(len(a)):
print(a[-i-1])
This way you are not dealing with string slices, only indexing the string and there isn't a bunch of extra numbers to figure out what they are doing.
answered Nov 19 '18 at 19:25
Anthony HerreraAnthony Herrera
1
I would do it this way:
a = "Hello"
for i in range(len(a)):
print(a[-i-1])
This way you are not dealing with string slices, only indexing the string and there isn't a bunch of extra numbers to figure out what they are doing.
answered Nov 19 '18 at 19:25
Anthony HerreraAnthony Herrera
1
answered Nov 19 '18 at 19:25
Anthony HerreraAnthony Herrera
1
answered Nov 19 '18 at 19:25
Anthony HerreraAnthony Herrera
1
answered Nov 19 '18 at 19:25
Anthony HerreraAnthony Herrera
1
1
Unfortunately, this won't work as you aren't defining any slices.
– jpp
Nov 19 '18 at 19:26
I see - I missed the requirement that the whole word is backwards. This method will print out each letter individually in the reverse order.
– Anthony Herrera
Nov 19 '18 at 19:34
add a comment |
Unfortunately, this won't work as you aren't defining any slices.
– jpp
Nov 19 '18 at 19:26
I see - I missed the requirement that the whole word is backwards. This method will print out each letter individually in the reverse order.
– Anthony Herrera
Nov 19 '18 at 19:34
Unfortunately, this won't work as you aren't defining any slices.
– jpp
Nov 19 '18 at 19:26
Unfortunately, this won't work as you aren't defining any slices.
– jpp
Nov 19 '18 at 19:26
I see - I missed the requirement that the whole word is backwards. This method will print out each letter individually in the reverse order.
– Anthony Herrera
Nov 19 '18 at 19:34
I see - I missed the requirement that the whole word is backwards. This method will print out each letter individually in the reverse order.
– Anthony Herrera
Nov 19 '18 at 19:34
add a comment |
You could also simply reverse the complete thing and print it sliced from the start to save you some headache:
b = "hello" # your input
h = b[::-1] # inverse all - so this is now olleh
# list slicing is from:exclusive to - so simply add 1 to fit with the ranges values 0-4
for k in ( h[0:i+1] for i in range(0,len(h)) ):
print(k)
Output:
o
ol
oll
olle
olleh
answered Nov 19 '18 at 19:25
Patrick ArtnerPatrick Artner
23.4k62343
add a comment |
You could also simply reverse the complete thing and print it sliced from the start to save you some headache:
b = "hello" # your input
h = b[::-1] # inverse all - so this is now olleh
# list slicing is from:exclusive to - so simply add 1 to fit with the ranges values 0-4
for k in ( h[0:i+1] for i in range(0,len(h)) ):
print(k)
Output:
o
ol
oll
olle
olleh
answered Nov 19 '18 at 19:25
Patrick ArtnerPatrick Artner
23.4k62343
add a comment |
You could also simply reverse the complete thing and print it sliced from the start to save you some headache:
b = "hello" # your input
h = b[::-1] # inverse all - so this is now olleh
# list slicing is from:exclusive to - so simply add 1 to fit with the ranges values 0-4
for k in ( h[0:i+1] for i in range(0,len(h)) ):
print(k)
Output:
o
ol
oll
olle
olleh
answered Nov 19 '18 at 19:25
Patrick ArtnerPatrick Artner
23.4k62343
You could also simply reverse the complete thing and print it sliced from the start to save you some headache:
b = "hello" # your input
h = b[::-1] # inverse all - so this is now olleh
# list slicing is from:exclusive to - so simply add 1 to fit with the ranges values 0-4
for k in ( h[0:i+1] for i in range(0,len(h)) ):
print(k)
Output:
o
ol
oll
olle
olleh
answered Nov 19 '18 at 19:25
Patrick ArtnerPatrick Artner
23.4k62343
answered Nov 19 '18 at 19:25
Patrick ArtnerPatrick Artner
23.4k62343
answered Nov 19 '18 at 19:25
Patrick ArtnerPatrick Artner
23.4k62343
answered Nov 19 '18 at 19:25
Patrick ArtnerPatrick Artner
23.4k62343
23.4k62343
add a comment |
add a comment |
The very basic method to reverse a string s is s[::-1] (and save it
in another variable, say s2).
Then, to print consecutive rows with increasing part of this string (s2),
you need a loop over range(1, len(s2)+1), stating the upper limit of s2
(excluding).
So the script can look like below:
s = 'hello'
s2 = s[::-1]
for i in range(1, len(s2)+1):
print(s2[:i])
answered Nov 19 '18 at 19:28
Valdi_BoValdi_Bo
4,7202815
add a comment |
The very basic method to reverse a string s is s[::-1] (and save it
in another variable, say s2).
Then, to print consecutive rows with increasing part of this string (s2),
you need a loop over range(1, len(s2)+1), stating the upper limit of s2
(excluding).
So the script can look like below:
s = 'hello'
s2 = s[::-1]
for i in range(1, len(s2)+1):
print(s2[:i])
answered Nov 19 '18 at 19:28
Valdi_BoValdi_Bo
4,7202815
add a comment |
The very basic method to reverse a string s is s[::-1] (and save it
in another variable, say s2).
Then, to print consecutive rows with increasing part of this string (s2),
you need a loop over range(1, len(s2)+1), stating the upper limit of s2
(excluding).
So the script can look like below:
s = 'hello'
s2 = s[::-1]
for i in range(1, len(s2)+1):
print(s2[:i])
answered Nov 19 '18 at 19:28
Valdi_BoValdi_Bo
4,7202815
The very basic method to reverse a string s is s[::-1] (and save it
in another variable, say s2).
Then, to print consecutive rows with increasing part of this string (s2),
you need a loop over range(1, len(s2)+1), stating the upper limit of s2
(excluding).
So the script can look like below:
s = 'hello'
s2 = s[::-1]
for i in range(1, len(s2)+1):
print(s2[:i])
answered Nov 19 '18 at 19:28
Valdi_BoValdi_Bo
4,7202815
answered Nov 19 '18 at 19:28
Valdi_BoValdi_Bo
4,7202815
answered Nov 19 '18 at 19:28
Valdi_BoValdi_Bo
4,7202815
answered Nov 19 '18 at 19:28
Valdi_BoValdi_Bo
4,7202815
4,7202815
add a comment |
add a comment |
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