Omega? Krypton? [closed]
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Since today is April Fool's Day... Yes! Omega Krypton! You are spotted!
This is an April Fool's Day game! Think of as many ways to change Omega to Krypton!
Rules:
1. You can use numbers, letters and symbols.
2. I'm not being strict, so... you can change two letters at a time (e.g. 1 number and 1 letter is okay)
3. Since this is an April Fool's Day game, if you can get 'April Fool's Day' in between your transition, you will get extra 10 points!
4. I will let my friend Omega Krypton look at the answers... The one he thinks that is most funniest will get extra 50 points!
5. The top 3 users with most ways will get on the Leaderboard!
6. I will put the result 3 days after this question is reopened!
LEADERBOARD
1.
2.
3.
wordplay open-ended
asked Apr 1 at 10:55
K SharingK Sharing
289114
$endgroup$
closed as too broad by athin, Rubio♦ Apr 1 at 19:28
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
|
show 2 more comments
$begingroup$
Since today is April Fool's Day... Yes! Omega Krypton! You are spotted!
This is an April Fool's Day game! Think of as many ways to change Omega to Krypton!
Rules:
1. You can use numbers, letters and symbols.
2. I'm not being strict, so... you can change two letters at a time (e.g. 1 number and 1 letter is okay)
3. Since this is an April Fool's Day game, if you can get 'April Fool's Day' in between your transition, you will get extra 10 points!
4. I will let my friend Omega Krypton look at the answers... The one he thinks that is most funniest will get extra 50 points!
5. The top 3 users with most ways will get on the Leaderboard!
6. I will put the result 3 days after this question is reopened!
LEADERBOARD
1.
2.
3.
wordplay open-ended
asked Apr 1 at 10:55
K SharingK Sharing
289114
$endgroup$
closed as too broad by athin, Rubio♦ Apr 1 at 19:28
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
$begingroup$
This question risks being flagged as too broad, unfortunately. Might you include a few restrictions, or is this part of a puzzle series in which such restrictions are familiar and I am just unaware of it?
$endgroup$
– user477343
Apr 1 at 11:05
2
$begingroup$
I suggest the OP observe our answers, and then block some of the loopholes that would not be widely accepted by the community afterwards. The OP is also suggested to encourage answerers to try their best to get creative ;)
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– Omega Krypton
Apr 1 at 11:23
1
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*harumph* Ok, fun detected, countermeasures activated.
$endgroup$
– Rubio♦
Apr 1 at 19:29
6
$begingroup$
(Ok but for reals, this is pretty much definitionally too broad and basically seeking lists of random "transformations", well outside the scope of this or any SE site. I do appreciate the levity, but this doesn't fit the Q&A paradigm here.)
$endgroup$
– Rubio♦
Apr 1 at 19:32
3
$begingroup$
My stock guidance: Puzzles with no "right" answer are generally discouraged; you should have some objective criteria, even if arbitrary, for determining the "best" or most "right" answer, so that we're not just assembling a collection of valid solutions. Open-ended questions that impose no practical limitations on what kinds of answer will be accepted are, pretty much by definition, Too Broad and very likely to be closed as such. Unfortunately, adding rules after you've received answers invalidates those answers, and can end up costing those answerers reputation. Better to let it go.
$endgroup$
– Rubio♦
Apr 2 at 16:57
|
show 2 more comments
$begingroup$
Since today is April Fool's Day... Yes! Omega Krypton! You are spotted!
This is an April Fool's Day game! Think of as many ways to change Omega to Krypton!
Rules:
1. You can use numbers, letters and symbols.
2. I'm not being strict, so... you can change two letters at a time (e.g. 1 number and 1 letter is okay)
3. Since this is an April Fool's Day game, if you can get 'April Fool's Day' in between your transition, you will get extra 10 points!
4. I will let my friend Omega Krypton look at the answers... The one he thinks that is most funniest will get extra 50 points!
5. The top 3 users with most ways will get on the Leaderboard!
6. I will put the result 3 days after this question is reopened!
LEADERBOARD
1.
2.
3.
wordplay open-ended
asked Apr 1 at 10:55
K SharingK Sharing
289114
$endgroup$
Since today is April Fool's Day... Yes! Omega Krypton! You are spotted!
This is an April Fool's Day game! Think of as many ways to change Omega to Krypton!
Rules:
1. You can use numbers, letters and symbols.
2. I'm not being strict, so... you can change two letters at a time (e.g. 1 number and 1 letter is okay)
3. Since this is an April Fool's Day game, if you can get 'April Fool's Day' in between your transition, you will get extra 10 points!
4. I will let my friend Omega Krypton look at the answers... The one he thinks that is most funniest will get extra 50 points!
5. The top 3 users with most ways will get on the Leaderboard!
6. I will put the result 3 days after this question is reopened!
LEADERBOARD
1.
2.
3.
wordplay open-ended
wordplay open-ended
asked Apr 1 at 10:55
K SharingK Sharing
289114
asked Apr 1 at 10:55
K SharingK Sharing
289114
edited Apr 2 at 12:56
K Sharing
asked Apr 1 at 10:55
K SharingK Sharing
289114
asked Apr 1 at 10:55
K SharingK Sharing
289114
asked Apr 1 at 10:55
K SharingK Sharing
289114
289114
closed as too broad by athin, Rubio♦ Apr 1 at 19:28
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as too broad by athin, Rubio♦ Apr 1 at 19:28
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
$begingroup$
This question risks being flagged as too broad, unfortunately. Might you include a few restrictions, or is this part of a puzzle series in which such restrictions are familiar and I am just unaware of it?
$endgroup$
– user477343
Apr 1 at 11:05
2
$begingroup$
I suggest the OP observe our answers, and then block some of the loopholes that would not be widely accepted by the community afterwards. The OP is also suggested to encourage answerers to try their best to get creative ;)
$endgroup$
– Omega Krypton
Apr 1 at 11:23
1
$begingroup$
*harumph* Ok, fun detected, countermeasures activated.
$endgroup$
– Rubio♦
Apr 1 at 19:29
6
$begingroup$
(Ok but for reals, this is pretty much definitionally too broad and basically seeking lists of random "transformations", well outside the scope of this or any SE site. I do appreciate the levity, but this doesn't fit the Q&A paradigm here.)
$endgroup$
– Rubio♦
Apr 1 at 19:32
3
$begingroup$
My stock guidance: Puzzles with no "right" answer are generally discouraged; you should have some objective criteria, even if arbitrary, for determining the "best" or most "right" answer, so that we're not just assembling a collection of valid solutions. Open-ended questions that impose no practical limitations on what kinds of answer will be accepted are, pretty much by definition, Too Broad and very likely to be closed as such. Unfortunately, adding rules after you've received answers invalidates those answers, and can end up costing those answerers reputation. Better to let it go.
$endgroup$
– Rubio♦
Apr 2 at 16:57
|
show 2 more comments
2
$begingroup$
This question risks being flagged as too broad, unfortunately. Might you include a few restrictions, or is this part of a puzzle series in which such restrictions are familiar and I am just unaware of it?
$endgroup$
– user477343
Apr 1 at 11:05
2
$begingroup$
I suggest the OP observe our answers, and then block some of the loopholes that would not be widely accepted by the community afterwards. The OP is also suggested to encourage answerers to try their best to get creative ;)
$endgroup$
– Omega Krypton
Apr 1 at 11:23
1
$begingroup$
*harumph* Ok, fun detected, countermeasures activated.
$endgroup$
– Rubio♦
Apr 1 at 19:29
6
$begingroup$
(Ok but for reals, this is pretty much definitionally too broad and basically seeking lists of random "transformations", well outside the scope of this or any SE site. I do appreciate the levity, but this doesn't fit the Q&A paradigm here.)
$endgroup$
– Rubio♦
Apr 1 at 19:32
3
$begingroup$
My stock guidance: Puzzles with no "right" answer are generally discouraged; you should have some objective criteria, even if arbitrary, for determining the "best" or most "right" answer, so that we're not just assembling a collection of valid solutions. Open-ended questions that impose no practical limitations on what kinds of answer will be accepted are, pretty much by definition, Too Broad and very likely to be closed as such. Unfortunately, adding rules after you've received answers invalidates those answers, and can end up costing those answerers reputation. Better to let it go.
$endgroup$
– Rubio♦
Apr 2 at 16:57
2
2
$begingroup$
This question risks being flagged as too broad, unfortunately. Might you include a few restrictions, or is this part of a puzzle series in which such restrictions are familiar and I am just unaware of it?
$endgroup$
– user477343
Apr 1 at 11:05
$begingroup$
This question risks being flagged as too broad, unfortunately. Might you include a few restrictions, or is this part of a puzzle series in which such restrictions are familiar and I am just unaware of it?
$endgroup$
– user477343
Apr 1 at 11:05
2
2
$begingroup$
I suggest the OP observe our answers, and then block some of the loopholes that would not be widely accepted by the community afterwards. The OP is also suggested to encourage answerers to try their best to get creative ;)
$endgroup$
– Omega Krypton
Apr 1 at 11:23
$begingroup$
I suggest the OP observe our answers, and then block some of the loopholes that would not be widely accepted by the community afterwards. The OP is also suggested to encourage answerers to try their best to get creative ;)
$endgroup$
– Omega Krypton
Apr 1 at 11:23
1
1
$begingroup$
*harumph* Ok, fun detected, countermeasures activated.
$endgroup$
– Rubio♦
Apr 1 at 19:29
$begingroup$
*harumph* Ok, fun detected, countermeasures activated.
$endgroup$
– Rubio♦
Apr 1 at 19:29
6
6
$begingroup$
(Ok but for reals, this is pretty much definitionally too broad and basically seeking lists of random "transformations", well outside the scope of this or any SE site. I do appreciate the levity, but this doesn't fit the Q&A paradigm here.)
$endgroup$
– Rubio♦
Apr 1 at 19:32
$begingroup$
(Ok but for reals, this is pretty much definitionally too broad and basically seeking lists of random "transformations", well outside the scope of this or any SE site. I do appreciate the levity, but this doesn't fit the Q&A paradigm here.)
$endgroup$
– Rubio♦
Apr 1 at 19:32
3
3
$begingroup$
My stock guidance: Puzzles with no "right" answer are generally discouraged; you should have some objective criteria, even if arbitrary, for determining the "best" or most "right" answer, so that we're not just assembling a collection of valid solutions. Open-ended questions that impose no practical limitations on what kinds of answer will be accepted are, pretty much by definition, Too Broad and very likely to be closed as such. Unfortunately, adding rules after you've received answers invalidates those answers, and can end up costing those answerers reputation. Better to let it go.
$endgroup$
– Rubio♦
Apr 2 at 16:57
$begingroup$
My stock guidance: Puzzles with no "right" answer are generally discouraged; you should have some objective criteria, even if arbitrary, for determining the "best" or most "right" answer, so that we're not just assembling a collection of valid solutions. Open-ended questions that impose no practical limitations on what kinds of answer will be accepted are, pretty much by definition, Too Broad and very likely to be closed as such. Unfortunately, adding rules after you've received answers invalidates those answers, and can end up costing those answerers reputation. Better to let it go.
$endgroup$
– Rubio♦
Apr 2 at 16:57
|
show 2 more comments
12 Answers
12
active
oldest
votes
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Replace a comic book villain's superpower by the birthplace of their arch nemesis.
For example:
- SPEED (superpower of Professor Zoom) → CENTRAL CITY (birthplace of the Flash)
- MAGNETISM (superpower of Magneto) → NEW YORK (birthplace of Professor X)
- CLAWS (superpower of Sabretooth) → ALBERTA (birthplace of Wolverine)
- OMEGA (superpower of Darkseid) → KRYPTON (birthplace of Superman)
answered Apr 1 at 12:27
jafejafe
25.7k474252
$endgroup$
add a comment |
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In Noblesville, Indiana, there is a car dealership called Omega Autosports.
Thus:
Omega -> Noblesville -> noble -> noble gas -> krypton
Also
If you rearrange the pixels that make the symbol "Ω", you can turn that symbol into a "K" for Krypton
Plus:
The characters "Ω" and "K" both take up one byte of storage. K stands for Krypton, obviously.
And everyone knows about the
Omega 83 Professional Boar Bristle Shaving Brush, Faux Chrome Handle
Obviously:
The Omega 83 refers to Krypton's molar mass of 83.80
Oh, and
Omega-3 and Omega-6 are both essential fatty acids. Krypton's atomic number is 36. Coincidence? I think not. If you take Omega-3 and Omega-6 and factor out the omega, you get Omega(36) = Krypton(36).
On a different note:
Darkseid uses something called "The Omega effect" against superman, whose weakness is Kryptonite. Fairly obvious connection here
Ooh, I have another:
Omega is obviously always paired with Alpha, which begins with the letter A. Krypton begins with the letter K. Put them together, and you have AK. This sounds like AK-47. And as we all know, Krypton is a gas, and is thus impervious to the attacks of an AK-47.
And don't forget:
Omega's lowercase symbol, "ω", is used to denote infinity. Obviously, if you had an infinite amount of Krypton, you would create a black hole and probably destroy the universe or something. Not a good time.
And
OMEGA is a brand that makes luxury watches. They have been doing it since 1848. Add the digits in 1848 and what do you get? That's right: 21. If you take 21 and add 15, the amount of Krypton atoms you would have if you had 15 krypton atoms, you get 36, the atomic number of krypton.
answered Apr 1 at 13:11
CubemasterCubemaster
1,677334
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2
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Great answer, but I don't quite understand what "the amount of Krypton atoms you would have if you had 15 krypton atoms," means......
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– Akari
Apr 1 at 13:53
1
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Sorry, that is a bit vague. In context, the line should be "If you take 21 and add 15, which is the amount of Krypton atoms you would have if you had 15 krypton atoms" Meaning that if you had 15 Krypton atoms, the number of krypton atoms you would have is 15
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– Cubemaster
Apr 1 at 16:25
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Umm.. If I understand it right, you mean something likeif (i = 15) then i = 15?
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– Akari
Apr 1 at 17:27
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@Akari precisely.
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– Cubemaster
Apr 1 at 18:21
add a comment |
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My effort:
Omega --> 24 (24th letter of Greek alphabet) --> 36 (*1.5) --> Krypton (36th element of Periodic Table)
answered Apr 1 at 11:07
Omega KryptonOmega Krypton
5,4642848
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1
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Well done Omega Krypton!
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– K Sharing
Apr 2 at 12:57
add a comment |
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Here is a perfectly general procedure you can apply for turning words into other words.
(1) Take your starting word. (2) Work down the PSE leaderboard until you find a user whose name begins with that word. (3) The rest of their username (after trimming leading spaces, of course) is your new word.
Astonishingly, it happens that this turns Omega into Krypton.
Here is another.
(1) Take your starting word. (2) Replace it with "Krypton".
This too amazingly turns out to send "Omega" to "Krypton".
Here's a mapping from Greek letters to other things.
Go to this list of naturally occurring isotopes and start counting from the top using Greek letters: alpha, beta, ..., omega, alpha, beta, ... etc. Stop when you reach your chosen letter for the fourth time. If your chosen letter is omega, you will stop on an isotope of krypton. (And this is not true for any other choice of letter.)
answered Apr 1 at 12:32
Gareth McCaughan♦Gareth McCaughan
67.2k3170261
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add a comment |
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Use the PowerPoint Morph transition.
Omega $rightarrow$ Ohm ($Omega$)
Ohm $rightarrow$ 3 (Number of letters in Ohm)
3 $rightarrow$ Gas (Gas has 3 letters)
Gas $rightarrow$ Krypton (Krypton is gas at room temperature)
answered Apr 1 at 12:33
u_ndefinedu_ndefined
2,7901437
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4
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That's so cool! I really like the first one
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– North
Apr 1 at 13:17
2
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I am saving your wonderful .gif... hope you dont mind...
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– Omega Krypton
Apr 1 at 14:19
add a comment |
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One way is:
Omega is the last Greek letter.
Krypton is a noble gas and thus the last in its row.
Thus, Omega $rightarrow$ Krypton
Another way:
Okay is often abbreviated as OK.
Omega starts with O.
Krypton starts with K.
So Omega$rightarrow$ Krypton
answered Apr 1 at 14:17
Krad CigolKrad Cigol
1,056210
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can you explain the logic for #2? thanks!
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– Omega Krypton
Apr 1 at 14:24
add a comment |
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A Whovian twist:
Omega is the
24th letter in the Greek alphabet.
Omega first appeared in the episode, "TheThreeDoctors".
He has been portrayed by Peter Davison (among others).
Peter also portrayed the5th Doctor.
He is also the father-in-law of David Tennant, who portayed the10th Doctor.
24 * 3 * 5 / 10 = 36, the atomic number of Krypton.
answered Apr 1 at 16:01
Herb WolfeHerb Wolfe
2,31911021
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add a comment |
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My effort:
$f(Omega)totext{Kr}$
answered Apr 1 at 11:05
JonMark PerryJonMark Perry
20.7k64099
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2
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Fun fact in Rot13: na nantenz bs X Funevat vf Nu, "Xe" Fvta!
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– user477343
Apr 1 at 11:15
add a comment |
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Using sed:
echo "Omega" | sed 's/Omega/Krypton/g'
This will print "Krypton"
In order to score the April Fool's Day bonus, here is another variant:
echo "Omega" | sed -e s/Omega/April Fool's Day/g -e s/April Fool's Day/Krypton/g
This will print "Krypton", but has "April Fool's Day" as intermediate result.
answered Apr 1 at 14:13
MechMK1MechMK1
1737
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add a comment |
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Using the Gnome hypothesis:
Step 1 -> Omega / Step 2 -> ??? / Step 3 -> Krypton
answered Apr 1 at 13:39
MohirlMohirl
2,517719
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add a comment |
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My Answer is:
Omega -> Omega Oils -> Skin Oil -> Skin Cream -> Sun Cream -> Factor 15 -> Krypton Factor -> Krypton.
answered Apr 1 at 15:32
SmockSmock
5018
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add a comment |
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My addition:
I added/changed a letter each iteration
----
omega ->krypton
----
komega
komegan
komegon
koyegon
kryegon
kryeton
krypton
answered Apr 1 at 15:21
SensoraySensoray
4,68311246
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add a comment |
12 Answers
12
active
oldest
votes
12 Answers
12
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Replace a comic book villain's superpower by the birthplace of their arch nemesis.
For example:
- SPEED (superpower of Professor Zoom) → CENTRAL CITY (birthplace of the Flash)
- MAGNETISM (superpower of Magneto) → NEW YORK (birthplace of Professor X)
- CLAWS (superpower of Sabretooth) → ALBERTA (birthplace of Wolverine)
- OMEGA (superpower of Darkseid) → KRYPTON (birthplace of Superman)
answered Apr 1 at 12:27
jafejafe
25.7k474252
$endgroup$
add a comment |
$begingroup$
Replace a comic book villain's superpower by the birthplace of their arch nemesis.
For example:
- SPEED (superpower of Professor Zoom) → CENTRAL CITY (birthplace of the Flash)
- MAGNETISM (superpower of Magneto) → NEW YORK (birthplace of Professor X)
- CLAWS (superpower of Sabretooth) → ALBERTA (birthplace of Wolverine)
- OMEGA (superpower of Darkseid) → KRYPTON (birthplace of Superman)
answered Apr 1 at 12:27
jafejafe
25.7k474252
$endgroup$
add a comment |
$begingroup$
Replace a comic book villain's superpower by the birthplace of their arch nemesis.
For example:
- SPEED (superpower of Professor Zoom) → CENTRAL CITY (birthplace of the Flash)
- MAGNETISM (superpower of Magneto) → NEW YORK (birthplace of Professor X)
- CLAWS (superpower of Sabretooth) → ALBERTA (birthplace of Wolverine)
- OMEGA (superpower of Darkseid) → KRYPTON (birthplace of Superman)
answered Apr 1 at 12:27
jafejafe
25.7k474252
$endgroup$
Replace a comic book villain's superpower by the birthplace of their arch nemesis.
For example:
- SPEED (superpower of Professor Zoom) → CENTRAL CITY (birthplace of the Flash)
- MAGNETISM (superpower of Magneto) → NEW YORK (birthplace of Professor X)
- CLAWS (superpower of Sabretooth) → ALBERTA (birthplace of Wolverine)
- OMEGA (superpower of Darkseid) → KRYPTON (birthplace of Superman)
answered Apr 1 at 12:27
jafejafe
25.7k474252
answered Apr 1 at 12:27
jafejafe
25.7k474252
answered Apr 1 at 12:27
jafejafe
25.7k474252
answered Apr 1 at 12:27
jafejafe
25.7k474252
25.7k474252
add a comment |
add a comment |
$begingroup$
In Noblesville, Indiana, there is a car dealership called Omega Autosports.
Thus:
Omega -> Noblesville -> noble -> noble gas -> krypton
Also
If you rearrange the pixels that make the symbol "Ω", you can turn that symbol into a "K" for Krypton
Plus:
The characters "Ω" and "K" both take up one byte of storage. K stands for Krypton, obviously.
And everyone knows about the
Omega 83 Professional Boar Bristle Shaving Brush, Faux Chrome Handle
Obviously:
The Omega 83 refers to Krypton's molar mass of 83.80
Oh, and
Omega-3 and Omega-6 are both essential fatty acids. Krypton's atomic number is 36. Coincidence? I think not. If you take Omega-3 and Omega-6 and factor out the omega, you get Omega(36) = Krypton(36).
On a different note:
Darkseid uses something called "The Omega effect" against superman, whose weakness is Kryptonite. Fairly obvious connection here
Ooh, I have another:
Omega is obviously always paired with Alpha, which begins with the letter A. Krypton begins with the letter K. Put them together, and you have AK. This sounds like AK-47. And as we all know, Krypton is a gas, and is thus impervious to the attacks of an AK-47.
And don't forget:
Omega's lowercase symbol, "ω", is used to denote infinity. Obviously, if you had an infinite amount of Krypton, you would create a black hole and probably destroy the universe or something. Not a good time.
And
OMEGA is a brand that makes luxury watches. They have been doing it since 1848. Add the digits in 1848 and what do you get? That's right: 21. If you take 21 and add 15, the amount of Krypton atoms you would have if you had 15 krypton atoms, you get 36, the atomic number of krypton.
answered Apr 1 at 13:11
CubemasterCubemaster
1,677334
$endgroup$
2
$begingroup$
Great answer, but I don't quite understand what "the amount of Krypton atoms you would have if you had 15 krypton atoms," means......
$endgroup$
– Akari
Apr 1 at 13:53
1
$begingroup$
Sorry, that is a bit vague. In context, the line should be "If you take 21 and add 15, which is the amount of Krypton atoms you would have if you had 15 krypton atoms" Meaning that if you had 15 Krypton atoms, the number of krypton atoms you would have is 15
$endgroup$
– Cubemaster
Apr 1 at 16:25
$begingroup$
Umm.. If I understand it right, you mean something likeif (i = 15) then i = 15?
$endgroup$
– Akari
Apr 1 at 17:27
$begingroup$
@Akari precisely.
$endgroup$
– Cubemaster
Apr 1 at 18:21
add a comment |
$begingroup$
In Noblesville, Indiana, there is a car dealership called Omega Autosports.
Thus:
Omega -> Noblesville -> noble -> noble gas -> krypton
Also
If you rearrange the pixels that make the symbol "Ω", you can turn that symbol into a "K" for Krypton
Plus:
The characters "Ω" and "K" both take up one byte of storage. K stands for Krypton, obviously.
And everyone knows about the
Omega 83 Professional Boar Bristle Shaving Brush, Faux Chrome Handle
Obviously:
The Omega 83 refers to Krypton's molar mass of 83.80
Oh, and
Omega-3 and Omega-6 are both essential fatty acids. Krypton's atomic number is 36. Coincidence? I think not. If you take Omega-3 and Omega-6 and factor out the omega, you get Omega(36) = Krypton(36).
On a different note:
Darkseid uses something called "The Omega effect" against superman, whose weakness is Kryptonite. Fairly obvious connection here
Ooh, I have another:
Omega is obviously always paired with Alpha, which begins with the letter A. Krypton begins with the letter K. Put them together, and you have AK. This sounds like AK-47. And as we all know, Krypton is a gas, and is thus impervious to the attacks of an AK-47.
And don't forget:
Omega's lowercase symbol, "ω", is used to denote infinity. Obviously, if you had an infinite amount of Krypton, you would create a black hole and probably destroy the universe or something. Not a good time.
And
OMEGA is a brand that makes luxury watches. They have been doing it since 1848. Add the digits in 1848 and what do you get? That's right: 21. If you take 21 and add 15, the amount of Krypton atoms you would have if you had 15 krypton atoms, you get 36, the atomic number of krypton.
answered Apr 1 at 13:11
CubemasterCubemaster
1,677334
$endgroup$
2
$begingroup$
Great answer, but I don't quite understand what "the amount of Krypton atoms you would have if you had 15 krypton atoms," means......
$endgroup$
– Akari
Apr 1 at 13:53
1
$begingroup$
Sorry, that is a bit vague. In context, the line should be "If you take 21 and add 15, which is the amount of Krypton atoms you would have if you had 15 krypton atoms" Meaning that if you had 15 Krypton atoms, the number of krypton atoms you would have is 15
$endgroup$
– Cubemaster
Apr 1 at 16:25
$begingroup$
Umm.. If I understand it right, you mean something likeif (i = 15) then i = 15?
$endgroup$
– Akari
Apr 1 at 17:27
$begingroup$
@Akari precisely.
$endgroup$
– Cubemaster
Apr 1 at 18:21
add a comment |
$begingroup$
In Noblesville, Indiana, there is a car dealership called Omega Autosports.
Thus:
Omega -> Noblesville -> noble -> noble gas -> krypton
Also
If you rearrange the pixels that make the symbol "Ω", you can turn that symbol into a "K" for Krypton
Plus:
The characters "Ω" and "K" both take up one byte of storage. K stands for Krypton, obviously.
And everyone knows about the
Omega 83 Professional Boar Bristle Shaving Brush, Faux Chrome Handle
Obviously:
The Omega 83 refers to Krypton's molar mass of 83.80
Oh, and
Omega-3 and Omega-6 are both essential fatty acids. Krypton's atomic number is 36. Coincidence? I think not. If you take Omega-3 and Omega-6 and factor out the omega, you get Omega(36) = Krypton(36).
On a different note:
Darkseid uses something called "The Omega effect" against superman, whose weakness is Kryptonite. Fairly obvious connection here
Ooh, I have another:
Omega is obviously always paired with Alpha, which begins with the letter A. Krypton begins with the letter K. Put them together, and you have AK. This sounds like AK-47. And as we all know, Krypton is a gas, and is thus impervious to the attacks of an AK-47.
And don't forget:
Omega's lowercase symbol, "ω", is used to denote infinity. Obviously, if you had an infinite amount of Krypton, you would create a black hole and probably destroy the universe or something. Not a good time.
And
OMEGA is a brand that makes luxury watches. They have been doing it since 1848. Add the digits in 1848 and what do you get? That's right: 21. If you take 21 and add 15, the amount of Krypton atoms you would have if you had 15 krypton atoms, you get 36, the atomic number of krypton.
answered Apr 1 at 13:11
CubemasterCubemaster
1,677334
$endgroup$
In Noblesville, Indiana, there is a car dealership called Omega Autosports.
Thus:
Omega -> Noblesville -> noble -> noble gas -> krypton
Also
If you rearrange the pixels that make the symbol "Ω", you can turn that symbol into a "K" for Krypton
Plus:
The characters "Ω" and "K" both take up one byte of storage. K stands for Krypton, obviously.
And everyone knows about the
Omega 83 Professional Boar Bristle Shaving Brush, Faux Chrome Handle
Obviously:
The Omega 83 refers to Krypton's molar mass of 83.80
Oh, and
Omega-3 and Omega-6 are both essential fatty acids. Krypton's atomic number is 36. Coincidence? I think not. If you take Omega-3 and Omega-6 and factor out the omega, you get Omega(36) = Krypton(36).
On a different note:
Darkseid uses something called "The Omega effect" against superman, whose weakness is Kryptonite. Fairly obvious connection here
Ooh, I have another:
Omega is obviously always paired with Alpha, which begins with the letter A. Krypton begins with the letter K. Put them together, and you have AK. This sounds like AK-47. And as we all know, Krypton is a gas, and is thus impervious to the attacks of an AK-47.
And don't forget:
Omega's lowercase symbol, "ω", is used to denote infinity. Obviously, if you had an infinite amount of Krypton, you would create a black hole and probably destroy the universe or something. Not a good time.
And
OMEGA is a brand that makes luxury watches. They have been doing it since 1848. Add the digits in 1848 and what do you get? That's right: 21. If you take 21 and add 15, the amount of Krypton atoms you would have if you had 15 krypton atoms, you get 36, the atomic number of krypton.
answered Apr 1 at 13:11
CubemasterCubemaster
1,677334
answered Apr 1 at 13:11
CubemasterCubemaster
1,677334
answered Apr 1 at 13:11
CubemasterCubemaster
1,677334
answered Apr 1 at 13:11
CubemasterCubemaster
1,677334
1,677334
2
$begingroup$
Great answer, but I don't quite understand what "the amount of Krypton atoms you would have if you had 15 krypton atoms," means......
$endgroup$
– Akari
Apr 1 at 13:53
1
$begingroup$
Sorry, that is a bit vague. In context, the line should be "If you take 21 and add 15, which is the amount of Krypton atoms you would have if you had 15 krypton atoms" Meaning that if you had 15 Krypton atoms, the number of krypton atoms you would have is 15
$endgroup$
– Cubemaster
Apr 1 at 16:25
$begingroup$
Umm.. If I understand it right, you mean something likeif (i = 15) then i = 15?
$endgroup$
– Akari
Apr 1 at 17:27
$begingroup$
@Akari precisely.
$endgroup$
– Cubemaster
Apr 1 at 18:21
add a comment |
2
$begingroup$
Great answer, but I don't quite understand what "the amount of Krypton atoms you would have if you had 15 krypton atoms," means......
$endgroup$
– Akari
Apr 1 at 13:53
1
$begingroup$
Sorry, that is a bit vague. In context, the line should be "If you take 21 and add 15, which is the amount of Krypton atoms you would have if you had 15 krypton atoms" Meaning that if you had 15 Krypton atoms, the number of krypton atoms you would have is 15
$endgroup$
– Cubemaster
Apr 1 at 16:25
$begingroup$
Umm.. If I understand it right, you mean something likeif (i = 15) then i = 15?
$endgroup$
– Akari
Apr 1 at 17:27
$begingroup$
@Akari precisely.
$endgroup$
– Cubemaster
Apr 1 at 18:21
2
2
$begingroup$
Great answer, but I don't quite understand what "the amount of Krypton atoms you would have if you had 15 krypton atoms," means......
$endgroup$
– Akari
Apr 1 at 13:53
$begingroup$
Great answer, but I don't quite understand what "the amount of Krypton atoms you would have if you had 15 krypton atoms," means......
$endgroup$
– Akari
Apr 1 at 13:53
1
1
$begingroup$
Sorry, that is a bit vague. In context, the line should be "If you take 21 and add 15, which is the amount of Krypton atoms you would have if you had 15 krypton atoms" Meaning that if you had 15 Krypton atoms, the number of krypton atoms you would have is 15
$endgroup$
– Cubemaster
Apr 1 at 16:25
$begingroup$
Sorry, that is a bit vague. In context, the line should be "If you take 21 and add 15, which is the amount of Krypton atoms you would have if you had 15 krypton atoms" Meaning that if you had 15 Krypton atoms, the number of krypton atoms you would have is 15
$endgroup$
– Cubemaster
Apr 1 at 16:25
$begingroup$
Umm.. If I understand it right, you mean something like
if (i = 15) then i = 15?$endgroup$
– Akari
Apr 1 at 17:27
$begingroup$
Umm.. If I understand it right, you mean something like
if (i = 15) then i = 15?$endgroup$
– Akari
Apr 1 at 17:27
$begingroup$
@Akari precisely.
$endgroup$
– Cubemaster
Apr 1 at 18:21
$begingroup$
@Akari precisely.
$endgroup$
– Cubemaster
Apr 1 at 18:21
add a comment |
$begingroup$
My effort:
Omega --> 24 (24th letter of Greek alphabet) --> 36 (*1.5) --> Krypton (36th element of Periodic Table)
answered Apr 1 at 11:07
Omega KryptonOmega Krypton
5,4642848
$endgroup$
1
$begingroup$
Well done Omega Krypton!
$endgroup$
– K Sharing
Apr 2 at 12:57
add a comment |
$begingroup$
My effort:
Omega --> 24 (24th letter of Greek alphabet) --> 36 (*1.5) --> Krypton (36th element of Periodic Table)
answered Apr 1 at 11:07
Omega KryptonOmega Krypton
5,4642848
$endgroup$
1
$begingroup$
Well done Omega Krypton!
$endgroup$
– K Sharing
Apr 2 at 12:57
add a comment |
$begingroup$
My effort:
Omega --> 24 (24th letter of Greek alphabet) --> 36 (*1.5) --> Krypton (36th element of Periodic Table)
answered Apr 1 at 11:07
Omega KryptonOmega Krypton
5,4642848
$endgroup$
My effort:
Omega --> 24 (24th letter of Greek alphabet) --> 36 (*1.5) --> Krypton (36th element of Periodic Table)
answered Apr 1 at 11:07
Omega KryptonOmega Krypton
5,4642848
edited Apr 1 at 14:56
answered Apr 1 at 11:07
Omega KryptonOmega Krypton
5,4642848
answered Apr 1 at 11:07
Omega KryptonOmega Krypton
5,4642848
answered Apr 1 at 11:07
Omega KryptonOmega Krypton
5,4642848
5,4642848
1
$begingroup$
Well done Omega Krypton!
$endgroup$
– K Sharing
Apr 2 at 12:57
add a comment |
1
$begingroup$
Well done Omega Krypton!
$endgroup$
– K Sharing
Apr 2 at 12:57
1
1
$begingroup$
Well done Omega Krypton!
$endgroup$
– K Sharing
Apr 2 at 12:57
$begingroup$
Well done Omega Krypton!
$endgroup$
– K Sharing
Apr 2 at 12:57
add a comment |
$begingroup$
Here is a perfectly general procedure you can apply for turning words into other words.
(1) Take your starting word. (2) Work down the PSE leaderboard until you find a user whose name begins with that word. (3) The rest of their username (after trimming leading spaces, of course) is your new word.
Astonishingly, it happens that this turns Omega into Krypton.
Here is another.
(1) Take your starting word. (2) Replace it with "Krypton".
This too amazingly turns out to send "Omega" to "Krypton".
Here's a mapping from Greek letters to other things.
Go to this list of naturally occurring isotopes and start counting from the top using Greek letters: alpha, beta, ..., omega, alpha, beta, ... etc. Stop when you reach your chosen letter for the fourth time. If your chosen letter is omega, you will stop on an isotope of krypton. (And this is not true for any other choice of letter.)
answered Apr 1 at 12:32
Gareth McCaughan♦Gareth McCaughan
67.2k3170261
$endgroup$
add a comment |
$begingroup$
Here is a perfectly general procedure you can apply for turning words into other words.
(1) Take your starting word. (2) Work down the PSE leaderboard until you find a user whose name begins with that word. (3) The rest of their username (after trimming leading spaces, of course) is your new word.
Astonishingly, it happens that this turns Omega into Krypton.
Here is another.
(1) Take your starting word. (2) Replace it with "Krypton".
This too amazingly turns out to send "Omega" to "Krypton".
Here's a mapping from Greek letters to other things.
Go to this list of naturally occurring isotopes and start counting from the top using Greek letters: alpha, beta, ..., omega, alpha, beta, ... etc. Stop when you reach your chosen letter for the fourth time. If your chosen letter is omega, you will stop on an isotope of krypton. (And this is not true for any other choice of letter.)
answered Apr 1 at 12:32
Gareth McCaughan♦Gareth McCaughan
67.2k3170261
$endgroup$
add a comment |
$begingroup$
Here is a perfectly general procedure you can apply for turning words into other words.
(1) Take your starting word. (2) Work down the PSE leaderboard until you find a user whose name begins with that word. (3) The rest of their username (after trimming leading spaces, of course) is your new word.
Astonishingly, it happens that this turns Omega into Krypton.
Here is another.
(1) Take your starting word. (2) Replace it with "Krypton".
This too amazingly turns out to send "Omega" to "Krypton".
Here's a mapping from Greek letters to other things.
Go to this list of naturally occurring isotopes and start counting from the top using Greek letters: alpha, beta, ..., omega, alpha, beta, ... etc. Stop when you reach your chosen letter for the fourth time. If your chosen letter is omega, you will stop on an isotope of krypton. (And this is not true for any other choice of letter.)
answered Apr 1 at 12:32
Gareth McCaughan♦Gareth McCaughan
67.2k3170261
$endgroup$
Here is a perfectly general procedure you can apply for turning words into other words.
(1) Take your starting word. (2) Work down the PSE leaderboard until you find a user whose name begins with that word. (3) The rest of their username (after trimming leading spaces, of course) is your new word.
Astonishingly, it happens that this turns Omega into Krypton.
Here is another.
(1) Take your starting word. (2) Replace it with "Krypton".
This too amazingly turns out to send "Omega" to "Krypton".
Here's a mapping from Greek letters to other things.
Go to this list of naturally occurring isotopes and start counting from the top using Greek letters: alpha, beta, ..., omega, alpha, beta, ... etc. Stop when you reach your chosen letter for the fourth time. If your chosen letter is omega, you will stop on an isotope of krypton. (And this is not true for any other choice of letter.)
answered Apr 1 at 12:32
Gareth McCaughan♦Gareth McCaughan
67.2k3170261
answered Apr 1 at 12:32
Gareth McCaughan♦Gareth McCaughan
67.2k3170261
answered Apr 1 at 12:32
Gareth McCaughan♦Gareth McCaughan
67.2k3170261
answered Apr 1 at 12:32
Gareth McCaughan♦Gareth McCaughan
67.2k3170261
67.2k3170261
add a comment |
add a comment |
$begingroup$
Use the PowerPoint Morph transition.
Omega $rightarrow$ Ohm ($Omega$)
Ohm $rightarrow$ 3 (Number of letters in Ohm)
3 $rightarrow$ Gas (Gas has 3 letters)
Gas $rightarrow$ Krypton (Krypton is gas at room temperature)
answered Apr 1 at 12:33
u_ndefinedu_ndefined
2,7901437
$endgroup$
4
$begingroup$
That's so cool! I really like the first one
$endgroup$
– North
Apr 1 at 13:17
2
$begingroup$
I am saving your wonderful .gif... hope you dont mind...
$endgroup$
– Omega Krypton
Apr 1 at 14:19
add a comment |
$begingroup$
Use the PowerPoint Morph transition.
Omega $rightarrow$ Ohm ($Omega$)
Ohm $rightarrow$ 3 (Number of letters in Ohm)
3 $rightarrow$ Gas (Gas has 3 letters)
Gas $rightarrow$ Krypton (Krypton is gas at room temperature)
answered Apr 1 at 12:33
u_ndefinedu_ndefined
2,7901437
$endgroup$
4
$begingroup$
That's so cool! I really like the first one
$endgroup$
– North
Apr 1 at 13:17
2
$begingroup$
I am saving your wonderful .gif... hope you dont mind...
$endgroup$
– Omega Krypton
Apr 1 at 14:19
add a comment |
$begingroup$
Use the PowerPoint Morph transition.
Omega $rightarrow$ Ohm ($Omega$)
Ohm $rightarrow$ 3 (Number of letters in Ohm)
3 $rightarrow$ Gas (Gas has 3 letters)
Gas $rightarrow$ Krypton (Krypton is gas at room temperature)
answered Apr 1 at 12:33
u_ndefinedu_ndefined
2,7901437
$endgroup$
Use the PowerPoint Morph transition.
Omega $rightarrow$ Ohm ($Omega$)
Ohm $rightarrow$ 3 (Number of letters in Ohm)
3 $rightarrow$ Gas (Gas has 3 letters)
Gas $rightarrow$ Krypton (Krypton is gas at room temperature)
answered Apr 1 at 12:33
u_ndefinedu_ndefined
2,7901437
edited Apr 1 at 12:46
answered Apr 1 at 12:33
u_ndefinedu_ndefined
2,7901437
answered Apr 1 at 12:33
u_ndefinedu_ndefined
2,7901437
answered Apr 1 at 12:33
u_ndefinedu_ndefined
2,7901437
2,7901437
4
$begingroup$
That's so cool! I really like the first one
$endgroup$
– North
Apr 1 at 13:17
2
$begingroup$
I am saving your wonderful .gif... hope you dont mind...
$endgroup$
– Omega Krypton
Apr 1 at 14:19
add a comment |
4
$begingroup$
That's so cool! I really like the first one
$endgroup$
– North
Apr 1 at 13:17
2
$begingroup$
I am saving your wonderful .gif... hope you dont mind...
$endgroup$
– Omega Krypton
Apr 1 at 14:19
4
4
$begingroup$
That's so cool! I really like the first one
$endgroup$
– North
Apr 1 at 13:17
$begingroup$
That's so cool! I really like the first one
$endgroup$
– North
Apr 1 at 13:17
2
2
$begingroup$
I am saving your wonderful .gif... hope you dont mind...
$endgroup$
– Omega Krypton
Apr 1 at 14:19
$begingroup$
I am saving your wonderful .gif... hope you dont mind...
$endgroup$
– Omega Krypton
Apr 1 at 14:19
add a comment |
$begingroup$
One way is:
Omega is the last Greek letter.
Krypton is a noble gas and thus the last in its row.
Thus, Omega $rightarrow$ Krypton
Another way:
Okay is often abbreviated as OK.
Omega starts with O.
Krypton starts with K.
So Omega$rightarrow$ Krypton
answered Apr 1 at 14:17
Krad CigolKrad Cigol
1,056210
$endgroup$
$begingroup$
can you explain the logic for #2? thanks!
$endgroup$
– Omega Krypton
Apr 1 at 14:24
add a comment |
$begingroup$
One way is:
Omega is the last Greek letter.
Krypton is a noble gas and thus the last in its row.
Thus, Omega $rightarrow$ Krypton
Another way:
Okay is often abbreviated as OK.
Omega starts with O.
Krypton starts with K.
So Omega$rightarrow$ Krypton
answered Apr 1 at 14:17
Krad CigolKrad Cigol
1,056210
$endgroup$
$begingroup$
can you explain the logic for #2? thanks!
$endgroup$
– Omega Krypton
Apr 1 at 14:24
add a comment |
$begingroup$
One way is:
Omega is the last Greek letter.
Krypton is a noble gas and thus the last in its row.
Thus, Omega $rightarrow$ Krypton
Another way:
Okay is often abbreviated as OK.
Omega starts with O.
Krypton starts with K.
So Omega$rightarrow$ Krypton
answered Apr 1 at 14:17
Krad CigolKrad Cigol
1,056210
$endgroup$
One way is:
Omega is the last Greek letter.
Krypton is a noble gas and thus the last in its row.
Thus, Omega $rightarrow$ Krypton
Another way:
Okay is often abbreviated as OK.
Omega starts with O.
Krypton starts with K.
So Omega$rightarrow$ Krypton
answered Apr 1 at 14:17
Krad CigolKrad Cigol
1,056210
answered Apr 1 at 14:17
Krad CigolKrad Cigol
1,056210
answered Apr 1 at 14:17
Krad CigolKrad Cigol
1,056210
answered Apr 1 at 14:17
Krad CigolKrad Cigol
1,056210
1,056210
$begingroup$
can you explain the logic for #2? thanks!
$endgroup$
– Omega Krypton
Apr 1 at 14:24
add a comment |
$begingroup$
can you explain the logic for #2? thanks!
$endgroup$
– Omega Krypton
Apr 1 at 14:24
$begingroup$
can you explain the logic for #2? thanks!
$endgroup$
– Omega Krypton
Apr 1 at 14:24
$begingroup$
can you explain the logic for #2? thanks!
$endgroup$
– Omega Krypton
Apr 1 at 14:24
add a comment |
$begingroup$
A Whovian twist:
Omega is the
24th letter in the Greek alphabet.
Omega first appeared in the episode, "TheThreeDoctors".
He has been portrayed by Peter Davison (among others).
Peter also portrayed the5th Doctor.
He is also the father-in-law of David Tennant, who portayed the10th Doctor.
24 * 3 * 5 / 10 = 36, the atomic number of Krypton.
answered Apr 1 at 16:01
Herb WolfeHerb Wolfe
2,31911021
$endgroup$
add a comment |
$begingroup$
A Whovian twist:
Omega is the
24th letter in the Greek alphabet.
Omega first appeared in the episode, "TheThreeDoctors".
He has been portrayed by Peter Davison (among others).
Peter also portrayed the5th Doctor.
He is also the father-in-law of David Tennant, who portayed the10th Doctor.
24 * 3 * 5 / 10 = 36, the atomic number of Krypton.
answered Apr 1 at 16:01
Herb WolfeHerb Wolfe
2,31911021
$endgroup$
add a comment |
$begingroup$
A Whovian twist:
Omega is the
24th letter in the Greek alphabet.
Omega first appeared in the episode, "TheThreeDoctors".
He has been portrayed by Peter Davison (among others).
Peter also portrayed the5th Doctor.
He is also the father-in-law of David Tennant, who portayed the10th Doctor.
24 * 3 * 5 / 10 = 36, the atomic number of Krypton.
answered Apr 1 at 16:01
Herb WolfeHerb Wolfe
2,31911021
$endgroup$
A Whovian twist:
Omega is the
24th letter in the Greek alphabet.
Omega first appeared in the episode, "TheThreeDoctors".
He has been portrayed by Peter Davison (among others).
Peter also portrayed the5th Doctor.
He is also the father-in-law of David Tennant, who portayed the10th Doctor.
24 * 3 * 5 / 10 = 36, the atomic number of Krypton.
answered Apr 1 at 16:01
Herb WolfeHerb Wolfe
2,31911021
answered Apr 1 at 16:01
Herb WolfeHerb Wolfe
2,31911021
answered Apr 1 at 16:01
Herb WolfeHerb Wolfe
2,31911021
answered Apr 1 at 16:01
Herb WolfeHerb Wolfe
2,31911021
2,31911021
add a comment |
add a comment |
$begingroup$
My effort:
$f(Omega)totext{Kr}$
answered Apr 1 at 11:05
JonMark PerryJonMark Perry
20.7k64099
$endgroup$
2
$begingroup$
Fun fact in Rot13: na nantenz bs X Funevat vf Nu, "Xe" Fvta!
$endgroup$
– user477343
Apr 1 at 11:15
add a comment |
$begingroup$
My effort:
$f(Omega)totext{Kr}$
answered Apr 1 at 11:05
JonMark PerryJonMark Perry
20.7k64099
$endgroup$
2
$begingroup$
Fun fact in Rot13: na nantenz bs X Funevat vf Nu, "Xe" Fvta!
$endgroup$
– user477343
Apr 1 at 11:15
add a comment |
$begingroup$
My effort:
$f(Omega)totext{Kr}$
answered Apr 1 at 11:05
JonMark PerryJonMark Perry
20.7k64099
$endgroup$
My effort:
$f(Omega)totext{Kr}$
answered Apr 1 at 11:05
JonMark PerryJonMark Perry
20.7k64099
answered Apr 1 at 11:05
JonMark PerryJonMark Perry
20.7k64099
answered Apr 1 at 11:05
JonMark PerryJonMark Perry
20.7k64099
answered Apr 1 at 11:05
JonMark PerryJonMark Perry
20.7k64099
20.7k64099
2
$begingroup$
Fun fact in Rot13: na nantenz bs X Funevat vf Nu, "Xe" Fvta!
$endgroup$
– user477343
Apr 1 at 11:15
add a comment |
2
$begingroup$
Fun fact in Rot13: na nantenz bs X Funevat vf Nu, "Xe" Fvta!
$endgroup$
– user477343
Apr 1 at 11:15
2
2
$begingroup$
Fun fact in Rot13: na nantenz bs X Funevat vf Nu, "Xe" Fvta!
$endgroup$
– user477343
Apr 1 at 11:15
$begingroup$
Fun fact in Rot13: na nantenz bs X Funevat vf Nu, "Xe" Fvta!
$endgroup$
– user477343
Apr 1 at 11:15
add a comment |
$begingroup$
Using sed:
echo "Omega" | sed 's/Omega/Krypton/g'
This will print "Krypton"
In order to score the April Fool's Day bonus, here is another variant:
echo "Omega" | sed -e s/Omega/April Fool's Day/g -e s/April Fool's Day/Krypton/g
This will print "Krypton", but has "April Fool's Day" as intermediate result.
answered Apr 1 at 14:13
MechMK1MechMK1
1737
$endgroup$
add a comment |
$begingroup$
Using sed:
echo "Omega" | sed 's/Omega/Krypton/g'
This will print "Krypton"
In order to score the April Fool's Day bonus, here is another variant:
echo "Omega" | sed -e s/Omega/April Fool's Day/g -e s/April Fool's Day/Krypton/g
This will print "Krypton", but has "April Fool's Day" as intermediate result.
answered Apr 1 at 14:13
MechMK1MechMK1
1737
$endgroup$
add a comment |
$begingroup$
Using sed:
echo "Omega" | sed 's/Omega/Krypton/g'
This will print "Krypton"
In order to score the April Fool's Day bonus, here is another variant:
echo "Omega" | sed -e s/Omega/April Fool's Day/g -e s/April Fool's Day/Krypton/g
This will print "Krypton", but has "April Fool's Day" as intermediate result.
answered Apr 1 at 14:13
MechMK1MechMK1
1737
$endgroup$
Using sed:
echo "Omega" | sed 's/Omega/Krypton/g'
This will print "Krypton"
In order to score the April Fool's Day bonus, here is another variant:
echo "Omega" | sed -e s/Omega/April Fool's Day/g -e s/April Fool's Day/Krypton/g
This will print "Krypton", but has "April Fool's Day" as intermediate result.
answered Apr 1 at 14:13
MechMK1MechMK1
1737
edited Apr 4 at 13:51
answered Apr 1 at 14:13
MechMK1MechMK1
1737
answered Apr 1 at 14:13
MechMK1MechMK1
1737
answered Apr 1 at 14:13
MechMK1MechMK1
1737
1737
add a comment |
add a comment |
$begingroup$
Using the Gnome hypothesis:
Step 1 -> Omega / Step 2 -> ??? / Step 3 -> Krypton
answered Apr 1 at 13:39
MohirlMohirl
2,517719
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Using the Gnome hypothesis:
Step 1 -> Omega / Step 2 -> ??? / Step 3 -> Krypton
answered Apr 1 at 13:39
MohirlMohirl
2,517719
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add a comment |
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Using the Gnome hypothesis:
Step 1 -> Omega / Step 2 -> ??? / Step 3 -> Krypton
answered Apr 1 at 13:39
MohirlMohirl
2,517719
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Using the Gnome hypothesis:
Step 1 -> Omega / Step 2 -> ??? / Step 3 -> Krypton
answered Apr 1 at 13:39
MohirlMohirl
2,517719
answered Apr 1 at 13:39
MohirlMohirl
2,517719
answered Apr 1 at 13:39
MohirlMohirl
2,517719
answered Apr 1 at 13:39
MohirlMohirl
2,517719
2,517719
add a comment |
add a comment |
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My Answer is:
Omega -> Omega Oils -> Skin Oil -> Skin Cream -> Sun Cream -> Factor 15 -> Krypton Factor -> Krypton.
answered Apr 1 at 15:32
SmockSmock
5018
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My Answer is:
Omega -> Omega Oils -> Skin Oil -> Skin Cream -> Sun Cream -> Factor 15 -> Krypton Factor -> Krypton.
answered Apr 1 at 15:32
SmockSmock
5018
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My Answer is:
Omega -> Omega Oils -> Skin Oil -> Skin Cream -> Sun Cream -> Factor 15 -> Krypton Factor -> Krypton.
answered Apr 1 at 15:32
SmockSmock
5018
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My Answer is:
Omega -> Omega Oils -> Skin Oil -> Skin Cream -> Sun Cream -> Factor 15 -> Krypton Factor -> Krypton.
answered Apr 1 at 15:32
SmockSmock
5018
answered Apr 1 at 15:32
SmockSmock
5018
answered Apr 1 at 15:32
SmockSmock
5018
answered Apr 1 at 15:32
SmockSmock
5018
5018
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My addition:
I added/changed a letter each iteration
----
omega ->krypton
----
komega
komegan
komegon
koyegon
kryegon
kryeton
krypton
answered Apr 1 at 15:21
SensoraySensoray
4,68311246
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add a comment |
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My addition:
I added/changed a letter each iteration
----
omega ->krypton
----
komega
komegan
komegon
koyegon
kryegon
kryeton
krypton
answered Apr 1 at 15:21
SensoraySensoray
4,68311246
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add a comment |
$begingroup$
My addition:
I added/changed a letter each iteration
----
omega ->krypton
----
komega
komegan
komegon
koyegon
kryegon
kryeton
krypton
answered Apr 1 at 15:21
SensoraySensoray
4,68311246
$endgroup$
My addition:
I added/changed a letter each iteration
----
omega ->krypton
----
komega
komegan
komegon
koyegon
kryegon
kryeton
krypton
answered Apr 1 at 15:21
SensoraySensoray
4,68311246
answered Apr 1 at 15:21
SensoraySensoray
4,68311246
answered Apr 1 at 15:21
SensoraySensoray
4,68311246
answered Apr 1 at 15:21
SensoraySensoray
4,68311246
4,68311246
add a comment |
add a comment |
2
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This question risks being flagged as too broad, unfortunately. Might you include a few restrictions, or is this part of a puzzle series in which such restrictions are familiar and I am just unaware of it?
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– user477343
Apr 1 at 11:05
2
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I suggest the OP observe our answers, and then block some of the loopholes that would not be widely accepted by the community afterwards. The OP is also suggested to encourage answerers to try their best to get creative ;)
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– Omega Krypton
Apr 1 at 11:23
1
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*harumph* Ok, fun detected, countermeasures activated.
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– Rubio♦
Apr 1 at 19:29
6
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(Ok but for reals, this is pretty much definitionally too broad and basically seeking lists of random "transformations", well outside the scope of this or any SE site. I do appreciate the levity, but this doesn't fit the Q&A paradigm here.)
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– Rubio♦
Apr 1 at 19:32
3
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My stock guidance: Puzzles with no "right" answer are generally discouraged; you should have some objective criteria, even if arbitrary, for determining the "best" or most "right" answer, so that we're not just assembling a collection of valid solutions. Open-ended questions that impose no practical limitations on what kinds of answer will be accepted are, pretty much by definition, Too Broad and very likely to be closed as such. Unfortunately, adding rules after you've received answers invalidates those answers, and can end up costing those answerers reputation. Better to let it go.
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– Rubio♦
Apr 2 at 16:57