Finding an intersection with respect to the decoration












3














in
Naming nodes in a decoration and draw lines from node to node
I asked a question, which was answered. The most help was the following.



    documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{decorations.markings}
begin{document}
begin{tikzpicture}[
decoration={
markings,
mark=at position 0.4 with {draw[->] (0,0)--(0,1);
draw[->] (0,0)--(2,-2) node[below]{A};
draw[<-] (0,0)--(-.8,-.8);}
}
]
draw[postaction={decorate}] plot [smooth cycle] coordinates {(0,0) (1,1) (3,1) (3,0) (2,-1)};
end{tikzpicture}
end{document}


Now, being able to draw those lines and naming the point, the follow up question is:
Can I find the intersection of A with the smooth plot in relation to the smooth plot. I'd like the intersection in terms of pos=.3 or something, so can do a decoration at the intersection. Is it possible and how can it be done?



Thanks a lot.
Greetings
Fabian










share|improve this question
























  • A is a node. What you mean by intersection of A with plot?
    – nidhin
    Nov 23 '18 at 9:04










  • A was the name i gave to the arrow to distinguish it. Sorry for the bad naming.
    – Fabian
    Nov 23 '18 at 9:12
















3














in
Naming nodes in a decoration and draw lines from node to node
I asked a question, which was answered. The most help was the following.



    documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{decorations.markings}
begin{document}
begin{tikzpicture}[
decoration={
markings,
mark=at position 0.4 with {draw[->] (0,0)--(0,1);
draw[->] (0,0)--(2,-2) node[below]{A};
draw[<-] (0,0)--(-.8,-.8);}
}
]
draw[postaction={decorate}] plot [smooth cycle] coordinates {(0,0) (1,1) (3,1) (3,0) (2,-1)};
end{tikzpicture}
end{document}


Now, being able to draw those lines and naming the point, the follow up question is:
Can I find the intersection of A with the smooth plot in relation to the smooth plot. I'd like the intersection in terms of pos=.3 or something, so can do a decoration at the intersection. Is it possible and how can it be done?



Thanks a lot.
Greetings
Fabian










share|improve this question
























  • A is a node. What you mean by intersection of A with plot?
    – nidhin
    Nov 23 '18 at 9:04










  • A was the name i gave to the arrow to distinguish it. Sorry for the bad naming.
    – Fabian
    Nov 23 '18 at 9:12














3












3








3


1





in
Naming nodes in a decoration and draw lines from node to node
I asked a question, which was answered. The most help was the following.



    documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{decorations.markings}
begin{document}
begin{tikzpicture}[
decoration={
markings,
mark=at position 0.4 with {draw[->] (0,0)--(0,1);
draw[->] (0,0)--(2,-2) node[below]{A};
draw[<-] (0,0)--(-.8,-.8);}
}
]
draw[postaction={decorate}] plot [smooth cycle] coordinates {(0,0) (1,1) (3,1) (3,0) (2,-1)};
end{tikzpicture}
end{document}


Now, being able to draw those lines and naming the point, the follow up question is:
Can I find the intersection of A with the smooth plot in relation to the smooth plot. I'd like the intersection in terms of pos=.3 or something, so can do a decoration at the intersection. Is it possible and how can it be done?



Thanks a lot.
Greetings
Fabian










share|improve this question















in
Naming nodes in a decoration and draw lines from node to node
I asked a question, which was answered. The most help was the following.



    documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{decorations.markings}
begin{document}
begin{tikzpicture}[
decoration={
markings,
mark=at position 0.4 with {draw[->] (0,0)--(0,1);
draw[->] (0,0)--(2,-2) node[below]{A};
draw[<-] (0,0)--(-.8,-.8);}
}
]
draw[postaction={decorate}] plot [smooth cycle] coordinates {(0,0) (1,1) (3,1) (3,0) (2,-1)};
end{tikzpicture}
end{document}


Now, being able to draw those lines and naming the point, the follow up question is:
Can I find the intersection of A with the smooth plot in relation to the smooth plot. I'd like the intersection in terms of pos=.3 or something, so can do a decoration at the intersection. Is it possible and how can it be done?



Thanks a lot.
Greetings
Fabian







tikz-pgf decorations intersections






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 8:32









AndréC

8,31611445




8,31611445










asked Nov 23 '18 at 8:30









FabianFabian

303




303












  • A is a node. What you mean by intersection of A with plot?
    – nidhin
    Nov 23 '18 at 9:04










  • A was the name i gave to the arrow to distinguish it. Sorry for the bad naming.
    – Fabian
    Nov 23 '18 at 9:12


















  • A is a node. What you mean by intersection of A with plot?
    – nidhin
    Nov 23 '18 at 9:04










  • A was the name i gave to the arrow to distinguish it. Sorry for the bad naming.
    – Fabian
    Nov 23 '18 at 9:12
















A is a node. What you mean by intersection of A with plot?
– nidhin
Nov 23 '18 at 9:04




A is a node. What you mean by intersection of A with plot?
– nidhin
Nov 23 '18 at 9:04












A was the name i gave to the arrow to distinguish it. Sorry for the bad naming.
– Fabian
Nov 23 '18 at 9:12




A was the name i gave to the arrow to distinguish it. Sorry for the bad naming.
– Fabian
Nov 23 '18 at 9:12










1 Answer
1






active

oldest

votes


















4














This question is actually less innocent than it might appear to you. Luckily pgfplots (!) has its means to decompose a path into intersection segments, which, in turn, one can decorate. In this MWE



documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{decorations.markings}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
usepgfplotslibrary{fillbetween}
begin{document}
begin{tikzpicture}
draw[postaction={decorate,decoration={
markings,
mark=at position 0.4 with {draw[->] (0,0)--(0,1);
draw[->,name path=pathA] (0,0)--(2,-2) node[below]{A};
draw[<-] (0,0)--(-.8,-.8);}
}},name path global=pathB] plot [smooth cycle] coordinates {(0,0) (1,1) (3,1) (3,0) (2,-1)};
path[ draw=blue,
postaction={decoration={
markings,
mark=at position 1 with {draw[->] (0,0)--(0,1);}
},decorate},
intersection segments={of=pathA and pathB,
sequence={R2},
},];
end{tikzpicture}
end{document}


enter image description here



I compute (and draw in blue for illustration purposes) the intersection segment to the point where the original smooth plot intersects with the line labeled A. This point with now have position 1 in the segment. One can then e.g. draw a normal vector at this point.






share|improve this answer

















  • 1




    I'm always learning new features from you!
    – CarLaTeX
    Nov 23 '18 at 12:50










  • @CarLaTeX Just don't tell your doctor that you are learning things from a marmot, bad things could happen. ;-)
    – marmot
    Nov 23 '18 at 20:03






  • 1




    Lol, my ducktor!
    – CarLaTeX
    Nov 23 '18 at 20:04











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4














This question is actually less innocent than it might appear to you. Luckily pgfplots (!) has its means to decompose a path into intersection segments, which, in turn, one can decorate. In this MWE



documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{decorations.markings}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
usepgfplotslibrary{fillbetween}
begin{document}
begin{tikzpicture}
draw[postaction={decorate,decoration={
markings,
mark=at position 0.4 with {draw[->] (0,0)--(0,1);
draw[->,name path=pathA] (0,0)--(2,-2) node[below]{A};
draw[<-] (0,0)--(-.8,-.8);}
}},name path global=pathB] plot [smooth cycle] coordinates {(0,0) (1,1) (3,1) (3,0) (2,-1)};
path[ draw=blue,
postaction={decoration={
markings,
mark=at position 1 with {draw[->] (0,0)--(0,1);}
},decorate},
intersection segments={of=pathA and pathB,
sequence={R2},
},];
end{tikzpicture}
end{document}


enter image description here



I compute (and draw in blue for illustration purposes) the intersection segment to the point where the original smooth plot intersects with the line labeled A. This point with now have position 1 in the segment. One can then e.g. draw a normal vector at this point.






share|improve this answer

















  • 1




    I'm always learning new features from you!
    – CarLaTeX
    Nov 23 '18 at 12:50










  • @CarLaTeX Just don't tell your doctor that you are learning things from a marmot, bad things could happen. ;-)
    – marmot
    Nov 23 '18 at 20:03






  • 1




    Lol, my ducktor!
    – CarLaTeX
    Nov 23 '18 at 20:04
















4














This question is actually less innocent than it might appear to you. Luckily pgfplots (!) has its means to decompose a path into intersection segments, which, in turn, one can decorate. In this MWE



documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{decorations.markings}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
usepgfplotslibrary{fillbetween}
begin{document}
begin{tikzpicture}
draw[postaction={decorate,decoration={
markings,
mark=at position 0.4 with {draw[->] (0,0)--(0,1);
draw[->,name path=pathA] (0,0)--(2,-2) node[below]{A};
draw[<-] (0,0)--(-.8,-.8);}
}},name path global=pathB] plot [smooth cycle] coordinates {(0,0) (1,1) (3,1) (3,0) (2,-1)};
path[ draw=blue,
postaction={decoration={
markings,
mark=at position 1 with {draw[->] (0,0)--(0,1);}
},decorate},
intersection segments={of=pathA and pathB,
sequence={R2},
},];
end{tikzpicture}
end{document}


enter image description here



I compute (and draw in blue for illustration purposes) the intersection segment to the point where the original smooth plot intersects with the line labeled A. This point with now have position 1 in the segment. One can then e.g. draw a normal vector at this point.






share|improve this answer

















  • 1




    I'm always learning new features from you!
    – CarLaTeX
    Nov 23 '18 at 12:50










  • @CarLaTeX Just don't tell your doctor that you are learning things from a marmot, bad things could happen. ;-)
    – marmot
    Nov 23 '18 at 20:03






  • 1




    Lol, my ducktor!
    – CarLaTeX
    Nov 23 '18 at 20:04














4












4








4






This question is actually less innocent than it might appear to you. Luckily pgfplots (!) has its means to decompose a path into intersection segments, which, in turn, one can decorate. In this MWE



documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{decorations.markings}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
usepgfplotslibrary{fillbetween}
begin{document}
begin{tikzpicture}
draw[postaction={decorate,decoration={
markings,
mark=at position 0.4 with {draw[->] (0,0)--(0,1);
draw[->,name path=pathA] (0,0)--(2,-2) node[below]{A};
draw[<-] (0,0)--(-.8,-.8);}
}},name path global=pathB] plot [smooth cycle] coordinates {(0,0) (1,1) (3,1) (3,0) (2,-1)};
path[ draw=blue,
postaction={decoration={
markings,
mark=at position 1 with {draw[->] (0,0)--(0,1);}
},decorate},
intersection segments={of=pathA and pathB,
sequence={R2},
},];
end{tikzpicture}
end{document}


enter image description here



I compute (and draw in blue for illustration purposes) the intersection segment to the point where the original smooth plot intersects with the line labeled A. This point with now have position 1 in the segment. One can then e.g. draw a normal vector at this point.






share|improve this answer












This question is actually less innocent than it might appear to you. Luckily pgfplots (!) has its means to decompose a path into intersection segments, which, in turn, one can decorate. In this MWE



documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{decorations.markings}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
usepgfplotslibrary{fillbetween}
begin{document}
begin{tikzpicture}
draw[postaction={decorate,decoration={
markings,
mark=at position 0.4 with {draw[->] (0,0)--(0,1);
draw[->,name path=pathA] (0,0)--(2,-2) node[below]{A};
draw[<-] (0,0)--(-.8,-.8);}
}},name path global=pathB] plot [smooth cycle] coordinates {(0,0) (1,1) (3,1) (3,0) (2,-1)};
path[ draw=blue,
postaction={decoration={
markings,
mark=at position 1 with {draw[->] (0,0)--(0,1);}
},decorate},
intersection segments={of=pathA and pathB,
sequence={R2},
},];
end{tikzpicture}
end{document}


enter image description here



I compute (and draw in blue for illustration purposes) the intersection segment to the point where the original smooth plot intersects with the line labeled A. This point with now have position 1 in the segment. One can then e.g. draw a normal vector at this point.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 23 '18 at 11:34









marmotmarmot

90.3k4104195




90.3k4104195








  • 1




    I'm always learning new features from you!
    – CarLaTeX
    Nov 23 '18 at 12:50










  • @CarLaTeX Just don't tell your doctor that you are learning things from a marmot, bad things could happen. ;-)
    – marmot
    Nov 23 '18 at 20:03






  • 1




    Lol, my ducktor!
    – CarLaTeX
    Nov 23 '18 at 20:04














  • 1




    I'm always learning new features from you!
    – CarLaTeX
    Nov 23 '18 at 12:50










  • @CarLaTeX Just don't tell your doctor that you are learning things from a marmot, bad things could happen. ;-)
    – marmot
    Nov 23 '18 at 20:03






  • 1




    Lol, my ducktor!
    – CarLaTeX
    Nov 23 '18 at 20:04








1




1




I'm always learning new features from you!
– CarLaTeX
Nov 23 '18 at 12:50




I'm always learning new features from you!
– CarLaTeX
Nov 23 '18 at 12:50












@CarLaTeX Just don't tell your doctor that you are learning things from a marmot, bad things could happen. ;-)
– marmot
Nov 23 '18 at 20:03




@CarLaTeX Just don't tell your doctor that you are learning things from a marmot, bad things could happen. ;-)
– marmot
Nov 23 '18 at 20:03




1




1




Lol, my ducktor!
– CarLaTeX
Nov 23 '18 at 20:04




Lol, my ducktor!
– CarLaTeX
Nov 23 '18 at 20:04


















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