Problem with fill color












3















I use the following command to create regular polygons. The 5th argument is there to insert options for styling the polygons. Though the line width is 0.3mm as I set it, it looks like the fill=red option is not accepted.



documentclass{article}
usepackage{amsmath,tikz,tkz-euclide,pgfplots,calculator}

newcommandpolygon[5]
{pgfmathsetmacro{angle}{360/#2}
pgfmathsetmacro{a}{(#2-1)/2}
FLOOR{a}{sol}
pgfmathsetmacro{startangle}{-90 + angle/2}
foreach i in {1,2,...,#2}
{pgfmathsetmacro{x}{startangle + angle*i}
draw[#5] (x:#3) -- (x + angle:#3) -- cycle;
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)}
foreach [count=i] j in {#4}{
pgfmathsetmacro{x}{startangle - angle*(i+sol)}
node[anchor=center] at (x:#3+.3) {$j$};}}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}

end{tikzpicture}
end{document}


I don't know if the structure of the command is not allowing any other option.










share|improve this question























  • In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

    – Kpym
    Apr 1 at 9:38













  • I want to fill the area inside the polygon and I thought that it can be done trough draw command.

    – mac
    Apr 1 at 9:51


















3















I use the following command to create regular polygons. The 5th argument is there to insert options for styling the polygons. Though the line width is 0.3mm as I set it, it looks like the fill=red option is not accepted.



documentclass{article}
usepackage{amsmath,tikz,tkz-euclide,pgfplots,calculator}

newcommandpolygon[5]
{pgfmathsetmacro{angle}{360/#2}
pgfmathsetmacro{a}{(#2-1)/2}
FLOOR{a}{sol}
pgfmathsetmacro{startangle}{-90 + angle/2}
foreach i in {1,2,...,#2}
{pgfmathsetmacro{x}{startangle + angle*i}
draw[#5] (x:#3) -- (x + angle:#3) -- cycle;
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)}
foreach [count=i] j in {#4}{
pgfmathsetmacro{x}{startangle - angle*(i+sol)}
node[anchor=center] at (x:#3+.3) {$j$};}}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}

end{tikzpicture}
end{document}


I don't know if the structure of the command is not allowing any other option.










share|improve this question























  • In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

    – Kpym
    Apr 1 at 9:38













  • I want to fill the area inside the polygon and I thought that it can be done trough draw command.

    – mac
    Apr 1 at 9:51
















3












3








3








I use the following command to create regular polygons. The 5th argument is there to insert options for styling the polygons. Though the line width is 0.3mm as I set it, it looks like the fill=red option is not accepted.



documentclass{article}
usepackage{amsmath,tikz,tkz-euclide,pgfplots,calculator}

newcommandpolygon[5]
{pgfmathsetmacro{angle}{360/#2}
pgfmathsetmacro{a}{(#2-1)/2}
FLOOR{a}{sol}
pgfmathsetmacro{startangle}{-90 + angle/2}
foreach i in {1,2,...,#2}
{pgfmathsetmacro{x}{startangle + angle*i}
draw[#5] (x:#3) -- (x + angle:#3) -- cycle;
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)}
foreach [count=i] j in {#4}{
pgfmathsetmacro{x}{startangle - angle*(i+sol)}
node[anchor=center] at (x:#3+.3) {$j$};}}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}

end{tikzpicture}
end{document}


I don't know if the structure of the command is not allowing any other option.










share|improve this question














I use the following command to create regular polygons. The 5th argument is there to insert options for styling the polygons. Though the line width is 0.3mm as I set it, it looks like the fill=red option is not accepted.



documentclass{article}
usepackage{amsmath,tikz,tkz-euclide,pgfplots,calculator}

newcommandpolygon[5]
{pgfmathsetmacro{angle}{360/#2}
pgfmathsetmacro{a}{(#2-1)/2}
FLOOR{a}{sol}
pgfmathsetmacro{startangle}{-90 + angle/2}
foreach i in {1,2,...,#2}
{pgfmathsetmacro{x}{startangle + angle*i}
draw[#5] (x:#3) -- (x + angle:#3) -- cycle;
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)}
foreach [count=i] j in {#4}{
pgfmathsetmacro{x}{startangle - angle*(i+sol)}
node[anchor=center] at (x:#3+.3) {$j$};}}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}

end{tikzpicture}
end{document}


I don't know if the structure of the command is not allowing any other option.







tikz-pgf tikz-styles fill polygon






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Apr 1 at 9:30









macmac

732716




732716













  • In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

    – Kpym
    Apr 1 at 9:38













  • I want to fill the area inside the polygon and I thought that it can be done trough draw command.

    – mac
    Apr 1 at 9:51





















  • In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

    – Kpym
    Apr 1 at 9:38













  • I want to fill the area inside the polygon and I thought that it can be done trough draw command.

    – mac
    Apr 1 at 9:51



















In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

– Kpym
Apr 1 at 9:38







In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

– Kpym
Apr 1 at 9:38















I want to fill the area inside the polygon and I thought that it can be done trough draw command.

– mac
Apr 1 at 9:51







I want to fill the area inside the polygon and I thought that it can be done trough draw command.

– mac
Apr 1 at 9:51












1 Answer
1






active

oldest

votes


















4














I am wondering why you don't follow approaches like this



documentclass{article}
usepackage{amsmath,tikz}
usetikzlibrary{shapes}

newcommandpolygon[5]{%
node[draw,#5,regular polygon,regular polygon sides=#2,minimum size=2*#3cm] (p) {};
foreach i[count=j] in {#4} {
path (p.center)--(p.corner j) node[pos=1.2] {$i$};
}
}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}
end{tikzpicture}
end{document}


enter image description here



However, I think you should not define a macro for this.





If you want to follow your way, Kpym has given you the right way: use (0,0) instead of cycle. However, one has to do a bit more. Also, there will be a very thin white line.



documentclass{article}
usepackage{amsmath,tikz,tkz-euclide,pgfplots,calculator}

newcommandpolygon[5]{%
pgfmathsetmacro{angle}{360/#2}
pgfmathsetmacro{a}{(#2-1)/2}
FLOOR{a}{sol}
pgfmathsetmacro{startangle}{-90 + angle/2}
foreach i in {1,2,...,#2} {
pgfmathsetmacro{x}{startangle + angle*i}
fill[#5] (x:#3) -- (x + angle:#3) -- (0,0);
draw[#5] (x:#3) -- (x + angle:#3);
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)
}
foreach [count=i] j in {#4} {
pgfmathsetmacro{x}{startangle - angle*(i+sol)}
node[anchor=center] at (x:#3+.3) {$j$};
}
foreach i in {1,2,...,#2} {
pgfmathsetmacro{x}{startangle + angle*i}
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)
}
}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}

end{tikzpicture}
end{document}


enter image description here






share|improve this answer





















  • 1





    The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

    – mac
    Apr 1 at 11:25











  • My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

    – Sebastiano
    Apr 1 at 11:37













  • @Sebastiano I will add in a while. However, I don't see anything strange.

    – JouleV
    Apr 1 at 11:38











  • @JouleV In the 2nd picture (2nd code).

    – Sebastiano
    Apr 1 at 11:40






  • 1





    Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

    – JouleV
    Apr 1 at 11:41












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

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active

oldest

votes









4














I am wondering why you don't follow approaches like this



documentclass{article}
usepackage{amsmath,tikz}
usetikzlibrary{shapes}

newcommandpolygon[5]{%
node[draw,#5,regular polygon,regular polygon sides=#2,minimum size=2*#3cm] (p) {};
foreach i[count=j] in {#4} {
path (p.center)--(p.corner j) node[pos=1.2] {$i$};
}
}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}
end{tikzpicture}
end{document}


enter image description here



However, I think you should not define a macro for this.





If you want to follow your way, Kpym has given you the right way: use (0,0) instead of cycle. However, one has to do a bit more. Also, there will be a very thin white line.



documentclass{article}
usepackage{amsmath,tikz,tkz-euclide,pgfplots,calculator}

newcommandpolygon[5]{%
pgfmathsetmacro{angle}{360/#2}
pgfmathsetmacro{a}{(#2-1)/2}
FLOOR{a}{sol}
pgfmathsetmacro{startangle}{-90 + angle/2}
foreach i in {1,2,...,#2} {
pgfmathsetmacro{x}{startangle + angle*i}
fill[#5] (x:#3) -- (x + angle:#3) -- (0,0);
draw[#5] (x:#3) -- (x + angle:#3);
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)
}
foreach [count=i] j in {#4} {
pgfmathsetmacro{x}{startangle - angle*(i+sol)}
node[anchor=center] at (x:#3+.3) {$j$};
}
foreach i in {1,2,...,#2} {
pgfmathsetmacro{x}{startangle + angle*i}
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)
}
}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}

end{tikzpicture}
end{document}


enter image description here






share|improve this answer





















  • 1





    The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

    – mac
    Apr 1 at 11:25











  • My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

    – Sebastiano
    Apr 1 at 11:37













  • @Sebastiano I will add in a while. However, I don't see anything strange.

    – JouleV
    Apr 1 at 11:38











  • @JouleV In the 2nd picture (2nd code).

    – Sebastiano
    Apr 1 at 11:40






  • 1





    Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

    – JouleV
    Apr 1 at 11:41
















4














I am wondering why you don't follow approaches like this



documentclass{article}
usepackage{amsmath,tikz}
usetikzlibrary{shapes}

newcommandpolygon[5]{%
node[draw,#5,regular polygon,regular polygon sides=#2,minimum size=2*#3cm] (p) {};
foreach i[count=j] in {#4} {
path (p.center)--(p.corner j) node[pos=1.2] {$i$};
}
}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}
end{tikzpicture}
end{document}


enter image description here



However, I think you should not define a macro for this.





If you want to follow your way, Kpym has given you the right way: use (0,0) instead of cycle. However, one has to do a bit more. Also, there will be a very thin white line.



documentclass{article}
usepackage{amsmath,tikz,tkz-euclide,pgfplots,calculator}

newcommandpolygon[5]{%
pgfmathsetmacro{angle}{360/#2}
pgfmathsetmacro{a}{(#2-1)/2}
FLOOR{a}{sol}
pgfmathsetmacro{startangle}{-90 + angle/2}
foreach i in {1,2,...,#2} {
pgfmathsetmacro{x}{startangle + angle*i}
fill[#5] (x:#3) -- (x + angle:#3) -- (0,0);
draw[#5] (x:#3) -- (x + angle:#3);
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)
}
foreach [count=i] j in {#4} {
pgfmathsetmacro{x}{startangle - angle*(i+sol)}
node[anchor=center] at (x:#3+.3) {$j$};
}
foreach i in {1,2,...,#2} {
pgfmathsetmacro{x}{startangle + angle*i}
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)
}
}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}

end{tikzpicture}
end{document}


enter image description here






share|improve this answer





















  • 1





    The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

    – mac
    Apr 1 at 11:25











  • My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

    – Sebastiano
    Apr 1 at 11:37













  • @Sebastiano I will add in a while. However, I don't see anything strange.

    – JouleV
    Apr 1 at 11:38











  • @JouleV In the 2nd picture (2nd code).

    – Sebastiano
    Apr 1 at 11:40






  • 1





    Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

    – JouleV
    Apr 1 at 11:41














4












4








4







I am wondering why you don't follow approaches like this



documentclass{article}
usepackage{amsmath,tikz}
usetikzlibrary{shapes}

newcommandpolygon[5]{%
node[draw,#5,regular polygon,regular polygon sides=#2,minimum size=2*#3cm] (p) {};
foreach i[count=j] in {#4} {
path (p.center)--(p.corner j) node[pos=1.2] {$i$};
}
}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}
end{tikzpicture}
end{document}


enter image description here



However, I think you should not define a macro for this.





If you want to follow your way, Kpym has given you the right way: use (0,0) instead of cycle. However, one has to do a bit more. Also, there will be a very thin white line.



documentclass{article}
usepackage{amsmath,tikz,tkz-euclide,pgfplots,calculator}

newcommandpolygon[5]{%
pgfmathsetmacro{angle}{360/#2}
pgfmathsetmacro{a}{(#2-1)/2}
FLOOR{a}{sol}
pgfmathsetmacro{startangle}{-90 + angle/2}
foreach i in {1,2,...,#2} {
pgfmathsetmacro{x}{startangle + angle*i}
fill[#5] (x:#3) -- (x + angle:#3) -- (0,0);
draw[#5] (x:#3) -- (x + angle:#3);
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)
}
foreach [count=i] j in {#4} {
pgfmathsetmacro{x}{startangle - angle*(i+sol)}
node[anchor=center] at (x:#3+.3) {$j$};
}
foreach i in {1,2,...,#2} {
pgfmathsetmacro{x}{startangle + angle*i}
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)
}
}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}

end{tikzpicture}
end{document}


enter image description here






share|improve this answer















I am wondering why you don't follow approaches like this



documentclass{article}
usepackage{amsmath,tikz}
usetikzlibrary{shapes}

newcommandpolygon[5]{%
node[draw,#5,regular polygon,regular polygon sides=#2,minimum size=2*#3cm] (p) {};
foreach i[count=j] in {#4} {
path (p.center)--(p.corner j) node[pos=1.2] {$i$};
}
}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}
end{tikzpicture}
end{document}


enter image description here



However, I think you should not define a macro for this.





If you want to follow your way, Kpym has given you the right way: use (0,0) instead of cycle. However, one has to do a bit more. Also, there will be a very thin white line.



documentclass{article}
usepackage{amsmath,tikz,tkz-euclide,pgfplots,calculator}

newcommandpolygon[5]{%
pgfmathsetmacro{angle}{360/#2}
pgfmathsetmacro{a}{(#2-1)/2}
FLOOR{a}{sol}
pgfmathsetmacro{startangle}{-90 + angle/2}
foreach i in {1,2,...,#2} {
pgfmathsetmacro{x}{startangle + angle*i}
fill[#5] (x:#3) -- (x + angle:#3) -- (0,0);
draw[#5] (x:#3) -- (x + angle:#3);
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)
}
foreach [count=i] j in {#4} {
pgfmathsetmacro{x}{startangle - angle*(i+sol)}
node[anchor=center] at (x:#3+.3) {$j$};
}
foreach i in {1,2,...,#2} {
pgfmathsetmacro{x}{startangle + angle*i}
tkzDefPoint(x:#3){A_#2}
tkzDrawPoint(A_#2)
}
}

begin{document}
begin{tikzpicture}
draw[line width=0.3mm] (0,0) circle (1);
polygon{6}{1}{A,B,varGamma,varDelta,E,Z}{line width=0.3mm,fill=red}

end{tikzpicture}
end{document}


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited Apr 1 at 11:46

























answered Apr 1 at 10:07









JouleVJouleV

12.3k22663




12.3k22663








  • 1





    The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

    – mac
    Apr 1 at 11:25











  • My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

    – Sebastiano
    Apr 1 at 11:37













  • @Sebastiano I will add in a while. However, I don't see anything strange.

    – JouleV
    Apr 1 at 11:38











  • @JouleV In the 2nd picture (2nd code).

    – Sebastiano
    Apr 1 at 11:40






  • 1





    Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

    – JouleV
    Apr 1 at 11:41














  • 1





    The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

    – mac
    Apr 1 at 11:25











  • My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

    – Sebastiano
    Apr 1 at 11:37













  • @Sebastiano I will add in a while. However, I don't see anything strange.

    – JouleV
    Apr 1 at 11:38











  • @JouleV In the 2nd picture (2nd code).

    – Sebastiano
    Apr 1 at 11:40






  • 1





    Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

    – JouleV
    Apr 1 at 11:41








1




1





The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

– mac
Apr 1 at 11:25





The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

– mac
Apr 1 at 11:25













My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

– Sebastiano
Apr 1 at 11:37







My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

– Sebastiano
Apr 1 at 11:37















@Sebastiano I will add in a while. However, I don't see anything strange.

– JouleV
Apr 1 at 11:38





@Sebastiano I will add in a while. However, I don't see anything strange.

– JouleV
Apr 1 at 11:38













@JouleV In the 2nd picture (2nd code).

– Sebastiano
Apr 1 at 11:40





@JouleV In the 2nd picture (2nd code).

– Sebastiano
Apr 1 at 11:40




1




1





Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

– JouleV
Apr 1 at 11:41





Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

– JouleV
Apr 1 at 11:41


















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