finging the formula for the radius of the cross section relation/ratio to x-cordinate dependent on the cuting...












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"banana shaped" body is located between two planes that cross with x-axis $ x=7 $ and $ x=-7 $. Cutting the body with the planes that cross with the form circles, that diameter that endpoints are located on the ellipses that are located on the half-plane $y>=0$



$(x/7)^2+(y/3)^2=1 $ and $(x/7)^2+(y/7)^2=1 $



I have to find the radius formula for one cross section relation/ratio to x-cordinate dependent on the cuting plane.



$ y(x)= $



I don't think it is as simple as finding the y form one formula but I did it anyway because that is all I am able to do atm.
$ y=3sqrt{1-x^2/49} $










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$endgroup$

















    0












    $begingroup$


    "banana shaped" body is located between two planes that cross with x-axis $ x=7 $ and $ x=-7 $. Cutting the body with the planes that cross with the form circles, that diameter that endpoints are located on the ellipses that are located on the half-plane $y>=0$



    $(x/7)^2+(y/3)^2=1 $ and $(x/7)^2+(y/7)^2=1 $



    I have to find the radius formula for one cross section relation/ratio to x-cordinate dependent on the cuting plane.



    $ y(x)= $



    I don't think it is as simple as finding the y form one formula but I did it anyway because that is all I am able to do atm.
    $ y=3sqrt{1-x^2/49} $










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      "banana shaped" body is located between two planes that cross with x-axis $ x=7 $ and $ x=-7 $. Cutting the body with the planes that cross with the form circles, that diameter that endpoints are located on the ellipses that are located on the half-plane $y>=0$



      $(x/7)^2+(y/3)^2=1 $ and $(x/7)^2+(y/7)^2=1 $



      I have to find the radius formula for one cross section relation/ratio to x-cordinate dependent on the cuting plane.



      $ y(x)= $



      I don't think it is as simple as finding the y form one formula but I did it anyway because that is all I am able to do atm.
      $ y=3sqrt{1-x^2/49} $










      share|cite|improve this question









      $endgroup$




      "banana shaped" body is located between two planes that cross with x-axis $ x=7 $ and $ x=-7 $. Cutting the body with the planes that cross with the form circles, that diameter that endpoints are located on the ellipses that are located on the half-plane $y>=0$



      $(x/7)^2+(y/3)^2=1 $ and $(x/7)^2+(y/7)^2=1 $



      I have to find the radius formula for one cross section relation/ratio to x-cordinate dependent on the cuting plane.



      $ y(x)= $



      I don't think it is as simple as finding the y form one formula but I did it anyway because that is all I am able to do atm.
      $ y=3sqrt{1-x^2/49} $







      calculus plane-geometry






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Dec 6 '18 at 22:09









      Student123Student123

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