Inproper Extreme Value Distribution of Type I (Gumbel) or badly estimated parameters?











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I would appreciate a leadverification on the following excercise.



Let $W$ denote the anual maximum wind load. The anual maximum of $W$ is distributed according to an asymptotic extreme value distribution of type I (Gumbel) with mean $mu_{W}=0.89,text{kN}/text{mm }^{2}$ and standard deviation $sigma_{W}=0.33,text{kN}/text{mm}^{2}$.



The probability density function is then given by $$fleft(wright)=frac{1}{beta}expleft[-frac{w-alpha}{beta}right]expleft[-expleft[-frac{w-alpha}{beta}right]right].$$



The mean of the Gumbel-distribution ia given by $mu_W=alpha +gamma beta$ while standard deviation is given by $sigma_W=frac{pi beta }{sqrt{6}}$. Thus, one has to calculate the location parameter $alpha$ and the scale parameter $beta$,



begin{aligned}beta=sqrt{6}frac{sigma_{W}}{pi}=0.257 & , & alpha & =mu_{W}-gammacdotbeta=0.741.end{aligned}.



However, calculating $frac{partial f}{partial w}=frac{1}{beta^{2}}expleft[frac{alpha-betaexpleft[frac{alpha-w}{beta}right]-2w}{beta}right]left(expleft[alpha/betaright]-expleft[w/betaright]right)equiv 0$, the maximum of $fleft(wright)$ is assumed at $w^ast=0.741482$, implying that $fleft(w^astright)=1.42977$ which is, of course, contrary to the definition of probabilit measures.



Now, was my approach wrong or was the parameters of excersise poorly chosen. However, I was thinking whether the appropriate distribution should be log-Gumbel as wind load cannot take values less then zero.



Thank you very much for your thoughts.



The plot of probability density function given mean $mu_W$ and standard deviation $omega_W$ using mathematica is given here.










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    I would appreciate a leadverification on the following excercise.



    Let $W$ denote the anual maximum wind load. The anual maximum of $W$ is distributed according to an asymptotic extreme value distribution of type I (Gumbel) with mean $mu_{W}=0.89,text{kN}/text{mm }^{2}$ and standard deviation $sigma_{W}=0.33,text{kN}/text{mm}^{2}$.



    The probability density function is then given by $$fleft(wright)=frac{1}{beta}expleft[-frac{w-alpha}{beta}right]expleft[-expleft[-frac{w-alpha}{beta}right]right].$$



    The mean of the Gumbel-distribution ia given by $mu_W=alpha +gamma beta$ while standard deviation is given by $sigma_W=frac{pi beta }{sqrt{6}}$. Thus, one has to calculate the location parameter $alpha$ and the scale parameter $beta$,



    begin{aligned}beta=sqrt{6}frac{sigma_{W}}{pi}=0.257 & , & alpha & =mu_{W}-gammacdotbeta=0.741.end{aligned}.



    However, calculating $frac{partial f}{partial w}=frac{1}{beta^{2}}expleft[frac{alpha-betaexpleft[frac{alpha-w}{beta}right]-2w}{beta}right]left(expleft[alpha/betaright]-expleft[w/betaright]right)equiv 0$, the maximum of $fleft(wright)$ is assumed at $w^ast=0.741482$, implying that $fleft(w^astright)=1.42977$ which is, of course, contrary to the definition of probabilit measures.



    Now, was my approach wrong or was the parameters of excersise poorly chosen. However, I was thinking whether the appropriate distribution should be log-Gumbel as wind load cannot take values less then zero.



    Thank you very much for your thoughts.



    The plot of probability density function given mean $mu_W$ and standard deviation $omega_W$ using mathematica is given here.










    share|cite|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I would appreciate a leadverification on the following excercise.



      Let $W$ denote the anual maximum wind load. The anual maximum of $W$ is distributed according to an asymptotic extreme value distribution of type I (Gumbel) with mean $mu_{W}=0.89,text{kN}/text{mm }^{2}$ and standard deviation $sigma_{W}=0.33,text{kN}/text{mm}^{2}$.



      The probability density function is then given by $$fleft(wright)=frac{1}{beta}expleft[-frac{w-alpha}{beta}right]expleft[-expleft[-frac{w-alpha}{beta}right]right].$$



      The mean of the Gumbel-distribution ia given by $mu_W=alpha +gamma beta$ while standard deviation is given by $sigma_W=frac{pi beta }{sqrt{6}}$. Thus, one has to calculate the location parameter $alpha$ and the scale parameter $beta$,



      begin{aligned}beta=sqrt{6}frac{sigma_{W}}{pi}=0.257 & , & alpha & =mu_{W}-gammacdotbeta=0.741.end{aligned}.



      However, calculating $frac{partial f}{partial w}=frac{1}{beta^{2}}expleft[frac{alpha-betaexpleft[frac{alpha-w}{beta}right]-2w}{beta}right]left(expleft[alpha/betaright]-expleft[w/betaright]right)equiv 0$, the maximum of $fleft(wright)$ is assumed at $w^ast=0.741482$, implying that $fleft(w^astright)=1.42977$ which is, of course, contrary to the definition of probabilit measures.



      Now, was my approach wrong or was the parameters of excersise poorly chosen. However, I was thinking whether the appropriate distribution should be log-Gumbel as wind load cannot take values less then zero.



      Thank you very much for your thoughts.



      The plot of probability density function given mean $mu_W$ and standard deviation $omega_W$ using mathematica is given here.










      share|cite|improve this question















      I would appreciate a leadverification on the following excercise.



      Let $W$ denote the anual maximum wind load. The anual maximum of $W$ is distributed according to an asymptotic extreme value distribution of type I (Gumbel) with mean $mu_{W}=0.89,text{kN}/text{mm }^{2}$ and standard deviation $sigma_{W}=0.33,text{kN}/text{mm}^{2}$.



      The probability density function is then given by $$fleft(wright)=frac{1}{beta}expleft[-frac{w-alpha}{beta}right]expleft[-expleft[-frac{w-alpha}{beta}right]right].$$



      The mean of the Gumbel-distribution ia given by $mu_W=alpha +gamma beta$ while standard deviation is given by $sigma_W=frac{pi beta }{sqrt{6}}$. Thus, one has to calculate the location parameter $alpha$ and the scale parameter $beta$,



      begin{aligned}beta=sqrt{6}frac{sigma_{W}}{pi}=0.257 & , & alpha & =mu_{W}-gammacdotbeta=0.741.end{aligned}.



      However, calculating $frac{partial f}{partial w}=frac{1}{beta^{2}}expleft[frac{alpha-betaexpleft[frac{alpha-w}{beta}right]-2w}{beta}right]left(expleft[alpha/betaright]-expleft[w/betaright]right)equiv 0$, the maximum of $fleft(wright)$ is assumed at $w^ast=0.741482$, implying that $fleft(w^astright)=1.42977$ which is, of course, contrary to the definition of probabilit measures.



      Now, was my approach wrong or was the parameters of excersise poorly chosen. However, I was thinking whether the appropriate distribution should be log-Gumbel as wind load cannot take values less then zero.



      Thank you very much for your thoughts.



      The plot of probability density function given mean $mu_W$ and standard deviation $omega_W$ using mathematica is given here.







      probability-distributions stochastic-calculus extreme-value-theorem






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      edited Nov 17 at 15:11









      Bernard

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      116k637108










      asked Nov 17 at 15:08









      Clemens Söhnchen

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