Integral $intlimits_0^infty text{d}q cos(qx) (omega^2-q^2)^{N-1} e^{-s(omega^2-q^2)^N}$











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In my research I am interested in finding the following expression:



$$ f{}_omega^N(x) := intlimits_0^{ell^{,2N}} text{d}s ~ mathcal{I}{}_omega^N(x,s) $$
where the main problem lies in finding an analytic expression for
$$ mathcal{I}{}_omega^N(x,s) := intlimits_0^infty frac{text{d}q}{pi} cos(qx) (omega^2-q^2)^{N-1} e^{-s(omega^2-q^2)^N} , , quad N ge 2 , , quad s > 0 , , quad x in mathbb{R} , .$$
For $s>0$ this integral is convergent, and it can be evaluated numerically in principle. However, it would be nice to have an analytic expression.



In the case $N=1$ the result can be specified in terms of the imaginary error function and one obtains
$$ mathcal{I}^1_omega(x,s) = frac{e^{x^2/(4s)-s,omega^2}}{4sqrt{pi s}}left[ text{erfi}left(frac{2qs-ix}{2sqrt{s}}right) + text{erfi}left(frac{2qs+ix}{2sqrt{s}}right) right] , ,$$
but in a general case (or even just for $N=2$) I cannot solve the integral. Any ideas?










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    up vote
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    down vote

    favorite












    In my research I am interested in finding the following expression:



    $$ f{}_omega^N(x) := intlimits_0^{ell^{,2N}} text{d}s ~ mathcal{I}{}_omega^N(x,s) $$
    where the main problem lies in finding an analytic expression for
    $$ mathcal{I}{}_omega^N(x,s) := intlimits_0^infty frac{text{d}q}{pi} cos(qx) (omega^2-q^2)^{N-1} e^{-s(omega^2-q^2)^N} , , quad N ge 2 , , quad s > 0 , , quad x in mathbb{R} , .$$
    For $s>0$ this integral is convergent, and it can be evaluated numerically in principle. However, it would be nice to have an analytic expression.



    In the case $N=1$ the result can be specified in terms of the imaginary error function and one obtains
    $$ mathcal{I}^1_omega(x,s) = frac{e^{x^2/(4s)-s,omega^2}}{4sqrt{pi s}}left[ text{erfi}left(frac{2qs-ix}{2sqrt{s}}right) + text{erfi}left(frac{2qs+ix}{2sqrt{s}}right) right] , ,$$
    but in a general case (or even just for $N=2$) I cannot solve the integral. Any ideas?










    share|cite|improve this question


























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      In my research I am interested in finding the following expression:



      $$ f{}_omega^N(x) := intlimits_0^{ell^{,2N}} text{d}s ~ mathcal{I}{}_omega^N(x,s) $$
      where the main problem lies in finding an analytic expression for
      $$ mathcal{I}{}_omega^N(x,s) := intlimits_0^infty frac{text{d}q}{pi} cos(qx) (omega^2-q^2)^{N-1} e^{-s(omega^2-q^2)^N} , , quad N ge 2 , , quad s > 0 , , quad x in mathbb{R} , .$$
      For $s>0$ this integral is convergent, and it can be evaluated numerically in principle. However, it would be nice to have an analytic expression.



      In the case $N=1$ the result can be specified in terms of the imaginary error function and one obtains
      $$ mathcal{I}^1_omega(x,s) = frac{e^{x^2/(4s)-s,omega^2}}{4sqrt{pi s}}left[ text{erfi}left(frac{2qs-ix}{2sqrt{s}}right) + text{erfi}left(frac{2qs+ix}{2sqrt{s}}right) right] , ,$$
      but in a general case (or even just for $N=2$) I cannot solve the integral. Any ideas?










      share|cite|improve this question















      In my research I am interested in finding the following expression:



      $$ f{}_omega^N(x) := intlimits_0^{ell^{,2N}} text{d}s ~ mathcal{I}{}_omega^N(x,s) $$
      where the main problem lies in finding an analytic expression for
      $$ mathcal{I}{}_omega^N(x,s) := intlimits_0^infty frac{text{d}q}{pi} cos(qx) (omega^2-q^2)^{N-1} e^{-s(omega^2-q^2)^N} , , quad N ge 2 , , quad s > 0 , , quad x in mathbb{R} , .$$
      For $s>0$ this integral is convergent, and it can be evaluated numerically in principle. However, it would be nice to have an analytic expression.



      In the case $N=1$ the result can be specified in terms of the imaginary error function and one obtains
      $$ mathcal{I}^1_omega(x,s) = frac{e^{x^2/(4s)-s,omega^2}}{4sqrt{pi s}}left[ text{erfi}left(frac{2qs-ix}{2sqrt{s}}right) + text{erfi}left(frac{2qs+ix}{2sqrt{s}}right) right] , ,$$
      but in a general case (or even just for $N=2$) I cannot solve the integral. Any ideas?







      integration definite-integrals






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      edited Nov 23 at 8:10

























      asked Nov 15 at 19:40









      Jens

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