Area of triangle with a perpendicular problem.
Given that triangle PRQ is a right angle. A line is perpendicular to PQ at point N on the line and it meets at R.
$NR=2.4cm$ and $QR=3cm$
How do I find the area of the triangle PRQ?
My teacher said I can't used trigonometry
$PR$ is the base.
$Area=frac{bh}{2}=frac{3PR}{2}$
area
asked Nov 21 '18 at 16:50
time
41
add a comment |
Given that triangle PRQ is a right angle. A line is perpendicular to PQ at point N on the line and it meets at R.
$NR=2.4cm$ and $QR=3cm$
How do I find the area of the triangle PRQ?
My teacher said I can't used trigonometry
$PR$ is the base.
$Area=frac{bh}{2}=frac{3PR}{2}$
area
asked Nov 21 '18 at 16:50
time
41
Here is a link to what the triangle looked like google.co.uk/…:
– time
Nov 21 '18 at 16:54
add a comment |
Given that triangle PRQ is a right angle. A line is perpendicular to PQ at point N on the line and it meets at R.
$NR=2.4cm$ and $QR=3cm$
How do I find the area of the triangle PRQ?
My teacher said I can't used trigonometry
$PR$ is the base.
$Area=frac{bh}{2}=frac{3PR}{2}$
area
asked Nov 21 '18 at 16:50
time
41
Given that triangle PRQ is a right angle. A line is perpendicular to PQ at point N on the line and it meets at R.
$NR=2.4cm$ and $QR=3cm$
How do I find the area of the triangle PRQ?
My teacher said I can't used trigonometry
$PR$ is the base.
$Area=frac{bh}{2}=frac{3PR}{2}$
area
area
asked Nov 21 '18 at 16:50
time
41
asked Nov 21 '18 at 16:50
time
41
asked Nov 21 '18 at 16:50
time
41
asked Nov 21 '18 at 16:50
time
41
asked Nov 21 '18 at 16:50
time
41
41
Here is a link to what the triangle looked like google.co.uk/…:
– time
Nov 21 '18 at 16:54
add a comment |
Here is a link to what the triangle looked like google.co.uk/…:
– time
Nov 21 '18 at 16:54
Here is a link to what the triangle looked like google.co.uk/…:
– time
Nov 21 '18 at 16:54
Here is a link to what the triangle looked like google.co.uk/…:
– time
Nov 21 '18 at 16:54
add a comment |
2 Answers
2
active
oldest
votes
First find $NQ=sqrt{RQ^2-NR^2}$. Then use similarity of triangles $NRQ$ and $PRQ$: $frac{NQ}{RQ}=frac{RQ}{PQ}$ to find $PQ$.
answered Nov 21 '18 at 17:11
Vasya
3,3241515
add a comment |
You can find it using the trigonometric ratios sine and cosine. This picture shows the working more clearly.
Once you have PR, you can find area- Area= (QR)*(PR)/2 = 6.
answered Nov 21 '18 at 17:06
karun mathews
244
1
No trigs allowed ...
– Michael Hoppe
Nov 21 '18 at 19:33
Wow, I've got to read questions better. Sorry!
– karun mathews
Nov 23 '18 at 2:47
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
First find $NQ=sqrt{RQ^2-NR^2}$. Then use similarity of triangles $NRQ$ and $PRQ$: $frac{NQ}{RQ}=frac{RQ}{PQ}$ to find $PQ$.
answered Nov 21 '18 at 17:11
Vasya
3,3241515
add a comment |
First find $NQ=sqrt{RQ^2-NR^2}$. Then use similarity of triangles $NRQ$ and $PRQ$: $frac{NQ}{RQ}=frac{RQ}{PQ}$ to find $PQ$.
answered Nov 21 '18 at 17:11
Vasya
3,3241515
add a comment |
First find $NQ=sqrt{RQ^2-NR^2}$. Then use similarity of triangles $NRQ$ and $PRQ$: $frac{NQ}{RQ}=frac{RQ}{PQ}$ to find $PQ$.
answered Nov 21 '18 at 17:11
Vasya
3,3241515
First find $NQ=sqrt{RQ^2-NR^2}$. Then use similarity of triangles $NRQ$ and $PRQ$: $frac{NQ}{RQ}=frac{RQ}{PQ}$ to find $PQ$.
answered Nov 21 '18 at 17:11
Vasya
3,3241515
answered Nov 21 '18 at 17:11
Vasya
3,3241515
answered Nov 21 '18 at 17:11
Vasya
3,3241515
answered Nov 21 '18 at 17:11
Vasya
3,3241515
3,3241515
add a comment |
add a comment |
You can find it using the trigonometric ratios sine and cosine. This picture shows the working more clearly.
Once you have PR, you can find area- Area= (QR)*(PR)/2 = 6.
answered Nov 21 '18 at 17:06
karun mathews
244
1
No trigs allowed ...
– Michael Hoppe
Nov 21 '18 at 19:33
Wow, I've got to read questions better. Sorry!
– karun mathews
Nov 23 '18 at 2:47
add a comment |
You can find it using the trigonometric ratios sine and cosine. This picture shows the working more clearly.
Once you have PR, you can find area- Area= (QR)*(PR)/2 = 6.
answered Nov 21 '18 at 17:06
karun mathews
244
1
No trigs allowed ...
– Michael Hoppe
Nov 21 '18 at 19:33
Wow, I've got to read questions better. Sorry!
– karun mathews
Nov 23 '18 at 2:47
add a comment |
You can find it using the trigonometric ratios sine and cosine. This picture shows the working more clearly.
Once you have PR, you can find area- Area= (QR)*(PR)/2 = 6.
answered Nov 21 '18 at 17:06
karun mathews
244
You can find it using the trigonometric ratios sine and cosine. This picture shows the working more clearly.
Once you have PR, you can find area- Area= (QR)*(PR)/2 = 6.
answered Nov 21 '18 at 17:06
karun mathews
244
answered Nov 21 '18 at 17:06
karun mathews
244
answered Nov 21 '18 at 17:06
karun mathews
244
answered Nov 21 '18 at 17:06
karun mathews
244
244
1
No trigs allowed ...
– Michael Hoppe
Nov 21 '18 at 19:33
Wow, I've got to read questions better. Sorry!
– karun mathews
Nov 23 '18 at 2:47
add a comment |
1
No trigs allowed ...
– Michael Hoppe
Nov 21 '18 at 19:33
Wow, I've got to read questions better. Sorry!
– karun mathews
Nov 23 '18 at 2:47
1
1
No trigs allowed ...
– Michael Hoppe
Nov 21 '18 at 19:33
No trigs allowed ...
– Michael Hoppe
Nov 21 '18 at 19:33
Wow, I've got to read questions better. Sorry!
– karun mathews
Nov 23 '18 at 2:47
Wow, I've got to read questions better. Sorry!
– karun mathews
Nov 23 '18 at 2:47
add a comment |
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Here is a link to what the triangle looked like google.co.uk/…:
– time
Nov 21 '18 at 16:54