how to open files that match a pattern in a subdirectory

Hello i have a problem finding and opening files in a subdirectory.
I have several different files called for example :

mouse_1_animal.txt

mouse_2_animal.txt
mouse_3_animal.txt

so i want to find all these files in the subdirectory of the working dir and open them and do something with there lines. This is my try:

i=1

for path, subdirs, files in os.walk(root) :

    for file in files :

        if file == "mouse_{0}_animal.txt".format(i) :

            #do something

            i = i + 1

but apparently it doesn't find all the files so i'm wondering if it's the way i'm using to find the file that is wrong.

asked Apr 9 '15 at 9:53

steT

4919

I'd suggest to get a list of all files which match the pattern and then open them, edit and close one by one.
– Igor T.
Apr 9 '15 at 9:55

1

It may be easier to use os.listdir() in case of a single subdirectory.
– user707650
Apr 9 '15 at 9:55

Note that files contains the filenames relative to the current path where os.walk is at that moment; so you'll need to concatenate the directory and file name (os.path.join()) to get the full path name.
– user707650
Apr 9 '15 at 9:58

stackoverflow.com/questions/14798220/…
– Christian K.
Apr 9 '15 at 9:59

add a comment |

Hello i have a problem finding and opening files in a subdirectory.
I have several different files called for example :

mouse_1_animal.txt

mouse_2_animal.txt
mouse_3_animal.txt

so i want to find all these files in the subdirectory of the working dir and open them and do something with there lines. This is my try:

i=1

for path, subdirs, files in os.walk(root) :

    for file in files :

        if file == "mouse_{0}_animal.txt".format(i) :

            #do something

            i = i + 1

but apparently it doesn't find all the files so i'm wondering if it's the way i'm using to find the file that is wrong.

asked Apr 9 '15 at 9:53

steT

4919

I'd suggest to get a list of all files which match the pattern and then open them, edit and close one by one.
– Igor T.
Apr 9 '15 at 9:55

1

It may be easier to use os.listdir() in case of a single subdirectory.
– user707650
Apr 9 '15 at 9:55

Note that files contains the filenames relative to the current path where os.walk is at that moment; so you'll need to concatenate the directory and file name (os.path.join()) to get the full path name.
– user707650
Apr 9 '15 at 9:58

stackoverflow.com/questions/14798220/…
– Christian K.
Apr 9 '15 at 9:59

add a comment |

Hello i have a problem finding and opening files in a subdirectory.
I have several different files called for example :

mouse_1_animal.txt

mouse_2_animal.txt
mouse_3_animal.txt

so i want to find all these files in the subdirectory of the working dir and open them and do something with there lines. This is my try:

i=1

for path, subdirs, files in os.walk(root) :

    for file in files :

        if file == "mouse_{0}_animal.txt".format(i) :

            #do something

            i = i + 1

but apparently it doesn't find all the files so i'm wondering if it's the way i'm using to find the file that is wrong.

asked Apr 9 '15 at 9:53

steT

4919

Hello i have a problem finding and opening files in a subdirectory.
I have several different files called for example :

mouse_1_animal.txt

mouse_2_animal.txt
mouse_3_animal.txt

so i want to find all these files in the subdirectory of the working dir and open them and do something with there lines. This is my try:

i=1

for path, subdirs, files in os.walk(root) :

    for file in files :

        if file == "mouse_{0}_animal.txt".format(i) :

            #do something

            i = i + 1

but apparently it doesn't find all the files so i'm wondering if it's the way i'm using to find the file that is wrong.

python

asked Apr 9 '15 at 9:53

steT

4919

asked Apr 9 '15 at 9:53

steT

4919

asked Apr 9 '15 at 9:53

steT

4919

asked Apr 9 '15 at 9:53

steT

4919

asked Apr 9 '15 at 9:53

steT

4919

I'd suggest to get a list of all files which match the pattern and then open them, edit and close one by one.
– Igor T.
Apr 9 '15 at 9:55

1

It may be easier to use os.listdir() in case of a single subdirectory.
– user707650
Apr 9 '15 at 9:55

Note that files contains the filenames relative to the current path where os.walk is at that moment; so you'll need to concatenate the directory and file name (os.path.join()) to get the full path name.
– user707650
Apr 9 '15 at 9:58

stackoverflow.com/questions/14798220/…
– Christian K.
Apr 9 '15 at 9:59

add a comment |

I'd suggest to get a list of all files which match the pattern and then open them, edit and close one by one.
– Igor T.
Apr 9 '15 at 9:55

1

It may be easier to use os.listdir() in case of a single subdirectory.
– user707650
Apr 9 '15 at 9:55

Note that files contains the filenames relative to the current path where os.walk is at that moment; so you'll need to concatenate the directory and file name (os.path.join()) to get the full path name.
– user707650
Apr 9 '15 at 9:58

stackoverflow.com/questions/14798220/…
– Christian K.
Apr 9 '15 at 9:59

I'd suggest to get a list of all files which match the pattern and then open them, edit and close one by one.
– Igor T.
Apr 9 '15 at 9:55

It may be easier to use os.listdir() in case of a single subdirectory.
– user707650
Apr 9 '15 at 9:55

Note that files contains the filenames relative to the current path where os.walk is at that moment; so you'll need to concatenate the directory and file name (os.path.join()) to get the full path name.
– user707650
Apr 9 '15 at 9:58

stackoverflow.com/questions/14798220/…
– Christian K.
Apr 9 '15 at 9:59

add a comment |

3 Answers
3

active

oldest

votes

The pythonic way:

import glob

for f in glob.glob('./subDir/mouse_*_animal.txt'):

    # do_something

answered Apr 9 '15 at 12:48

haavee

3,8211620

add a comment |

ok i've solvd my problem like this

 file_list = 

 for name in glob.glob('./subDir/mouse_*_animal.txt'):

    file_list.append(name)

 for i in range(len(file_list)+1):

     if './subDir/mouse_*_animal.txt'.format(i) in file_list:

        #do something

answered Apr 9 '15 at 12:43

steT

4919

1

glob.glob() already returns a list of filenames. So you should shorten your code to: for f in glob.glob('./subDir/mouse_*_animal.txt'): do_something(f)
– haavee
Apr 9 '15 at 12:47

add a comment |

import fnmatch

import os

src = 'sourceDirPath'

for root, dirnames, filenames in os.walk(src):

  for filename in fnmatch.filter(filenames, 'mouse*.txt'):

      #do something

        i = i + 1

for older python version you might want to try glob instead of fnmatch

edited Nov 18 '18 at 23:45

e_i_pi

2,56021632

answered Apr 9 '15 at 10:23

kewlkiev

117

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

The pythonic way:

import glob

for f in glob.glob('./subDir/mouse_*_animal.txt'):

    # do_something

answered Apr 9 '15 at 12:48

haavee

3,8211620

add a comment |

The pythonic way:

import glob

for f in glob.glob('./subDir/mouse_*_animal.txt'):

    # do_something

answered Apr 9 '15 at 12:48

haavee

3,8211620

add a comment |

The pythonic way:

import glob

for f in glob.glob('./subDir/mouse_*_animal.txt'):

    # do_something

answered Apr 9 '15 at 12:48

haavee

3,8211620

The pythonic way:

import glob

for f in glob.glob('./subDir/mouse_*_animal.txt'):

    # do_something

answered Apr 9 '15 at 12:48

haavee

3,8211620

answered Apr 9 '15 at 12:48

haavee

3,8211620

answered Apr 9 '15 at 12:48

haavee

3,8211620

answered Apr 9 '15 at 12:48

haavee

3,8211620

add a comment |

ok i've solvd my problem like this

 file_list = 

 for name in glob.glob('./subDir/mouse_*_animal.txt'):

    file_list.append(name)

 for i in range(len(file_list)+1):

     if './subDir/mouse_*_animal.txt'.format(i) in file_list:

        #do something

answered Apr 9 '15 at 12:43

steT

4919

1

glob.glob() already returns a list of filenames. So you should shorten your code to: for f in glob.glob('./subDir/mouse_*_animal.txt'): do_something(f)
– haavee
Apr 9 '15 at 12:47

add a comment |

ok i've solvd my problem like this

 file_list = 

 for name in glob.glob('./subDir/mouse_*_animal.txt'):

    file_list.append(name)

 for i in range(len(file_list)+1):

     if './subDir/mouse_*_animal.txt'.format(i) in file_list:

        #do something

answered Apr 9 '15 at 12:43

steT

4919

1

glob.glob() already returns a list of filenames. So you should shorten your code to: for f in glob.glob('./subDir/mouse_*_animal.txt'): do_something(f)
– haavee
Apr 9 '15 at 12:47

add a comment |

ok i've solvd my problem like this

 file_list = 

 for name in glob.glob('./subDir/mouse_*_animal.txt'):

    file_list.append(name)

 for i in range(len(file_list)+1):

     if './subDir/mouse_*_animal.txt'.format(i) in file_list:

        #do something

answered Apr 9 '15 at 12:43

steT

4919

ok i've solvd my problem like this

 file_list = 

 for name in glob.glob('./subDir/mouse_*_animal.txt'):

    file_list.append(name)

 for i in range(len(file_list)+1):

     if './subDir/mouse_*_animal.txt'.format(i) in file_list:

        #do something

answered Apr 9 '15 at 12:43

steT

4919

answered Apr 9 '15 at 12:43

steT

4919

answered Apr 9 '15 at 12:43

steT

4919

answered Apr 9 '15 at 12:43

steT

4919

1

glob.glob() already returns a list of filenames. So you should shorten your code to: for f in glob.glob('./subDir/mouse_*_animal.txt'): do_something(f)
– haavee
Apr 9 '15 at 12:47

add a comment |

1

glob.glob() already returns a list of filenames. So you should shorten your code to: for f in glob.glob('./subDir/mouse_*_animal.txt'): do_something(f)
– haavee
Apr 9 '15 at 12:47

glob.glob() already returns a list of filenames. So you should shorten your code to: for f in glob.glob('./subDir/mouse_*_animal.txt'): do_something(f)
– haavee
Apr 9 '15 at 12:47

add a comment |

import fnmatch

import os

src = 'sourceDirPath'

for root, dirnames, filenames in os.walk(src):

  for filename in fnmatch.filter(filenames, 'mouse*.txt'):

      #do something

        i = i + 1

for older python version you might want to try glob instead of fnmatch

edited Nov 18 '18 at 23:45

e_i_pi

2,56021632

answered Apr 9 '15 at 10:23

kewlkiev

117

add a comment |

import fnmatch

import os

src = 'sourceDirPath'

for root, dirnames, filenames in os.walk(src):

  for filename in fnmatch.filter(filenames, 'mouse*.txt'):

      #do something

        i = i + 1

for older python version you might want to try glob instead of fnmatch

edited Nov 18 '18 at 23:45

e_i_pi

2,56021632

answered Apr 9 '15 at 10:23

kewlkiev

117

add a comment |

import fnmatch

import os

src = 'sourceDirPath'

for root, dirnames, filenames in os.walk(src):

  for filename in fnmatch.filter(filenames, 'mouse*.txt'):

      #do something

        i = i + 1

for older python version you might want to try glob instead of fnmatch

edited Nov 18 '18 at 23:45

e_i_pi

2,56021632

answered Apr 9 '15 at 10:23

kewlkiev

117

import fnmatch

import os

src = 'sourceDirPath'

for root, dirnames, filenames in os.walk(src):

  for filename in fnmatch.filter(filenames, 'mouse*.txt'):

      #do something

        i = i + 1

for older python version you might want to try glob instead of fnmatch

edited Nov 18 '18 at 23:45

e_i_pi

2,56021632

answered Apr 9 '15 at 10:23

kewlkiev

117

edited Nov 18 '18 at 23:45

e_i_pi

2,56021632

edited Nov 18 '18 at 23:45

e_i_pi

2,56021632

edited Nov 18 '18 at 23:45

e_i_pi

2,56021632

answered Apr 9 '15 at 10:23

kewlkiev

117

answered Apr 9 '15 at 10:23

kewlkiev

117

answered Apr 9 '15 at 10:23

kewlkiev

117

add a comment |

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