finging the formula for the radius of the cross section relation/ratio to x-cordinate dependent on the cuting...
$begingroup$
"banana shaped" body is located between two planes that cross with x-axis $ x=7 $ and $ x=-7 $. Cutting the body with the planes that cross with the form circles, that diameter that endpoints are located on the ellipses that are located on the half-plane $y>=0$
$(x/7)^2+(y/3)^2=1 $ and $(x/7)^2+(y/7)^2=1 $
I have to find the radius formula for one cross section relation/ratio to x-cordinate dependent on the cuting plane.
$ y(x)= $
I don't think it is as simple as finding the y form one formula but I did it anyway because that is all I am able to do atm.
$ y=3sqrt{1-x^2/49} $
calculus plane-geometry
$endgroup$
add a comment |
$begingroup$
"banana shaped" body is located between two planes that cross with x-axis $ x=7 $ and $ x=-7 $. Cutting the body with the planes that cross with the form circles, that diameter that endpoints are located on the ellipses that are located on the half-plane $y>=0$
$(x/7)^2+(y/3)^2=1 $ and $(x/7)^2+(y/7)^2=1 $
I have to find the radius formula for one cross section relation/ratio to x-cordinate dependent on the cuting plane.
$ y(x)= $
I don't think it is as simple as finding the y form one formula but I did it anyway because that is all I am able to do atm.
$ y=3sqrt{1-x^2/49} $
calculus plane-geometry
$endgroup$
add a comment |
$begingroup$
"banana shaped" body is located between two planes that cross with x-axis $ x=7 $ and $ x=-7 $. Cutting the body with the planes that cross with the form circles, that diameter that endpoints are located on the ellipses that are located on the half-plane $y>=0$
$(x/7)^2+(y/3)^2=1 $ and $(x/7)^2+(y/7)^2=1 $
I have to find the radius formula for one cross section relation/ratio to x-cordinate dependent on the cuting plane.
$ y(x)= $
I don't think it is as simple as finding the y form one formula but I did it anyway because that is all I am able to do atm.
$ y=3sqrt{1-x^2/49} $
calculus plane-geometry
$endgroup$
"banana shaped" body is located between two planes that cross with x-axis $ x=7 $ and $ x=-7 $. Cutting the body with the planes that cross with the form circles, that diameter that endpoints are located on the ellipses that are located on the half-plane $y>=0$
$(x/7)^2+(y/3)^2=1 $ and $(x/7)^2+(y/7)^2=1 $
I have to find the radius formula for one cross section relation/ratio to x-cordinate dependent on the cuting plane.
$ y(x)= $
I don't think it is as simple as finding the y form one formula but I did it anyway because that is all I am able to do atm.
$ y=3sqrt{1-x^2/49} $
calculus plane-geometry
calculus plane-geometry
asked Dec 6 '18 at 22:09
Student123Student123
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