Derivative of a scalar function with respect to a contravariant vector
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So in the steps below, a scalar function, $f(x^2)$, is partial differentiated with respect to a contravarient vector:
Where η is the metric tensor used for special relativity. I understand all the steps in this derivation but I have no idea how the initial step (196) is achieved. May someone explain or show the steps for this please?
Thank you for your time.
calculus partial-derivative tensors special-relativity
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up vote
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So in the steps below, a scalar function, $f(x^2)$, is partial differentiated with respect to a contravarient vector:
Where η is the metric tensor used for special relativity. I understand all the steps in this derivation but I have no idea how the initial step (196) is achieved. May someone explain or show the steps for this please?
Thank you for your time.
calculus partial-derivative tensors special-relativity
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
So in the steps below, a scalar function, $f(x^2)$, is partial differentiated with respect to a contravarient vector:
Where η is the metric tensor used for special relativity. I understand all the steps in this derivation but I have no idea how the initial step (196) is achieved. May someone explain or show the steps for this please?
Thank you for your time.
calculus partial-derivative tensors special-relativity
So in the steps below, a scalar function, $f(x^2)$, is partial differentiated with respect to a contravarient vector:
Where η is the metric tensor used for special relativity. I understand all the steps in this derivation but I have no idea how the initial step (196) is achieved. May someone explain or show the steps for this please?
Thank you for your time.
calculus partial-derivative tensors special-relativity
calculus partial-derivative tensors special-relativity
asked Nov 17 at 15:20
s.twenty
104
104
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