create and update column in MySQL
0
I need this code to create one column and then make it another foreign key.
I do not want another code, I need this for certain reasons. How can I add code to modify the created column and make it a foreign key?
-- Actualizando la tabla: action
DELIMITER $$
SET @s = (SELECT IF(
(SELECT COUNT(*)
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_name = 'action'
AND table_schema = 'ibexsales_dev'
AND column_name = 'company_id'
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL"
));
PREPARE stmt FROM @s;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
$$ DELIMITER ;
I need add this code:
ALTER TABLE `ibexsales_dev`.`action`
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`);
I tried this but it does not work:
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL",
" ALTER TABLE `ibexsales_dev`.`action`
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`); "
));
mysql mysql-workbench
asked Nov 19 '18 at 9:42
CarlosCarlos
517
add a comment |
0
I need this code to create one column and then make it another foreign key.
I do not want another code, I need this for certain reasons. How can I add code to modify the created column and make it a foreign key?
-- Actualizando la tabla: action
DELIMITER $$
SET @s = (SELECT IF(
(SELECT COUNT(*)
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_name = 'action'
AND table_schema = 'ibexsales_dev'
AND column_name = 'company_id'
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL"
));
PREPARE stmt FROM @s;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
$$ DELIMITER ;
I need add this code:
ALTER TABLE `ibexsales_dev`.`action`
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`);
I tried this but it does not work:
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL",
" ALTER TABLE `ibexsales_dev`.`action`
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`); "
));
mysql mysql-workbench
asked Nov 19 '18 at 9:42
CarlosCarlos
517
add a comment |
0
0
0
I need this code to create one column and then make it another foreign key.
I do not want another code, I need this for certain reasons. How can I add code to modify the created column and make it a foreign key?
-- Actualizando la tabla: action
DELIMITER $$
SET @s = (SELECT IF(
(SELECT COUNT(*)
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_name = 'action'
AND table_schema = 'ibexsales_dev'
AND column_name = 'company_id'
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL"
));
PREPARE stmt FROM @s;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
$$ DELIMITER ;
I need add this code:
ALTER TABLE `ibexsales_dev`.`action`
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`);
I tried this but it does not work:
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL",
" ALTER TABLE `ibexsales_dev`.`action`
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`); "
));
mysql mysql-workbench
asked Nov 19 '18 at 9:42
CarlosCarlos
517
I need this code to create one column and then make it another foreign key.
I do not want another code, I need this for certain reasons. How can I add code to modify the created column and make it a foreign key?
-- Actualizando la tabla: action
DELIMITER $$
SET @s = (SELECT IF(
(SELECT COUNT(*)
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_name = 'action'
AND table_schema = 'ibexsales_dev'
AND column_name = 'company_id'
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL"
));
PREPARE stmt FROM @s;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
$$ DELIMITER ;
I need add this code:
ALTER TABLE `ibexsales_dev`.`action`
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`);
I tried this but it does not work:
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL",
" ALTER TABLE `ibexsales_dev`.`action`
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`); "
));
mysql mysql-workbench
mysql mysql-workbench
asked Nov 19 '18 at 9:42
CarlosCarlos
517
asked Nov 19 '18 at 9:42
CarlosCarlos
517
asked Nov 19 '18 at 9:42
CarlosCarlos
517
asked Nov 19 '18 at 9:42
CarlosCarlos
517
asked Nov 19 '18 at 9:42
CarlosCarlos
517
517
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
You don't repeat ALTER TABLE. A single ALTER TABLE query can contain multiple alterations, separated by comma.
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL,
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`); "
));
answered Nov 19 '18 at 10:16
BarmarBarmar
422k35244346
Perfect, thank you. What is the name of the structure I used? (I did not know what could be done that way, I have seen the example on the internet)
– Carlos
Nov 19 '18 at 10:24
You had too many arguments toIF(). It's justIF(condition, trueResult, falseResult), but you hadIF(condition, trueResult, falseResult, anotherFalseResult). The "name" is syntax error.
– Barmar
Nov 19 '18 at 15:30
Thank you :) :)
– Carlos
Nov 19 '18 at 16:17
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You don't repeat ALTER TABLE. A single ALTER TABLE query can contain multiple alterations, separated by comma.
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL,
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`); "
));
answered Nov 19 '18 at 10:16
BarmarBarmar
422k35244346
Perfect, thank you. What is the name of the structure I used? (I did not know what could be done that way, I have seen the example on the internet)
– Carlos
Nov 19 '18 at 10:24
You had too many arguments toIF(). It's justIF(condition, trueResult, falseResult), but you hadIF(condition, trueResult, falseResult, anotherFalseResult). The "name" is syntax error.
– Barmar
Nov 19 '18 at 15:30
Thank you :) :)
– Carlos
Nov 19 '18 at 16:17
add a comment |
1
You don't repeat ALTER TABLE. A single ALTER TABLE query can contain multiple alterations, separated by comma.
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL,
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`); "
));
answered Nov 19 '18 at 10:16
BarmarBarmar
422k35244346
Perfect, thank you. What is the name of the structure I used? (I did not know what could be done that way, I have seen the example on the internet)
– Carlos
Nov 19 '18 at 10:24
You had too many arguments toIF(). It's justIF(condition, trueResult, falseResult), but you hadIF(condition, trueResult, falseResult, anotherFalseResult). The "name" is syntax error.
– Barmar
Nov 19 '18 at 15:30
Thank you :) :)
– Carlos
Nov 19 '18 at 16:17
add a comment |
1
1
1
You don't repeat ALTER TABLE. A single ALTER TABLE query can contain multiple alterations, separated by comma.
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL,
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`); "
));
answered Nov 19 '18 at 10:16
BarmarBarmar
422k35244346
You don't repeat ALTER TABLE. A single ALTER TABLE query can contain multiple alterations, separated by comma.
) > 0,
"SELECT 1",
"ALTER TABLE action ADD company_id INT(11) NOT NULL,
ADD CONSTRAINT `fk_company_id_action`
FOREIGN KEY (`company_id`) REFERENCES company(`company_id`); "
));
answered Nov 19 '18 at 10:16
BarmarBarmar
422k35244346
answered Nov 19 '18 at 10:16
BarmarBarmar
422k35244346
answered Nov 19 '18 at 10:16
BarmarBarmar
422k35244346
answered Nov 19 '18 at 10:16
BarmarBarmar
422k35244346
422k35244346
Perfect, thank you. What is the name of the structure I used? (I did not know what could be done that way, I have seen the example on the internet)
– Carlos
Nov 19 '18 at 10:24
You had too many arguments toIF(). It's justIF(condition, trueResult, falseResult), but you hadIF(condition, trueResult, falseResult, anotherFalseResult). The "name" is syntax error.
– Barmar
Nov 19 '18 at 15:30
Thank you :) :)
– Carlos
Nov 19 '18 at 16:17
add a comment |
Perfect, thank you. What is the name of the structure I used? (I did not know what could be done that way, I have seen the example on the internet)
– Carlos
Nov 19 '18 at 10:24
You had too many arguments toIF(). It's justIF(condition, trueResult, falseResult), but you hadIF(condition, trueResult, falseResult, anotherFalseResult). The "name" is syntax error.
– Barmar
Nov 19 '18 at 15:30
Thank you :) :)
– Carlos
Nov 19 '18 at 16:17
Perfect, thank you. What is the name of the structure I used? (I did not know what could be done that way, I have seen the example on the internet)
– Carlos
Nov 19 '18 at 10:24
Perfect, thank you. What is the name of the structure I used? (I did not know what could be done that way, I have seen the example on the internet)
– Carlos
Nov 19 '18 at 10:24
You had too many arguments to
IF(). It's just IF(condition, trueResult, falseResult), but you had IF(condition, trueResult, falseResult, anotherFalseResult). The "name" is syntax error.– Barmar
Nov 19 '18 at 15:30
You had too many arguments to
IF(). It's just IF(condition, trueResult, falseResult), but you had IF(condition, trueResult, falseResult, anotherFalseResult). The "name" is syntax error.– Barmar
Nov 19 '18 at 15:30
Thank you :) :)
– Carlos
Nov 19 '18 at 16:17
Thank you :) :)
– Carlos
Nov 19 '18 at 16:17
add a comment |
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