How to pivot a dataframe with two columns with no index
I am trying to pivot my current two column dataframe which currently looks like this:
one two
a 12
b 32
c 12
I want to pivot this resulting in neither column becoming the index. My expected result is:
a b c
12 32 12
a, b, and c are the new columns. 12, 32, 12 are the values in the row.
Thanks
python pandas
add a comment |
I am trying to pivot my current two column dataframe which currently looks like this:
one two
a 12
b 32
c 12
I want to pivot this resulting in neither column becoming the index. My expected result is:
a b c
12 32 12
a, b, and c are the new columns. 12, 32, 12 are the values in the row.
Thanks
python pandas
add a comment |
I am trying to pivot my current two column dataframe which currently looks like this:
one two
a 12
b 32
c 12
I want to pivot this resulting in neither column becoming the index. My expected result is:
a b c
12 32 12
a, b, and c are the new columns. 12, 32, 12 are the values in the row.
Thanks
python pandas
I am trying to pivot my current two column dataframe which currently looks like this:
one two
a 12
b 32
c 12
I want to pivot this resulting in neither column becoming the index. My expected result is:
a b c
12 32 12
a, b, and c are the new columns. 12, 32, 12 are the values in the row.
Thanks
python pandas
python pandas
edited Mar 1 at 19:26
asked Mar 1 at 19:16
user11132841
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Use set_index to move column 'one' into the index, then use T to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
answered Mar 1 at 19:30
Scott BostonScott Boston
56.4k73157
add a comment |
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose() results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
answered Mar 1 at 19:23
Niklas MertschNiklas Mertsch
463116
You can usea.Tfor short.
– Scott Boston
Mar 1 at 19:26
add a comment |
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
answered Mar 1 at 20:12
ALollzALollz
14.7k31737
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54950958%2fhow-to-pivot-a-dataframe-with-two-columns-with-no-index%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use set_index to move column 'one' into the index, then use T to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
answered Mar 1 at 19:30
Scott BostonScott Boston
56.4k73157
add a comment |
Use set_index to move column 'one' into the index, then use T to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
answered Mar 1 at 19:30
Scott BostonScott Boston
56.4k73157
add a comment |
Use set_index to move column 'one' into the index, then use T to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
answered Mar 1 at 19:30
Scott BostonScott Boston
56.4k73157
Use set_index to move column 'one' into the index, then use T to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
answered Mar 1 at 19:30
Scott BostonScott Boston
56.4k73157
answered Mar 1 at 19:30
Scott BostonScott Boston
56.4k73157
answered Mar 1 at 19:30
Scott BostonScott Boston
56.4k73157
answered Mar 1 at 19:30
Scott BostonScott Boston
56.4k73157
56.4k73157
add a comment |
add a comment |
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose() results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
answered Mar 1 at 19:23
Niklas MertschNiklas Mertsch
463116
You can usea.Tfor short.
– Scott Boston
Mar 1 at 19:26
add a comment |
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose() results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
answered Mar 1 at 19:23
Niklas MertschNiklas Mertsch
463116
You can usea.Tfor short.
– Scott Boston
Mar 1 at 19:26
add a comment |
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose() results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
answered Mar 1 at 19:23
Niklas MertschNiklas Mertsch
463116
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose() results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
answered Mar 1 at 19:23
Niklas MertschNiklas Mertsch
463116
answered Mar 1 at 19:23
Niklas MertschNiklas Mertsch
463116
answered Mar 1 at 19:23
Niklas MertschNiklas Mertsch
463116
answered Mar 1 at 19:23
Niklas MertschNiklas Mertsch
463116
463116
You can usea.Tfor short.
– Scott Boston
Mar 1 at 19:26
add a comment |
You can usea.Tfor short.
– Scott Boston
Mar 1 at 19:26
You can use
a.T for short.– Scott Boston
Mar 1 at 19:26
You can use
a.T for short.– Scott Boston
Mar 1 at 19:26
add a comment |
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
answered Mar 1 at 20:12
ALollzALollz
14.7k31737
add a comment |
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
answered Mar 1 at 20:12
ALollzALollz
14.7k31737
add a comment |
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
answered Mar 1 at 20:12
ALollzALollz
14.7k31737
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
answered Mar 1 at 20:12
ALollzALollz
14.7k31737
answered Mar 1 at 20:12
ALollzALollz
14.7k31737
answered Mar 1 at 20:12
ALollzALollz
14.7k31737
answered Mar 1 at 20:12
ALollzALollz
14.7k31737
14.7k31737
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54950958%2fhow-to-pivot-a-dataframe-with-two-columns-with-no-index%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
