Calling subscribe in subscribe, rxjs, angular
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I know there are few other posts for calling subscribe inside subsribe, but I am not able to find a solution.
I am calling subscribe inside subscribe which I know it does not work correctly. The console.log prints head in random sequence. e.g. S1 has H1, S2 as H2, S3 as H3. The current program will print sometimes S1, S3, S2 and at other times S2, S3, S1.
The expectation is that the head of the state is printed sequentially. How can I achive it?
GetStates(countryID).subscribe(
data => {
let states = JSON.parse(data);
states.forEach(
entry => {
GetHeadOfState(entry.ID).subscribe(
head => {
console.log(head)
}
)
}
)
})
angular rxjs asked Nov 22 '18 at 20:00
NingombaNingomba
112
add a comment |
I know there are few other posts for calling subscribe inside subsribe, but I am not able to find a solution.
I am calling subscribe inside subscribe which I know it does not work correctly. The console.log prints head in random sequence. e.g. S1 has H1, S2 as H2, S3 as H3. The current program will print sometimes S1, S3, S2 and at other times S2, S3, S1.
The expectation is that the head of the state is printed sequentially. How can I achive it?
GetStates(countryID).subscribe(
data => {
let states = JSON.parse(data);
states.forEach(
entry => {
GetHeadOfState(entry.ID).subscribe(
head => {
console.log(head)
}
)
}
)
})
asked Nov 22 '18 at 20:00
NingombaNingomba
112
add a comment |
I know there are few other posts for calling subscribe inside subsribe, but I am not able to find a solution.
I am calling subscribe inside subscribe which I know it does not work correctly. The console.log prints head in random sequence. e.g. S1 has H1, S2 as H2, S3 as H3. The current program will print sometimes S1, S3, S2 and at other times S2, S3, S1.
The expectation is that the head of the state is printed sequentially. How can I achive it?
GetStates(countryID).subscribe(
data => {
let states = JSON.parse(data);
states.forEach(
entry => {
GetHeadOfState(entry.ID).subscribe(
head => {
console.log(head)
}
)
}
)
})
asked Nov 22 '18 at 20:00
NingombaNingomba
112
I know there are few other posts for calling subscribe inside subsribe, but I am not able to find a solution.
I am calling subscribe inside subscribe which I know it does not work correctly. The console.log prints head in random sequence. e.g. S1 has H1, S2 as H2, S3 as H3. The current program will print sometimes S1, S3, S2 and at other times S2, S3, S1.
The expectation is that the head of the state is printed sequentially. How can I achive it?
GetStates(countryID).subscribe(
data => {
let states = JSON.parse(data);
states.forEach(
entry => {
GetHeadOfState(entry.ID).subscribe(
head => {
console.log(head)
}
)
}
)
})
asked Nov 22 '18 at 20:00
NingombaNingomba
112
asked Nov 22 '18 at 20:00
NingombaNingomba
112
asked Nov 22 '18 at 20:00
NingombaNingomba
112
asked Nov 22 '18 at 20:00
NingombaNingomba
112
asked Nov 22 '18 at 20:00
NingombaNingomba
112
112
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
There are multiple ways to do it but if the states you want are in fact an array you can first unpack the array (with concatAll/mergeAll) and then call concatMap on each state. The concatMap operator will run for each item and wait until it completes:
GetStates(countryID).pipe(
map(data => JSON.parse(data)),
concatAll(),
concatMap(state => GetHeadOfState(state.ID)),
).subscribe(headOfState => ...);
answered Nov 23 '18 at 10:14
martinmartin
47.2k1196139
add a comment |
You can use mergeMap/mergeAll operator here
getStatesAndCountry(countryID) {
let states = GetStates(countryID);
return states.pipe(
mergeMap(map(state) => GetHeadOfState(state.ID))
)
}
this.getStatesAndCountry(countryId).subscribe(
value => console.log(val)
)
answered Nov 22 '18 at 20:15
Pankaj ParkarPankaj Parkar
115k16167240
You can use mergeMap() to shorten it a bit learnrxjs.io/operators/transformation/mergemap.html
– Andrei Dumitrescu-Tudor
Nov 22 '18 at 20:19
@AndreiDumitrescu-Tudor thanks for tip, updated the answer :)
– Pankaj Parkar
Nov 22 '18 at 20:22
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
There are multiple ways to do it but if the states you want are in fact an array you can first unpack the array (with concatAll/mergeAll) and then call concatMap on each state. The concatMap operator will run for each item and wait until it completes:
GetStates(countryID).pipe(
map(data => JSON.parse(data)),
concatAll(),
concatMap(state => GetHeadOfState(state.ID)),
).subscribe(headOfState => ...);
answered Nov 23 '18 at 10:14
martinmartin
47.2k1196139
add a comment |
There are multiple ways to do it but if the states you want are in fact an array you can first unpack the array (with concatAll/mergeAll) and then call concatMap on each state. The concatMap operator will run for each item and wait until it completes:
GetStates(countryID).pipe(
map(data => JSON.parse(data)),
concatAll(),
concatMap(state => GetHeadOfState(state.ID)),
).subscribe(headOfState => ...);
answered Nov 23 '18 at 10:14
martinmartin
47.2k1196139
add a comment |
There are multiple ways to do it but if the states you want are in fact an array you can first unpack the array (with concatAll/mergeAll) and then call concatMap on each state. The concatMap operator will run for each item and wait until it completes:
GetStates(countryID).pipe(
map(data => JSON.parse(data)),
concatAll(),
concatMap(state => GetHeadOfState(state.ID)),
).subscribe(headOfState => ...);
answered Nov 23 '18 at 10:14
martinmartin
47.2k1196139
There are multiple ways to do it but if the states you want are in fact an array you can first unpack the array (with concatAll/mergeAll) and then call concatMap on each state. The concatMap operator will run for each item and wait until it completes:
GetStates(countryID).pipe(
map(data => JSON.parse(data)),
concatAll(),
concatMap(state => GetHeadOfState(state.ID)),
).subscribe(headOfState => ...);
answered Nov 23 '18 at 10:14
martinmartin
47.2k1196139
answered Nov 23 '18 at 10:14
martinmartin
47.2k1196139
answered Nov 23 '18 at 10:14
martinmartin
47.2k1196139
answered Nov 23 '18 at 10:14
martinmartin
47.2k1196139
47.2k1196139
add a comment |
add a comment |
You can use mergeMap/mergeAll operator here
getStatesAndCountry(countryID) {
let states = GetStates(countryID);
return states.pipe(
mergeMap(map(state) => GetHeadOfState(state.ID))
)
}
this.getStatesAndCountry(countryId).subscribe(
value => console.log(val)
)
answered Nov 22 '18 at 20:15
Pankaj ParkarPankaj Parkar
115k16167240
You can use mergeMap() to shorten it a bit learnrxjs.io/operators/transformation/mergemap.html
– Andrei Dumitrescu-Tudor
Nov 22 '18 at 20:19
@AndreiDumitrescu-Tudor thanks for tip, updated the answer :)
– Pankaj Parkar
Nov 22 '18 at 20:22
add a comment |
You can use mergeMap/mergeAll operator here
getStatesAndCountry(countryID) {
let states = GetStates(countryID);
return states.pipe(
mergeMap(map(state) => GetHeadOfState(state.ID))
)
}
this.getStatesAndCountry(countryId).subscribe(
value => console.log(val)
)
answered Nov 22 '18 at 20:15
Pankaj ParkarPankaj Parkar
115k16167240
You can use mergeMap() to shorten it a bit learnrxjs.io/operators/transformation/mergemap.html
– Andrei Dumitrescu-Tudor
Nov 22 '18 at 20:19
@AndreiDumitrescu-Tudor thanks for tip, updated the answer :)
– Pankaj Parkar
Nov 22 '18 at 20:22
add a comment |
You can use mergeMap/mergeAll operator here
getStatesAndCountry(countryID) {
let states = GetStates(countryID);
return states.pipe(
mergeMap(map(state) => GetHeadOfState(state.ID))
)
}
this.getStatesAndCountry(countryId).subscribe(
value => console.log(val)
)
answered Nov 22 '18 at 20:15
Pankaj ParkarPankaj Parkar
115k16167240
You can use mergeMap/mergeAll operator here
getStatesAndCountry(countryID) {
let states = GetStates(countryID);
return states.pipe(
mergeMap(map(state) => GetHeadOfState(state.ID))
)
}
this.getStatesAndCountry(countryId).subscribe(
value => console.log(val)
)
answered Nov 22 '18 at 20:15
Pankaj ParkarPankaj Parkar
115k16167240
edited Nov 22 '18 at 20:22
answered Nov 22 '18 at 20:15
Pankaj ParkarPankaj Parkar
115k16167240
answered Nov 22 '18 at 20:15
Pankaj ParkarPankaj Parkar
115k16167240
answered Nov 22 '18 at 20:15
Pankaj ParkarPankaj Parkar
115k16167240
115k16167240
You can use mergeMap() to shorten it a bit learnrxjs.io/operators/transformation/mergemap.html
– Andrei Dumitrescu-Tudor
Nov 22 '18 at 20:19
@AndreiDumitrescu-Tudor thanks for tip, updated the answer :)
– Pankaj Parkar
Nov 22 '18 at 20:22
add a comment |
You can use mergeMap() to shorten it a bit learnrxjs.io/operators/transformation/mergemap.html
– Andrei Dumitrescu-Tudor
Nov 22 '18 at 20:19
@AndreiDumitrescu-Tudor thanks for tip, updated the answer :)
– Pankaj Parkar
Nov 22 '18 at 20:22
You can use mergeMap() to shorten it a bit learnrxjs.io/operators/transformation/mergemap.html
– Andrei Dumitrescu-Tudor
Nov 22 '18 at 20:19
You can use mergeMap() to shorten it a bit learnrxjs.io/operators/transformation/mergemap.html
– Andrei Dumitrescu-Tudor
Nov 22 '18 at 20:19
@AndreiDumitrescu-Tudor thanks for tip, updated the answer :)
– Pankaj Parkar
Nov 22 '18 at 20:22
@AndreiDumitrescu-Tudor thanks for tip, updated the answer :)
– Pankaj Parkar
Nov 22 '18 at 20:22
add a comment |
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