Mysql Select Between values not including same values
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I am trying to select data between two dates using:
SELECT `timein`,
`date`
FROM `clock`
WHERE `eid` = '189'
AND date BETWEEN '2018-10-01' AND '2018-10-31'
This provides me with all of the data, but I need to exclude selecting the same date.
For example:
Date: 2018-10-11 | Value: 1
Date: 2018-10-12 | Value: 2
Date: 2018-10-13 | Value: 3
Date: 2018-10-11 | Value: 4 **<-- Do not select**
mysql
add a comment |
I am trying to select data between two dates using:
SELECT `timein`,
`date`
FROM `clock`
WHERE `eid` = '189'
AND date BETWEEN '2018-10-01' AND '2018-10-31'
This provides me with all of the data, but I need to exclude selecting the same date.
For example:
Date: 2018-10-11 | Value: 1
Date: 2018-10-12 | Value: 2
Date: 2018-10-13 | Value: 3
Date: 2018-10-11 | Value: 4 **<-- Do not select**
mysql
1
How come you want Value 1 and not Value 4?
– jarlh
Nov 22 '18 at 19:46
Please add relevant tags only. I have removed the rest of the irrelevant ones.
– Chowkidar Madhur Bhaiya
Nov 22 '18 at 19:47
The query has the columns timein and date, and the sample data has date and value... In different order.
– jarlh
Nov 22 '18 at 19:49
add a comment |
I am trying to select data between two dates using:
SELECT `timein`,
`date`
FROM `clock`
WHERE `eid` = '189'
AND date BETWEEN '2018-10-01' AND '2018-10-31'
This provides me with all of the data, but I need to exclude selecting the same date.
For example:
Date: 2018-10-11 | Value: 1
Date: 2018-10-12 | Value: 2
Date: 2018-10-13 | Value: 3
Date: 2018-10-11 | Value: 4 **<-- Do not select**
mysql
I am trying to select data between two dates using:
SELECT `timein`,
`date`
FROM `clock`
WHERE `eid` = '189'
AND date BETWEEN '2018-10-01' AND '2018-10-31'
This provides me with all of the data, but I need to exclude selecting the same date.
For example:
Date: 2018-10-11 | Value: 1
Date: 2018-10-12 | Value: 2
Date: 2018-10-13 | Value: 3
Date: 2018-10-11 | Value: 4 **<-- Do not select**
mysql
mysql
edited Nov 22 '18 at 19:47
Chowkidar Madhur Bhaiya
19.8k62336
19.8k62336
asked Nov 22 '18 at 19:45
Roman BRoman B
31
31
1
How come you want Value 1 and not Value 4?
– jarlh
Nov 22 '18 at 19:46
Please add relevant tags only. I have removed the rest of the irrelevant ones.
– Chowkidar Madhur Bhaiya
Nov 22 '18 at 19:47
The query has the columns timein and date, and the sample data has date and value... In different order.
– jarlh
Nov 22 '18 at 19:49
add a comment |
1
How come you want Value 1 and not Value 4?
– jarlh
Nov 22 '18 at 19:46
Please add relevant tags only. I have removed the rest of the irrelevant ones.
– Chowkidar Madhur Bhaiya
Nov 22 '18 at 19:47
The query has the columns timein and date, and the sample data has date and value... In different order.
– jarlh
Nov 22 '18 at 19:49
1
1
How come you want Value 1 and not Value 4?
– jarlh
Nov 22 '18 at 19:46
How come you want Value 1 and not Value 4?
– jarlh
Nov 22 '18 at 19:46
Please add relevant tags only. I have removed the rest of the irrelevant ones.
– Chowkidar Madhur Bhaiya
Nov 22 '18 at 19:47
Please add relevant tags only. I have removed the rest of the irrelevant ones.
– Chowkidar Madhur Bhaiya
Nov 22 '18 at 19:47
The query has the columns timein and date, and the sample data has date and value... In different order.
– jarlh
Nov 22 '18 at 19:49
The query has the columns timein and date, and the sample data has date and value... In different order.
– jarlh
Nov 22 '18 at 19:49
add a comment |
1 Answer
1
active
oldest
votes
Do a GROUP BY
, use MIN()
to pick the lowest timein value:
SELECT date, min(timein)
FROM clock
WHERE eID = '189' AND date BETWEEN '2018-10-01' AND '2018-10-31'
group by date
Thank you, that works perfectly.
– Roman B
Nov 22 '18 at 20:20
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Do a GROUP BY
, use MIN()
to pick the lowest timein value:
SELECT date, min(timein)
FROM clock
WHERE eID = '189' AND date BETWEEN '2018-10-01' AND '2018-10-31'
group by date
Thank you, that works perfectly.
– Roman B
Nov 22 '18 at 20:20
add a comment |
Do a GROUP BY
, use MIN()
to pick the lowest timein value:
SELECT date, min(timein)
FROM clock
WHERE eID = '189' AND date BETWEEN '2018-10-01' AND '2018-10-31'
group by date
Thank you, that works perfectly.
– Roman B
Nov 22 '18 at 20:20
add a comment |
Do a GROUP BY
, use MIN()
to pick the lowest timein value:
SELECT date, min(timein)
FROM clock
WHERE eID = '189' AND date BETWEEN '2018-10-01' AND '2018-10-31'
group by date
Do a GROUP BY
, use MIN()
to pick the lowest timein value:
SELECT date, min(timein)
FROM clock
WHERE eID = '189' AND date BETWEEN '2018-10-01' AND '2018-10-31'
group by date
answered Nov 22 '18 at 19:46
jarlhjarlh
30.2k52138
30.2k52138
Thank you, that works perfectly.
– Roman B
Nov 22 '18 at 20:20
add a comment |
Thank you, that works perfectly.
– Roman B
Nov 22 '18 at 20:20
Thank you, that works perfectly.
– Roman B
Nov 22 '18 at 20:20
Thank you, that works perfectly.
– Roman B
Nov 22 '18 at 20:20
add a comment |
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1
How come you want Value 1 and not Value 4?
– jarlh
Nov 22 '18 at 19:46
Please add relevant tags only. I have removed the rest of the irrelevant ones.
– Chowkidar Madhur Bhaiya
Nov 22 '18 at 19:47
The query has the columns timein and date, and the sample data has date and value... In different order.
– jarlh
Nov 22 '18 at 19:49