Matrix function











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If we have $n$ by $n$ A matrix I want to ask about the general method to compute the matrix function.
For example how I can compute:



$cos(A)$ or
$sin(A)$ or
$e^{A}$ or
$log(A)$



or any other functions?










share|cite|improve this question




























    up vote
    0
    down vote

    favorite












    If we have $n$ by $n$ A matrix I want to ask about the general method to compute the matrix function.
    For example how I can compute:



    $cos(A)$ or
    $sin(A)$ or
    $e^{A}$ or
    $log(A)$



    or any other functions?










    share|cite|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      If we have $n$ by $n$ A matrix I want to ask about the general method to compute the matrix function.
      For example how I can compute:



      $cos(A)$ or
      $sin(A)$ or
      $e^{A}$ or
      $log(A)$



      or any other functions?










      share|cite|improve this question















      If we have $n$ by $n$ A matrix I want to ask about the general method to compute the matrix function.
      For example how I can compute:



      $cos(A)$ or
      $sin(A)$ or
      $e^{A}$ or
      $log(A)$



      or any other functions?







      matrix-calculus






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Nov 15 at 3:22









      Seth

      42312




      42312










      asked Nov 15 at 2:59









      hmeteir

      163




      163






















          3 Answers
          3






          active

          oldest

          votes

















          up vote
          1
          down vote



          accepted










          A consequence of the Cayley-Hamilton theorem is that any analytic function $f$ of an $ntimes n$ matrix $A$ can be expressed as a polynomial $p(A)$ of degree at most $n-1$. It’s also the case that if $lambda$ is an eigenvalue of $A$, then $f(lambda)=p(lambda)$. If you know $A$’s eigenvalues, you can therefore generate a system of linear equations in the unknown coefficients of $p$. If there are repeated eigenvalues, this system will be underdetermined, but you can generate additional independent equations by repeatedly differentiating $f$ and $p$.






          share|cite|improve this answer




























            up vote
            1
            down vote













            We can define functions $F: mathcal{M}_{ntimes n}(mathbb{R})rightarrow mathcal{M}_{ntimes n}(mathbb{R})$ analogous to analytic functions $f: mathbb{R}rightarrowmathbb{R}$ in the following way:



            Let $Ainmathcal{M}_{ntimes n}(mathbb{R})$. Define $A^0 = I$. Then, define $A^k = Acdot A^{k-1}$ recursively, via the usual matrix product. For any polynomial $p(x) = sumlimits_{i=1}^k c_ix^i$, we can now define the matrix polynomial $P(A) = sumlimits_{i=1}^k c_iA^i$.



            For functions which are not polynomials, but are analytic, we can use their power series expansion. Let $f(x)$ be an analytic function with power series $sumlimits_{i=1}^infty c_ix^i$. Then, we can define the matrix function $F(A)$ by its power series $ sumlimits_{i=1}^infty c_iA^i$, given that such a series converges to a unique matrix value for each $A$. Here is an example of proving convergence for the matrix exponential, $exp(A) := sumlimits_{i=1}^infty frac{1}{i!}A^i$. A similar method can be used to show convergence of other matrix power series corresponding to real analytic functions.






            share|cite|improve this answer




























              up vote
              0
              down vote













              Calculate the eigenvalue decomposition of the matrix
              $$A=QDQ^{-1}$$ where $D$ is a diagonal matrix whose entries are the eigenvalues of $A$, and the columns of $Q$ are the corresponding eigenvectors.



              With this decomposition in hand, any function can be evaluated as
              $$f(A)=Q,f(D),Q^{-1}$$
              which is very convenient; just evaluate the function at each diagonal element.



              If $A$ cannot be diagonalized or $Q$ is ill-conditioned, add a small random perturbation to the matrix and try again.
              $$eqalign{
              A' &= A+E cr
              |E| &approx |A|cdot 10^{-14} cr
              }$$






              share|cite|improve this answer





















                Your Answer





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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes








                up vote
                1
                down vote



                accepted










                A consequence of the Cayley-Hamilton theorem is that any analytic function $f$ of an $ntimes n$ matrix $A$ can be expressed as a polynomial $p(A)$ of degree at most $n-1$. It’s also the case that if $lambda$ is an eigenvalue of $A$, then $f(lambda)=p(lambda)$. If you know $A$’s eigenvalues, you can therefore generate a system of linear equations in the unknown coefficients of $p$. If there are repeated eigenvalues, this system will be underdetermined, but you can generate additional independent equations by repeatedly differentiating $f$ and $p$.






                share|cite|improve this answer

























                  up vote
                  1
                  down vote



                  accepted










                  A consequence of the Cayley-Hamilton theorem is that any analytic function $f$ of an $ntimes n$ matrix $A$ can be expressed as a polynomial $p(A)$ of degree at most $n-1$. It’s also the case that if $lambda$ is an eigenvalue of $A$, then $f(lambda)=p(lambda)$. If you know $A$’s eigenvalues, you can therefore generate a system of linear equations in the unknown coefficients of $p$. If there are repeated eigenvalues, this system will be underdetermined, but you can generate additional independent equations by repeatedly differentiating $f$ and $p$.






                  share|cite|improve this answer























                    up vote
                    1
                    down vote



                    accepted







                    up vote
                    1
                    down vote



                    accepted






                    A consequence of the Cayley-Hamilton theorem is that any analytic function $f$ of an $ntimes n$ matrix $A$ can be expressed as a polynomial $p(A)$ of degree at most $n-1$. It’s also the case that if $lambda$ is an eigenvalue of $A$, then $f(lambda)=p(lambda)$. If you know $A$’s eigenvalues, you can therefore generate a system of linear equations in the unknown coefficients of $p$. If there are repeated eigenvalues, this system will be underdetermined, but you can generate additional independent equations by repeatedly differentiating $f$ and $p$.






                    share|cite|improve this answer












                    A consequence of the Cayley-Hamilton theorem is that any analytic function $f$ of an $ntimes n$ matrix $A$ can be expressed as a polynomial $p(A)$ of degree at most $n-1$. It’s also the case that if $lambda$ is an eigenvalue of $A$, then $f(lambda)=p(lambda)$. If you know $A$’s eigenvalues, you can therefore generate a system of linear equations in the unknown coefficients of $p$. If there are repeated eigenvalues, this system will be underdetermined, but you can generate additional independent equations by repeatedly differentiating $f$ and $p$.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered Nov 15 at 7:38









                    amd

                    28.5k21049




                    28.5k21049






















                        up vote
                        1
                        down vote













                        We can define functions $F: mathcal{M}_{ntimes n}(mathbb{R})rightarrow mathcal{M}_{ntimes n}(mathbb{R})$ analogous to analytic functions $f: mathbb{R}rightarrowmathbb{R}$ in the following way:



                        Let $Ainmathcal{M}_{ntimes n}(mathbb{R})$. Define $A^0 = I$. Then, define $A^k = Acdot A^{k-1}$ recursively, via the usual matrix product. For any polynomial $p(x) = sumlimits_{i=1}^k c_ix^i$, we can now define the matrix polynomial $P(A) = sumlimits_{i=1}^k c_iA^i$.



                        For functions which are not polynomials, but are analytic, we can use their power series expansion. Let $f(x)$ be an analytic function with power series $sumlimits_{i=1}^infty c_ix^i$. Then, we can define the matrix function $F(A)$ by its power series $ sumlimits_{i=1}^infty c_iA^i$, given that such a series converges to a unique matrix value for each $A$. Here is an example of proving convergence for the matrix exponential, $exp(A) := sumlimits_{i=1}^infty frac{1}{i!}A^i$. A similar method can be used to show convergence of other matrix power series corresponding to real analytic functions.






                        share|cite|improve this answer

























                          up vote
                          1
                          down vote













                          We can define functions $F: mathcal{M}_{ntimes n}(mathbb{R})rightarrow mathcal{M}_{ntimes n}(mathbb{R})$ analogous to analytic functions $f: mathbb{R}rightarrowmathbb{R}$ in the following way:



                          Let $Ainmathcal{M}_{ntimes n}(mathbb{R})$. Define $A^0 = I$. Then, define $A^k = Acdot A^{k-1}$ recursively, via the usual matrix product. For any polynomial $p(x) = sumlimits_{i=1}^k c_ix^i$, we can now define the matrix polynomial $P(A) = sumlimits_{i=1}^k c_iA^i$.



                          For functions which are not polynomials, but are analytic, we can use their power series expansion. Let $f(x)$ be an analytic function with power series $sumlimits_{i=1}^infty c_ix^i$. Then, we can define the matrix function $F(A)$ by its power series $ sumlimits_{i=1}^infty c_iA^i$, given that such a series converges to a unique matrix value for each $A$. Here is an example of proving convergence for the matrix exponential, $exp(A) := sumlimits_{i=1}^infty frac{1}{i!}A^i$. A similar method can be used to show convergence of other matrix power series corresponding to real analytic functions.






                          share|cite|improve this answer























                            up vote
                            1
                            down vote










                            up vote
                            1
                            down vote









                            We can define functions $F: mathcal{M}_{ntimes n}(mathbb{R})rightarrow mathcal{M}_{ntimes n}(mathbb{R})$ analogous to analytic functions $f: mathbb{R}rightarrowmathbb{R}$ in the following way:



                            Let $Ainmathcal{M}_{ntimes n}(mathbb{R})$. Define $A^0 = I$. Then, define $A^k = Acdot A^{k-1}$ recursively, via the usual matrix product. For any polynomial $p(x) = sumlimits_{i=1}^k c_ix^i$, we can now define the matrix polynomial $P(A) = sumlimits_{i=1}^k c_iA^i$.



                            For functions which are not polynomials, but are analytic, we can use their power series expansion. Let $f(x)$ be an analytic function with power series $sumlimits_{i=1}^infty c_ix^i$. Then, we can define the matrix function $F(A)$ by its power series $ sumlimits_{i=1}^infty c_iA^i$, given that such a series converges to a unique matrix value for each $A$. Here is an example of proving convergence for the matrix exponential, $exp(A) := sumlimits_{i=1}^infty frac{1}{i!}A^i$. A similar method can be used to show convergence of other matrix power series corresponding to real analytic functions.






                            share|cite|improve this answer












                            We can define functions $F: mathcal{M}_{ntimes n}(mathbb{R})rightarrow mathcal{M}_{ntimes n}(mathbb{R})$ analogous to analytic functions $f: mathbb{R}rightarrowmathbb{R}$ in the following way:



                            Let $Ainmathcal{M}_{ntimes n}(mathbb{R})$. Define $A^0 = I$. Then, define $A^k = Acdot A^{k-1}$ recursively, via the usual matrix product. For any polynomial $p(x) = sumlimits_{i=1}^k c_ix^i$, we can now define the matrix polynomial $P(A) = sumlimits_{i=1}^k c_iA^i$.



                            For functions which are not polynomials, but are analytic, we can use their power series expansion. Let $f(x)$ be an analytic function with power series $sumlimits_{i=1}^infty c_ix^i$. Then, we can define the matrix function $F(A)$ by its power series $ sumlimits_{i=1}^infty c_iA^i$, given that such a series converges to a unique matrix value for each $A$. Here is an example of proving convergence for the matrix exponential, $exp(A) := sumlimits_{i=1}^infty frac{1}{i!}A^i$. A similar method can be used to show convergence of other matrix power series corresponding to real analytic functions.







                            share|cite|improve this answer












                            share|cite|improve this answer



                            share|cite|improve this answer










                            answered Nov 15 at 3:15









                            AlexanderJ93

                            5,279522




                            5,279522






















                                up vote
                                0
                                down vote













                                Calculate the eigenvalue decomposition of the matrix
                                $$A=QDQ^{-1}$$ where $D$ is a diagonal matrix whose entries are the eigenvalues of $A$, and the columns of $Q$ are the corresponding eigenvectors.



                                With this decomposition in hand, any function can be evaluated as
                                $$f(A)=Q,f(D),Q^{-1}$$
                                which is very convenient; just evaluate the function at each diagonal element.



                                If $A$ cannot be diagonalized or $Q$ is ill-conditioned, add a small random perturbation to the matrix and try again.
                                $$eqalign{
                                A' &= A+E cr
                                |E| &approx |A|cdot 10^{-14} cr
                                }$$






                                share|cite|improve this answer

























                                  up vote
                                  0
                                  down vote













                                  Calculate the eigenvalue decomposition of the matrix
                                  $$A=QDQ^{-1}$$ where $D$ is a diagonal matrix whose entries are the eigenvalues of $A$, and the columns of $Q$ are the corresponding eigenvectors.



                                  With this decomposition in hand, any function can be evaluated as
                                  $$f(A)=Q,f(D),Q^{-1}$$
                                  which is very convenient; just evaluate the function at each diagonal element.



                                  If $A$ cannot be diagonalized or $Q$ is ill-conditioned, add a small random perturbation to the matrix and try again.
                                  $$eqalign{
                                  A' &= A+E cr
                                  |E| &approx |A|cdot 10^{-14} cr
                                  }$$






                                  share|cite|improve this answer























                                    up vote
                                    0
                                    down vote










                                    up vote
                                    0
                                    down vote









                                    Calculate the eigenvalue decomposition of the matrix
                                    $$A=QDQ^{-1}$$ where $D$ is a diagonal matrix whose entries are the eigenvalues of $A$, and the columns of $Q$ are the corresponding eigenvectors.



                                    With this decomposition in hand, any function can be evaluated as
                                    $$f(A)=Q,f(D),Q^{-1}$$
                                    which is very convenient; just evaluate the function at each diagonal element.



                                    If $A$ cannot be diagonalized or $Q$ is ill-conditioned, add a small random perturbation to the matrix and try again.
                                    $$eqalign{
                                    A' &= A+E cr
                                    |E| &approx |A|cdot 10^{-14} cr
                                    }$$






                                    share|cite|improve this answer












                                    Calculate the eigenvalue decomposition of the matrix
                                    $$A=QDQ^{-1}$$ where $D$ is a diagonal matrix whose entries are the eigenvalues of $A$, and the columns of $Q$ are the corresponding eigenvectors.



                                    With this decomposition in hand, any function can be evaluated as
                                    $$f(A)=Q,f(D),Q^{-1}$$
                                    which is very convenient; just evaluate the function at each diagonal element.



                                    If $A$ cannot be diagonalized or $Q$ is ill-conditioned, add a small random perturbation to the matrix and try again.
                                    $$eqalign{
                                    A' &= A+E cr
                                    |E| &approx |A|cdot 10^{-14} cr
                                    }$$







                                    share|cite|improve this answer












                                    share|cite|improve this answer



                                    share|cite|improve this answer










                                    answered Nov 15 at 3:50









                                    greg

                                    7,1901719




                                    7,1901719






























                                         

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