Python: Convert Edgelist from NetworkX into dataframe
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1
down vote
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I have a weird data structure (don't know if it's a list or tuple) as a results of using Networkx. I need to convert it into a dataframe.
The 'list' I have, has the following structure:
[('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2}),... ]
and I need a dataframe as follows:
Inf Prov Weight
a a 2
a ! 0
a c 2
a b 1
a q 1
a s 2
Can somebody give me hand, please?
python list dataframe tuples networkx
add a comment |
up vote
1
down vote
favorite
I have a weird data structure (don't know if it's a list or tuple) as a results of using Networkx. I need to convert it into a dataframe.
The 'list' I have, has the following structure:
[('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2}),... ]
and I need a dataframe as follows:
Inf Prov Weight
a a 2
a ! 0
a c 2
a b 1
a q 1
a s 2
Can somebody give me hand, please?
python list dataframe tuples networkx
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have a weird data structure (don't know if it's a list or tuple) as a results of using Networkx. I need to convert it into a dataframe.
The 'list' I have, has the following structure:
[('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2}),... ]
and I need a dataframe as follows:
Inf Prov Weight
a a 2
a ! 0
a c 2
a b 1
a q 1
a s 2
Can somebody give me hand, please?
python list dataframe tuples networkx
I have a weird data structure (don't know if it's a list or tuple) as a results of using Networkx. I need to convert it into a dataframe.
The 'list' I have, has the following structure:
[('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2}),... ]
and I need a dataframe as follows:
Inf Prov Weight
a a 2
a ! 0
a c 2
a b 1
a q 1
a s 2
Can somebody give me hand, please?
python list dataframe tuples networkx
python list dataframe tuples networkx
asked Nov 15 at 1:37
PAstudilloE
127111
127111
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2 Answers
2
active
oldest
votes
up vote
1
down vote
It is probably easiest to simplify the data a bit first before creating the dataframe.
Depending on the operation that gave you the initial data (a list of tuples, each one containing 2 strings and a dict), it may be possible to have that operation give you simplified data. But in the case that this is not possible -- or more generally, when you don't have control over data structures generated by a given library, you can do some simple manipulations, e.g. like this:
import pandas as pd
# initial data from qu
raw_data = [('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2}),]
# transform data to extract the value of each weight
data = [(elem1, elem2, d_elem.get('weight', 0)) for (elem1, elem2, d_elem) in raw_data]
# put together the dataframe from the list of records
df = pd.DataFrame.from_records(data, columns=['Inf', 'Prov', 'Weight'])
print(df)
gives the result as desired:
Inf Prov Weight
0 a a 2
1 a ! 0
2 a c 2
3 a b 1
4 a q 1
5 a s 2
using dict.get
allows us to specify a default value if it is not defined, rather than raising a KeyError.
add a comment |
up vote
0
down vote
import pandas as pd
x=[('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2})]
inf_list=list()
prov_list=list()
weight_list=list()
for tuple in x:
inf_list.append(tuple[0])
prov_list.append(tuple[1])
weight_list.append(tuple[2])
df=pd.DataFrame()
df['inf']=inf_list
df['prov']=prov_list
df['weight']=weight_list
df['weight']=df['weight'].map(lambda x:x['weight'])
print(df)
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
It is probably easiest to simplify the data a bit first before creating the dataframe.
Depending on the operation that gave you the initial data (a list of tuples, each one containing 2 strings and a dict), it may be possible to have that operation give you simplified data. But in the case that this is not possible -- or more generally, when you don't have control over data structures generated by a given library, you can do some simple manipulations, e.g. like this:
import pandas as pd
# initial data from qu
raw_data = [('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2}),]
# transform data to extract the value of each weight
data = [(elem1, elem2, d_elem.get('weight', 0)) for (elem1, elem2, d_elem) in raw_data]
# put together the dataframe from the list of records
df = pd.DataFrame.from_records(data, columns=['Inf', 'Prov', 'Weight'])
print(df)
gives the result as desired:
Inf Prov Weight
0 a a 2
1 a ! 0
2 a c 2
3 a b 1
4 a q 1
5 a s 2
using dict.get
allows us to specify a default value if it is not defined, rather than raising a KeyError.
add a comment |
up vote
1
down vote
It is probably easiest to simplify the data a bit first before creating the dataframe.
Depending on the operation that gave you the initial data (a list of tuples, each one containing 2 strings and a dict), it may be possible to have that operation give you simplified data. But in the case that this is not possible -- or more generally, when you don't have control over data structures generated by a given library, you can do some simple manipulations, e.g. like this:
import pandas as pd
# initial data from qu
raw_data = [('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2}),]
# transform data to extract the value of each weight
data = [(elem1, elem2, d_elem.get('weight', 0)) for (elem1, elem2, d_elem) in raw_data]
# put together the dataframe from the list of records
df = pd.DataFrame.from_records(data, columns=['Inf', 'Prov', 'Weight'])
print(df)
gives the result as desired:
Inf Prov Weight
0 a a 2
1 a ! 0
2 a c 2
3 a b 1
4 a q 1
5 a s 2
using dict.get
allows us to specify a default value if it is not defined, rather than raising a KeyError.
add a comment |
up vote
1
down vote
up vote
1
down vote
It is probably easiest to simplify the data a bit first before creating the dataframe.
Depending on the operation that gave you the initial data (a list of tuples, each one containing 2 strings and a dict), it may be possible to have that operation give you simplified data. But in the case that this is not possible -- or more generally, when you don't have control over data structures generated by a given library, you can do some simple manipulations, e.g. like this:
import pandas as pd
# initial data from qu
raw_data = [('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2}),]
# transform data to extract the value of each weight
data = [(elem1, elem2, d_elem.get('weight', 0)) for (elem1, elem2, d_elem) in raw_data]
# put together the dataframe from the list of records
df = pd.DataFrame.from_records(data, columns=['Inf', 'Prov', 'Weight'])
print(df)
gives the result as desired:
Inf Prov Weight
0 a a 2
1 a ! 0
2 a c 2
3 a b 1
4 a q 1
5 a s 2
using dict.get
allows us to specify a default value if it is not defined, rather than raising a KeyError.
It is probably easiest to simplify the data a bit first before creating the dataframe.
Depending on the operation that gave you the initial data (a list of tuples, each one containing 2 strings and a dict), it may be possible to have that operation give you simplified data. But in the case that this is not possible -- or more generally, when you don't have control over data structures generated by a given library, you can do some simple manipulations, e.g. like this:
import pandas as pd
# initial data from qu
raw_data = [('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2}),]
# transform data to extract the value of each weight
data = [(elem1, elem2, d_elem.get('weight', 0)) for (elem1, elem2, d_elem) in raw_data]
# put together the dataframe from the list of records
df = pd.DataFrame.from_records(data, columns=['Inf', 'Prov', 'Weight'])
print(df)
gives the result as desired:
Inf Prov Weight
0 a a 2
1 a ! 0
2 a c 2
3 a b 1
4 a q 1
5 a s 2
using dict.get
allows us to specify a default value if it is not defined, rather than raising a KeyError.
answered Nov 15 at 11:19
Bonlenfum
11k13041
11k13041
add a comment |
add a comment |
up vote
0
down vote
import pandas as pd
x=[('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2})]
inf_list=list()
prov_list=list()
weight_list=list()
for tuple in x:
inf_list.append(tuple[0])
prov_list.append(tuple[1])
weight_list.append(tuple[2])
df=pd.DataFrame()
df['inf']=inf_list
df['prov']=prov_list
df['weight']=weight_list
df['weight']=df['weight'].map(lambda x:x['weight'])
print(df)
add a comment |
up vote
0
down vote
import pandas as pd
x=[('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2})]
inf_list=list()
prov_list=list()
weight_list=list()
for tuple in x:
inf_list.append(tuple[0])
prov_list.append(tuple[1])
weight_list.append(tuple[2])
df=pd.DataFrame()
df['inf']=inf_list
df['prov']=prov_list
df['weight']=weight_list
df['weight']=df['weight'].map(lambda x:x['weight'])
print(df)
add a comment |
up vote
0
down vote
up vote
0
down vote
import pandas as pd
x=[('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2})]
inf_list=list()
prov_list=list()
weight_list=list()
for tuple in x:
inf_list.append(tuple[0])
prov_list.append(tuple[1])
weight_list.append(tuple[2])
df=pd.DataFrame()
df['inf']=inf_list
df['prov']=prov_list
df['weight']=weight_list
df['weight']=df['weight'].map(lambda x:x['weight'])
print(df)
import pandas as pd
x=[('a', 'a', {'weight': 2}),
('a', '!', {'weight': 0}),
('a', 'c', {'weight': 2}),
('a', 'b', {'weight': 1}),
('a', 'q', {'weight': 1}),
('a', 's', {'weight': 2})]
inf_list=list()
prov_list=list()
weight_list=list()
for tuple in x:
inf_list.append(tuple[0])
prov_list.append(tuple[1])
weight_list.append(tuple[2])
df=pd.DataFrame()
df['inf']=inf_list
df['prov']=prov_list
df['weight']=weight_list
df['weight']=df['weight'].map(lambda x:x['weight'])
print(df)
answered Nov 29 at 21:03
Mohammad Hoseini
214
214
add a comment |
add a comment |
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