Is it possible to use union of types in derived complexType?

I have an XSD type that contains an element with an abstract type.
There are some implementations of this type.
Does XSD provide a way to show, that some of the derived types can be used?

In the example below I have 3 implementations of BasicSequence. Does exist a way to say, that only two of them can be used in RealRoot?

<?xml version="1.0" encoding="UTF-8"?>

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified">

    <xs:complexType name="BasicSequence" abstract="true">

        <xs:sequence>

            <xs:element name="ElementA" type="xs:string"/>

            <xs:any/>

        </xs:sequence>

    </xs:complexType>



    <xs:complexType name="BasicRoot">

        <xs:sequence>

            <xs:element name="RealRoot" type="BasicSequence"/>

        </xs:sequence>

    </xs:complexType>



    <xs:complexType name="MySequence1">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB1" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="MySequence2">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB2" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="MySequence3">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB3" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="RealRoot">

        <xs:complexContent>

            <xs:restriction base="BasicRoot">

                <xs:sequence>

                    <!-- Use union of MySequence1 and MySequence2 here! -->

                    <xs:element name="RealRoot" type="BasicSequence"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>

</xs:schema>

asked Nov 16 '18 at 16:25

Igorious

264

add a comment |

I have an XSD type that contains an element with an abstract type.
There are some implementations of this type.
Does XSD provide a way to show, that some of the derived types can be used?

In the example below I have 3 implementations of BasicSequence. Does exist a way to say, that only two of them can be used in RealRoot?

<?xml version="1.0" encoding="UTF-8"?>

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified">

    <xs:complexType name="BasicSequence" abstract="true">

        <xs:sequence>

            <xs:element name="ElementA" type="xs:string"/>

            <xs:any/>

        </xs:sequence>

    </xs:complexType>



    <xs:complexType name="BasicRoot">

        <xs:sequence>

            <xs:element name="RealRoot" type="BasicSequence"/>

        </xs:sequence>

    </xs:complexType>



    <xs:complexType name="MySequence1">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB1" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="MySequence2">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB2" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="MySequence3">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB3" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="RealRoot">

        <xs:complexContent>

            <xs:restriction base="BasicRoot">

                <xs:sequence>

                    <!-- Use union of MySequence1 and MySequence2 here! -->

                    <xs:element name="RealRoot" type="BasicSequence"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>

</xs:schema>

asked Nov 16 '18 at 16:25

Igorious

264

add a comment |

I have an XSD type that contains an element with an abstract type.
There are some implementations of this type.
Does XSD provide a way to show, that some of the derived types can be used?

In the example below I have 3 implementations of BasicSequence. Does exist a way to say, that only two of them can be used in RealRoot?

<?xml version="1.0" encoding="UTF-8"?>

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified">

    <xs:complexType name="BasicSequence" abstract="true">

        <xs:sequence>

            <xs:element name="ElementA" type="xs:string"/>

            <xs:any/>

        </xs:sequence>

    </xs:complexType>



    <xs:complexType name="BasicRoot">

        <xs:sequence>

            <xs:element name="RealRoot" type="BasicSequence"/>

        </xs:sequence>

    </xs:complexType>



    <xs:complexType name="MySequence1">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB1" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="MySequence2">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB2" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="MySequence3">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB3" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="RealRoot">

        <xs:complexContent>

            <xs:restriction base="BasicRoot">

                <xs:sequence>

                    <!-- Use union of MySequence1 and MySequence2 here! -->

                    <xs:element name="RealRoot" type="BasicSequence"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>

</xs:schema>

asked Nov 16 '18 at 16:25

Igorious

264

I have an XSD type that contains an element with an abstract type.
There are some implementations of this type.
Does XSD provide a way to show, that some of the derived types can be used?

In the example below I have 3 implementations of BasicSequence. Does exist a way to say, that only two of them can be used in RealRoot?

<?xml version="1.0" encoding="UTF-8"?>

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified">

    <xs:complexType name="BasicSequence" abstract="true">

        <xs:sequence>

            <xs:element name="ElementA" type="xs:string"/>

            <xs:any/>

        </xs:sequence>

    </xs:complexType>



    <xs:complexType name="BasicRoot">

        <xs:sequence>

            <xs:element name="RealRoot" type="BasicSequence"/>

        </xs:sequence>

    </xs:complexType>



    <xs:complexType name="MySequence1">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB1" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="MySequence2">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB2" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="MySequence3">

        <xs:complexContent>

            <xs:restriction base="BasicSequence">

                <xs:sequence>

                    <xs:element name="ElementA" type="xs:string"/>

                    <xs:element name="ElementB3" type="xs:string"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>



    <xs:complexType name="RealRoot">

        <xs:complexContent>

            <xs:restriction base="BasicRoot">

                <xs:sequence>

                    <!-- Use union of MySequence1 and MySequence2 here! -->

                    <xs:element name="RealRoot" type="BasicSequence"/>

                </xs:sequence>

            </xs:restriction>

        </xs:complexContent>

    </xs:complexType>

</xs:schema>

xsd restriction complextype

asked Nov 16 '18 at 16:25

Igorious

264

asked Nov 16 '18 at 16:25

Igorious

264

asked Nov 16 '18 at 16:25

Igorious

264

asked Nov 16 '18 at 16:25

Igorious

264

asked Nov 16 '18 at 16:25

Igorious

264

add a comment |

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