Difference in the determination of the span of the vectors made of 2x1 and 1x2 matrices











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I am trying to understand how to check whether the vectors belong to a span or not. However, I am confused with the difference in solutions between the determination of the span of the vectors made of 2x1 and 1x2 matrices. In the solutions to my textbook problems, I encounter with two different solutions.
For 1x2 matrices, like [1 2] and [-1 1], it is written that



c_1 v_1 + c_2 v_2 = v



I am okay with that, but in the next step the vectors which are 1x2 matrices are converted to 2x1 matrices and the solution goes on like (in augmented matrix)



1 -1 . a



2 1 . b



and it is being checked whether it is consistent or not. I do not get why we are converting our 1x2 matrices to 2x1 matrices.



After that, I checked for 2x1 matrices. This time, the solutions starting with defining a 2x1 vector v with all the terms equal to 1. Then, it continues with writing the 2x1 vector and also the new v vector in an augmented matrix where v is in the augmented part. Then, it ends up similarly with checking the matrix is consistency.



I know that giving 1 to every term is an arbitrary thing, but I did not get the logic behind them all.



Thanks










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    I am trying to understand how to check whether the vectors belong to a span or not. However, I am confused with the difference in solutions between the determination of the span of the vectors made of 2x1 and 1x2 matrices. In the solutions to my textbook problems, I encounter with two different solutions.
    For 1x2 matrices, like [1 2] and [-1 1], it is written that



    c_1 v_1 + c_2 v_2 = v



    I am okay with that, but in the next step the vectors which are 1x2 matrices are converted to 2x1 matrices and the solution goes on like (in augmented matrix)



    1 -1 . a



    2 1 . b



    and it is being checked whether it is consistent or not. I do not get why we are converting our 1x2 matrices to 2x1 matrices.



    After that, I checked for 2x1 matrices. This time, the solutions starting with defining a 2x1 vector v with all the terms equal to 1. Then, it continues with writing the 2x1 vector and also the new v vector in an augmented matrix where v is in the augmented part. Then, it ends up similarly with checking the matrix is consistency.



    I know that giving 1 to every term is an arbitrary thing, but I did not get the logic behind them all.



    Thanks










    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I am trying to understand how to check whether the vectors belong to a span or not. However, I am confused with the difference in solutions between the determination of the span of the vectors made of 2x1 and 1x2 matrices. In the solutions to my textbook problems, I encounter with two different solutions.
      For 1x2 matrices, like [1 2] and [-1 1], it is written that



      c_1 v_1 + c_2 v_2 = v



      I am okay with that, but in the next step the vectors which are 1x2 matrices are converted to 2x1 matrices and the solution goes on like (in augmented matrix)



      1 -1 . a



      2 1 . b



      and it is being checked whether it is consistent or not. I do not get why we are converting our 1x2 matrices to 2x1 matrices.



      After that, I checked for 2x1 matrices. This time, the solutions starting with defining a 2x1 vector v with all the terms equal to 1. Then, it continues with writing the 2x1 vector and also the new v vector in an augmented matrix where v is in the augmented part. Then, it ends up similarly with checking the matrix is consistency.



      I know that giving 1 to every term is an arbitrary thing, but I did not get the logic behind them all.



      Thanks










      share|cite|improve this question













      I am trying to understand how to check whether the vectors belong to a span or not. However, I am confused with the difference in solutions between the determination of the span of the vectors made of 2x1 and 1x2 matrices. In the solutions to my textbook problems, I encounter with two different solutions.
      For 1x2 matrices, like [1 2] and [-1 1], it is written that



      c_1 v_1 + c_2 v_2 = v



      I am okay with that, but in the next step the vectors which are 1x2 matrices are converted to 2x1 matrices and the solution goes on like (in augmented matrix)



      1 -1 . a



      2 1 . b



      and it is being checked whether it is consistent or not. I do not get why we are converting our 1x2 matrices to 2x1 matrices.



      After that, I checked for 2x1 matrices. This time, the solutions starting with defining a 2x1 vector v with all the terms equal to 1. Then, it continues with writing the 2x1 vector and also the new v vector in an augmented matrix where v is in the augmented part. Then, it ends up similarly with checking the matrix is consistency.



      I know that giving 1 to every term is an arbitrary thing, but I did not get the logic behind them all.



      Thanks







      linear-algebra matrices






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      asked Nov 14 at 18:31









      spica

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