Does $int_1^infty f(x)ln(x)dx$ converge if $int_1^infty f(x)dx $ converges?












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Suppose a function $f:[1,infty)tomathbb R$ is such that $int_1^infty f(x),dx $ converges. Is it possible that $$int_1^infty f(x)ln(x),dx $$ diverges? I have a hard time finding such a function.

Edit: no idea why, but I had just thought naively (without checking) that $int frac 1{xln^k(x)},dx $ diverges for all $k$ just because $int frac 1{xln(x)},dx $ diverges. Sorry!










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  • 1




    $begingroup$
    Below you will find a hint. Please show your effort and share with us your thoughts.
    $endgroup$
    – Robert Z
    Nov 24 '18 at 16:21
















-3












$begingroup$


Suppose a function $f:[1,infty)tomathbb R$ is such that $int_1^infty f(x),dx $ converges. Is it possible that $$int_1^infty f(x)ln(x),dx $$ diverges? I have a hard time finding such a function.

Edit: no idea why, but I had just thought naively (without checking) that $int frac 1{xln^k(x)},dx $ diverges for all $k$ just because $int frac 1{xln(x)},dx $ diverges. Sorry!










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    Below you will find a hint. Please show your effort and share with us your thoughts.
    $endgroup$
    – Robert Z
    Nov 24 '18 at 16:21














-3












-3








-3





$begingroup$


Suppose a function $f:[1,infty)tomathbb R$ is such that $int_1^infty f(x),dx $ converges. Is it possible that $$int_1^infty f(x)ln(x),dx $$ diverges? I have a hard time finding such a function.

Edit: no idea why, but I had just thought naively (without checking) that $int frac 1{xln^k(x)},dx $ diverges for all $k$ just because $int frac 1{xln(x)},dx $ diverges. Sorry!










share|cite|improve this question











$endgroup$




Suppose a function $f:[1,infty)tomathbb R$ is such that $int_1^infty f(x),dx $ converges. Is it possible that $$int_1^infty f(x)ln(x),dx $$ diverges? I have a hard time finding such a function.

Edit: no idea why, but I had just thought naively (without checking) that $int frac 1{xln^k(x)},dx $ diverges for all $k$ just because $int frac 1{xln(x)},dx $ diverges. Sorry!







calculus integration convergence






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edited Nov 24 '18 at 19:54







Wolfgang

















asked Nov 24 '18 at 16:16









WolfgangWolfgang

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320612








  • 1




    $begingroup$
    Below you will find a hint. Please show your effort and share with us your thoughts.
    $endgroup$
    – Robert Z
    Nov 24 '18 at 16:21














  • 1




    $begingroup$
    Below you will find a hint. Please show your effort and share with us your thoughts.
    $endgroup$
    – Robert Z
    Nov 24 '18 at 16:21








1




1




$begingroup$
Below you will find a hint. Please show your effort and share with us your thoughts.
$endgroup$
– Robert Z
Nov 24 '18 at 16:21




$begingroup$
Below you will find a hint. Please show your effort and share with us your thoughts.
$endgroup$
– Robert Z
Nov 24 '18 at 16:21










1 Answer
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$begingroup$

Hint. Consider the function $$f(x)=frac{1}{xln^2(1+x)}.$$



Is $int_1^infty f(x)dx$ convergent? What about $int_1^infty f(x)ln(x) dx$?






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    1












    $begingroup$

    Hint. Consider the function $$f(x)=frac{1}{xln^2(1+x)}.$$



    Is $int_1^infty f(x)dx$ convergent? What about $int_1^infty f(x)ln(x) dx$?






    share|cite|improve this answer









    $endgroup$


















      1












      $begingroup$

      Hint. Consider the function $$f(x)=frac{1}{xln^2(1+x)}.$$



      Is $int_1^infty f(x)dx$ convergent? What about $int_1^infty f(x)ln(x) dx$?






      share|cite|improve this answer









      $endgroup$
















        1












        1








        1





        $begingroup$

        Hint. Consider the function $$f(x)=frac{1}{xln^2(1+x)}.$$



        Is $int_1^infty f(x)dx$ convergent? What about $int_1^infty f(x)ln(x) dx$?






        share|cite|improve this answer









        $endgroup$



        Hint. Consider the function $$f(x)=frac{1}{xln^2(1+x)}.$$



        Is $int_1^infty f(x)dx$ convergent? What about $int_1^infty f(x)ln(x) dx$?







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 24 '18 at 16:19









        Robert ZRobert Z

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        94.3k1063134






























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