Is 1/vector is a vector or not?
Let $vec { A } = a hat { i } + b hat { j } + c hat { k }$. Is $frac { 1 } { vec { A } }$ a vector or not, and if it is, then what are its components?"
vectors
asked Nov 23 '18 at 13:57
HawkingoHawkingo
12
add a comment |
Let $vec { A } = a hat { i } + b hat { j } + c hat { k }$. Is $frac { 1 } { vec { A } }$ a vector or not, and if it is, then what are its components?"
vectors
asked Nov 23 '18 at 13:57
HawkingoHawkingo
12
1
The inverse (one over something) is closely related to multiplication. But for vectors, there is no simple (unique) definition of multiplication. Therefore, it's a little difficult to imagine what would be "one divided by a vector".
– Matti P.
Nov 23 '18 at 13:59
1
$frac { 1 } { vec { A } }$ is like "the square root of blue", i.e. meaningless.
– TonyK
Nov 23 '18 at 14:01
How do you define $frac{1}{vec{A}}$?
– 5xum
Nov 23 '18 at 14:02
add a comment |
Let $vec { A } = a hat { i } + b hat { j } + c hat { k }$. Is $frac { 1 } { vec { A } }$ a vector or not, and if it is, then what are its components?"
vectors
asked Nov 23 '18 at 13:57
HawkingoHawkingo
12
Let $vec { A } = a hat { i } + b hat { j } + c hat { k }$. Is $frac { 1 } { vec { A } }$ a vector or not, and if it is, then what are its components?"
vectors
vectors
asked Nov 23 '18 at 13:57
HawkingoHawkingo
12
asked Nov 23 '18 at 13:57
HawkingoHawkingo
12
asked Nov 23 '18 at 13:57
HawkingoHawkingo
12
asked Nov 23 '18 at 13:57
HawkingoHawkingo
12
asked Nov 23 '18 at 13:57
HawkingoHawkingo
12
12
1
The inverse (one over something) is closely related to multiplication. But for vectors, there is no simple (unique) definition of multiplication. Therefore, it's a little difficult to imagine what would be "one divided by a vector".
– Matti P.
Nov 23 '18 at 13:59
1
$frac { 1 } { vec { A } }$ is like "the square root of blue", i.e. meaningless.
– TonyK
Nov 23 '18 at 14:01
How do you define $frac{1}{vec{A}}$?
– 5xum
Nov 23 '18 at 14:02
add a comment |
1
The inverse (one over something) is closely related to multiplication. But for vectors, there is no simple (unique) definition of multiplication. Therefore, it's a little difficult to imagine what would be "one divided by a vector".
– Matti P.
Nov 23 '18 at 13:59
1
$frac { 1 } { vec { A } }$ is like "the square root of blue", i.e. meaningless.
– TonyK
Nov 23 '18 at 14:01
How do you define $frac{1}{vec{A}}$?
– 5xum
Nov 23 '18 at 14:02
1
1
The inverse (one over something) is closely related to multiplication. But for vectors, there is no simple (unique) definition of multiplication. Therefore, it's a little difficult to imagine what would be "one divided by a vector".
– Matti P.
Nov 23 '18 at 13:59
The inverse (one over something) is closely related to multiplication. But for vectors, there is no simple (unique) definition of multiplication. Therefore, it's a little difficult to imagine what would be "one divided by a vector".
– Matti P.
Nov 23 '18 at 13:59
1
1
$frac { 1 } { vec { A } }$ is like "the square root of blue", i.e. meaningless.
– TonyK
Nov 23 '18 at 14:01
$frac { 1 } { vec { A } }$ is like "the square root of blue", i.e. meaningless.
– TonyK
Nov 23 '18 at 14:01
How do you define $frac{1}{vec{A}}$?
– 5xum
Nov 23 '18 at 14:02
How do you define $frac{1}{vec{A}}$?
– 5xum
Nov 23 '18 at 14:02
add a comment |
1 Answer
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There is no standard definition of $frac{1}{boldsymbol{x}}$ where $boldsymbol{x}$ is a vector. Therefore, the expression "$frac{1}{boldsymbol{x}}$" is generally meaningless (undefined), unless it is specifically defined in the context where it is used.
answered Nov 23 '18 at 14:02
EffEff
11.5k21638
add a comment |
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There is no standard definition of $frac{1}{boldsymbol{x}}$ where $boldsymbol{x}$ is a vector. Therefore, the expression "$frac{1}{boldsymbol{x}}$" is generally meaningless (undefined), unless it is specifically defined in the context where it is used.
answered Nov 23 '18 at 14:02
EffEff
11.5k21638
add a comment |
There is no standard definition of $frac{1}{boldsymbol{x}}$ where $boldsymbol{x}$ is a vector. Therefore, the expression "$frac{1}{boldsymbol{x}}$" is generally meaningless (undefined), unless it is specifically defined in the context where it is used.
answered Nov 23 '18 at 14:02
EffEff
11.5k21638
add a comment |
There is no standard definition of $frac{1}{boldsymbol{x}}$ where $boldsymbol{x}$ is a vector. Therefore, the expression "$frac{1}{boldsymbol{x}}$" is generally meaningless (undefined), unless it is specifically defined in the context where it is used.
answered Nov 23 '18 at 14:02
EffEff
11.5k21638
There is no standard definition of $frac{1}{boldsymbol{x}}$ where $boldsymbol{x}$ is a vector. Therefore, the expression "$frac{1}{boldsymbol{x}}$" is generally meaningless (undefined), unless it is specifically defined in the context where it is used.
answered Nov 23 '18 at 14:02
EffEff
11.5k21638
answered Nov 23 '18 at 14:02
EffEff
11.5k21638
answered Nov 23 '18 at 14:02
EffEff
11.5k21638
answered Nov 23 '18 at 14:02
EffEff
11.5k21638
11.5k21638
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1
The inverse (one over something) is closely related to multiplication. But for vectors, there is no simple (unique) definition of multiplication. Therefore, it's a little difficult to imagine what would be "one divided by a vector".
– Matti P.
Nov 23 '18 at 13:59
1
$frac { 1 } { vec { A } }$ is like "the square root of blue", i.e. meaningless.
– TonyK
Nov 23 '18 at 14:01
How do you define $frac{1}{vec{A}}$?
– 5xum
Nov 23 '18 at 14:02