How to split a string that contains a set in Ruby?
4
I am new to the forum. I am currently trying to take this string:
65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010
and split it in order to get this:
65101km
Sedan
Manual
18131A
FWD
Used
5.5L/100km
Toyota
camry
SE
{AC, Heated Seats, Heated Mirrors, Keyless Entry}
2010
I have the following regex:
data_from_file.split(/[{},]+/)
But I am having a hard time keeping the set.
Any ideas?
ruby regex split
asked Nov 16 '18 at 15:13
Andres V.
234
add a comment |
4
I am new to the forum. I am currently trying to take this string:
65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010
and split it in order to get this:
65101km
Sedan
Manual
18131A
FWD
Used
5.5L/100km
Toyota
camry
SE
{AC, Heated Seats, Heated Mirrors, Keyless Entry}
2010
I have the following regex:
data_from_file.split(/[{},]+/)
But I am having a hard time keeping the set.
Any ideas?
ruby regex split
asked Nov 16 '18 at 15:13
Andres V.
234
Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel
– vovan
Nov 16 '18 at 15:57
In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.
– Cary Swoveland
Nov 17 '18 at 20:23
add a comment |
4
4
4
1
I am new to the forum. I am currently trying to take this string:
65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010
and split it in order to get this:
65101km
Sedan
Manual
18131A
FWD
Used
5.5L/100km
Toyota
camry
SE
{AC, Heated Seats, Heated Mirrors, Keyless Entry}
2010
I have the following regex:
data_from_file.split(/[{},]+/)
But I am having a hard time keeping the set.
Any ideas?
ruby regex split
asked Nov 16 '18 at 15:13
Andres V.
234
I am new to the forum. I am currently trying to take this string:
65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010
and split it in order to get this:
65101km
Sedan
Manual
18131A
FWD
Used
5.5L/100km
Toyota
camry
SE
{AC, Heated Seats, Heated Mirrors, Keyless Entry}
2010
I have the following regex:
data_from_file.split(/[{},]+/)
But I am having a hard time keeping the set.
Any ideas?
ruby regex split
ruby regex split
asked Nov 16 '18 at 15:13
Andres V.
234
asked Nov 16 '18 at 15:13
Andres V.
234
asked Nov 16 '18 at 15:13
Andres V.
234
asked Nov 16 '18 at 15:13
Andres V.
234
asked Nov 16 '18 at 15:13
Andres V.
234
234
Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel
– vovan
Nov 16 '18 at 15:57
In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.
– Cary Swoveland
Nov 17 '18 at 20:23
add a comment |
Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel
– vovan
Nov 16 '18 at 15:57
In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.
– Cary Swoveland
Nov 17 '18 at 20:23
Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel
– vovan
Nov 16 '18 at 15:57
Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel
– vovan
Nov 16 '18 at 15:57
In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (
["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.– Cary Swoveland
Nov 17 '18 at 20:23
In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (
["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.– Cary Swoveland
Nov 17 '18 at 20:23
add a comment |
2 Answers
2
active
oldest
votes
1
You may use
s.scan(/(?:{[^{}]*}|[^,])+/)
See the Rubular and Regex.101 demos.
Pattern details
(?:- start of a non-capturing group:
{[^{}]*}-{, 0 or more chars other than{and}and then}
|- or
[^,]- any 1 char other than,
)+- repeated 1 or more times.
answered Nov 16 '18 at 16:55
Wiktor Stribiżew
308k16126202
1
Simple and clean!
– Cary Swoveland
Nov 17 '18 at 3:05
1
This is really nice! Thank you so much
– Andres V.
Nov 17 '18 at 17:39
add a comment |
1
str = "65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010"
r = /
(?<=A|,) # match the beginning of the string or a comma in a positive lookbehind
(?: # begin a non-capture group
{.*?} # match an open brace followed by any number of characters,
# lazily, followed by a closed brace
| # or
.*? # match any number of characters, lazily
) # close non-capture group
(?=,|z) # match a comma or the end of the string in a positive lookahead
/x # free-spacing regex definition mode
str.scan r
#=> ["65101km", "Sedan", "Manual", "18131A", "FWD", "Used", "5.5L/100km", "Toyota",
# "camry", "SE", "{AC,Heated Seats, Heated Mirrors, Keyless Entry}", "2010"]
Two notes follow. I'll illustrate these with a simpler string.
str = "65101km,Sedan,{AC,Heated Seats},2010"
{.*?} must precede .*? in (?:{.*?}|.*?)
If
r = /(?<=A|,)(?:.*?|{.*?})(?=,|z)/
then
str.scan r
#=> ["65101km", "Sedan", "{AC", "Heated Seats}", "2010"]
The matches .* must be lazy (aka non-greedy)
If
r = /(?<=A|,)(?:{.*?}|.*)(?=,|z)/
then
str.scan r
#=> ["65101km,Sedan,{AC,Heated Seats},2010"]
If
r = /(?<=A|,)(?:{.*}|.*?)(?=,|z)/
then
"65101km,Sedan,{AC,Heated Seats},2010,{starter motor, pneumatic tires}".scan r
#=> ["65101km", "Sedan", "{AC,Heated Seats},2010,{starter motor, pneumatic tires}"]
answered Nov 16 '18 at 15:55
Cary Swoveland
67.6k53965
Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !
– Andres V.
Nov 16 '18 at 16:03
1
What can I say? Ruby matches"2010". Did you perchance test with a string that contains a space between the last comma and "2010"?
– Cary Swoveland
Nov 16 '18 at 16:21
1
At Regex101,2010is matched.
– Wiktor Stribiżew
Nov 16 '18 at 16:53
just tried it out its perfect! Thanks guys. I had put a space like Gary said.
– Andres V.
Nov 17 '18 at 17:37
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You may use
s.scan(/(?:{[^{}]*}|[^,])+/)
See the Rubular and Regex.101 demos.
Pattern details
(?:- start of a non-capturing group:
{[^{}]*}-{, 0 or more chars other than{and}and then}
|- or
[^,]- any 1 char other than,
)+- repeated 1 or more times.
answered Nov 16 '18 at 16:55
Wiktor Stribiżew
308k16126202
1
Simple and clean!
– Cary Swoveland
Nov 17 '18 at 3:05
1
This is really nice! Thank you so much
– Andres V.
Nov 17 '18 at 17:39
add a comment |
1
You may use
s.scan(/(?:{[^{}]*}|[^,])+/)
See the Rubular and Regex.101 demos.
Pattern details
(?:- start of a non-capturing group:
{[^{}]*}-{, 0 or more chars other than{and}and then}
|- or
[^,]- any 1 char other than,
)+- repeated 1 or more times.
answered Nov 16 '18 at 16:55
Wiktor Stribiżew
308k16126202
1
Simple and clean!
– Cary Swoveland
Nov 17 '18 at 3:05
1
This is really nice! Thank you so much
– Andres V.
Nov 17 '18 at 17:39
add a comment |
1
1
1
You may use
s.scan(/(?:{[^{}]*}|[^,])+/)
See the Rubular and Regex.101 demos.
Pattern details
(?:- start of a non-capturing group:
{[^{}]*}-{, 0 or more chars other than{and}and then}
|- or
[^,]- any 1 char other than,
)+- repeated 1 or more times.
answered Nov 16 '18 at 16:55
Wiktor Stribiżew
308k16126202
You may use
s.scan(/(?:{[^{}]*}|[^,])+/)
See the Rubular and Regex.101 demos.
Pattern details
(?:- start of a non-capturing group:
{[^{}]*}-{, 0 or more chars other than{and}and then}
|- or
[^,]- any 1 char other than,
)+- repeated 1 or more times.
answered Nov 16 '18 at 16:55
Wiktor Stribiżew
308k16126202
answered Nov 16 '18 at 16:55
Wiktor Stribiżew
308k16126202
answered Nov 16 '18 at 16:55
Wiktor Stribiżew
308k16126202
answered Nov 16 '18 at 16:55
Wiktor Stribiżew
308k16126202
308k16126202
1
Simple and clean!
– Cary Swoveland
Nov 17 '18 at 3:05
1
This is really nice! Thank you so much
– Andres V.
Nov 17 '18 at 17:39
add a comment |
1
Simple and clean!
– Cary Swoveland
Nov 17 '18 at 3:05
1
This is really nice! Thank you so much
– Andres V.
Nov 17 '18 at 17:39
1
1
Simple and clean!
– Cary Swoveland
Nov 17 '18 at 3:05
Simple and clean!
– Cary Swoveland
Nov 17 '18 at 3:05
1
1
This is really nice! Thank you so much
– Andres V.
Nov 17 '18 at 17:39
This is really nice! Thank you so much
– Andres V.
Nov 17 '18 at 17:39
add a comment |
1
str = "65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010"
r = /
(?<=A|,) # match the beginning of the string or a comma in a positive lookbehind
(?: # begin a non-capture group
{.*?} # match an open brace followed by any number of characters,
# lazily, followed by a closed brace
| # or
.*? # match any number of characters, lazily
) # close non-capture group
(?=,|z) # match a comma or the end of the string in a positive lookahead
/x # free-spacing regex definition mode
str.scan r
#=> ["65101km", "Sedan", "Manual", "18131A", "FWD", "Used", "5.5L/100km", "Toyota",
# "camry", "SE", "{AC,Heated Seats, Heated Mirrors, Keyless Entry}", "2010"]
Two notes follow. I'll illustrate these with a simpler string.
str = "65101km,Sedan,{AC,Heated Seats},2010"
{.*?} must precede .*? in (?:{.*?}|.*?)
If
r = /(?<=A|,)(?:.*?|{.*?})(?=,|z)/
then
str.scan r
#=> ["65101km", "Sedan", "{AC", "Heated Seats}", "2010"]
The matches .* must be lazy (aka non-greedy)
If
r = /(?<=A|,)(?:{.*?}|.*)(?=,|z)/
then
str.scan r
#=> ["65101km,Sedan,{AC,Heated Seats},2010"]
If
r = /(?<=A|,)(?:{.*}|.*?)(?=,|z)/
then
"65101km,Sedan,{AC,Heated Seats},2010,{starter motor, pneumatic tires}".scan r
#=> ["65101km", "Sedan", "{AC,Heated Seats},2010,{starter motor, pneumatic tires}"]
answered Nov 16 '18 at 15:55
Cary Swoveland
67.6k53965
Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !
– Andres V.
Nov 16 '18 at 16:03
1
What can I say? Ruby matches"2010". Did you perchance test with a string that contains a space between the last comma and "2010"?
– Cary Swoveland
Nov 16 '18 at 16:21
1
At Regex101,2010is matched.
– Wiktor Stribiżew
Nov 16 '18 at 16:53
just tried it out its perfect! Thanks guys. I had put a space like Gary said.
– Andres V.
Nov 17 '18 at 17:37
add a comment |
1
str = "65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010"
r = /
(?<=A|,) # match the beginning of the string or a comma in a positive lookbehind
(?: # begin a non-capture group
{.*?} # match an open brace followed by any number of characters,
# lazily, followed by a closed brace
| # or
.*? # match any number of characters, lazily
) # close non-capture group
(?=,|z) # match a comma or the end of the string in a positive lookahead
/x # free-spacing regex definition mode
str.scan r
#=> ["65101km", "Sedan", "Manual", "18131A", "FWD", "Used", "5.5L/100km", "Toyota",
# "camry", "SE", "{AC,Heated Seats, Heated Mirrors, Keyless Entry}", "2010"]
Two notes follow. I'll illustrate these with a simpler string.
str = "65101km,Sedan,{AC,Heated Seats},2010"
{.*?} must precede .*? in (?:{.*?}|.*?)
If
r = /(?<=A|,)(?:.*?|{.*?})(?=,|z)/
then
str.scan r
#=> ["65101km", "Sedan", "{AC", "Heated Seats}", "2010"]
The matches .* must be lazy (aka non-greedy)
If
r = /(?<=A|,)(?:{.*?}|.*)(?=,|z)/
then
str.scan r
#=> ["65101km,Sedan,{AC,Heated Seats},2010"]
If
r = /(?<=A|,)(?:{.*}|.*?)(?=,|z)/
then
"65101km,Sedan,{AC,Heated Seats},2010,{starter motor, pneumatic tires}".scan r
#=> ["65101km", "Sedan", "{AC,Heated Seats},2010,{starter motor, pneumatic tires}"]
answered Nov 16 '18 at 15:55
Cary Swoveland
67.6k53965
Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !
– Andres V.
Nov 16 '18 at 16:03
1
What can I say? Ruby matches"2010". Did you perchance test with a string that contains a space between the last comma and "2010"?
– Cary Swoveland
Nov 16 '18 at 16:21
1
At Regex101,2010is matched.
– Wiktor Stribiżew
Nov 16 '18 at 16:53
just tried it out its perfect! Thanks guys. I had put a space like Gary said.
– Andres V.
Nov 17 '18 at 17:37
add a comment |
1
1
1
str = "65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010"
r = /
(?<=A|,) # match the beginning of the string or a comma in a positive lookbehind
(?: # begin a non-capture group
{.*?} # match an open brace followed by any number of characters,
# lazily, followed by a closed brace
| # or
.*? # match any number of characters, lazily
) # close non-capture group
(?=,|z) # match a comma or the end of the string in a positive lookahead
/x # free-spacing regex definition mode
str.scan r
#=> ["65101km", "Sedan", "Manual", "18131A", "FWD", "Used", "5.5L/100km", "Toyota",
# "camry", "SE", "{AC,Heated Seats, Heated Mirrors, Keyless Entry}", "2010"]
Two notes follow. I'll illustrate these with a simpler string.
str = "65101km,Sedan,{AC,Heated Seats},2010"
{.*?} must precede .*? in (?:{.*?}|.*?)
If
r = /(?<=A|,)(?:.*?|{.*?})(?=,|z)/
then
str.scan r
#=> ["65101km", "Sedan", "{AC", "Heated Seats}", "2010"]
The matches .* must be lazy (aka non-greedy)
If
r = /(?<=A|,)(?:{.*?}|.*)(?=,|z)/
then
str.scan r
#=> ["65101km,Sedan,{AC,Heated Seats},2010"]
If
r = /(?<=A|,)(?:{.*}|.*?)(?=,|z)/
then
"65101km,Sedan,{AC,Heated Seats},2010,{starter motor, pneumatic tires}".scan r
#=> ["65101km", "Sedan", "{AC,Heated Seats},2010,{starter motor, pneumatic tires}"]
answered Nov 16 '18 at 15:55
Cary Swoveland
67.6k53965
str = "65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010"
r = /
(?<=A|,) # match the beginning of the string or a comma in a positive lookbehind
(?: # begin a non-capture group
{.*?} # match an open brace followed by any number of characters,
# lazily, followed by a closed brace
| # or
.*? # match any number of characters, lazily
) # close non-capture group
(?=,|z) # match a comma or the end of the string in a positive lookahead
/x # free-spacing regex definition mode
str.scan r
#=> ["65101km", "Sedan", "Manual", "18131A", "FWD", "Used", "5.5L/100km", "Toyota",
# "camry", "SE", "{AC,Heated Seats, Heated Mirrors, Keyless Entry}", "2010"]
Two notes follow. I'll illustrate these with a simpler string.
str = "65101km,Sedan,{AC,Heated Seats},2010"
{.*?} must precede .*? in (?:{.*?}|.*?)
If
r = /(?<=A|,)(?:.*?|{.*?})(?=,|z)/
then
str.scan r
#=> ["65101km", "Sedan", "{AC", "Heated Seats}", "2010"]
The matches .* must be lazy (aka non-greedy)
If
r = /(?<=A|,)(?:{.*?}|.*)(?=,|z)/
then
str.scan r
#=> ["65101km,Sedan,{AC,Heated Seats},2010"]
If
r = /(?<=A|,)(?:{.*}|.*?)(?=,|z)/
then
"65101km,Sedan,{AC,Heated Seats},2010,{starter motor, pneumatic tires}".scan r
#=> ["65101km", "Sedan", "{AC,Heated Seats},2010,{starter motor, pneumatic tires}"]
answered Nov 16 '18 at 15:55
Cary Swoveland
67.6k53965
edited Nov 16 '18 at 17:50
answered Nov 16 '18 at 15:55
Cary Swoveland
67.6k53965
answered Nov 16 '18 at 15:55
Cary Swoveland
67.6k53965
answered Nov 16 '18 at 15:55
Cary Swoveland
67.6k53965
67.6k53965
Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !
– Andres V.
Nov 16 '18 at 16:03
1
What can I say? Ruby matches"2010". Did you perchance test with a string that contains a space between the last comma and "2010"?
– Cary Swoveland
Nov 16 '18 at 16:21
1
At Regex101,2010is matched.
– Wiktor Stribiżew
Nov 16 '18 at 16:53
just tried it out its perfect! Thanks guys. I had put a space like Gary said.
– Andres V.
Nov 17 '18 at 17:37
add a comment |
Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !
– Andres V.
Nov 16 '18 at 16:03
1
What can I say? Ruby matches"2010". Did you perchance test with a string that contains a space between the last comma and "2010"?
– Cary Swoveland
Nov 16 '18 at 16:21
1
At Regex101,2010is matched.
– Wiktor Stribiżew
Nov 16 '18 at 16:53
just tried it out its perfect! Thanks guys. I had put a space like Gary said.
– Andres V.
Nov 17 '18 at 17:37
Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !
– Andres V.
Nov 16 '18 at 16:03
Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !
– Andres V.
Nov 16 '18 at 16:03
1
1
What can I say? Ruby matches
"2010". Did you perchance test with a string that contains a space between the last comma and "2010"?– Cary Swoveland
Nov 16 '18 at 16:21
What can I say? Ruby matches
"2010". Did you perchance test with a string that contains a space between the last comma and "2010"?– Cary Swoveland
Nov 16 '18 at 16:21
1
1
At Regex101,
2010 is matched.– Wiktor Stribiżew
Nov 16 '18 at 16:53
At Regex101,
2010 is matched.– Wiktor Stribiżew
Nov 16 '18 at 16:53
just tried it out its perfect! Thanks guys. I had put a space like Gary said.
– Andres V.
Nov 17 '18 at 17:37
just tried it out its perfect! Thanks guys. I had put a space like Gary said.
– Andres V.
Nov 17 '18 at 17:37
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Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel
– vovan
Nov 16 '18 at 15:57
In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (
["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.– Cary Swoveland
Nov 17 '18 at 20:23