How do I make my nicefrac fraction line larger?
I am trying to replicate this formula with LaTeX:
However, I am struggling to make the fraction look the same. This is my attempt:
begin{equation}
label{eq:alphaK}
alpha(k) = frac{1}{(N-k)} nicefrac{ left( displaystyle sum_{i=k+1}^{N} lambda_i right) }{left( displaystyle prod_{i=k+1}^N lambda_i right)^{frac{1}{N-k}}}
end{equation}
Which results in the following:
I am looking for a way to increase the size of the "slash" (/) that separates the numerator and denominator. I know I could use a normal frac
instead of nicefrac
but I like how it looks when num/den are displayed side by side.
Is there any way I can force the fraction to look more like the first pictured one?
math-mode fractions nicefrac
add a comment |
I am trying to replicate this formula with LaTeX:
However, I am struggling to make the fraction look the same. This is my attempt:
begin{equation}
label{eq:alphaK}
alpha(k) = frac{1}{(N-k)} nicefrac{ left( displaystyle sum_{i=k+1}^{N} lambda_i right) }{left( displaystyle prod_{i=k+1}^N lambda_i right)^{frac{1}{N-k}}}
end{equation}
Which results in the following:
I am looking for a way to increase the size of the "slash" (/) that separates the numerator and denominator. I know I could use a normal frac
instead of nicefrac
but I like how it looks when num/den are displayed side by side.
Is there any way I can force the fraction to look more like the first pictured one?
math-mode fractions nicefrac
1
welcome to tex.se! please, always provide complete small document (beginning withdocumentclass
followed by necessary preamble and ending withend{document}
).
– Zarko
Dec 12 '18 at 16:50
1
My apologies, I will do so in future
– David Scott
Dec 12 '18 at 17:10
add a comment |
I am trying to replicate this formula with LaTeX:
However, I am struggling to make the fraction look the same. This is my attempt:
begin{equation}
label{eq:alphaK}
alpha(k) = frac{1}{(N-k)} nicefrac{ left( displaystyle sum_{i=k+1}^{N} lambda_i right) }{left( displaystyle prod_{i=k+1}^N lambda_i right)^{frac{1}{N-k}}}
end{equation}
Which results in the following:
I am looking for a way to increase the size of the "slash" (/) that separates the numerator and denominator. I know I could use a normal frac
instead of nicefrac
but I like how it looks when num/den are displayed side by side.
Is there any way I can force the fraction to look more like the first pictured one?
math-mode fractions nicefrac
I am trying to replicate this formula with LaTeX:
However, I am struggling to make the fraction look the same. This is my attempt:
begin{equation}
label{eq:alphaK}
alpha(k) = frac{1}{(N-k)} nicefrac{ left( displaystyle sum_{i=k+1}^{N} lambda_i right) }{left( displaystyle prod_{i=k+1}^N lambda_i right)^{frac{1}{N-k}}}
end{equation}
Which results in the following:
I am looking for a way to increase the size of the "slash" (/) that separates the numerator and denominator. I know I could use a normal frac
instead of nicefrac
but I like how it looks when num/den are displayed side by side.
Is there any way I can force the fraction to look more like the first pictured one?
math-mode fractions nicefrac
math-mode fractions nicefrac
edited Dec 12 '18 at 17:10
andselisk
8752624
8752624
asked Dec 12 '18 at 16:43
David Scott
133
133
1
welcome to tex.se! please, always provide complete small document (beginning withdocumentclass
followed by necessary preamble and ending withend{document}
).
– Zarko
Dec 12 '18 at 16:50
1
My apologies, I will do so in future
– David Scott
Dec 12 '18 at 17:10
add a comment |
1
welcome to tex.se! please, always provide complete small document (beginning withdocumentclass
followed by necessary preamble and ending withend{document}
).
– Zarko
Dec 12 '18 at 16:50
1
My apologies, I will do so in future
– David Scott
Dec 12 '18 at 17:10
1
1
welcome to tex.se! please, always provide complete small document (beginning with
documentclass
followed by necessary preamble and ending with end{document}
).– Zarko
Dec 12 '18 at 16:50
welcome to tex.se! please, always provide complete small document (beginning with
documentclass
followed by necessary preamble and ending with end{document}
).– Zarko
Dec 12 '18 at 16:50
1
1
My apologies, I will do so in future
– David Scott
Dec 12 '18 at 17:10
My apologies, I will do so in future
– David Scott
Dec 12 '18 at 17:10
add a comment |
2 Answers
2
active
oldest
votes
There are many ways. You will find two different in some variation below. The last one looks more like your desired output.
documentclass{memoir}
usepackage{amsmath,xfrac,mathtools}
begin{document}
begin{align}
alpha(k)
&=frac{1}{(N-k)}
left.
left(sum_{i=k+1}^{N} lambda_i right)
right/
left(prod_{i=k+1}^N lambda_i right)^{sfrac 1{(N-k)}}label{eq:alphaK}\
&=frac{1}{N-k}
left.
left(sum_{i=k+1}^{N} lambda_i right)
middle/
left(prod_{i=k+1}^N lambda_i right)^{frac 1{N-k}}
right.\
&=frac{1}{N-k}
biggl(,sum_{i=k+1}^{N} lambda_i biggr)
bigg/
biggl(,prod_{i=k+1}^N lambda_i biggr)^{1/{(N-k)}}\
%space added as suggested by Enrico Gregorio
&=frac
{sumlimits_{i=k+1}^{N} lambda_i}
{(N-k), sqrt[N-k]{prodlimits_{i=k+1}^Nlambda_i}}
&geq 1 textup{ (by the AM–GM inequality)}
end{align}
end{document}
Remarks.
Please pay attention to Zarko's comment.
The nicefrac package might be replaced by https://ctan.org/pkg/xfrac.
The question mathtools brackets larger than Bigg might be of interest for you.
Another useful package is https://ctan.org/pkg/mathtools, look for the sections dealing with delimiters.
Observe that I changed some aspects of the formula, which might collide with your notation.
1
in your solutions you can omitdisplaystyle
in both "fraction" terms. and if you usealign
, please add ampersands before equal signs.
– Zarko
Dec 12 '18 at 17:07
1
This worked perfectly, thank you very much!
– David Scott
Dec 12 '18 at 17:08
@Zarko Right, I did not noticed that it was there.
– CampanIgnis
Dec 12 '18 at 17:10
2
+1, for considering my comment :-)
– Zarko
Dec 12 '18 at 17:25
@DavidScott You are welcome.
– CampanIgnis
Dec 12 '18 at 23:23
add a comment |
a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):
documentclass{article}
usepackage{nccmath}
begin{document}
begin{equation}%label{eq:alphaK}
alpha(k) = frac{1}{(N-k)}
left(sum_{i=k+1}^{N} lambda_i middle)
!middle/!
middle(prod_{i=k+1}^N lambda_i right)^{mfrac{1}{N-k}}
end{equation}
end{document}
Very nice :-)...for the frozen fingers.
– Sebastiano
Dec 12 '18 at 21:15
@Zarko I then recommend you some お茶 for your fingers.
– CampanIgnis
Dec 12 '18 at 23:13
@Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
– CampanIgnis
Dec 12 '18 at 23:20
@CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach:left(<nominator>right)left(<denominator>right)^{-1}
– Zarko
Dec 12 '18 at 23:34
add a comment |
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2 Answers
2
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oldest
votes
2 Answers
2
active
oldest
votes
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oldest
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oldest
votes
There are many ways. You will find two different in some variation below. The last one looks more like your desired output.
documentclass{memoir}
usepackage{amsmath,xfrac,mathtools}
begin{document}
begin{align}
alpha(k)
&=frac{1}{(N-k)}
left.
left(sum_{i=k+1}^{N} lambda_i right)
right/
left(prod_{i=k+1}^N lambda_i right)^{sfrac 1{(N-k)}}label{eq:alphaK}\
&=frac{1}{N-k}
left.
left(sum_{i=k+1}^{N} lambda_i right)
middle/
left(prod_{i=k+1}^N lambda_i right)^{frac 1{N-k}}
right.\
&=frac{1}{N-k}
biggl(,sum_{i=k+1}^{N} lambda_i biggr)
bigg/
biggl(,prod_{i=k+1}^N lambda_i biggr)^{1/{(N-k)}}\
%space added as suggested by Enrico Gregorio
&=frac
{sumlimits_{i=k+1}^{N} lambda_i}
{(N-k), sqrt[N-k]{prodlimits_{i=k+1}^Nlambda_i}}
&geq 1 textup{ (by the AM–GM inequality)}
end{align}
end{document}
Remarks.
Please pay attention to Zarko's comment.
The nicefrac package might be replaced by https://ctan.org/pkg/xfrac.
The question mathtools brackets larger than Bigg might be of interest for you.
Another useful package is https://ctan.org/pkg/mathtools, look for the sections dealing with delimiters.
Observe that I changed some aspects of the formula, which might collide with your notation.
1
in your solutions you can omitdisplaystyle
in both "fraction" terms. and if you usealign
, please add ampersands before equal signs.
– Zarko
Dec 12 '18 at 17:07
1
This worked perfectly, thank you very much!
– David Scott
Dec 12 '18 at 17:08
@Zarko Right, I did not noticed that it was there.
– CampanIgnis
Dec 12 '18 at 17:10
2
+1, for considering my comment :-)
– Zarko
Dec 12 '18 at 17:25
@DavidScott You are welcome.
– CampanIgnis
Dec 12 '18 at 23:23
add a comment |
There are many ways. You will find two different in some variation below. The last one looks more like your desired output.
documentclass{memoir}
usepackage{amsmath,xfrac,mathtools}
begin{document}
begin{align}
alpha(k)
&=frac{1}{(N-k)}
left.
left(sum_{i=k+1}^{N} lambda_i right)
right/
left(prod_{i=k+1}^N lambda_i right)^{sfrac 1{(N-k)}}label{eq:alphaK}\
&=frac{1}{N-k}
left.
left(sum_{i=k+1}^{N} lambda_i right)
middle/
left(prod_{i=k+1}^N lambda_i right)^{frac 1{N-k}}
right.\
&=frac{1}{N-k}
biggl(,sum_{i=k+1}^{N} lambda_i biggr)
bigg/
biggl(,prod_{i=k+1}^N lambda_i biggr)^{1/{(N-k)}}\
%space added as suggested by Enrico Gregorio
&=frac
{sumlimits_{i=k+1}^{N} lambda_i}
{(N-k), sqrt[N-k]{prodlimits_{i=k+1}^Nlambda_i}}
&geq 1 textup{ (by the AM–GM inequality)}
end{align}
end{document}
Remarks.
Please pay attention to Zarko's comment.
The nicefrac package might be replaced by https://ctan.org/pkg/xfrac.
The question mathtools brackets larger than Bigg might be of interest for you.
Another useful package is https://ctan.org/pkg/mathtools, look for the sections dealing with delimiters.
Observe that I changed some aspects of the formula, which might collide with your notation.
1
in your solutions you can omitdisplaystyle
in both "fraction" terms. and if you usealign
, please add ampersands before equal signs.
– Zarko
Dec 12 '18 at 17:07
1
This worked perfectly, thank you very much!
– David Scott
Dec 12 '18 at 17:08
@Zarko Right, I did not noticed that it was there.
– CampanIgnis
Dec 12 '18 at 17:10
2
+1, for considering my comment :-)
– Zarko
Dec 12 '18 at 17:25
@DavidScott You are welcome.
– CampanIgnis
Dec 12 '18 at 23:23
add a comment |
There are many ways. You will find two different in some variation below. The last one looks more like your desired output.
documentclass{memoir}
usepackage{amsmath,xfrac,mathtools}
begin{document}
begin{align}
alpha(k)
&=frac{1}{(N-k)}
left.
left(sum_{i=k+1}^{N} lambda_i right)
right/
left(prod_{i=k+1}^N lambda_i right)^{sfrac 1{(N-k)}}label{eq:alphaK}\
&=frac{1}{N-k}
left.
left(sum_{i=k+1}^{N} lambda_i right)
middle/
left(prod_{i=k+1}^N lambda_i right)^{frac 1{N-k}}
right.\
&=frac{1}{N-k}
biggl(,sum_{i=k+1}^{N} lambda_i biggr)
bigg/
biggl(,prod_{i=k+1}^N lambda_i biggr)^{1/{(N-k)}}\
%space added as suggested by Enrico Gregorio
&=frac
{sumlimits_{i=k+1}^{N} lambda_i}
{(N-k), sqrt[N-k]{prodlimits_{i=k+1}^Nlambda_i}}
&geq 1 textup{ (by the AM–GM inequality)}
end{align}
end{document}
Remarks.
Please pay attention to Zarko's comment.
The nicefrac package might be replaced by https://ctan.org/pkg/xfrac.
The question mathtools brackets larger than Bigg might be of interest for you.
Another useful package is https://ctan.org/pkg/mathtools, look for the sections dealing with delimiters.
Observe that I changed some aspects of the formula, which might collide with your notation.
There are many ways. You will find two different in some variation below. The last one looks more like your desired output.
documentclass{memoir}
usepackage{amsmath,xfrac,mathtools}
begin{document}
begin{align}
alpha(k)
&=frac{1}{(N-k)}
left.
left(sum_{i=k+1}^{N} lambda_i right)
right/
left(prod_{i=k+1}^N lambda_i right)^{sfrac 1{(N-k)}}label{eq:alphaK}\
&=frac{1}{N-k}
left.
left(sum_{i=k+1}^{N} lambda_i right)
middle/
left(prod_{i=k+1}^N lambda_i right)^{frac 1{N-k}}
right.\
&=frac{1}{N-k}
biggl(,sum_{i=k+1}^{N} lambda_i biggr)
bigg/
biggl(,prod_{i=k+1}^N lambda_i biggr)^{1/{(N-k)}}\
%space added as suggested by Enrico Gregorio
&=frac
{sumlimits_{i=k+1}^{N} lambda_i}
{(N-k), sqrt[N-k]{prodlimits_{i=k+1}^Nlambda_i}}
&geq 1 textup{ (by the AM–GM inequality)}
end{align}
end{document}
Remarks.
Please pay attention to Zarko's comment.
The nicefrac package might be replaced by https://ctan.org/pkg/xfrac.
The question mathtools brackets larger than Bigg might be of interest for you.
Another useful package is https://ctan.org/pkg/mathtools, look for the sections dealing with delimiters.
Observe that I changed some aspects of the formula, which might collide with your notation.
edited Dec 16 '18 at 12:02
answered Dec 12 '18 at 16:57
CampanIgnis
2,5092831
2,5092831
1
in your solutions you can omitdisplaystyle
in both "fraction" terms. and if you usealign
, please add ampersands before equal signs.
– Zarko
Dec 12 '18 at 17:07
1
This worked perfectly, thank you very much!
– David Scott
Dec 12 '18 at 17:08
@Zarko Right, I did not noticed that it was there.
– CampanIgnis
Dec 12 '18 at 17:10
2
+1, for considering my comment :-)
– Zarko
Dec 12 '18 at 17:25
@DavidScott You are welcome.
– CampanIgnis
Dec 12 '18 at 23:23
add a comment |
1
in your solutions you can omitdisplaystyle
in both "fraction" terms. and if you usealign
, please add ampersands before equal signs.
– Zarko
Dec 12 '18 at 17:07
1
This worked perfectly, thank you very much!
– David Scott
Dec 12 '18 at 17:08
@Zarko Right, I did not noticed that it was there.
– CampanIgnis
Dec 12 '18 at 17:10
2
+1, for considering my comment :-)
– Zarko
Dec 12 '18 at 17:25
@DavidScott You are welcome.
– CampanIgnis
Dec 12 '18 at 23:23
1
1
in your solutions you can omit
displaystyle
in both "fraction" terms. and if you use align
, please add ampersands before equal signs.– Zarko
Dec 12 '18 at 17:07
in your solutions you can omit
displaystyle
in both "fraction" terms. and if you use align
, please add ampersands before equal signs.– Zarko
Dec 12 '18 at 17:07
1
1
This worked perfectly, thank you very much!
– David Scott
Dec 12 '18 at 17:08
This worked perfectly, thank you very much!
– David Scott
Dec 12 '18 at 17:08
@Zarko Right, I did not noticed that it was there.
– CampanIgnis
Dec 12 '18 at 17:10
@Zarko Right, I did not noticed that it was there.
– CampanIgnis
Dec 12 '18 at 17:10
2
2
+1, for considering my comment :-)
– Zarko
Dec 12 '18 at 17:25
+1, for considering my comment :-)
– Zarko
Dec 12 '18 at 17:25
@DavidScott You are welcome.
– CampanIgnis
Dec 12 '18 at 23:23
@DavidScott You are welcome.
– CampanIgnis
Dec 12 '18 at 23:23
add a comment |
a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):
documentclass{article}
usepackage{nccmath}
begin{document}
begin{equation}%label{eq:alphaK}
alpha(k) = frac{1}{(N-k)}
left(sum_{i=k+1}^{N} lambda_i middle)
!middle/!
middle(prod_{i=k+1}^N lambda_i right)^{mfrac{1}{N-k}}
end{equation}
end{document}
Very nice :-)...for the frozen fingers.
– Sebastiano
Dec 12 '18 at 21:15
@Zarko I then recommend you some お茶 for your fingers.
– CampanIgnis
Dec 12 '18 at 23:13
@Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
– CampanIgnis
Dec 12 '18 at 23:20
@CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach:left(<nominator>right)left(<denominator>right)^{-1}
– Zarko
Dec 12 '18 at 23:34
add a comment |
a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):
documentclass{article}
usepackage{nccmath}
begin{document}
begin{equation}%label{eq:alphaK}
alpha(k) = frac{1}{(N-k)}
left(sum_{i=k+1}^{N} lambda_i middle)
!middle/!
middle(prod_{i=k+1}^N lambda_i right)^{mfrac{1}{N-k}}
end{equation}
end{document}
Very nice :-)...for the frozen fingers.
– Sebastiano
Dec 12 '18 at 21:15
@Zarko I then recommend you some お茶 for your fingers.
– CampanIgnis
Dec 12 '18 at 23:13
@Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
– CampanIgnis
Dec 12 '18 at 23:20
@CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach:left(<nominator>right)left(<denominator>right)^{-1}
– Zarko
Dec 12 '18 at 23:34
add a comment |
a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):
documentclass{article}
usepackage{nccmath}
begin{document}
begin{equation}%label{eq:alphaK}
alpha(k) = frac{1}{(N-k)}
left(sum_{i=k+1}^{N} lambda_i middle)
!middle/!
middle(prod_{i=k+1}^N lambda_i right)^{mfrac{1}{N-k}}
end{equation}
end{document}
a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):
documentclass{article}
usepackage{nccmath}
begin{document}
begin{equation}%label{eq:alphaK}
alpha(k) = frac{1}{(N-k)}
left(sum_{i=k+1}^{N} lambda_i middle)
!middle/!
middle(prod_{i=k+1}^N lambda_i right)^{mfrac{1}{N-k}}
end{equation}
end{document}
answered Dec 12 '18 at 17:37
Zarko
121k865156
121k865156
Very nice :-)...for the frozen fingers.
– Sebastiano
Dec 12 '18 at 21:15
@Zarko I then recommend you some お茶 for your fingers.
– CampanIgnis
Dec 12 '18 at 23:13
@Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
– CampanIgnis
Dec 12 '18 at 23:20
@CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach:left(<nominator>right)left(<denominator>right)^{-1}
– Zarko
Dec 12 '18 at 23:34
add a comment |
Very nice :-)...for the frozen fingers.
– Sebastiano
Dec 12 '18 at 21:15
@Zarko I then recommend you some お茶 for your fingers.
– CampanIgnis
Dec 12 '18 at 23:13
@Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
– CampanIgnis
Dec 12 '18 at 23:20
@CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach:left(<nominator>right)left(<denominator>right)^{-1}
– Zarko
Dec 12 '18 at 23:34
Very nice :-)...for the frozen fingers.
– Sebastiano
Dec 12 '18 at 21:15
Very nice :-)...for the frozen fingers.
– Sebastiano
Dec 12 '18 at 21:15
@Zarko I then recommend you some お茶 for your fingers.
– CampanIgnis
Dec 12 '18 at 23:13
@Zarko I then recommend you some お茶 for your fingers.
– CampanIgnis
Dec 12 '18 at 23:13
@Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
– CampanIgnis
Dec 12 '18 at 23:20
@Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional?
– CampanIgnis
Dec 12 '18 at 23:20
@CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach:
left(<nominator>right)left(<denominator>right)^{-1}
– Zarko
Dec 12 '18 at 23:34
@CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach:
left(<nominator>right)left(<denominator>right)^{-1}
– Zarko
Dec 12 '18 at 23:34
add a comment |
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welcome to tex.se! please, always provide complete small document (beginning with
documentclass
followed by necessary preamble and ending withend{document}
).– Zarko
Dec 12 '18 at 16:50
1
My apologies, I will do so in future
– David Scott
Dec 12 '18 at 17:10