Python: Convert Edgelist from NetworkX into dataframe











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I have a weird data structure (don't know if it's a list or tuple) as a results of using Networkx. I need to convert it into a dataframe.



The 'list' I have, has the following structure:



[('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2}),... ]


and I need a dataframe as follows:



Inf   Prov  Weight
a a 2
a ! 0
a c 2
a b 1
a q 1
a s 2


Can somebody give me hand, please?










share|improve this question


























    up vote
    1
    down vote

    favorite












    I have a weird data structure (don't know if it's a list or tuple) as a results of using Networkx. I need to convert it into a dataframe.



    The 'list' I have, has the following structure:



    [('a', 'a', {'weight': 2}),
    ('a', '!', {'weight': 0}),
    ('a', 'c', {'weight': 2}),
    ('a', 'b', {'weight': 1}),
    ('a', 'q', {'weight': 1}),
    ('a', 's', {'weight': 2}),... ]


    and I need a dataframe as follows:



    Inf   Prov  Weight
    a a 2
    a ! 0
    a c 2
    a b 1
    a q 1
    a s 2


    Can somebody give me hand, please?










    share|improve this question
























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I have a weird data structure (don't know if it's a list or tuple) as a results of using Networkx. I need to convert it into a dataframe.



      The 'list' I have, has the following structure:



      [('a', 'a', {'weight': 2}),
      ('a', '!', {'weight': 0}),
      ('a', 'c', {'weight': 2}),
      ('a', 'b', {'weight': 1}),
      ('a', 'q', {'weight': 1}),
      ('a', 's', {'weight': 2}),... ]


      and I need a dataframe as follows:



      Inf   Prov  Weight
      a a 2
      a ! 0
      a c 2
      a b 1
      a q 1
      a s 2


      Can somebody give me hand, please?










      share|improve this question













      I have a weird data structure (don't know if it's a list or tuple) as a results of using Networkx. I need to convert it into a dataframe.



      The 'list' I have, has the following structure:



      [('a', 'a', {'weight': 2}),
      ('a', '!', {'weight': 0}),
      ('a', 'c', {'weight': 2}),
      ('a', 'b', {'weight': 1}),
      ('a', 'q', {'weight': 1}),
      ('a', 's', {'weight': 2}),... ]


      and I need a dataframe as follows:



      Inf   Prov  Weight
      a a 2
      a ! 0
      a c 2
      a b 1
      a q 1
      a s 2


      Can somebody give me hand, please?







      python list dataframe tuples networkx






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      asked Nov 15 at 1:37









      PAstudilloE

      127111




      127111
























          2 Answers
          2






          active

          oldest

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          up vote
          1
          down vote













          It is probably easiest to simplify the data a bit first before creating the dataframe.
          Depending on the operation that gave you the initial data (a list of tuples, each one containing 2 strings and a dict), it may be possible to have that operation give you simplified data. But in the case that this is not possible -- or more generally, when you don't have control over data structures generated by a given library, you can do some simple manipulations, e.g. like this:



          import pandas as pd
          # initial data from qu
          raw_data = [('a', 'a', {'weight': 2}),
          ('a', '!', {'weight': 0}),
          ('a', 'c', {'weight': 2}),
          ('a', 'b', {'weight': 1}),
          ('a', 'q', {'weight': 1}),
          ('a', 's', {'weight': 2}),]

          # transform data to extract the value of each weight
          data = [(elem1, elem2, d_elem.get('weight', 0)) for (elem1, elem2, d_elem) in raw_data]

          # put together the dataframe from the list of records
          df = pd.DataFrame.from_records(data, columns=['Inf', 'Prov', 'Weight'])
          print(df)


          gives the result as desired:



            Inf Prov  Weight
          0 a a 2
          1 a ! 0
          2 a c 2
          3 a b 1
          4 a q 1
          5 a s 2


          using dict.get allows us to specify a default value if it is not defined, rather than raising a KeyError.






          share|improve this answer




























            up vote
            0
            down vote













            import pandas as pd
            x=[('a', 'a', {'weight': 2}),
            ('a', '!', {'weight': 0}),
            ('a', 'c', {'weight': 2}),
            ('a', 'b', {'weight': 1}),
            ('a', 'q', {'weight': 1}),
            ('a', 's', {'weight': 2})]

            inf_list=list()
            prov_list=list()
            weight_list=list()

            for tuple in x:
            inf_list.append(tuple[0])
            prov_list.append(tuple[1])
            weight_list.append(tuple[2])

            df=pd.DataFrame()
            df['inf']=inf_list
            df['prov']=prov_list
            df['weight']=weight_list

            df['weight']=df['weight'].map(lambda x:x['weight'])

            print(df)





            share|improve this answer





















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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

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              active

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              up vote
              1
              down vote













              It is probably easiest to simplify the data a bit first before creating the dataframe.
              Depending on the operation that gave you the initial data (a list of tuples, each one containing 2 strings and a dict), it may be possible to have that operation give you simplified data. But in the case that this is not possible -- or more generally, when you don't have control over data structures generated by a given library, you can do some simple manipulations, e.g. like this:



              import pandas as pd
              # initial data from qu
              raw_data = [('a', 'a', {'weight': 2}),
              ('a', '!', {'weight': 0}),
              ('a', 'c', {'weight': 2}),
              ('a', 'b', {'weight': 1}),
              ('a', 'q', {'weight': 1}),
              ('a', 's', {'weight': 2}),]

              # transform data to extract the value of each weight
              data = [(elem1, elem2, d_elem.get('weight', 0)) for (elem1, elem2, d_elem) in raw_data]

              # put together the dataframe from the list of records
              df = pd.DataFrame.from_records(data, columns=['Inf', 'Prov', 'Weight'])
              print(df)


              gives the result as desired:



                Inf Prov  Weight
              0 a a 2
              1 a ! 0
              2 a c 2
              3 a b 1
              4 a q 1
              5 a s 2


              using dict.get allows us to specify a default value if it is not defined, rather than raising a KeyError.






              share|improve this answer

























                up vote
                1
                down vote













                It is probably easiest to simplify the data a bit first before creating the dataframe.
                Depending on the operation that gave you the initial data (a list of tuples, each one containing 2 strings and a dict), it may be possible to have that operation give you simplified data. But in the case that this is not possible -- or more generally, when you don't have control over data structures generated by a given library, you can do some simple manipulations, e.g. like this:



                import pandas as pd
                # initial data from qu
                raw_data = [('a', 'a', {'weight': 2}),
                ('a', '!', {'weight': 0}),
                ('a', 'c', {'weight': 2}),
                ('a', 'b', {'weight': 1}),
                ('a', 'q', {'weight': 1}),
                ('a', 's', {'weight': 2}),]

                # transform data to extract the value of each weight
                data = [(elem1, elem2, d_elem.get('weight', 0)) for (elem1, elem2, d_elem) in raw_data]

                # put together the dataframe from the list of records
                df = pd.DataFrame.from_records(data, columns=['Inf', 'Prov', 'Weight'])
                print(df)


                gives the result as desired:



                  Inf Prov  Weight
                0 a a 2
                1 a ! 0
                2 a c 2
                3 a b 1
                4 a q 1
                5 a s 2


                using dict.get allows us to specify a default value if it is not defined, rather than raising a KeyError.






                share|improve this answer























                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  It is probably easiest to simplify the data a bit first before creating the dataframe.
                  Depending on the operation that gave you the initial data (a list of tuples, each one containing 2 strings and a dict), it may be possible to have that operation give you simplified data. But in the case that this is not possible -- or more generally, when you don't have control over data structures generated by a given library, you can do some simple manipulations, e.g. like this:



                  import pandas as pd
                  # initial data from qu
                  raw_data = [('a', 'a', {'weight': 2}),
                  ('a', '!', {'weight': 0}),
                  ('a', 'c', {'weight': 2}),
                  ('a', 'b', {'weight': 1}),
                  ('a', 'q', {'weight': 1}),
                  ('a', 's', {'weight': 2}),]

                  # transform data to extract the value of each weight
                  data = [(elem1, elem2, d_elem.get('weight', 0)) for (elem1, elem2, d_elem) in raw_data]

                  # put together the dataframe from the list of records
                  df = pd.DataFrame.from_records(data, columns=['Inf', 'Prov', 'Weight'])
                  print(df)


                  gives the result as desired:



                    Inf Prov  Weight
                  0 a a 2
                  1 a ! 0
                  2 a c 2
                  3 a b 1
                  4 a q 1
                  5 a s 2


                  using dict.get allows us to specify a default value if it is not defined, rather than raising a KeyError.






                  share|improve this answer












                  It is probably easiest to simplify the data a bit first before creating the dataframe.
                  Depending on the operation that gave you the initial data (a list of tuples, each one containing 2 strings and a dict), it may be possible to have that operation give you simplified data. But in the case that this is not possible -- or more generally, when you don't have control over data structures generated by a given library, you can do some simple manipulations, e.g. like this:



                  import pandas as pd
                  # initial data from qu
                  raw_data = [('a', 'a', {'weight': 2}),
                  ('a', '!', {'weight': 0}),
                  ('a', 'c', {'weight': 2}),
                  ('a', 'b', {'weight': 1}),
                  ('a', 'q', {'weight': 1}),
                  ('a', 's', {'weight': 2}),]

                  # transform data to extract the value of each weight
                  data = [(elem1, elem2, d_elem.get('weight', 0)) for (elem1, elem2, d_elem) in raw_data]

                  # put together the dataframe from the list of records
                  df = pd.DataFrame.from_records(data, columns=['Inf', 'Prov', 'Weight'])
                  print(df)


                  gives the result as desired:



                    Inf Prov  Weight
                  0 a a 2
                  1 a ! 0
                  2 a c 2
                  3 a b 1
                  4 a q 1
                  5 a s 2


                  using dict.get allows us to specify a default value if it is not defined, rather than raising a KeyError.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 15 at 11:19









                  Bonlenfum

                  11k13041




                  11k13041
























                      up vote
                      0
                      down vote













                      import pandas as pd
                      x=[('a', 'a', {'weight': 2}),
                      ('a', '!', {'weight': 0}),
                      ('a', 'c', {'weight': 2}),
                      ('a', 'b', {'weight': 1}),
                      ('a', 'q', {'weight': 1}),
                      ('a', 's', {'weight': 2})]

                      inf_list=list()
                      prov_list=list()
                      weight_list=list()

                      for tuple in x:
                      inf_list.append(tuple[0])
                      prov_list.append(tuple[1])
                      weight_list.append(tuple[2])

                      df=pd.DataFrame()
                      df['inf']=inf_list
                      df['prov']=prov_list
                      df['weight']=weight_list

                      df['weight']=df['weight'].map(lambda x:x['weight'])

                      print(df)





                      share|improve this answer

























                        up vote
                        0
                        down vote













                        import pandas as pd
                        x=[('a', 'a', {'weight': 2}),
                        ('a', '!', {'weight': 0}),
                        ('a', 'c', {'weight': 2}),
                        ('a', 'b', {'weight': 1}),
                        ('a', 'q', {'weight': 1}),
                        ('a', 's', {'weight': 2})]

                        inf_list=list()
                        prov_list=list()
                        weight_list=list()

                        for tuple in x:
                        inf_list.append(tuple[0])
                        prov_list.append(tuple[1])
                        weight_list.append(tuple[2])

                        df=pd.DataFrame()
                        df['inf']=inf_list
                        df['prov']=prov_list
                        df['weight']=weight_list

                        df['weight']=df['weight'].map(lambda x:x['weight'])

                        print(df)





                        share|improve this answer























                          up vote
                          0
                          down vote










                          up vote
                          0
                          down vote









                          import pandas as pd
                          x=[('a', 'a', {'weight': 2}),
                          ('a', '!', {'weight': 0}),
                          ('a', 'c', {'weight': 2}),
                          ('a', 'b', {'weight': 1}),
                          ('a', 'q', {'weight': 1}),
                          ('a', 's', {'weight': 2})]

                          inf_list=list()
                          prov_list=list()
                          weight_list=list()

                          for tuple in x:
                          inf_list.append(tuple[0])
                          prov_list.append(tuple[1])
                          weight_list.append(tuple[2])

                          df=pd.DataFrame()
                          df['inf']=inf_list
                          df['prov']=prov_list
                          df['weight']=weight_list

                          df['weight']=df['weight'].map(lambda x:x['weight'])

                          print(df)





                          share|improve this answer












                          import pandas as pd
                          x=[('a', 'a', {'weight': 2}),
                          ('a', '!', {'weight': 0}),
                          ('a', 'c', {'weight': 2}),
                          ('a', 'b', {'weight': 1}),
                          ('a', 'q', {'weight': 1}),
                          ('a', 's', {'weight': 2})]

                          inf_list=list()
                          prov_list=list()
                          weight_list=list()

                          for tuple in x:
                          inf_list.append(tuple[0])
                          prov_list.append(tuple[1])
                          weight_list.append(tuple[2])

                          df=pd.DataFrame()
                          df['inf']=inf_list
                          df['prov']=prov_list
                          df['weight']=weight_list

                          df['weight']=df['weight'].map(lambda x:x['weight'])

                          print(df)






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 29 at 21:03









                          Mohammad Hoseini

                          214




                          214






























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