How do I make my nicefrac fraction line larger?












2














I am trying to replicate this formula with LaTeX:



enter image description here



However, I am struggling to make the fraction look the same. This is my attempt:



begin{equation}

label{eq:alphaK}

alpha(k) = frac{1}{(N-k)} nicefrac{ left( displaystyle sum_{i=k+1}^{N} lambda_i right) }{left( displaystyle prod_{i=k+1}^N lambda_i right)^{frac{1}{N-k}}}

end{equation}


Which results in the following:



enter image description here



I am looking for a way to increase the size of the "slash" (/) that separates the numerator and denominator. I know I could use a normal frac instead of nicefrac but I like how it looks when num/den are displayed side by side.



Is there any way I can force the fraction to look more like the first pictured one?










share|improve this question




















  • 1




    welcome to tex.se! please, always provide complete small document (beginning with documentclass followed by necessary preamble and ending with end{document}).
    – Zarko
    Dec 12 '18 at 16:50








  • 1




    My apologies, I will do so in future
    – David Scott
    Dec 12 '18 at 17:10
















2














I am trying to replicate this formula with LaTeX:



enter image description here



However, I am struggling to make the fraction look the same. This is my attempt:



begin{equation}

label{eq:alphaK}

alpha(k) = frac{1}{(N-k)} nicefrac{ left( displaystyle sum_{i=k+1}^{N} lambda_i right) }{left( displaystyle prod_{i=k+1}^N lambda_i right)^{frac{1}{N-k}}}

end{equation}


Which results in the following:



enter image description here



I am looking for a way to increase the size of the "slash" (/) that separates the numerator and denominator. I know I could use a normal frac instead of nicefrac but I like how it looks when num/den are displayed side by side.



Is there any way I can force the fraction to look more like the first pictured one?










share|improve this question




















  • 1




    welcome to tex.se! please, always provide complete small document (beginning with documentclass followed by necessary preamble and ending with end{document}).
    – Zarko
    Dec 12 '18 at 16:50








  • 1




    My apologies, I will do so in future
    – David Scott
    Dec 12 '18 at 17:10














2












2








2


0





I am trying to replicate this formula with LaTeX:



enter image description here



However, I am struggling to make the fraction look the same. This is my attempt:



begin{equation}

label{eq:alphaK}

alpha(k) = frac{1}{(N-k)} nicefrac{ left( displaystyle sum_{i=k+1}^{N} lambda_i right) }{left( displaystyle prod_{i=k+1}^N lambda_i right)^{frac{1}{N-k}}}

end{equation}


Which results in the following:



enter image description here



I am looking for a way to increase the size of the "slash" (/) that separates the numerator and denominator. I know I could use a normal frac instead of nicefrac but I like how it looks when num/den are displayed side by side.



Is there any way I can force the fraction to look more like the first pictured one?










share|improve this question















I am trying to replicate this formula with LaTeX:



enter image description here



However, I am struggling to make the fraction look the same. This is my attempt:



begin{equation}

label{eq:alphaK}

alpha(k) = frac{1}{(N-k)} nicefrac{ left( displaystyle sum_{i=k+1}^{N} lambda_i right) }{left( displaystyle prod_{i=k+1}^N lambda_i right)^{frac{1}{N-k}}}

end{equation}


Which results in the following:



enter image description here



I am looking for a way to increase the size of the "slash" (/) that separates the numerator and denominator. I know I could use a normal frac instead of nicefrac but I like how it looks when num/den are displayed side by side.



Is there any way I can force the fraction to look more like the first pictured one?







math-mode fractions nicefrac






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 12 '18 at 17:10









andselisk

8752624




8752624










asked Dec 12 '18 at 16:43









David Scott

133




133








  • 1




    welcome to tex.se! please, always provide complete small document (beginning with documentclass followed by necessary preamble and ending with end{document}).
    – Zarko
    Dec 12 '18 at 16:50








  • 1




    My apologies, I will do so in future
    – David Scott
    Dec 12 '18 at 17:10














  • 1




    welcome to tex.se! please, always provide complete small document (beginning with documentclass followed by necessary preamble and ending with end{document}).
    – Zarko
    Dec 12 '18 at 16:50








  • 1




    My apologies, I will do so in future
    – David Scott
    Dec 12 '18 at 17:10








1




1




welcome to tex.se! please, always provide complete small document (beginning with documentclass followed by necessary preamble and ending with end{document}).
– Zarko
Dec 12 '18 at 16:50






welcome to tex.se! please, always provide complete small document (beginning with documentclass followed by necessary preamble and ending with end{document}).
– Zarko
Dec 12 '18 at 16:50






1




1




My apologies, I will do so in future
– David Scott
Dec 12 '18 at 17:10




My apologies, I will do so in future
– David Scott
Dec 12 '18 at 17:10










2 Answers
2






active

oldest

votes


















6














There are many ways. You will find two different in some variation below. The last one looks more like your desired output.



documentclass{memoir}
usepackage{amsmath,xfrac,mathtools}

begin{document}
begin{align}
alpha(k)
&=frac{1}{(N-k)}
left.
left(sum_{i=k+1}^{N} lambda_i right)
right/
left(prod_{i=k+1}^N lambda_i right)^{sfrac 1{(N-k)}}label{eq:alphaK}\
&=frac{1}{N-k}
left.
left(sum_{i=k+1}^{N} lambda_i right)
middle/
left(prod_{i=k+1}^N lambda_i right)^{frac 1{N-k}}
right.\
&=frac{1}{N-k}
biggl(,sum_{i=k+1}^{N} lambda_i biggr)
bigg/
biggl(,prod_{i=k+1}^N lambda_i biggr)^{1/{(N-k)}}\
%space added as suggested by Enrico Gregorio
&=frac
{sumlimits_{i=k+1}^{N} lambda_i}
{(N-k), sqrt[N-k]{prodlimits_{i=k+1}^Nlambda_i}}
&geq 1 textup{ (by the AM–GM inequality)}
end{align}
end{document}


enter image description here





Remarks.




  • Please pay attention to Zarko's comment.


  • The nicefrac package might be replaced by https://ctan.org/pkg/xfrac.


  • The question mathtools brackets larger than Bigg might be of interest for you.


  • Another useful package is https://ctan.org/pkg/mathtools, look for the sections dealing with delimiters.


  • Observe that I changed some aspects of the formula, which might collide with your notation.







share|improve this answer



















  • 1




    in your solutions you can omit displaystyle in both "fraction" terms. and if you use align, please add ampersands before equal signs.
    – Zarko
    Dec 12 '18 at 17:07








  • 1




    This worked perfectly, thank you very much!
    – David Scott
    Dec 12 '18 at 17:08










  • @Zarko Right, I did not noticed that it was there.
    – CampanIgnis
    Dec 12 '18 at 17:10






  • 2




    +1, for considering my comment :-)
    – Zarko
    Dec 12 '18 at 17:25










  • @DavidScott You are welcome.
    – CampanIgnis
    Dec 12 '18 at 23:23



















3














a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):



documentclass{article}
usepackage{nccmath}

begin{document}
begin{equation}%label{eq:alphaK}
alpha(k) = frac{1}{(N-k)}
left(sum_{i=k+1}^{N} lambda_i middle)
!middle/!
middle(prod_{i=k+1}^N lambda_i right)^{mfrac{1}{N-k}}
end{equation}
end{document}


enter image description here






share|improve this answer





















  • Very nice :-)...for the frozen fingers.
    – Sebastiano
    Dec 12 '18 at 21:15










  • @Zarko I then recommend you some お茶 for your fingers.
    – CampanIgnis
    Dec 12 '18 at 23:13












  • @Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
    – CampanIgnis
    Dec 12 '18 at 23:20












  • @CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach: left(<nominator>right)left(<denominator>right)^{-1}
    – Zarko
    Dec 12 '18 at 23:34













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









6














There are many ways. You will find two different in some variation below. The last one looks more like your desired output.



documentclass{memoir}
usepackage{amsmath,xfrac,mathtools}

begin{document}
begin{align}
alpha(k)
&=frac{1}{(N-k)}
left.
left(sum_{i=k+1}^{N} lambda_i right)
right/
left(prod_{i=k+1}^N lambda_i right)^{sfrac 1{(N-k)}}label{eq:alphaK}\
&=frac{1}{N-k}
left.
left(sum_{i=k+1}^{N} lambda_i right)
middle/
left(prod_{i=k+1}^N lambda_i right)^{frac 1{N-k}}
right.\
&=frac{1}{N-k}
biggl(,sum_{i=k+1}^{N} lambda_i biggr)
bigg/
biggl(,prod_{i=k+1}^N lambda_i biggr)^{1/{(N-k)}}\
%space added as suggested by Enrico Gregorio
&=frac
{sumlimits_{i=k+1}^{N} lambda_i}
{(N-k), sqrt[N-k]{prodlimits_{i=k+1}^Nlambda_i}}
&geq 1 textup{ (by the AM–GM inequality)}
end{align}
end{document}


enter image description here





Remarks.




  • Please pay attention to Zarko's comment.


  • The nicefrac package might be replaced by https://ctan.org/pkg/xfrac.


  • The question mathtools brackets larger than Bigg might be of interest for you.


  • Another useful package is https://ctan.org/pkg/mathtools, look for the sections dealing with delimiters.


  • Observe that I changed some aspects of the formula, which might collide with your notation.







share|improve this answer



















  • 1




    in your solutions you can omit displaystyle in both "fraction" terms. and if you use align, please add ampersands before equal signs.
    – Zarko
    Dec 12 '18 at 17:07








  • 1




    This worked perfectly, thank you very much!
    – David Scott
    Dec 12 '18 at 17:08










  • @Zarko Right, I did not noticed that it was there.
    – CampanIgnis
    Dec 12 '18 at 17:10






  • 2




    +1, for considering my comment :-)
    – Zarko
    Dec 12 '18 at 17:25










  • @DavidScott You are welcome.
    – CampanIgnis
    Dec 12 '18 at 23:23
















6














There are many ways. You will find two different in some variation below. The last one looks more like your desired output.



documentclass{memoir}
usepackage{amsmath,xfrac,mathtools}

begin{document}
begin{align}
alpha(k)
&=frac{1}{(N-k)}
left.
left(sum_{i=k+1}^{N} lambda_i right)
right/
left(prod_{i=k+1}^N lambda_i right)^{sfrac 1{(N-k)}}label{eq:alphaK}\
&=frac{1}{N-k}
left.
left(sum_{i=k+1}^{N} lambda_i right)
middle/
left(prod_{i=k+1}^N lambda_i right)^{frac 1{N-k}}
right.\
&=frac{1}{N-k}
biggl(,sum_{i=k+1}^{N} lambda_i biggr)
bigg/
biggl(,prod_{i=k+1}^N lambda_i biggr)^{1/{(N-k)}}\
%space added as suggested by Enrico Gregorio
&=frac
{sumlimits_{i=k+1}^{N} lambda_i}
{(N-k), sqrt[N-k]{prodlimits_{i=k+1}^Nlambda_i}}
&geq 1 textup{ (by the AM–GM inequality)}
end{align}
end{document}


enter image description here





Remarks.




  • Please pay attention to Zarko's comment.


  • The nicefrac package might be replaced by https://ctan.org/pkg/xfrac.


  • The question mathtools brackets larger than Bigg might be of interest for you.


  • Another useful package is https://ctan.org/pkg/mathtools, look for the sections dealing with delimiters.


  • Observe that I changed some aspects of the formula, which might collide with your notation.







share|improve this answer



















  • 1




    in your solutions you can omit displaystyle in both "fraction" terms. and if you use align, please add ampersands before equal signs.
    – Zarko
    Dec 12 '18 at 17:07








  • 1




    This worked perfectly, thank you very much!
    – David Scott
    Dec 12 '18 at 17:08










  • @Zarko Right, I did not noticed that it was there.
    – CampanIgnis
    Dec 12 '18 at 17:10






  • 2




    +1, for considering my comment :-)
    – Zarko
    Dec 12 '18 at 17:25










  • @DavidScott You are welcome.
    – CampanIgnis
    Dec 12 '18 at 23:23














6












6








6






There are many ways. You will find two different in some variation below. The last one looks more like your desired output.



documentclass{memoir}
usepackage{amsmath,xfrac,mathtools}

begin{document}
begin{align}
alpha(k)
&=frac{1}{(N-k)}
left.
left(sum_{i=k+1}^{N} lambda_i right)
right/
left(prod_{i=k+1}^N lambda_i right)^{sfrac 1{(N-k)}}label{eq:alphaK}\
&=frac{1}{N-k}
left.
left(sum_{i=k+1}^{N} lambda_i right)
middle/
left(prod_{i=k+1}^N lambda_i right)^{frac 1{N-k}}
right.\
&=frac{1}{N-k}
biggl(,sum_{i=k+1}^{N} lambda_i biggr)
bigg/
biggl(,prod_{i=k+1}^N lambda_i biggr)^{1/{(N-k)}}\
%space added as suggested by Enrico Gregorio
&=frac
{sumlimits_{i=k+1}^{N} lambda_i}
{(N-k), sqrt[N-k]{prodlimits_{i=k+1}^Nlambda_i}}
&geq 1 textup{ (by the AM–GM inequality)}
end{align}
end{document}


enter image description here





Remarks.




  • Please pay attention to Zarko's comment.


  • The nicefrac package might be replaced by https://ctan.org/pkg/xfrac.


  • The question mathtools brackets larger than Bigg might be of interest for you.


  • Another useful package is https://ctan.org/pkg/mathtools, look for the sections dealing with delimiters.


  • Observe that I changed some aspects of the formula, which might collide with your notation.







share|improve this answer














There are many ways. You will find two different in some variation below. The last one looks more like your desired output.



documentclass{memoir}
usepackage{amsmath,xfrac,mathtools}

begin{document}
begin{align}
alpha(k)
&=frac{1}{(N-k)}
left.
left(sum_{i=k+1}^{N} lambda_i right)
right/
left(prod_{i=k+1}^N lambda_i right)^{sfrac 1{(N-k)}}label{eq:alphaK}\
&=frac{1}{N-k}
left.
left(sum_{i=k+1}^{N} lambda_i right)
middle/
left(prod_{i=k+1}^N lambda_i right)^{frac 1{N-k}}
right.\
&=frac{1}{N-k}
biggl(,sum_{i=k+1}^{N} lambda_i biggr)
bigg/
biggl(,prod_{i=k+1}^N lambda_i biggr)^{1/{(N-k)}}\
%space added as suggested by Enrico Gregorio
&=frac
{sumlimits_{i=k+1}^{N} lambda_i}
{(N-k), sqrt[N-k]{prodlimits_{i=k+1}^Nlambda_i}}
&geq 1 textup{ (by the AM–GM inequality)}
end{align}
end{document}


enter image description here





Remarks.




  • Please pay attention to Zarko's comment.


  • The nicefrac package might be replaced by https://ctan.org/pkg/xfrac.


  • The question mathtools brackets larger than Bigg might be of interest for you.


  • Another useful package is https://ctan.org/pkg/mathtools, look for the sections dealing with delimiters.


  • Observe that I changed some aspects of the formula, which might collide with your notation.








share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 16 '18 at 12:02

























answered Dec 12 '18 at 16:57









CampanIgnis

2,5092831




2,5092831








  • 1




    in your solutions you can omit displaystyle in both "fraction" terms. and if you use align, please add ampersands before equal signs.
    – Zarko
    Dec 12 '18 at 17:07








  • 1




    This worked perfectly, thank you very much!
    – David Scott
    Dec 12 '18 at 17:08










  • @Zarko Right, I did not noticed that it was there.
    – CampanIgnis
    Dec 12 '18 at 17:10






  • 2




    +1, for considering my comment :-)
    – Zarko
    Dec 12 '18 at 17:25










  • @DavidScott You are welcome.
    – CampanIgnis
    Dec 12 '18 at 23:23














  • 1




    in your solutions you can omit displaystyle in both "fraction" terms. and if you use align, please add ampersands before equal signs.
    – Zarko
    Dec 12 '18 at 17:07








  • 1




    This worked perfectly, thank you very much!
    – David Scott
    Dec 12 '18 at 17:08










  • @Zarko Right, I did not noticed that it was there.
    – CampanIgnis
    Dec 12 '18 at 17:10






  • 2




    +1, for considering my comment :-)
    – Zarko
    Dec 12 '18 at 17:25










  • @DavidScott You are welcome.
    – CampanIgnis
    Dec 12 '18 at 23:23








1




1




in your solutions you can omit displaystyle in both "fraction" terms. and if you use align, please add ampersands before equal signs.
– Zarko
Dec 12 '18 at 17:07






in your solutions you can omit displaystyle in both "fraction" terms. and if you use align, please add ampersands before equal signs.
– Zarko
Dec 12 '18 at 17:07






1




1




This worked perfectly, thank you very much!
– David Scott
Dec 12 '18 at 17:08




This worked perfectly, thank you very much!
– David Scott
Dec 12 '18 at 17:08












@Zarko Right, I did not noticed that it was there.
– CampanIgnis
Dec 12 '18 at 17:10




@Zarko Right, I did not noticed that it was there.
– CampanIgnis
Dec 12 '18 at 17:10




2




2




+1, for considering my comment :-)
– Zarko
Dec 12 '18 at 17:25




+1, for considering my comment :-)
– Zarko
Dec 12 '18 at 17:25












@DavidScott You are welcome.
– CampanIgnis
Dec 12 '18 at 23:23




@DavidScott You are welcome.
– CampanIgnis
Dec 12 '18 at 23:23











3














a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):



documentclass{article}
usepackage{nccmath}

begin{document}
begin{equation}%label{eq:alphaK}
alpha(k) = frac{1}{(N-k)}
left(sum_{i=k+1}^{N} lambda_i middle)
!middle/!
middle(prod_{i=k+1}^N lambda_i right)^{mfrac{1}{N-k}}
end{equation}
end{document}


enter image description here






share|improve this answer





















  • Very nice :-)...for the frozen fingers.
    – Sebastiano
    Dec 12 '18 at 21:15










  • @Zarko I then recommend you some お茶 for your fingers.
    – CampanIgnis
    Dec 12 '18 at 23:13












  • @Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
    – CampanIgnis
    Dec 12 '18 at 23:20












  • @CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach: left(<nominator>right)left(<denominator>right)^{-1}
    – Zarko
    Dec 12 '18 at 23:34


















3














a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):



documentclass{article}
usepackage{nccmath}

begin{document}
begin{equation}%label{eq:alphaK}
alpha(k) = frac{1}{(N-k)}
left(sum_{i=k+1}^{N} lambda_i middle)
!middle/!
middle(prod_{i=k+1}^N lambda_i right)^{mfrac{1}{N-k}}
end{equation}
end{document}


enter image description here






share|improve this answer





















  • Very nice :-)...for the frozen fingers.
    – Sebastiano
    Dec 12 '18 at 21:15










  • @Zarko I then recommend you some お茶 for your fingers.
    – CampanIgnis
    Dec 12 '18 at 23:13












  • @Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
    – CampanIgnis
    Dec 12 '18 at 23:20












  • @CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach: left(<nominator>right)left(<denominator>right)^{-1}
    – Zarko
    Dec 12 '18 at 23:34
















3












3








3






a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):



documentclass{article}
usepackage{nccmath}

begin{document}
begin{equation}%label{eq:alphaK}
alpha(k) = frac{1}{(N-k)}
left(sum_{i=k+1}^{N} lambda_i middle)
!middle/!
middle(prod_{i=k+1}^N lambda_i right)^{mfrac{1}{N-k}}
end{equation}
end{document}


enter image description here






share|improve this answer












a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):



documentclass{article}
usepackage{nccmath}

begin{document}
begin{equation}%label{eq:alphaK}
alpha(k) = frac{1}{(N-k)}
left(sum_{i=k+1}^{N} lambda_i middle)
!middle/!
middle(prod_{i=k+1}^N lambda_i right)^{mfrac{1}{N-k}}
end{equation}
end{document}


enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 12 '18 at 17:37









Zarko

121k865156




121k865156












  • Very nice :-)...for the frozen fingers.
    – Sebastiano
    Dec 12 '18 at 21:15










  • @Zarko I then recommend you some お茶 for your fingers.
    – CampanIgnis
    Dec 12 '18 at 23:13












  • @Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
    – CampanIgnis
    Dec 12 '18 at 23:20












  • @CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach: left(<nominator>right)left(<denominator>right)^{-1}
    – Zarko
    Dec 12 '18 at 23:34




















  • Very nice :-)...for the frozen fingers.
    – Sebastiano
    Dec 12 '18 at 21:15










  • @Zarko I then recommend you some お茶 for your fingers.
    – CampanIgnis
    Dec 12 '18 at 23:13












  • @Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
    – CampanIgnis
    Dec 12 '18 at 23:20












  • @CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach: left(<nominator>right)left(<denominator>right)^{-1}
    – Zarko
    Dec 12 '18 at 23:34


















Very nice :-)...for the frozen fingers.
– Sebastiano
Dec 12 '18 at 21:15




Very nice :-)...for the frozen fingers.
– Sebastiano
Dec 12 '18 at 21:15












@Zarko I then recommend you some お茶 for your fingers.
– CampanIgnis
Dec 12 '18 at 23:13






@Zarko I then recommend you some お茶 for your fingers.
– CampanIgnis
Dec 12 '18 at 23:13














@Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
– CampanIgnis
Dec 12 '18 at 23:20






@Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
– CampanIgnis
Dec 12 '18 at 23:20














@CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach: left(<nominator>right)left(<denominator>right)^{-1}
– Zarko
Dec 12 '18 at 23:34






@CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach: left(<nominator>right)left(<denominator>right)^{-1}
– Zarko
Dec 12 '18 at 23:34




















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