SignalR Core call function when connection is established
When my client successfully connects to the hub, I want the client to immediately join a group. I have a method in my hub to do that, I just need an event handler for when the connection is established, just like
connection.start().done(
function () {
connection.invoke('JoinGroup', 'GroupName');
});
in SignalR for plain ASP.Net.
Can I do that or do I have to set a timer to do it after x seconds after the start(); call was made?
Edit:
I found out I can do
connection.start(
function (){
connection.invoke('JoinGroup', 'GroupName');
}
);
but it tells me that it Cannot send data if the connection is not in the 'Connected' State.
what do?
signalr.client asp.net-core-signalr
asked Nov 21 '18 at 13:13
lennyylennyy
152117
add a comment |
When my client successfully connects to the hub, I want the client to immediately join a group. I have a method in my hub to do that, I just need an event handler for when the connection is established, just like
connection.start().done(
function () {
connection.invoke('JoinGroup', 'GroupName');
});
in SignalR for plain ASP.Net.
Can I do that or do I have to set a timer to do it after x seconds after the start(); call was made?
Edit:
I found out I can do
connection.start(
function (){
connection.invoke('JoinGroup', 'GroupName');
}
);
but it tells me that it Cannot send data if the connection is not in the 'Connected' State.
what do?
signalr.client asp.net-core-signalr
asked Nov 21 '18 at 13:13
lennyylennyy
152117
add a comment |
When my client successfully connects to the hub, I want the client to immediately join a group. I have a method in my hub to do that, I just need an event handler for when the connection is established, just like
connection.start().done(
function () {
connection.invoke('JoinGroup', 'GroupName');
});
in SignalR for plain ASP.Net.
Can I do that or do I have to set a timer to do it after x seconds after the start(); call was made?
Edit:
I found out I can do
connection.start(
function (){
connection.invoke('JoinGroup', 'GroupName');
}
);
but it tells me that it Cannot send data if the connection is not in the 'Connected' State.
what do?
signalr.client asp.net-core-signalr
asked Nov 21 '18 at 13:13
lennyylennyy
152117
When my client successfully connects to the hub, I want the client to immediately join a group. I have a method in my hub to do that, I just need an event handler for when the connection is established, just like
connection.start().done(
function () {
connection.invoke('JoinGroup', 'GroupName');
});
in SignalR for plain ASP.Net.
Can I do that or do I have to set a timer to do it after x seconds after the start(); call was made?
Edit:
I found out I can do
connection.start(
function (){
connection.invoke('JoinGroup', 'GroupName');
}
);
but it tells me that it Cannot send data if the connection is not in the 'Connected' State.
what do?
signalr.client asp.net-core-signalr
signalr.client asp.net-core-signalr
asked Nov 21 '18 at 13:13
lennyylennyy
152117
asked Nov 21 '18 at 13:13
lennyylennyy
152117
asked Nov 21 '18 at 13:13
lennyylennyy
152117
asked Nov 21 '18 at 13:13
lennyylennyy
152117
asked Nov 21 '18 at 13:13
lennyylennyy
152117
152117
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
SignalR is notoriously difficult due to version mismatches etc.
Please see the following article: https://docs.microsoft.com/en-us/aspnet/core/tutorials/signalr?view=aspnetcore-2.1&tabs=visual-studio
In it, there's a section that specifies how to start (and wait for connection to be established):
var connection = new signalR.HubConnectionBuilder().withUrl("/chatHub").build();
connection.start().then(() => {
//try some stuff here :)
})
.catch(function (err) {
//failed to connect
return console.error(err.toString());
});
The javascript client uses promises that have to be resolved/rejected before you can use it.
The other option is to wrap inside async method and await the call (not sure if this will work correctly). Such as:
await connection.start();
//connection should be started now. beware of exceptions though
answered Nov 21 '18 at 13:29
NealNeal
283111
I triedawait connection.start()but it told me that's only for async functions. I'll try thethen. thanks for the quick reply.
– lennyy
Nov 21 '18 at 13:41
1
Yeah that's correct, it has to be inside an async function(){} :-). No problem. Good luck!
– Neal
Nov 21 '18 at 13:44
It's still sayingCannot send data if the connection is not in the 'Connected' State.but it does recieve method calls sent to the client group it's supposed to join. I guess that's good enough.
– lennyy
Nov 21 '18 at 13:45
1
Check out in the hub, there are two methods called OnConnected and OnDisconnected that you can override from inherited hub for troubleshooting.
– Neal
Nov 21 '18 at 13:46
1
"Experience is simply the name we give our mistakes" - Oscar Wilde. :-) So, I suspect that the client that's failing to connect you get some error before it stating failed to negotiate (or something to that effect) The answer is to enable something called CORS. Basic example here: stackoverflow.com/questions/48185985/… I recommend you look into the CORS stuff for ASP core and setup a policy only whitelisting your domain.
– Neal
Nov 21 '18 at 14:30
|
show 2 more comments
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53412852%2fsignalr-core-call-function-when-connection-is-established%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
SignalR is notoriously difficult due to version mismatches etc.
Please see the following article: https://docs.microsoft.com/en-us/aspnet/core/tutorials/signalr?view=aspnetcore-2.1&tabs=visual-studio
In it, there's a section that specifies how to start (and wait for connection to be established):
var connection = new signalR.HubConnectionBuilder().withUrl("/chatHub").build();
connection.start().then(() => {
//try some stuff here :)
})
.catch(function (err) {
//failed to connect
return console.error(err.toString());
});
The javascript client uses promises that have to be resolved/rejected before you can use it.
The other option is to wrap inside async method and await the call (not sure if this will work correctly). Such as:
await connection.start();
//connection should be started now. beware of exceptions though
answered Nov 21 '18 at 13:29
NealNeal
283111
I triedawait connection.start()but it told me that's only for async functions. I'll try thethen. thanks for the quick reply.
– lennyy
Nov 21 '18 at 13:41
1
Yeah that's correct, it has to be inside an async function(){} :-). No problem. Good luck!
– Neal
Nov 21 '18 at 13:44
It's still sayingCannot send data if the connection is not in the 'Connected' State.but it does recieve method calls sent to the client group it's supposed to join. I guess that's good enough.
– lennyy
Nov 21 '18 at 13:45
1
Check out in the hub, there are two methods called OnConnected and OnDisconnected that you can override from inherited hub for troubleshooting.
– Neal
Nov 21 '18 at 13:46
1
"Experience is simply the name we give our mistakes" - Oscar Wilde. :-) So, I suspect that the client that's failing to connect you get some error before it stating failed to negotiate (or something to that effect) The answer is to enable something called CORS. Basic example here: stackoverflow.com/questions/48185985/… I recommend you look into the CORS stuff for ASP core and setup a policy only whitelisting your domain.
– Neal
Nov 21 '18 at 14:30
|
show 2 more comments
SignalR is notoriously difficult due to version mismatches etc.
Please see the following article: https://docs.microsoft.com/en-us/aspnet/core/tutorials/signalr?view=aspnetcore-2.1&tabs=visual-studio
In it, there's a section that specifies how to start (and wait for connection to be established):
var connection = new signalR.HubConnectionBuilder().withUrl("/chatHub").build();
connection.start().then(() => {
//try some stuff here :)
})
.catch(function (err) {
//failed to connect
return console.error(err.toString());
});
The javascript client uses promises that have to be resolved/rejected before you can use it.
The other option is to wrap inside async method and await the call (not sure if this will work correctly). Such as:
await connection.start();
//connection should be started now. beware of exceptions though
answered Nov 21 '18 at 13:29
NealNeal
283111
I triedawait connection.start()but it told me that's only for async functions. I'll try thethen. thanks for the quick reply.
– lennyy
Nov 21 '18 at 13:41
1
Yeah that's correct, it has to be inside an async function(){} :-). No problem. Good luck!
– Neal
Nov 21 '18 at 13:44
It's still sayingCannot send data if the connection is not in the 'Connected' State.but it does recieve method calls sent to the client group it's supposed to join. I guess that's good enough.
– lennyy
Nov 21 '18 at 13:45
1
Check out in the hub, there are two methods called OnConnected and OnDisconnected that you can override from inherited hub for troubleshooting.
– Neal
Nov 21 '18 at 13:46
1
"Experience is simply the name we give our mistakes" - Oscar Wilde. :-) So, I suspect that the client that's failing to connect you get some error before it stating failed to negotiate (or something to that effect) The answer is to enable something called CORS. Basic example here: stackoverflow.com/questions/48185985/… I recommend you look into the CORS stuff for ASP core and setup a policy only whitelisting your domain.
– Neal
Nov 21 '18 at 14:30
|
show 2 more comments
SignalR is notoriously difficult due to version mismatches etc.
Please see the following article: https://docs.microsoft.com/en-us/aspnet/core/tutorials/signalr?view=aspnetcore-2.1&tabs=visual-studio
In it, there's a section that specifies how to start (and wait for connection to be established):
var connection = new signalR.HubConnectionBuilder().withUrl("/chatHub").build();
connection.start().then(() => {
//try some stuff here :)
})
.catch(function (err) {
//failed to connect
return console.error(err.toString());
});
The javascript client uses promises that have to be resolved/rejected before you can use it.
The other option is to wrap inside async method and await the call (not sure if this will work correctly). Such as:
await connection.start();
//connection should be started now. beware of exceptions though
answered Nov 21 '18 at 13:29
NealNeal
283111
SignalR is notoriously difficult due to version mismatches etc.
Please see the following article: https://docs.microsoft.com/en-us/aspnet/core/tutorials/signalr?view=aspnetcore-2.1&tabs=visual-studio
In it, there's a section that specifies how to start (and wait for connection to be established):
var connection = new signalR.HubConnectionBuilder().withUrl("/chatHub").build();
connection.start().then(() => {
//try some stuff here :)
})
.catch(function (err) {
//failed to connect
return console.error(err.toString());
});
The javascript client uses promises that have to be resolved/rejected before you can use it.
The other option is to wrap inside async method and await the call (not sure if this will work correctly). Such as:
await connection.start();
//connection should be started now. beware of exceptions though
answered Nov 21 '18 at 13:29
NealNeal
283111
answered Nov 21 '18 at 13:29
NealNeal
283111
answered Nov 21 '18 at 13:29
NealNeal
283111
answered Nov 21 '18 at 13:29
NealNeal
283111
283111
I triedawait connection.start()but it told me that's only for async functions. I'll try thethen. thanks for the quick reply.
– lennyy
Nov 21 '18 at 13:41
1
Yeah that's correct, it has to be inside an async function(){} :-). No problem. Good luck!
– Neal
Nov 21 '18 at 13:44
It's still sayingCannot send data if the connection is not in the 'Connected' State.but it does recieve method calls sent to the client group it's supposed to join. I guess that's good enough.
– lennyy
Nov 21 '18 at 13:45
1
Check out in the hub, there are two methods called OnConnected and OnDisconnected that you can override from inherited hub for troubleshooting.
– Neal
Nov 21 '18 at 13:46
1
"Experience is simply the name we give our mistakes" - Oscar Wilde. :-) So, I suspect that the client that's failing to connect you get some error before it stating failed to negotiate (or something to that effect) The answer is to enable something called CORS. Basic example here: stackoverflow.com/questions/48185985/… I recommend you look into the CORS stuff for ASP core and setup a policy only whitelisting your domain.
– Neal
Nov 21 '18 at 14:30
|
show 2 more comments
I triedawait connection.start()but it told me that's only for async functions. I'll try thethen. thanks for the quick reply.
– lennyy
Nov 21 '18 at 13:41
1
Yeah that's correct, it has to be inside an async function(){} :-). No problem. Good luck!
– Neal
Nov 21 '18 at 13:44
It's still sayingCannot send data if the connection is not in the 'Connected' State.but it does recieve method calls sent to the client group it's supposed to join. I guess that's good enough.
– lennyy
Nov 21 '18 at 13:45
1
Check out in the hub, there are two methods called OnConnected and OnDisconnected that you can override from inherited hub for troubleshooting.
– Neal
Nov 21 '18 at 13:46
1
"Experience is simply the name we give our mistakes" - Oscar Wilde. :-) So, I suspect that the client that's failing to connect you get some error before it stating failed to negotiate (or something to that effect) The answer is to enable something called CORS. Basic example here: stackoverflow.com/questions/48185985/… I recommend you look into the CORS stuff for ASP core and setup a policy only whitelisting your domain.
– Neal
Nov 21 '18 at 14:30
I tried
await connection.start() but it told me that's only for async functions. I'll try the then. thanks for the quick reply.– lennyy
Nov 21 '18 at 13:41
I tried
await connection.start() but it told me that's only for async functions. I'll try the then. thanks for the quick reply.– lennyy
Nov 21 '18 at 13:41
1
1
Yeah that's correct, it has to be inside an async function(){} :-). No problem. Good luck!
– Neal
Nov 21 '18 at 13:44
Yeah that's correct, it has to be inside an async function(){} :-). No problem. Good luck!
– Neal
Nov 21 '18 at 13:44
It's still saying
Cannot send data if the connection is not in the 'Connected' State. but it does recieve method calls sent to the client group it's supposed to join. I guess that's good enough.– lennyy
Nov 21 '18 at 13:45
It's still saying
Cannot send data if the connection is not in the 'Connected' State. but it does recieve method calls sent to the client group it's supposed to join. I guess that's good enough.– lennyy
Nov 21 '18 at 13:45
1
1
Check out in the hub, there are two methods called OnConnected and OnDisconnected that you can override from inherited hub for troubleshooting.
– Neal
Nov 21 '18 at 13:46
Check out in the hub, there are two methods called OnConnected and OnDisconnected that you can override from inherited hub for troubleshooting.
– Neal
Nov 21 '18 at 13:46
1
1
"Experience is simply the name we give our mistakes" - Oscar Wilde. :-) So, I suspect that the client that's failing to connect you get some error before it stating failed to negotiate (or something to that effect) The answer is to enable something called CORS. Basic example here: stackoverflow.com/questions/48185985/… I recommend you look into the CORS stuff for ASP core and setup a policy only whitelisting your domain.
– Neal
Nov 21 '18 at 14:30
"Experience is simply the name we give our mistakes" - Oscar Wilde. :-) So, I suspect that the client that's failing to connect you get some error before it stating failed to negotiate (or something to that effect) The answer is to enable something called CORS. Basic example here: stackoverflow.com/questions/48185985/… I recommend you look into the CORS stuff for ASP core and setup a policy only whitelisting your domain.
– Neal
Nov 21 '18 at 14:30
|
show 2 more comments
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53412852%2fsignalr-core-call-function-when-connection-is-established%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
