Aliasing - Nyquist frequency
$begingroup$
According to Wolfram
"
in order to recover all Fourier components of a periodic waveform, it is necessary to use a sampling rate $nu$ at least twice textit{highest} waveform frequency. The Nyquist frequency, also called the Nyquist limit is the highest frequency that can be coded ata a given sampling rate in order to tbe able to fully reconstruct the signal, i.e.,
$$
f_{text{Nyquist}} = frac{1}{2}v
$$
"
Here what I don't understand: how can this equality be true when you have a frequency (e.g. with unit Hz) on one side and a velocity (e.g. with using m/s) on the other side of the equation?
fourier-analysis fourier-series signal-processing
asked Nov 24 '18 at 11:08
ecjbecjb
1618
$endgroup$
add a comment |
$begingroup$
According to Wolfram
"
in order to recover all Fourier components of a periodic waveform, it is necessary to use a sampling rate $nu$ at least twice textit{highest} waveform frequency. The Nyquist frequency, also called the Nyquist limit is the highest frequency that can be coded ata a given sampling rate in order to tbe able to fully reconstruct the signal, i.e.,
$$
f_{text{Nyquist}} = frac{1}{2}v
$$
"
Here what I don't understand: how can this equality be true when you have a frequency (e.g. with unit Hz) on one side and a velocity (e.g. with using m/s) on the other side of the equation?
fourier-analysis fourier-series signal-processing
asked Nov 24 '18 at 11:08
ecjbecjb
1618
$endgroup$
add a comment |
$begingroup$
According to Wolfram
"
in order to recover all Fourier components of a periodic waveform, it is necessary to use a sampling rate $nu$ at least twice textit{highest} waveform frequency. The Nyquist frequency, also called the Nyquist limit is the highest frequency that can be coded ata a given sampling rate in order to tbe able to fully reconstruct the signal, i.e.,
$$
f_{text{Nyquist}} = frac{1}{2}v
$$
"
Here what I don't understand: how can this equality be true when you have a frequency (e.g. with unit Hz) on one side and a velocity (e.g. with using m/s) on the other side of the equation?
fourier-analysis fourier-series signal-processing
asked Nov 24 '18 at 11:08
ecjbecjb
1618
$endgroup$
According to Wolfram
"
in order to recover all Fourier components of a periodic waveform, it is necessary to use a sampling rate $nu$ at least twice textit{highest} waveform frequency. The Nyquist frequency, also called the Nyquist limit is the highest frequency that can be coded ata a given sampling rate in order to tbe able to fully reconstruct the signal, i.e.,
$$
f_{text{Nyquist}} = frac{1}{2}v
$$
"
Here what I don't understand: how can this equality be true when you have a frequency (e.g. with unit Hz) on one side and a velocity (e.g. with using m/s) on the other side of the equation?
fourier-analysis fourier-series signal-processing
fourier-analysis fourier-series signal-processing
asked Nov 24 '18 at 11:08
ecjbecjb
1618
asked Nov 24 '18 at 11:08
ecjbecjb
1618
asked Nov 24 '18 at 11:08
ecjbecjb
1618
asked Nov 24 '18 at 11:08
ecjbecjb
1618
asked Nov 24 '18 at 11:08
ecjbecjb
1618
1618
add a comment |
add a comment |
1 Answer
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$begingroup$
Sampling rate ν is also in Hz. It is the number of observations per second - the rate at which you are sampling data.
Both sides of the equation are in the same units. Hertz.
And that’s a Greek letter ν (nu), not an English letter v.
answered Nov 24 '18 at 11:51
ip6ip6
54839
$endgroup$
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Sampling rate ν is also in Hz. It is the number of observations per second - the rate at which you are sampling data.
Both sides of the equation are in the same units. Hertz.
And that’s a Greek letter ν (nu), not an English letter v.
answered Nov 24 '18 at 11:51
ip6ip6
54839
$endgroup$
add a comment |
$begingroup$
Sampling rate ν is also in Hz. It is the number of observations per second - the rate at which you are sampling data.
Both sides of the equation are in the same units. Hertz.
And that’s a Greek letter ν (nu), not an English letter v.
answered Nov 24 '18 at 11:51
ip6ip6
54839
$endgroup$
add a comment |
$begingroup$
Sampling rate ν is also in Hz. It is the number of observations per second - the rate at which you are sampling data.
Both sides of the equation are in the same units. Hertz.
And that’s a Greek letter ν (nu), not an English letter v.
answered Nov 24 '18 at 11:51
ip6ip6
54839
$endgroup$
Sampling rate ν is also in Hz. It is the number of observations per second - the rate at which you are sampling data.
Both sides of the equation are in the same units. Hertz.
And that’s a Greek letter ν (nu), not an English letter v.
answered Nov 24 '18 at 11:51
ip6ip6
54839
answered Nov 24 '18 at 11:51
ip6ip6
54839
answered Nov 24 '18 at 11:51
ip6ip6
54839
answered Nov 24 '18 at 11:51
ip6ip6
54839
54839
add a comment |
add a comment |
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