Why is $inf g sup g = frac{9}{16} $?











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Consider this question here :



Why is $sup f_- (n) inf f_+ (m) = frac{5}{4} $?



Call that conjecture about $frac{5}{4} $ conjecture $1$.



Let $g(n) = prod_{i=0}^n (sin^2(n) + frac{9}{16}) ) $



Conjecture $3$ :



——-



Conjecture $2$ is :



$$ sup g(n) space inf g(n) = frac{9}{16} $$



And this follows from conjecture $1$ or vice versa.



——-



It feels like this second conjecture could somehow follow from the first conjecture since



$$-(cos(n) + frac{5}{4})(cos(n) - frac{5}{4}) = - cos^2(n) + frac{25}{16} = sin^2(n) + frac{9}{16} $$



This question is about the connection ( conjecture $3$).



If you can prove conjecture $1$ or $2$ post it in the other thread.



Btw $ int_0^{2 pi} ln(sin^2(x) + frac{9}{16}) dx = 0 $ indeed as you probably already knew or guessed.










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    up vote
    2
    down vote

    favorite
    3












    Consider this question here :



    Why is $sup f_- (n) inf f_+ (m) = frac{5}{4} $?



    Call that conjecture about $frac{5}{4} $ conjecture $1$.



    Let $g(n) = prod_{i=0}^n (sin^2(n) + frac{9}{16}) ) $



    Conjecture $3$ :



    ——-



    Conjecture $2$ is :



    $$ sup g(n) space inf g(n) = frac{9}{16} $$



    And this follows from conjecture $1$ or vice versa.



    ——-



    It feels like this second conjecture could somehow follow from the first conjecture since



    $$-(cos(n) + frac{5}{4})(cos(n) - frac{5}{4}) = - cos^2(n) + frac{25}{16} = sin^2(n) + frac{9}{16} $$



    This question is about the connection ( conjecture $3$).



    If you can prove conjecture $1$ or $2$ post it in the other thread.



    Btw $ int_0^{2 pi} ln(sin^2(x) + frac{9}{16}) dx = 0 $ indeed as you probably already knew or guessed.










    share|cite|improve this question
























      up vote
      2
      down vote

      favorite
      3









      up vote
      2
      down vote

      favorite
      3






      3





      Consider this question here :



      Why is $sup f_- (n) inf f_+ (m) = frac{5}{4} $?



      Call that conjecture about $frac{5}{4} $ conjecture $1$.



      Let $g(n) = prod_{i=0}^n (sin^2(n) + frac{9}{16}) ) $



      Conjecture $3$ :



      ——-



      Conjecture $2$ is :



      $$ sup g(n) space inf g(n) = frac{9}{16} $$



      And this follows from conjecture $1$ or vice versa.



      ——-



      It feels like this second conjecture could somehow follow from the first conjecture since



      $$-(cos(n) + frac{5}{4})(cos(n) - frac{5}{4}) = - cos^2(n) + frac{25}{16} = sin^2(n) + frac{9}{16} $$



      This question is about the connection ( conjecture $3$).



      If you can prove conjecture $1$ or $2$ post it in the other thread.



      Btw $ int_0^{2 pi} ln(sin^2(x) + frac{9}{16}) dx = 0 $ indeed as you probably already knew or guessed.










      share|cite|improve this question













      Consider this question here :



      Why is $sup f_- (n) inf f_+ (m) = frac{5}{4} $?



      Call that conjecture about $frac{5}{4} $ conjecture $1$.



      Let $g(n) = prod_{i=0}^n (sin^2(n) + frac{9}{16}) ) $



      Conjecture $3$ :



      ——-



      Conjecture $2$ is :



      $$ sup g(n) space inf g(n) = frac{9}{16} $$



      And this follows from conjecture $1$ or vice versa.



      ——-



      It feels like this second conjecture could somehow follow from the first conjecture since



      $$-(cos(n) + frac{5}{4})(cos(n) - frac{5}{4}) = - cos^2(n) + frac{25}{16} = sin^2(n) + frac{9}{16} $$



      This question is about the connection ( conjecture $3$).



      If you can prove conjecture $1$ or $2$ post it in the other thread.



      Btw $ int_0^{2 pi} ln(sin^2(x) + frac{9}{16}) dx = 0 $ indeed as you probably already knew or guessed.







      calculus geometry fractions limsup-and-liminf products






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      asked Nov 15 at 22:45









      mick

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